Forces

17
Forces

description

Forces. Normal Stress. A stress measures the surface force per unit area. Elastic for small changes A normal stress acts normal to a surface. Compression or tension. A. D x. A. Deformation is relative to the size of an object. The displacement compared to the length is the strain e. - PowerPoint PPT Presentation

Transcript of Forces

Page 1: Forces

Forces

Page 2: Forces

Normal Stress

A stress measures the surface force per unit area. Elastic for small changes

A normal stress acts normal to a surface. Compression or tension

F

A

A

Ft

F

A

x

Page 3: Forces

Strain

Deformation is relative to the size of an object.

The displacement compared to the length is the strain .

L

L

LL

Page 4: Forces

Shear Stress

A shear stress acts parallel to a surface. Also elastic for small changes

Ideal fluids at rest have no shear stress. Solids Viscous fluids

F

A

x

A (goes into screen)

L

F

A

Ft

Page 5: Forces

Volume Stress

Fluids exert a force in all directions. Same force in all directions

The force compared to the area is the pressure.

F

A

A

FP

F

F

P

V

V

A (surface area)

Page 6: Forces

Surface Force

Any area in the fluid experiences equal forces from each direction. Law of inertia All forces balanced

Any arbitrary volume in the fluid has balanced forces.

Page 7: Forces

Force Prism

Consider a small prism of fluid in a continuous fluid. Stress vector t at any point Normal area vectors S form a

triangle

The stress function is linear.

1Sd

2Sd

21 SdSd

)( 2Sdt

)( 1Sdt

)( 21 SdSdt

)()( SdtcScdt

)()( SdtSdt

)()()( 2121 SdSdtSdtSdt

Page 8: Forces

Stress Function

The stress function is symmetric with 6 components.

To represent the stress function requires something more than a vector. Define a tensor

If the only stress is pressure the tensor is diagonal.

The total force is found by integration.

SdSdP

P)(

SdpSdSdP

1P)(

S

SdF

P

Page 9: Forces

Transformation Matrix

A Cartesian vector can be defined by its transformation rule.

Another transformation matrix T transforms similarly.

x1

x2

x3

jiji xlx

iijj xlx

1x

2x

3x

ijjqippq TllT

pqjqipij TllT

Page 10: Forces

Order and Rank

For a Cartesian coordinate system a tensor is defined by its transformation rule.

The order or rank of a tensor determines the number of separate transformations. Rank 0: scalar Rank 1: vector Rank 2 and up: Tensor

The Kronecker delta is the unit rank-2 tensor.

ss Scalars are independent of coordinate system.

iijj xlx

ijjqippq TllT

nnnn iipipipp TllT 1111

ijjqippq ll

Page 11: Forces

Direct Product

A rank 2 tensor can be represented as a matrix.

Two vectors can be combined into a matrix. Vector direct product Old name dyad Indices transform as separate

vectors

332313

322212

312111

bababa

bababa

bababa

BABA T

C

C

333231

232221

131211

CCC

CCC

CCC

C

Page 12: Forces

Tensor Algebra

Tensors form a linear vector space. Tensors T, U Scalars f, g

Tensor algebra includes addition and scalar multiplication. Operations by component Usual rules of algebra

TT1

TT )()( fggf

UTUT fff )(

ijij UT UT

TUUT

TTT gfgf )(

Page 13: Forces

Contraction

The summation rule applies to tensors of different ranks. Dot product Sum of ranks reduce by 2

A tensor can be contracted by summing over a pair of indices. Reduces rank by 2 Rank 2 tensor contracts to the trace

iiij TT

jiji bAc

iibas

jijkik vT

3

1

tri

iiijij TTT

Page 14: Forces

Symmetric Tensor

The transpose of a rank-2 tensor reverses the indices. Transposed products and

products transposed

A symmetric tensor is its own transpose. Antisymmetric is negative

transpose

All tensors are the sums of symmetric and antisymmetric parts.

jiijij TTT ~T

jiij SS

AST

TTT)( TUTU

jiij AA

TTTTT~~

21

21

Page 15: Forces

Stress Tensor

Represent the stress function by a tensor. Normal vector n = dS Tij component acts on surface

element

The components transform like a tensor. Transformation l Dummy subscript changes

),(),,( txTnSdtxt ijij

ijij Tnt

ijqqippj Tnltl

ijqqiipipj TnlTnl

ijqqirjipipjrj TnllTnll

ijqqirjiriipirp TnllTnTn

ijrjqiqqrq TllnTn ijrjqiqr TllT

Page 16: Forces

Symmetric Form

The stress tensor includes normal and shear stresses.

Diagonal normal Off-diagonal shear

An ideal fluid has only pressure. Normal stress Isotropic

A viscous fluid includes shear. Symmetric 6 component tensor

ijij PT

33231

23221

13121

T

jiij TT

32313

23212

13121

T

Page 17: Forces

Force Density

The total force is found by integration. Closed volume with Gauss’

law Outward unit vectors

A force density due to stress can be defined from the tensor. Due to differences in stress as

a function of position

S

dSnF ˆT

V

dVF T

PSf

S

SdF

T