GE 6163 - Physics Lab Manual.pdf
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Transcript of GE 6163 - Physics Lab Manual.pdf
SI.No Name of the Experiments
MEASUREING INSTRUMENTS
M1 VERNIER CALIPER
M2 SCREW GAUGE
M3 TRAVELLING MICROSCOPE
M4 SPECTROMETER
PHYSICS LABORATORY - I
1.(A)
1.(B)
1.(C)
LASER PARAMETERS
PARTICLE SIZE – DETERMINATION BY DIODE LASER
DETERMINATION OF NUMERICAL APERTURE AND
ACCEPTANCE ANGLE – OPTICAL FIBER
2. SPECTROMETER - GRATING
3.
THERMAL CONDUCTIVITY OF A BAD CONDUCTOT –
LEE’S DISC
4.
AIR - WEDGE
5. ULTRASONIC - INTERFEROMETER
KININDIA
M1 SCREW GAUGE
ZERO ERROR & ZERO CORRECTION
Pitch = Distance moved by the head scale on the pitch scale
No .of the Rotations given
LEAST COUNT = Pitch / Total no.of divisions on the head scale = 1 m.m / 100
L.C = 0.01 mm or 0.01×10-3
m
KININDIA
M2 VERNIER CALIPERS
Jaws in different
positions
LEAST COUNT = 1 Main scale division – 1 Vernier scale Division
= 1MSD – 1VSD
Value of 1 MSD = 1/10 cm = 0.1×10-2
m
No of divisions on vernier scale = 10
9MSD = 10VSD ; 1VSD = (9/10)MSD = (9/10)(1/10) = 9/100 cm
Therefore L.C = 0.01 cm or 0.01×10-2
m
KININDIA
M3 TRAVELLING MICROSCOPE
Least count = 1MSD – 1VSD
20 MSD = 1cm
Value of 1 MSD = 1/20 cm = 0.05 cm
No.of divisions in vernier scale = 50
50VSD = 49 MSD
Therefore 1VSD = (49/50)MSD = (49/50)0.05 = 0.049
LC = 0.05 – 0.049 = 0.001 cm ]
L.C = 0.001×10-2
m
KININDIA
M4 SPECTROMETER
Least count.
20 MSD = 10°
1MSD = 1°/ 2 = 0.5° = 30’
LC = 1MSD – 1VSD
No of Divisions in Vernier scale = 30
30VSD = 29MSD
1VSD = (29/30)MSD = 29’
LC = 30’ – 29’
LC = 1’( ONE MINUTE)
KININDIA
E 01 SEMICONDUCTOR LASER
Aim:
a. To determine the wavelength of the Laser light.
b. To determine the size of the particle.
c. To find out acceptance angle and Numerical aperture of the fiber.
Apparatus Required:
Diode laser, Fine micro particles nearly like same size ( Lycopodium powder), Glass plate,
Screen , Meter scale
Formula:
a. Wavelength of the Laser source = sin n m
b. Particle size d is given by d = nD / xn m
c. Acceptance angle r / d
Numerical aperture NA = sin
Angle of the diffraction degree
N = Number of lines per meter in the grating
n = order of diffraction.
Wavelength of laser light used. m
D = distance between glass plate and the screen. m
xn = Distance between central bright spot and the nth
ring. m
r = Radius of the circular image. m
d = Distance from fiber end to circular image.m
KININDIA
Wavelength of LASER
Size of the particle
Diffraction pattern
KININDIA
Angle of divergence
Numerical Aperture
KININDIA
Procedure:
a. Wavelength of the Laser source
The grating is kept in between the source and the screen at a distance , D, from the
screen. When the laser beam passes though the grating, diffraction occurs and spots are
seen on the screen.
The positions of 1st , 2
nd , 3
rd ……. Order spots are measured from the central (direct)
spot by measuring on both sides.
b. Particle size.
The grating is removed and a glass plate on which lycopodium powder is sprinkled is
placed. Its position is adjusted to clear diffraction rings. The radii of 1st, 2
nd, 3
rd, .order
rings are measured. If D1 is the distance between the glass plate and screen, the size of
the particle
c. Acceptance angle and Numerical aperture
One end of the fiber is connected to the source and the other end to a NA jig Light
through the fiber passes the aperture of the Jig and a circular patch is seen on the screen.
The opening is slowly closed so that the circular patch just cuts. If r is the radius of
opening and l is the distance between jig and fiber tip , the acceptance angle = r/l and
NA = Sin. This is repeated for different l.
KININDIA
DETERMINATION OF WAVELENGTH OF LASER LIGHT SOURSE-
OBSERVATIONS
Distance between grating and screen (D) = ……………… cm = ………………. x 10-2
m
Number of lines in grating per meter = …………………………lines / meter
Particle size determination – observation
S.No
Order of
diffraction
(n)
Readings for the diffracted image
Mean
θ λ
Left side Right side
Distance of
different
orders (Xn)
from the
central spot
Tan θ1 θ1
Distance
of
different
order
(Xn) from
the spot
Tan θ2 θ2
Unit cm cm (nm)
1. 1 X1= X1=
2. 2 X2= X2=
3. 3 X3= X3=
4. 4 X4= X4=
SI.NO.
Distance between
screen and glass
plate (D)
Order of
diffraction
n
Distance between
the central bright
point and nth fringe
xn
Particle size
Unit Cm cm cm
1
1
2
3
2
1
2
3
3
1
2
3
Mean = ………………………….. KININDIA
Wavelength of laser source λ = 6900 A˚
= 6900 x 10-10
meter
To determine acceptance angle and numerical aperture
S.No.
Distance from
the fiber end to
circular image
‘d’
Radius of the
circular image ‘r’
Acceptance
angle
NA = sin θa
Mean
Result:
Wavelength of the laser light source = ---------------- m
Average size of the particle = -----------------------m
Numerical aperture of the optical fiber = ------------
Acceptance angle of the optical fiber = --------------
KININDIA
E 02 - SPECTROMETER (GRATING)
Aim: To determine the wavelength of the lines of the mercury spectrum.
Apparatus Required: Spectrometer, Grating , Sodium vapour lamp , Mercury
vapour lamp, Reading lens.
Formula:
The number of lines of grating = N = Sins n
s = wavelength of the sodium light
n = order of diffraction
Angle of diffraction
The wavelength of the prominent spectral
Lines of the mercury spectrum
Hg = Sinn N 10-10
m
Procedure: Preliminary adjustments are made with the spectrometer. The direct ray is made to
coincide with the vertical crosswire of the telescope. The vernier scales are adjusted to read 00
and 1800. The telescope is rotated through 90
0 and fixed. The grating is mounted on the grating
table and adjusted so that the reflected ray coincides with the cross wire. The vernier table is
rotated through 450. Now, the light is incident normal to grating. This is normal incidence.
The slit is illuminated with sodium vapor lamp. The telescope is released and rotated to get the
diffracted light on either side (left & right). The readings are taken on Vernier A and Vernier B. KININDIA
The difference in readings on both the scales for the two sides gives 2. Hence is noted.
Next the sodium lamp is replaced by Hg lamp and for each line is measured as before and
for each line is calculated from the relation
Determination of wavelength of various spectral lines – Spectrometer readings
N = ………………..lines/metre Order of the spectrum n = ……1….
Total readings (TR) = MSR +(VSR x LC) Least count (LC) = 1’
Spectral
lines
(colours)
Reading for the diffracted image Diffference
between the
readings Mean
2θ
Mean
θ λ
Left side Right side
Vernier A
A1 Vernier B B1 Vernier A A2 Vernier B B 2 2θ
A1~A2
2θ
B1~B2 MSR VSC TR MSR VSC TR MSR VSC TR MSR VSC TR
deg div deg deg Div deg deg div Deg deg div deg
Violet-1
Violet-2
Blue Bluiesh
Green
Green
Yellow-
1
Yellow-
2
Red
Result:
The wavelength of the prominent spectral lines in the mercury source are calculated and
tabulated. KININDIA
E 03 - Lees disc
Aim: To measure the thermal conductivity of a bad conductor (Cardboard,
Glass etc)
Apparatus Required: Lees Disc apparatus, Bad conductors, Thermometers, Stop-clock, Steam
boiler, Screw gauge, Vernier calipers
Formula: Thermal conductivity of a bad conductor.
MS { d dt } .d ( r + 2h)
K = ------------------------------- Wm-1
K-1
R2 ( 1 - 2 ) ( 2R + H)
M = mass of the disc
S = specific heat of the disc
D = thickness of the bad conductor (m)
R = radius of the disc (m)
H = thickness of disc (m)
KININDIA
Procedure:
This consists of a hot chamber and a metal disc. The material is placed in between the chamber
and the metal disc.
Steam from water heater is passed through the chamber. Heat is conducted to the disc through
the bad conductor. The steady state temperature 1 (of the chamber) and 2 (of the disc) are
noted.
Now, the bad conductor is removed and the disc is heated by placing the chamber directly on the
disc. When the temperature of the disc is 2 + 100 (say ), the chamber is removed and disc is
allowed to cool. When the temperature of the disc is 2 + 50 , stop warch is started and the time
is noted in steps for every degree upto 2 - 50C. A graph is drawn between time
vs temperature and slope d/dt at 2 is found out.
MEASUREMENT OF THE RADIUS OF THE METALLIC DISC (r)
Z.E = ±----------- div
L.C = 0.01×102m Z.C = ± -----------div
S.No MSR VSC OBSERVED READING =
MSR+VSC(LC)
CORRECT
READING
= OR + ZC
Unit ×102m div ×10
-2m ×10
-2m
1
2
3
4
5
Mean Diameter ‘D’ = ---------×10-2
m
KININDIA
TO FIND THE THICKNESS OF THE BAD CONDUCTOR (d)
Z.E = ±----------- div
L.C = 0.01×102m Z.C = ± -----------div
S.No PSR HSC OBSERVED READING =
PSR+HSC(LC)
CORRECT
READING
= OR + ZC
Unit ×103m Div ×10
-3m ×10
-3m
1
2
3
4
5
Mean thickness‘d’ = ---------×10-3
m
TO FIND THE THICKNESS OF THE METALLIC DISC (h)
S.No PSR HSC OBSERVED READING =
PSR+HSC(LC)
CORRECT
READING
= OR + ZC
Unit ×103m Div ×10
-3m ×10
-3m
1
2
3
4
5
Mean thickness‘d’ = ---------×10-3
m
KININDIA
DETERMINATION OF THE RATE OF COOLING OF METALLIC DISC. { d dt }
Steady temperature in the metallic disc ( 2) = -----------------0C
TEMPERATURE TIME (t) TEMPERATURE( TIME(t)
0C Second
0C Second
Result
Thermal conductivity of the bad conductor = …………………………W m-1
K-1
KININDIA
E 04 - AIR WEDGE
Aim: To determine the thickness of a thin wire by Air Wedge.
Apparatus Required:
Travelling microscope, Sodium vapor lamp, Two optically plane glass plate, Condensing lens,
Thin wire, Reading lens.
Formula:
Thickness of the thin wire T = L 2 m
= wavelength of the light.
L = Distance of the wire from the edge of contact
Mean width of one fringe
Procedure
The wire is introduced at one end between two optically plane glass plates. A parallel beam of
monochromatic light is incident on this at right angles. The rays of light reflected from the front
and back surfaces interfere and produce dark and bright fringes. The vertical cross-wire of the
travelling microscope is made to coincide with nth , n + 5th
, n + 10th
etc fringes and readings
are taken. From this , the fringe width , , is calculated.
KININDIA
TO FIND THE FRINGE WIDTH: LC= 0.001 cm
Order of the
band
Microscope Readings Width of 5
bands
Mean Width
of one fringe
( ) MSR VSC TR =
MSR+(VSC×LC)
Unit ×102m Div ×10
2m ×10
2m ×10
2m
n
n+5
n+10
n+15
n+20
n+25
n+30
n+35
n+40
n+45
Mean fringe Width = --------×102m
To determine the distance between edge of contact and specimen wire
Position MSR VSC TR=MSR+(VSC+LC)
×102m Div ×10
2m
Rubber band
(edge of contact)
R1
Specimen wire R2
L = R1- R2 = ----------------------------×102m
Result :
Thickness of the given thin wire = ---------------- meter
KININDIA
E 05 - ULTRASONIC INTERFEROMETER
Aim: To determine the Ultrasonic velocity and compressibility of liquids.
Apparatus Required: Ultrasonic interferometer, Wave generator, Liquids.
Formula:
Wavelength of the Ultrasonic waves = d/n m
Velocity in liquid u = s frequency of crystal ms-1
Compressibility of the liquid = K = 1 / u2 m
2 N
-1
d = Distance moved by the reflector
n = Number of oscillations
ρ = Density of the liquid Kg / m3
Procedure:
The liquid is taken in the cell. This has a crystal transducer at the bottom and a metal reflector
attached to a micrometer screw is immersed. When the reflector is moved, the ammeter shows
maximum when the distance between the crystal and reflector is equal to whole multiplies by
sound due to the formation of standing waves.
The micrometer reading is noted for a particular maximum in the ammeter. Then readings are
noted for every five maxima. The difference in reading for two consecutive maxima gives
sound / 2. Thus sound is measured.
KININDIA
TO FIND THE WAVELENGTH OF THE ULTRASONIC WAVES
Type of liquid = Water
Frequency of the generator (f) = 2 MHz (Constant value as per the experimenmtal set up )
Least Count (LC) = 0.01 mm
Total Readings (TR) = PSR + (HSC x LC)
S.No No.of
oscillation
(n)
Readings for ‘n’ oscillations Distance
moved by
reflector d
= R1-R2
Wave
length
d/n
Initial reading(R1) Initial reading(R2)
PSR HSC TR PSR HSC TR
×10-
3m
div ×10-
3m
×10-
3m
div ×10-
3m
×10-3
m ×10-3
m
1
2
3
4
5
Mean(m/s
Result :
Velocity of the Ultrasonic waves in the liquid = --------------------------- m/s
Compressibility of the given liquid = ----------------------- m2 N
-1
KININDIA