Exp#7: RMS value of an AC...
Transcript of Exp#7: RMS value of an AC...
Exp#7:RMS value of an AC waveform
By: Eng.Tamar Jomaa
Practical wok:
I will use new simulation program called Proteus.
Do not worry, I do not want you to learn the program only analysis the results.
Part#1:
1) Connect the circuit as shown:
Part#1:
2) Draw the direct voltage (appeared on ch1) using oscilloscope.
3) Vary the potentiometer and notice the movement of the dot on Ch2 while varying, then draw the waveform.
Part#1:
At 5% of 1KΩ potentiometer, Ch2 result:
Part#1:
In the report calculate the value of the previous
voltage, if you know the configuration of oscilloscope
as shown:
Part#1:
Remember:
The value of voltage = # of square x scale of ch
So the solution of the previous voltage is
V= - 0.9 x 5 = - 4.5 volte
At 25% of 1KΩ potentiometer:
Part#1:
Ch2 result, in report calculate the value of voltage?
At 55% of 1KΩ potentiometer the result of Ch2:
At 80% of 1KΩ potentiometer the result of Ch2:
At 100% of 1KΩ potentiometer the result of Ch2:
At 5% of 1KΩ potentiometer the result of Ch1:
At 25% of 1KΩ potentiometer the result of Ch1:
At 55% of 1KΩ potentiometer the result of Ch1:
At 80% of 1KΩ potentiometer the result of Ch1:
At 100% of 1KΩ potentiometer the result of Ch1:
Now fill this table according your results:
Ch2 voltageCh1 voltageVariable resistor
5% of 1KΩ
25% of 1KΩ
55% of 1KΩ
80% of 1KΩ
100% of 1KΩ
Note:
Insert your calculation in each part.
Part#2:
1) Connect the circuit as shown:
Part#2:
2) switch link to the left. The lamp should be one.
Notice the intensity of the lamp.
Part#2:
The value of channel A:
Part#2:
3) Switch the link to the right and adjust the amplitude
of the function generator until the intensity is nearly
the same as before.
Part#2:
The value of Channel B
Part#2:
4- Find the value of the output rms value then should
equal to 5V. From the oscilloscope, determine Vpeak.
Vrms=………..
Vpeak=………
5- obtain the peak factor=
Note:In each part show your calculations.
Be free to ask any question