Example 10.2a

5
CGAM Problem - Ideal Gas Fuel 0.00000 lb/s 0.000 T2 ( R) 1400.00 T3 ( R) 15.900 P2 (bar) 0.000 P3 (bar) 0.0000 Air Feed 1 lb/s 536.67 T1 ( R) 0.000 1.013 P1 (bar) W_AC_or_GT (kW) 2500 0.000 Stack 0.0000 lb/s 0.000 T7( R) 1.013 P7 (bar) 0.0000 lb/s 536.670 T8( R) Preheat/Economizer Evaporato 20.000 P8 (bar) 0.0000 BTU/s 0.0000 Variables Physical 1 1.4 0.87 0.24 15.9 536.67 1400 CH4(BTU/lb) = 21500 Fair (lb/s) = γa = nAC = p,a (BTU/lb-R) = P2 (bar) = Tref (R) = T3 (R) =

description

e

Transcript of Example 10.2a

CGAM Problem - Ideal GasFuel0.00000 lb/s0.000 T2 ( R) 1400.00 T3 ( R)15.900 P2 (bar) 0.000 P3 (bar)0.0000Air Feed1 lb/s536.67 T1 ( R) 0.0001.013 P1 (bar) W_AC_or_GT (kW) 25000.000Sa!" 0.0000 lb/s0.000 T7( R)1.013 P7 (bar)0.0000 lb/s536.670 T8( R) Pre#ea$%!o&omi'er %(a)oraor20.000 P8 (bar) 0.0000 BTU/s 0.0000*ariables P#+si!al1 1.40.87 0.2415.9 53.71400 C!4(BTU/lb)" 21500#a$r (lb/s) " %a "&AC " C'(a (BTU/lb)R) "P2 (bar) " Tr*+ (R) "T3 (R) "2500 1.33,A 0.280.89 BTU/lb3 BTU/lb27 BTU/lbMaerial a&d %&er,+ -ala&!es.em)eraures /0eal1 2o,3Mea&3.em)s Pressures53.7 1.01353.7 1.01315.900,/A1.01353.7 20.00020.000874 20.0004ea 5or"0.0000.000-./0/01To2al Cos2 (3/s)" -./0/01T4 (R) " %4 "&GT " C'(4 (BTU/lb)R) "&PT "56(874R( 20) "T'$&75 ( R) "5l(847 R( 20) "Ta''roa75 ( R) "5l(53 R(20) "T0 (R) " P0 (bar) "T1 (R) " P1 (bar) "T2 (R) " P2 (bar) "T3 (R) " 8T9:;7o& (R) " P3 (bar) "T4 (R) " 8T9:;6a' (R) " P4 (bar) "T5 (R) " 8T9:AP! (R) " P5 (bar) "T (R) " P (bar) "T7'(R) " P7' (bar) "T7 (R) " P7 (bar) "T8 (R) " P8 (bar) "T8' (R) " P8' (bar) "T9 (R) " P9 (bar) "