Experimental Status

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Experimental Status K + + - e + e 28 + 0.05 using Roy eqn. & ratio a 0 /a 2 from ChPT: a 0 = 0.216 + 0.013(stat) + 0.004(sys) + 0.005 using Roy eqn. & ratio a 0 /a 2 (universal curve) a 0 = 0.228 + 0.012(stat) + 0.004(sys) +0.006 -0.012 Pislak et al. BNL - E865 (2001) Rosselet et al., (1977 using Roy eqn. & ratio a 0 /a 2 from ChPT: a 0 = 0.221 + 0.026 (95% c.l.) a 0 = 0.220 + 0.005 (2-loop ChPT) Colangelo, Gasser, Leutwyler (2001) M 2 = M 2 l 3 M 4 M 2 = (m u + m d ) B B = |<0|uu|0>| / F 2 m u , m d 0 32 2 F 2 94%

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Experimental Status. K + p + p - e + n e. a 0 = 0.28 + 0.05. Rosselet et al., (1977). using Roy eqn. & ratio a 0 /a 2 from ChPT: a 0 = 0.216 + 0.013(stat) + 0.004(sys) + 0.005(theo). Pislak et al., BNL - E865 (2001). using Roy eqn. & ratio a 0 /a 2 (universal curve): - PowerPoint PPT Presentation

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Page 1: Experimental Status

Experimental Status

K+ +-e+e

a0 = 0.28 + 0.05

using Roy eqn. & ratio a0/a2 from ChPT:a0 = 0.216 + 0.013(stat) + 0.004(sys) + 0.005(theo)

using Roy eqn. & ratio a0/a2 (universal curve):a0 = 0.228 + 0.012(stat) + 0.004(sys) +0.006

-0.012

Pislak et al.,BNL - E865

(2001)

Rosselet et al., (1977)

using Roy eqn. & ratio a0/a2 from ChPT:a0 = 0.221 + 0.026 (95% c.l.)a0 = 0.220 + 0.005 (2-loop ChPT)

Colangelo, Gasser,Leutwyler (2001)

M2 = M2

l3M4

M2 = (mu + md) B

B = |<0|uu|0>| / F2 mu, md 0322F294%