EXAMPLE 1 Graph an equation of a parabola SOLUTION STEP 1 Rewrite the equation in standard form....
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Transcript of EXAMPLE 1 Graph an equation of a parabola SOLUTION STEP 1 Rewrite the equation in standard form....
EXAMPLE 1 Graph an equation of a parabola
SOLUTION
STEP 1
Rewrite the equation in standard form.18
x = – Write original equation.
18
Graph x = – y2. Identify the focus, directrix, and axis
of symmetry.
–8x = y2 Multiply each side by –8.
EXAMPLE 1 Graph an equation of a parabola
STEP 2
Identify the focus, directrix, and axis of symmetry. The equation has the form y2 = 4px where p = –2. The focus is (p, 0), or (–2, 0). The directrix is x = –p, or x = 2. Because y is squared, the axis of symmetry is the x - axis.
STEP 3
Draw the parabola by making a table of values and plotting points. Because p < 0, the parabola opens to the left. So, use only negative x - values.
EXAMPLE 1 Graph an equation of a parabola
EXAMPLE 2 Write an equation of a parabola
SOLUTION
The graph shows that the vertex is (0, 0) and the directrix is y = –p = for p in the standard form of the equation of a parabola.
3 2
–
x2 = 4py Standard form, vertical axis of symmetry
x2 = 4( )y3 2
Substitute for p3 2
x2 = 6y Simplify.
Write an equation of the parabola shown.
GUIDED PRACTICE for Examples 1, and 2
Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola.
1. y2 = –6x
SOLUTION
(– , 0), x = , y = 0 32
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GUIDED PRACTICE for Examples 1 and 2
Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola.
2. x2 = 2y
SOLUTION
(0, ), x = 0 , y = –12
12
GUIDED PRACTICE for Examples 1 and 2
SOLUTION
Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola.
3. y = – x214
(0, –1 ), x = 0 , y = 1
GUIDED PRACTICE for Examples 1 and 2
SOLUTION
Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola.
4. x = – y213
( , 0), x = – , y = 033
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GUIDED PRACTICE for Examples 1 and 2
Write the standard form of the equation of the parabola with vertex at (0, 0) and the given directrix or focus.
5. Directrix: y = 2
x2 = – 8ySOLUTION
6. Directrix: x = 4
y2 = – 16xSOLUTION
7. Focus: (–2, 0)
y2 = – 8xSOLUTION
GUIDED PRACTICE for Examples 1 and 2
Write the standard form of the equation of the parabola with vertex at (0, 0) and the given directrix or focus.
x2 = 12y
8. Focus: (0, 3)
SOLUTION