1st equation can be written in 2 formsa. ionic equation: Cu2+ + 4NH3 -> Cu(NH3)4

2+

b. chemical equation: Cu(NO3)2 + 4NH3 -> Cu(NH3)4(NO3)2

2nd equationCu(NH3)4

2+ + 2NO3- + 2C5H8O2 -> C10H16CuO4 + 4NH3 + N2 + 3O2

From the equations above, we can conclude that:1 mol of Cu2+ produces 1 mol of Cu(NH3)4 2+

and

1 mol of Cu(NH3)4 2+ produce 1 mol of C10H16CuO4

no of mol of copper(II) nitrate =

= y mol

y mol of Cu(NO3)2 = y mol of C10H16CuO4

Theoretical mass of C10H16CuO4 = y mol x 263.764 g/mol = z g

Percentage Yield =