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Transcript of funmilayo
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Head Losses - compressible fluid (ga
A) Calculation of Head losses , knowing the inlet condition and
Input data
piping
material cs
rugosity 5.00E-02
diameter D 219.70
length L 2000.00
loss friction ki 0.00
fittings
fluid viscosiy 0.01Molecular weight Mw 21.68
Compressibility Z 0.94
Temperature T 27.00
Pressure inlet P1 41000.00
process
flowrate inlet Qv1 1953.00
others perfect gas cte 8.31
output data
density (T1,P1) 1 37.903
G 5.424E+02
Re 10833244
B 1.01E+22
fdarcy 0.01422
velocity U1 14.31
head loss P 538790
5458
Pressure outlet P2 356121035612
density(T1,P2) 2 32.92
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B) Calculation of flow rate , knowing the inlet and outlet Press
Input data
piping
material SS
rugosity 1.00E-03
diameter D 800.00
length L 200.00
loss friction ki 5.00
fittings
fluid viscosiy 0.01
Molecular weight Mw 44.00
Compressibility Z 1.00Temperature T 45.00
Pressure inlet P1 2600.00
Pressure outlet P2 2402.00
process
estimate friction fvk (-2log10((/D)/3.7)))^-2
factor .Von karman
others perfect gas cte 8.31
output data
density (T1,P1) 1 4.326
G 1.512E+02
Re 10998132
B 8.29E+23
fdarcy 0.00819
velocity U1 34.96
Volumetric flow Qv1 18
density(T1,P2) 2 4.00
U2 38
Volumetric flow Qv2 19
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)
the piping arrangement
engineering SI energy balance to solve :
units units
*dP+G^2*ln( 1/2 ) + (f*L/D+ki)*
mm 5.00E-05 SI
mm 2.20E-01 SI after integration with T=cte
m 2.00E+03 SI
M/(Z*R*T)*(P2^2-P1^2)+2*G^2* Ln(P1
unitless 0.00 unitless or
to solve : F(p2) =0
with F'(p2)
cpo 1.10E-05 SI Newton Raphson : P2(n+1)=P2(g/mol 2.17E-02 SI
0.94
C 300.15 K P1 P2 (n) A B
mbars 4.10E+06 Pa 4.1000E+06 4.0590E+06 9.2446E-06 5.8840E+05
3.5919E+06 9.2446E-06 5.8840E+05
3.5613E+06 9.2446E-06 5.8840E+05
m3/h 5.43E-01 SI 3.5612E+06 9.2446E-06 5.8840E+05
3.5612E+06 9.2446E-06 5.8840E+05
SI 8.31E+00 SI 3.5612E+06 9.2446E-06 5.8840E+05
3.5612E+06 9.2446E-06 5.8840E+05
3.5612E+06 9.2446E-06 5.8840E+05
3.5612E+06 9.2446E-06 5.8840E+05
3.5612E+06 9.2446E-06 5.8840E+05
3.5612E+06 9.2446E-06 5.8840E+05
kg/m3
kg/s/m2
unitless
unitless
m/s
Pa
mbars
Pambars
kg/m3
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ure and the piping arrangement
engineering SI energy balance to solve :
units units
*dP+G^2*ln( 1/2 ) + (f*L/D+ki)*
mm 1.00E-06 SI
mm 8.00E-01 SI after integration with T=cte
m 2.00E+02 SI
M/(Z*R*T)*(P2^2-P1^2)+2*G^2* Ln(P1
unitless 5.00 unitless
or
G^2 =M/(Z*R*T) *(P1^2-P2^2)/ (2*ln(P1
cpo 1.10E-05 SI
g/mol 4.40E-02 SI
1.00 Iterative calculation :C 318.15 K Assume f(n) , calculate G,
mbars 2.60E+05 Pa
mbars 2.40E+05 Pa f(n) G Re
5.97E-03 5.9698E-03 1.5741E+02 1.1448E+07
8.1485E-03 1.5133E+02 1.1006E+07
SI 8.31E+00 SI 8.1887E-03 1.5123E+02 1.0998E+07
8.1894E-03 1.5122E+02 1.0998E+07
8.1894E-03 1.5122E+02 1.0998E+07
8.1894E-03 1.5122E+02 1.0998E+07
8.1894E-03 1.5122E+02 1.0998E+07
kg/m3
kg/s/m2
unitless
unitless
m/s
m3/s 63256.54 m3/h
kg/m3
m/s
m3/s 68470.86 m3/h
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^2/2 = 0
/P2) +(f*L/D +ki) *G^2=0
A*(P2^2-P1^2) +B*Ln(P1/P2) + C =0
A*2*P2-B/P2
) -F(p2)/F'(p2)
C F(P2) F'(P2) P2(n+1)
3.8077E+07 3.4990E+07 7.4903E+01 3.5919E+06 -4.6714E+05
3.8077E+07 2.0216E+06 6.6247E+01 3.5613E+06 -3.0516E+04
3.8077E+07 8.6303E+03 6.5681E+01 3.5612E+06 -1.3140E+02
3.8077E+07 1.6001E-01 6.5679E+01 3.5612E+06 -2.4362E-03
3.8077E+07 0.0000E+00 6.5679E+01 3.5612E+06 0.0000E+00
3.8077E+07 0.0000E+00 6.5679E+01 3.5612E+06 0.0000E+00
3.8077E+07 0.0000E+00 6.5679E+01 3.5612E+06 0.0000E+00
3.8077E+07 0.0000E+00 6.5679E+01 3.5612E+06 0.0000E+00
3.8077E+07 0.0000E+00 6.5679E+01 3.5612E+06 0.0000E+00
3.8077E+07 0.0000E+00 6.5679E+01 3.5612E+06 0.0000E+00
3.8077E+07 0.0000E+00 6.5679E+01 3.5612E+06 0.0000E+00
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^2/2 = 0
/P2) +(f*L/D +ki) *G^2=0
/P2)+f*L/D+ki)
alculate Re , calculate f(n+1) , compare f(n+1) vs f(n)
B f(n+1)
8.63E+23 8.1485E-03 2.1787E-03
8.30E+23 8.1887E-03 4.0218E-05
8.29E+23 8.1894E-03 7.1761E-07
8.29E+23 8.1894E-03 1.2797E-08
8.29E+23 8.1894E-03 2.2819E-10
8.29E+23 8.1894E-03 4.0690E-12
8.29E+23 8.1894E-03 7.2548E-14
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Head Losses - compressible fluid (gas
A) Calculation of Head losses , knowing the inlet condition and
Input data
piping
material SS
rugosity 1.00E-03
diameter D 800.00
length L 200.00
loss friction ki 5.00
fittings
CP/CV k 1.40
fluid viscosiy 0.01
Molecular weight Mw 44.00
Compressibility Z 1.00
Temperature inlet T1 45.00
Pressure inlet P1 2600.00
(k-1)/k
(k+1)/k
process flowrate Qv 63621.00
others perfect gas cte 8.31
output data
density (T1,P1) 1 4.326
G 1.521E+02
Re 11061499
B 8.34E+23
fdarcy 0.00818
velocity U 35.16
head loss P 19675
199
Pressure outlet P2 240325
2403
Temperature outlet T2 311
density(T1,P2) 2 4.09
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B) Calculation of flow rate , knowing the inlet and outlet Press
Input data
pipingmaterial SS
rugosity 1.00E-03
diameter D 800.00
length L 200.00
loss friction ki 5.00
fittings
CP/CV k 1.40
fluid viscosiy 0.01
Molecular weight Mw 44.00
Compressibility Z 1.00
Temperature inlet T1 45.00
Pressure inlet P1 2600.00
Pressure outlet P2 2403.00
(k-1)/k
(k+1)/k
process estimate friction
factor .Von karman fvk (-2log10((/D)/3.7)))^-2
others perfect gas cte 8.31
output data
density (T1,P1) 1 4.326
G 1.522E+02
Re 11068364
B 8.35E+23
fdarcy 0.00818
velocity U1 35.18
Volumetric flow Qv1 18
density(T1,P2) 2 4.09
U2 37
Volumetric flow Qv2 19
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)
the piping arrangement
engineering SI energy balance to solve :
units units
*dP+G^2*ln( 1/2 ) + (f*L/D+ki)*
mm 1.00E-06 SI
mm 8.00E-01 SI after integration with P/^k=cte
m 2.00E+02 SI
M/(Z*R*T1)*[k/(k+1)]*p1^[(k-1)/k]*(P
unitless 5.00 unitless or
to solve : F(p2) =0
with F'(p2)
unitless 1.40 unitless
cpo 1.10E-05 SI Newton Raphson : P2(n+1)=P2(
g/mol 4.40E-02 SI
1.00
C 318.15 K P1 P2 (n) A' B'
mbars 2.60E+05 Pa 2.6000E+05 2.5740E+05 3.4211E-04 1.652E+04
2.86E-01 2.4075E+05 3.4211E-04 1.652E+04
1.71 2.4033E+05 3.4211E-04 1.652E+04
m3/h 1.77E+01 SI 2.4033E+05 3.4211E-04 1.652E+04
2.4033E+05 3.4211E-04 1.652E+04
SI 8.31E+00 SI 2.4033E+05 3.4211E-04 1.652E+042.4033E+05 3.4211E-04 1.652E+04
2.4033E+05 3.4211E-04 1.652E+04
2.4033E+05 3.4211E-04 1.652E+04
2.4033E+05 3.4211E-04 1.652E+04
2.4033E+05 3.4211E-04 1.652E+04
kg/m3
kg/s/m2
unitless
unitless
m/s
Pa
mbars
Pa
mbars
K 37.93 C
kg/m3
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ure and the piping arrangement
energy balance to solve :
engineering SI
units units *dP+G^2*ln( 1/2 ) + (f*L/D+ki)*
mm 1.00E-06 SI after integration with P/^k=cte
mm 8.00E-01 SI
m 2.00E+02 SI M/(Z*R*T1)*[k/(k+1)]*p1^[(k-1)/k]*(P
or
unitless 5.00 unitless
G^2 =2*M/(Z*R*T1) *k/(k+1)*P1^(k-1)/
unitless 1.40 unitless
cpo 1.10E-05 SI
g/mol 4.40E-02 SI Iterative calculation :
1.00 Assume f(n) , calculate G,
C 318.15 K
mbars 2.60E+05 Pa f(n) G Re
mbars 2.40E+05 Pa
2.86E-01 5.9698E-03 1.5844E+02 1.1523E+07
1.71 8.1419E-03 1.5230E+02 1.1076E+07
8.1822E-03 1.5219E+02 1.1069E+07
5.97E-03 8.1829E-03 1.5219E+02 1.1068E+07
8.1829E-03 1.5219E+02 1.1068E+07
SI 8.31E+00 SI 8.1829E-03 1.5219E+02 1.1068E+078.1829E-03 1.5219E+02 1.1068E+07
kg/m3
kg/s/m2
unitless
unitless
m/s
m3/s 63660.48 m3/h
kg/m3
m/s
m3/s 67346.10 m3/h
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^2/2 = 0
^ [(k+1)/k)]-P1^[(k+1)/k)]+G^2*1/k* Ln(P1/P2) +(f*L/D +ki) *G^2/2=0
A'*(P2^x-P1^x) +B'*Ln(P1/P2) + C' =0
A'*x*P2^x-1-B'/P2
) -F(p2)/F'(p2)
C' F(P2) F'(P2) P2(n+1)
8.1496E+04 7.0455E+04 4.2309E+00 2.4075E+05 -1.6653E+04
8.1496E+04 1.6991E+03 4.0261E+00 2.4033E+05 -4.2204E+02
8.1496E+04 1.1075E+00 4.0208E+00 2.4033E+05 -2.7545E-01
8.1496E+04 4.7221E-07 4.0208E+00 2.4033E+05 -1.1743E-07
8.1496E+04 -4.6566E-10 4.0208E+00 2.4033E+05 0.0000E+00
8.1496E+04 -4.8021E-10 4.0208E+00 2.4033E+05 0.0000E+008.1496E+04 1.5571E-09 4.0208E+00 2.4033E+05 -3.7835E-10
8.1496E+04 -4.6566E-10 4.0208E+00 2.4033E+05 0.0000E+00
8.1496E+04 -4.6566E-10 4.0208E+00 2.4033E+05 0.0000E+00
8.1496E+04 -4.8021E-10 4.0208E+00 2.4033E+05 0.0000E+00
8.1496E+04 -4.8021E-10 4.0208E+00 2.4033E+05 0.0000E+00
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^2/2 = 0
^ [(k+1)/k)]-P1^[(k+1)/k)]+G^2*1/k* Ln(P1/P2) +(f*L/D +ki) *G^2/2=0
k*(P1^(k+1)/k-P2^(k+1)/k) /(2/k*ln(P1/P2)+f*L/D+ki)
alculate Re , calculate f(n+1) , compare f(n+1) vs f(n)
B f(n+1)
8.69E+23 8.1419E-03 2.1721E-03
8.35E+23 8.1822E-03 4.0293E-05
8.35E+23 8.1829E-03 7.2238E-07
8.35E+23 8.1829E-03 1.2943E-08
8.35E+23 8.1829E-03 2.3190E-10
8.35E+23 8.1829E-03 4.1550E-128.35E+23 8.1829E-03 7.4444E-14
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