Exercise Sp Log
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Transcript of Exercise Sp Log
Problem0 100
1375TVDm
1400TVDm
1425TVDm
From Logging data :• Temperature @ Surface = 25 C• Temperature @ 1500 TVDm = 75 C• SP curve as shown picture on the left side
From Mud Logging data :• Rmf @ 25 C = 0.09 ohm-m
Questions :• Find Rw@ depth 2000 MDm (1390 TVDm) ?• Find Rw@ depth 2050 MDm (1420 TVDm) ?• Do they use Fresh mud, Salt mud or Oil based mud ?
Notes :TVD m = meter True Vertical DepthMD m = meter Measured Depth
Solution• Determine the temperature at the depth were asked
Temperature gradient25 C ?? 75 C
Surface
calculation is always using TVD !!
1390 m
1420 m
1500 m
Temperature gradient = (75-25)/(1500-0) = 0.033 C/m
Temperature@ 1390 TVDm = 25+(0.033*1390)
= 71.33 C
Temperature@ 1420 TVDm = 25+(0.033*1420)
= 72.33 C
1390 TVDmRmf @ 25 C = 0.09 ohm-m
Temperature@ 1390 TVDm = 71.33
C Rmf @ 71.3 C = 0.045 ohm-m
SSP = -25 mV
Rw @ 1390 TVDm
= 0.028 ohm-m
@ 1390 TVDm
• SSP = -K log (Rmfe/Rwe)• K = 60+0.133T (F)• T @ 1390 TVDm = 71.3 C = 160.4 F• K = 60+(0.133x160.4) = 81.33
We need Rmfe and Rwe data !!!!!!!!!!!
Determination of RmfeT @ 1390 TVDm = 71.3 C
= 160.4 F
Rmf @ 71.3 C = 0.045 ohm-m
Rmfe @ 160.4 F = 0.035 ohm-m
Determination of RweT @ 1390 TVDm = 71.3 C
= 160.4 F
Rmfe @ 160.4 F = 0.035 ohm-m
SSP = -25 mV
Rwe @ 160.4 F = 0.017 ohm-m
Determination of RweT @ 1390 TVDm = 71.3 C
= 160.4 F
Rwe @ 160.4 F = 0.017 ohm-m
Rw @ 160.4 F = 0.03 ohm-m