Experiment No. 3 Answers to Questions
3
1 a. Humidification – involves the transfer of material between a pure liquid p nearly insoluble in liquid. b. Dehumidification – The removal of moisture from the ambient air by physica c. Air onditioning – the process of altering the properties of air to more c typically with the aim of distributing the conditioned air to an improve thermal comfort and indoor air quality. d. "ater ooling – when warm liquid is brought into contact with unsaturated evaporates and the liquid temperature drops. # Air entering a drier has a temperature $dry bulb% of &' ' and a dew point of #&.( ' . )sing the psychrometric chart! determine the actual humidity! percentage humidity! humi in *+ and ,nglish units. H = 0.0087 kg H 2 O kgd.air = 0.0087 lb H 2 O lbd.air )sing Antoine ,quation! log P A ° = 7.96681 − 1668.21 228 + 26.7 ℃ P A ° = 26.13mmHg× 101.325 kPa 760mmHg = 3.48kPa H s = 18 28.84 × 3.48 101.325 − 3.48 ¿ 0.0222 kg H 2 O kgd.air H A = H H s × 100 ¿ 0.0087 0.0222 × 100 H A = 39.19 c s = 0.24 + 0.46 H ¿ 0.24 + 0.46 ( 0.0087 ) c s = 0.2440 BTU lb ∙ ℉ c s = 1.02 kJ k g ∙ K υ H = 0.0224 T 273 ( 1 M B + H M A ) ¿ 0.0224 ( 60+ 273 ) 273 ( 1 28.84 + 0.0087 18 ) × 1000 υ H = 0.9606 m 3 k g d . a . υ H = 359T 492 ( 1 M B + H M A ) ¿ 359 ( 140 + 460 ) 492 ( 1 28.84 + 0.0087 18 ) υ H = 15.39 ft 3 l b d . a .
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Humidification questions
Transcript of Experiment No. 3 Answers to Questions
0. a. Humidification involves the transfer of material between a pure liquid phase and a fixed gas that isnearly insoluble in liquid.b. Dehumidification The removal of moisture from the ambientairby physical or chemical c. Air Conditioning the process of altering the properties of air to more comfortable conditions,typically with the aim of distributing the conditioned air to an occupied space to improve thermal comfort and indoor air quality.d. Water Cooling when warm liquid is brought into contact with unsaturated gas, part of the liquidevaporates and the liquid temperature drops.0. Air entering a drier has a temperature (dry bulb) of 60 0C and a dew point of 26.7 0C. Using the psychrometric chart, determine the actual humidity, percentage humidity, humid heat and humid volume in SI and English units.
Using Antoine Equation,
0. The partial pressure of water vapor in a mixture of water vapor and air at a total pressure of 106.6 kPa and a temperature of 60 0C is 13.3 kPa. Express the concentration of water vapor in 1. mole fraction
1. volume fraction
1. absolute humidity
1. relative humidity
1. g water/ m3 of mixture.
The vapor pressure of water at 60 0C is 19.9 kPa.
0. An air-water vapor mixture has a dry bulb temperature of 65.6 0C and a wet bulb temperature of 32.2 0C. What is the humidity of the mixture? Using psychrometric chart,
0. The humidity of an air-water vapor mixture is 0.030 kg water vapor per kg dry air. The dry bulb temperature of the mixture is 60 0C. What is the wet bulb temperature?
