Exam#1 (chapter 1-6) - Purdue University

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Exam#1 (chapter 1-6) time: Tuesday 02/19 8:00 pm- 10:00 pm Note: we have regular class on Wedesday (02/20) but will cancel two classes (02/27 and 03/01). Location: physics building room 112 If you can not make it, please let me know by Friday 02/15 so that I can arrange a make-up exam. If you have special needs, e.g. exam time extension, and has not contact me before, please bring me the letter from the Office of the Dean of Students before Friday 02/15. AOB 40 multiple choice problems. Prepare your own scratch paper, pencils, erasers, etc. Use only pencil for the answer sheet Bring your own calculators No cell phones, no text messaging, no computers No crib sheet of any kind is allowed. Equation sheet will be provided. 1

Transcript of Exam#1 (chapter 1-6) - Purdue University

Page 1: Exam#1 (chapter 1-6) - Purdue University

Exam#1 (chapter 1-6)

time: Tuesday 02/19 8:00 pm- 10:00 pmNote: we have regular class on Wedesday (02/20) but will cancel two classes (02/27 and 03/01).

Location: physics building room 112

If you can not make it, please let me know by Friday 02/15 so that I can arrange a make-up exam.

If you have special needs, e.g. exam time extension, and has not contact me before, please bring me the letter from the Office of the Dean of Students before Friday 02/15.

AOB•40 multiple choice problems. •Prepare your own scratch paper, pencils, erasers, etc. •Use only pencil for the answer sheet•Bring your own calculators•No cell phones, no text messaging, no computers •No crib sheet of any kind is allowed. Equation sheet will be provided.

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Page 2: Exam#1 (chapter 1-6) - Purdue University

Torque and BalanceWhat causes the merry-go-round to rotate in the first

place?What determines whether an object will rotate? If an unbalanced force causes linear motion, what

causes rotational motion?

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Page 3: Exam#1 (chapter 1-6) - Purdue University

Torque and BalanceWhen is a balance balanced?Consider a thin but rigid beam supported by a fulcrum or

pivot point. If equal weights are placed at equal distances from the

fulcrum, the beam will not tend to rotate: it will be balanced.

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To balance a weight twice as large as a smaller weight, the smaller weight must be placed twice as far from the fulcrum as the larger weight.Both the weight and the distance from the fulcrum

are important.The product of the force and the distance from the

fulcrum is called the torque.

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The distance from the fulcrum to the point of application of the force must be measured in a direction perpendicular to the line of action of the force.This distance is

called the lever armor moment arm.For a force F and a

lever arm l, the resulting torque is:

A longer lever arm produces a greater torque.

Fl

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Which of the forces pictured as acting upon the rod will produce a torque about an axis

perpendicular to the plane of the diagram at the left end of the rod?

a) F1b) F2c) Both.d) Neither.

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The two forces in the diagram have the same magnitude. Which force will produce the greater

torque on the wheel?

a) F1b) F2c) Both.d) Neither.

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A 50-N force is applied at the end of a wrench handle that is 24 cm long. The force is applied in a direction perpendicular to the handle as shown. What is the torque applied to the nut by the wrench?

a) 6 N·mb) 12 N·mc) 26 N·md) 120 N·m

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What would the torque be if the force were applied half way up the handle instead of at the end?

a) 6 N·mb) 12 N·mc) 26 N·md) 120 N·m

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What’s the lever arm between F and the fulcrum?

A. l B. a C. b

ab

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When the applied force is not perpendicular to the crowbar, for example, the lever arm is found by drawing the perpendicular line from the fulcrum to the line of action of the force.We call torques

that produce counterclockwiserotation positive, and torques that produce clockwise rotation negative.

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What is the net torque acting on the merry-go-round?

a) +36 N·mb) -36 N·mc) +96 N·md) -60 N·me) +126 N·m

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How far do we have to place the 3-N weight from the fulcrum to balance the system?

a) 2 cmb) 27 cmc) 33 cmd) 53 cm

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is the point about which the weight of the object itself exerts no torque.We can locate the center of gravity by finding the point

where it balances on a fulcrum.

What’s the center of gravity of a disk? A. any point on the edge of the disk. B. Center of the disk C. Any point half way between the center and the edge.

The center of gravity

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For a more complex object, we locate the center of gravity by suspending the object from two different points, drawing a line straight down from the point of suspension in each case, and locating the point of intersection of the two lines.

The center of gravity

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Where is the Center of Gravity of the cut

board ?

1J-21 Center of Gravity of an Irregular Lamina

How can we find the Center of Gravity of Irregular shapes?

Why does the mass on the string hang

straight down ?

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If the center of gravity lies below the pivot point, the object will automatically regain its balance when disturbed.The center of gravity

returns to the position directly below the pivot point, where the weight of the object produces no torque.

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How difficult is it to balance this system on

a sharp point ?

1J-23 Corks & Forks

THE CENTER OF GRAVITY IS NOT ON THE OBJECT. IT ACTUALLY LIES ALONG THE VERTICAL BELOW THE SHARP POINT.WHEN THE FORK IS MOVED THE CM RISES AND THIS MEANS THE SYSTEM IS IN STABLE EQUILIBRIUM .

Can the Center of Gravity lie at a point not on the object?

Where is the C of G ?

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1J - 24 double cone

The force causing the object to move is gravity and we know that by energy conservation that if the object gains kinetic energy it must lose potential energy. Therefore the center of mass must be falling and the kinetic energy = mgh where h is the distance the CM falls.

What happens to the center of mass ?

A). Going down the hillB). Going uphill C). Stay at restD). Depend on the object shape

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Can you safely walk to the end of the

plank ?

1J-16 Walk the Plank

EVEN WITH A MASS AT THE END OF THE PLANK, THE SYSTEM CAN STILL BE IN EQUILIBRIUM

Sum of Torque about PivotX M g – x m g = 0

m = M X / x

What happens when a mass is placed at the end of a massive plank?

One can solve for either M or m, if the other quantity is known

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1m1x 2x 2m

M

How does this system Balance?

1J-28 Wine Bottle Holder

THE CENTER OF GRAVITY OF THE BOTTLE PLUS THE WOOD MUST LIE DIRECTLY OVER AND WITHIN THE BOUNDARY OF THE SUPPORT (PIVOT). FOR BALANCE THERE CAN BE NO NET TORQUE ON SYSTEM.

Sum of Torque about Pivotm1x1g - m2x2g = 0

Balance a Bottle and a Wooden Holder by Eliminating Net Torque

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How far can the child walk without tipping

the plank?

• For a uniform plank, its center of gravity is at its geometric center.• The pivot point will be the edge of the supporting platform.• The plank will not tip as long as the counterclockwise torque from the

weight of the plank is larger than the clockwise torque from the weight of the child.

• The plank will verge on tipping when the magnitude of the torque of the child equals that of the plank.

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An 80-N plank is placed on a dock as shown. The plank is uniform in density so the center of gravity of

the plank is located at the center of the plank. A 150-N boy standing on the plank walks out slowly from the edge of the dock. What is the torque

exerted by the weight of the plank about the pivot point at the edge of the dock?

a) +80 N·mb) -80 N·mc) +160 N·md) -160 N·me) +240 N·mf) -240 N·m

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