Fundamental Concepts of Vibration-presentation

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Dr. Millerjothi, BITS Pilani, Dubai Campus Chapter:1 Brief review of fundamental concepts of vibration Vibration Analysis Analysis of Simple vibrating systems

Transcript of Fundamental Concepts of Vibration-presentation

Page 1: Fundamental Concepts of Vibration-presentation

Dr. Millerjothi, BITS Pilani, Dubai Campus

Chapter:1 ▪ Brief review of fundamental concepts of vibration ▪ Vibration Analysis ▪ Analysis of Simple vibrating systems

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✓Vibrations can lead to excessive deflections and failure on the machines and structures.

✓ To reduce vibration through proper design of machines and their mountings.

✓ To utilize profitably in several consumer and industrial applications.

✓ To improve the efficiency of certain machining, casting, forging & welding processes.

✓ To stimulate earthquakes for geological research and conduct studies in design of nuclear reactors.

Importance of the Study of Vibration

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!✓Vibrational problems of prime movers due to

inherent unbalance in the engine. ✓Wheel of some locomotive rise more than

centimeter off the track – high speeds – due to imbalance.

✓ Turbines – vibration cause spectacular mechanical failure.

EXAMPLE OF PROBLEMS

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DISADVANTAGES

!✓Cause rapid wear. ✓Create excessive noise. ✓ Leads to poor surface finish (eg: in metal

cutting process, vibration cause chatter). ✓Resonance – natural frequency of vibration of a

machine/structure coincide with the frequency of the external excitation (eg: Tacoma Narrow Bridge – 1948)

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Applications

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Basic Concepts of Vibration

❑ Vibration = any motion that repeats itself after an interval of time. !

❑ Vibratory System consists of: 1) spring or elasticity 2) mass or inertia 3) damper !!❑ Involves transfer of potential energy to kinetic energy and vice

versa.

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❑ Degree of Freedom (d.o.f.) = min. no. of independent coordinates required to determine completely the positions of all parts of a system at any instant of time

❑ Examples of single degree-of-freedom systems:

Basic Concepts of Vibration

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Basic Concepts of Vibration

❑ Examples of single degree-of-freedom systems:

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Basic Concepts of Vibration

❑ Examples of Two degree-of-freedom systems:

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Basic Concepts of Vibration

❑ Examples of Three degree of freedom systems:

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Basic Concepts of Vibration

❑ Example of Infinite number of degrees of freedom system: !!!

❑ Infinite number of degrees of freedom system are termed continuous or distributed systems.

❑ Finite number of degrees of freedom are termed discrete or lumped parameter systems.

❑ More accurate results obtained by increasing number of degrees of freedom.

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Classification  of  vibration

❑ Free Vibration:A system is left to vibrate on its own after an initial disturbance and no external force acts on the system. E.g. simple pendulum

❑ Forced Vibration:A system that is subjected to a repeating external force. E.g. oscillation arises from diesel engines ➢Resonance occurs when the frequency of the external

force coincides with one of the natural frequencies of the system

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❑ Undamped Vibration:When no energy is lost or dissipated in friction or other resistance during oscillations

❑ Damped Vibration: When any energy is lost or dissipated in friction or other resistance during oscillations

❑ Linear Vibration:When all basic components of a vibratory system, i.e. the spring, the mass and the damper behave linearly

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Damped and Undamped vibrations

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❑ Nonlinear Vibration:If any of the components behave nonlinearly

❑ Deterministic Vibration:If the value or magnitude of the excitation (force or motion) acting on a vibratory system is known at any given time

❑ Nondeterministic or random Vibration: When the value of the excitation at a given time cannot be predicted

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❑ Examples of deterministic and random excitation:

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Harmonic motion

❑ Periodic Motion: motion repeated after equal intervals of time

❑ Harmonic Motion: simplest type of periodic motion ❑ Displacement (x): !❑ Velocity: !

❑ Acceleration:

τπt

Ax 2sin=

)2/sin(cos πωωωω +=== tAtAdtdx

x!

)(sinsin 222

2

πωωωω +=−== tAtAdtxd

x!!

xx 2ω−=!!

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The similarity between cyclic (harmonic) and sinusoidal motion.

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The trigonometric functions of sine and cosine are related to the exponential function by Euler’s equation.

exp(iθ) = cos(θ) + i sin(θ) The vector P rotating at constant angular Speed ω can be represented as !!!!Where x =real component and y = imaginery component.

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Vibrations of several different frequencies exist simultaneously. Such vibrations result in a complex waveform which is repeated periodically as shown

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A periodic function:

Harmonic Analysis

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Fourier Series Expansion: If x(t) is a periodic function with periodic τ, its Fourier Series representation is given by

∑∞

=

++=

+++

+++=

1

0

21

210

)sincos(2

...2sinsin

...2coscos2

)(

nnn tnbtna

a

tbtb

tataatx

ωω

ωω

ωω

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•Complex  Fourier  Series: The  Fourier  series  can  also  be  represented  in  terms  of  complex  numbers.  

titetite

ti

ti

ωω

ωωω

ω

sincos

sincos

−=

+=−

Also,

ieet

eet

titi

titi

2sin

2cos

ωω

ωω

ω

ω

−=

+=

and

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•Frequency  Spectrum:  Harmonics  plotted  as  vertical  lines  on  a  diagram  of  amplitude  (an  and  bn  or  dn  and  Φn)  versus  frequency  (nω).

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Even and odd functions:

∑∞

=

+=

=−

1

0 cos2

)(

)()(

nn tna

atx

txtx

ω

Even  function  &  its  Fourier  series  expansion

Odd  function  &  its  Fourier  series  expansion

∑∞

=

=

−=−

1

sin)(

)()(

nn tnbtx

txtx

ω

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Half-Range Expansions:

The  function  is  extended  to  include  the  interval    –  τ to  0  as  shown  in  the  figure.  The  Fourier  series  expansions  of  x1(t)  and  x2(t)  are  known  as  half-­‐range  expansions.

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Example 1Addition of Harmonic Motions

Find the sum of the two harmonic motions

!

Solution: Method 1: By using trigonometric relations:

Since the circular frequency is the same for both x1(t) and x2(t), we express the sum as

).2cos(15)( and cos10)(21

+== ttxttx ωω

E.1)()()()cos()(21txtxtAtx +=+= αω

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That is, !!That is, !!By equating the corresponding coefficients of cosωt and sinωt

on both sides, we obtain

( )E.2)()2sinsin2cos(cos15cos10

)2cos(15cos10sinsincoscosttt

ttttAωωω

ωωαωαω

−+=

++=−

E.3)()2sin15(sin)2cos1510(cos)sin(sin)cos(cos

ttAtAtω

ωαωαω

+=−

( )1477.14

)2sin15(2cos1510

2sin15sin2cos1510cos

22

=

++=

=

+=

A

AA

α

α

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and

E.5)(5963.742cos1510

2sin15tan 1

°=

!"#

$%&

+= −α

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Method 2: By using complex number representation:: the two harmonic motions can be denoted in terms of complex numbers:

!!!!The sum of x1(t) and x2(t) can be expressed as

[ ] [ ][ ] [ ] E.7)(15ReRe)(

10ReRe)()2()2(

22

11

++ ≡=

≡=titi

titi

eeAtxeeAtx

ωω

ωω

[ ] E.8)(Re)( )( αω += tiAetx

Example  2

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where A and α can be determined using the following equations

!!!!!!and A = 14.1477 and α = 74.5963º

2,1;)( 22 =+= jbaA jjj

2,1;tan 1 =!!"

#$$%

&= − j

ab

j

jjθ

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Vibration Terminology

❑ Definitions of Terminology: ➢Amplitude (A) is the maximum displacement of a vibrating

body from its equilibrium position

➢Period of oscillation (T) is time taken to complete one cycle of motion !

➢Frequency of oscillation (f) is the no. of cycles per unit time

ωπ2

=T

πω2

1==

Tf

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➢Natural frequency is the frequency which a system oscillates without external forces

➢Phase angle (φ) is the angular difference between two synchronous harmonic motions

( )φω

ω

+=

=

tAxtAx

sinsin

22

11

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➢Beats are formed when two harmonic motions, with frequencies close to one another, are added

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➢The peak value generally indicates the maximum stress that the vibrating part is undergoing.

➢The average value indicates a steady or static value. It is found from

!!For example, the average value of complete A sin t is zero, but

of a half cycle

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➢The mean square value of a time function x(t) is found from average of the squared values, integrated over some time interval T

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➢Decibel   is   originally   defined   as   a   ratio   of   electric  powers.  It  is  now  often  used  as  a  notation  of  various  quantities   such   as   displacement,   velocity,  acceleration,  pressure,  and  power

!!"

#$$%

&=

!!"

#$$%

&=

0

0

log20dB

log10dB

XX

PP

where  P0  is  some  reference  value  of  power  and  X0  is  specified  reference  voltage.

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Problem 3

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Solution

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