Finite Element Method-Problem

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  • 8/13/2019 Finite Element Method-Problem

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    :

    .

    : 20

    : 5 2

    :

    C: E = 290000 /2 = 0.20

    : E = 2100000 /2 = 0.30

    : = 1000

    D

    A

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    : 2D (AE42)

    2D (1)

    B (2D/ ),

    .

    ,

    ( ) ( 3 3).

    (E):

    / .

    :

    . A . A

    , .

    . !

    , ( ).

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    :

    ( ).

    ( ).

    , . ,

    .

    . ,

    (D)

    .

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    /E7!

    E,1, 42,,,3

    E,2,1

    !

    ,1,20

    ,2,5

    !

    ,E,1,290000

    ,,1,0.20

    ,E,2,2100000

    ,,1,0.30

    !

    ,1,300,0

    ,5,600,0

    ,1,5

    E,7,5,1,5,1,0,100

    ,36,0,300,37,100,300

    ,38,200,300

    ,39,100,200

    ,40,200,200

    ,41,700,600

    ,42,800,600

    ,43,900,600

    ,44,700,500

    ,45,800,500!

    E,1

    A,1

    EA,1

    !

    E,1,2,7,6

    EE,4,1,1

    EE,6,5,1,4,1

    !

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    E,2

    A,2

    EA,2

    !

    E,36,37E,37,38

    E,38,16

    E,39,40

    E,40,11

    E,39,37

    E,40,38

    E,36,39

    E,37,40

    E,38,11

    !

    E,35,41

    E,41,42

    E,42,43

    E,30,44

    E,44,45

    E,44,41

    E,45,42E,30,41

    E,44,42

    E,45,43

    !

    E,,0

    D,A,A,0

    A

    !

    ,36,,1000,43,,1000

    ,31,,1000

    ,20,,1000

    !

    AE

    !