Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich...

7
Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length

description

| 9.2 | 9.3 | 9.4 | 9.5 | 9.6 | 9.7 | 9.8 | 9.9 | 9.10 | 9.11 | 9.12 | 9.14 | Background Information n Suppose that the fast-food manager from the previous example wants to estimate the proportion of customers who have tried its new sandwich. n It wants a 90% confidence interval for this proportion to have half-length n For example, if the sample proportion turns out to be 0.42, then a 90% confidence interval should be (approximately) or n How many customers need to be surveyed?

Transcript of Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich...

Page 1: Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length.

Example 9.13Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich

Controlling Confidence Interval Length

Page 2: Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length.

9.1 | 9.2 | 9.3 | 9.4 | 9.5 | 9.6 | 9.7 | 9.8 | 9.9 | 9.10 | 9.11 | 9.12 | 9.14 | 9.15

Objective

To find the sample size of customers required to achieve a sufficiently narrow confidence for the proportion of high ratings for the new sandwich.

Page 3: Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length.

9.1 | 9.2 | 9.3 | 9.4 | 9.5 | 9.6 | 9.7 | 9.8 | 9.9 | 9.10 | 9.11 | 9.12 | 9.14 | 9.15

Background Information Suppose that the fast-food manager from the previous

example wants to estimate the proportion of customers who have tried its new sandwich.

It wants a 90% confidence interval for this proportion to have half-length 0.05.

For example, if the sample proportion turns out to be 0.42, then a 90% confidence interval should be (approximately) 0.42 +or - 0.05.

How many customers need to be surveyed?

Page 4: Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length.

9.1 | 9.2 | 9.3 | 9.4 | 9.5 | 9.6 | 9.7 | 9.8 | 9.9 | 9.10 | 9.11 | 9.12 | 9.14 | 9.15

Sample Size Estimation The sample size estimation for the mean carries over

with few changes to other parameters such as the proportion, difference between two means, and the difference between two proportions.

The confidence interval for the difference between means uses a t-multiple which should be replaced with the z-multiple.

The confidence intervals for differences between means or proportions requires two sample sizes, one for each sample.

Page 5: Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length.

9.1 | 9.2 | 9.3 | 9.4 | 9.5 | 9.6 | 9.7 | 9.8 | 9.9 | 9.10 | 9.11 | 9.12 | 9.14 | 9.15

Sample Size Estimation -- continued The sample size for a proportion is

Here pest is the estimate of the population proportion p. A conservative value of n can be obtained by using pest = 0.5. This guarantees a confidence interval half-length no greater than B.

271)5.01)(5.0(05.0

645.12

n

Page 6: Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length.

9.1 | 9.2 | 9.3 | 9.4 | 9.5 | 9.6 | 9.7 | 9.8 | 9.9 | 9.10 | 9.11 | 9.12 | 9.14 | 9.15

Calculation Since the manager has “no idea” what the proportions

are, then she can use pest = 0.5 in the equation to obtain a conservative value of n.

The appropriate z-multiple is now 1.645 because this value cuts off probability 0.05 in each tail of the standard normal distribution.

The formula yields a rounded result of n = 271.

StatPro can be used to do the same calculation. Using pest = 0.3 gives a result of 228.

Page 7: Example 9.13 Sample Size Selection for Estimating the Proportion Who Have Tried a New Sandwich Controlling Confidence Interval Length.

9.1 | 9.2 | 9.3 | 9.4 | 9.5 | 9.6 | 9.7 | 9.8 | 9.9 | 9.10 | 9.11 | 9.12 | 9.14 | 9.15

Results

The calculations indicate that if we have more specific information about the unknown proportion, we can get by with a smaller sample size - in this case 228 instead of 271.

We also selected a lower confidence level of 90% which gives us less confidence in the result, but it requires a smaller sample size.