ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to...

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Transcript of ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to...

Page 1: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
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Page 2: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 3: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 4: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 5: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 6: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 7: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 8: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 9: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 10: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 11: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 12: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 13: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 14: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 15: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 16: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 17: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 18: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following
Page 19: ExamCompetition€¦ · When 0.1 mol Mn04 — is oxidised the quantity of electricity required to completely oxidise Mn04 to Mn04- is: (2) 9650 c (3) 96.50 c (4) 96500 c Of the following

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JEE Main Mock Test Paper 1 JEE 2018 - FIITJEE … paper/XII/XII-I.pdf= 0.0821 Lit atm 11 =1.987 2 Cal 11 Avogadro’s Number N a = 6.023 10 23 1 Faraday = 96500 coulomb 1 calorie =

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 · in a redox titration, a suitable oxidizing agent is A. B. c. D S042 in acid. H P04 in acid Mn04 in acid Mn04 in base. As a metal corrodes, A. it gains electrons.

 · in a redox titration, a suitable oxidizing agent is A. B. c. D S042 in acid. H P04 in acid Mn04 in acid Mn04 in base. As a metal corrodes, A. it gains electrons.

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