'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… ·...

6
Point O is the center of the circle. GEOMETRY Review for Chapter l2 Test ng=BC rnAB = l40o nZABC = '-10 XU =ZU YU=4 WU=12 XU= Vrl --- Ll(tz) ={-x 4t -- x'' lft = l20o c MZBAC = 3O 'fiì = l8) nIACB = /L t=D' G +X tz -- zX QR is tangent 7.= L{1 concentric circles radius of small is 6 radius of large is 8 QR= QR=3 RS=12 VT=4 D X (/.r{) - s(3ttz) Nz+4x -- 1+Sc yL+ rlX - qt-- o (x+r)Q-r) =o a a !=f AB is tangent AB=8 BC=4 + PA and Lz- -\ ,l PB are tangents mZP = 40o IG r(r) -- 'l u') Lq --.lx

Transcript of 'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… ·...

Page 1: 'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… · 'fiì = l8) nIACB = /L t=D' G +X tz -- zX QR is tangent 7.= L{1 concentric circles radius

Point O is the center of the circle.

GEOMETRY

Review for Chapter l2 Test

ng=BCrnAB = l40o

nZABC = '-10

XU =ZUYU=4WU=12

XU=

Vrl---

Ll(tz) ={-x4t -- x''

lft

= l20o

cMZBAC = 3O

'fiì = l8)nIACB =

/L t=D'G +Xtz -- zX

QR is tangent 7.= L{1concentric circlesradius of small is 6radius of large is 8

QR=

QR=3RS=12VT=4

D

X (/.r{) - s(3ttz)Nz+4x -- 1+ScyL+ rlX - qt-- o

(x+r)Q-r) =o

aa!=f

AB is tangentAB=8 BC=4

+PA and

Lz- -\ ,l

PB are tangentsmZP = 40o

IG

r(r) -- 'l u')Lq --.lx

Page 2: 'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… · 'fiì = l8) nIACB = /L t=D' G +X tz -- zX QR is tangent 7.= L{1 concentric circles radius

mZLNM = 600

m/LOM= lLo

nZABC = 80o

13.

ruZADC = lÖÔ

= f(rO

AB is tangent

mCA = l00o

mtCAD = l3O

mZA =70omlB = 55o

mzc= 5ímAB =

.6è = l'-lÔ

.ft= llÒ

15.

<)A a tangentmCD = 70o

nZCAD =

nZDAE=

mZA=(3x+12)omZB - (3x)"mZC=(5x-8)o

3x+tz +51-8 --tgo

8K {-4--ttotx -- t7ç

*=LL

sfØs5

c 10 -35')

mZD = I l'l

+PT is tangentmZP = 25o

rß= (rS

¿-ô = s 'Gz)-- çG

mBD = l00o

mCA = 40o

mZP =

I Oo -'loL

Page 3: 'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… · 'fiì = l8) nIACB = /L t=D' G +X tz -- zX QR is tangent 7.= L{1 concentric circles radius

17. ABCD is a parallelogram.-^

mAB - 80" mBG = 50o

mzt = G5ml2 = 5O

mZ3 = 40

mz4= 1Ô

mZ5= 50mz6 = 4Ò

mzt = 50

mZ| = {Ô

mz9 = 25

mZlT = ljlmZll = b5mZl| = z5

Af;o+130

L

,otfoL

nn ll co

mfi = 100"

1o ,n6ì = eoo

mzAOC= îf

t9,

mAD = 100o

mBC = 60o

nZAXD= 8Ô

gDTAC

mAD = 60o

fü= bo

'G = lLo

mAB = 40o

mBC = 60o

mAD = l00o

nZDBC = ÍO

Page 4: 'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… · 'fiì = l8) nIACB = /L t=D' G +X tz -- zX QR is tangent 7.= L{1 concentric circles radius

ç(t) = x (x+zx)30 = 3xz

r¿ =fL' ¡=z f3A(-gB

+fÅ'6

22. AB is a tangent

BC:CD = 1:2 AB = 6

+

4x = t,ß)

23. AE=6 BE=4CE=8

DE= IL

N

25. LK = 2{Z +OLM=3

.-MN= -)

ztî(zf¿ +ql?) =- 2¿l = "ll}x

M33 (s tx)

24. AB I- CD

AB=26 OX=5

cD= z4

28. Write the equation of the circle that has a center at (3 , -4) and a radius of ó cm.

(r-s)"+ (y--1)t= uz

26. nZADB =70ozonIBDC = '

¿{o

6x+{ qf-

21. rnñ=6x+4,^mBC=4x-4

mAD =

' ûCto)+'l

mlE=20

10.C.

Grtl - (rx-r)â

G X +.{ -{X +-4=4ô

tA' Zx+î --qoLx = 3L

x =l(e

=¿o

Page 5: 'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… · 'fiì = l8) nIACB = /L t=D' G +X tz -- zX QR is tangent 7.= L{1 concentric circles radius

1o,180

29. AC I- DB

mAD = 600 mDC = 80o

,nG= too^.mBC = lL6

32. Find the equation of the circle that has its center at (3, - 1) and passes through the point (5, 7).

30. rnAC = 115o mCD = l80o

mlB = 2l115'uS-n

r(q) = x(18-x)1Z = l8Å -xz

>.2 -lgl +1L=Ô

R (x - c')(x-rz =o

31, QV=8 RT=18

SV=9TV= tL

X=G,lz

33.

B

mCD = 60o

AB II DC

'ß= Go

34. mAB

nZACD = '/O= l00o

T+35. TS is a tangent

SR=

ST=

x(x) = sß)¡12- z?

Page 6: 'fiì l8) - LEMAN'S DOMAINlemansdomain.weebly.com/uploads/1/0/0/1/10014528/chapter_12_re… · 'fiì = l8) nIACB = /L t=D' G +X tz -- zX QR is tangent 7.= L{1 concentric circles radius

36 Find the ""** :":;:- i'i: :,'\with an "o'"'ïi'Ji; î'l ; i ; i, +'t =

ç--4 (x-,)" r(u+z¡z=tu37.

^QRS is inscribed circle is inscribed in ÂABC

mZA = 80o mZB = 60o

38. mAD = l20o

nZBAC = 70o

nZDXC= 5O

41. Graph (x + 2)2 + (y - 3)' = 49

tl t^ t

+y

++39. PS and PT are tangents

nZTPX = 60o PX = 9

Pr= tÎ

Con{.c: (-2,3)

PS=

ç---1

lf

80=

^40. mQT = (3x + l2)"

mRS=(6x+4).

mZRVS = 80o

rS= lE

ü* t{

bxrl +(3xttz)L

lbo -- 1* + tbH4 =1r

x= lG