Exam1-15-2
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Transcript of Exam1-15-2
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Machine Component Design
(INME 4011)- Prof. Pablo G. Caceres-Valencia
1st Exam
Student Number :___________________ Name: _________________________________
Section (circle): 7:30AM 9:00AM Date: October 12th
, 2015
Notes: This is an open book examination. Others items needed are calculators, pencils, pens andrulers. Please ensure that you have a complete copy of the exam. Only clear and concise answerswill be considered. Total Points = 100. Time Allowed: 120 minutes
-------------------------------------------------------------------------------------------------------1. (70 points) The component below has been made of a steel pipewith an outside diameter
(OD) of 170mmand a thickness (t) of 6mm. A design safety factor of 3was used in thiscomponent. The internal pressure in the pipe is 5000kPaand there are twoconcentrated loads
acting at the end B, one in the positive x-direction (F=6000N) and the other in the negativey-direction (P=7000N). Determine if the component has been properly designed if the materialhas a yield stress of 520MPa.
Data: a=600mm , b=900mm , c=600mm ,Elastic Modulus = 200GPa;Poissons ratio = 0.3.
Stress Concentration factors at the wall : Kbending=1.7 , Ktorsion=1.6 , Kshear=1.4 , Kaxial-pressure=1.8.If a delta strain rosette is placed in the point H (K), with one of the strain gauges (a) parallel to
the x-direction and the triangle pointing towards the positive z-direction (y-direction), what willbe the readings in the strain gauges a, b and c (see figure below).
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You should do the calculation for the point .............. H KTo receive full points, you must draw the direction of the stresses on the cube elements
Write the formula and the results in the given area
Area (A)
Moment of
Inertia (I) and
(J)
G- modulus
Stresses due to
force in x-
direction (F)
Stresses due to
force in y-
direction (P)
y
z
x
y
z
x
y
z
x
y
z
x
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Stresses due to
pressure
Total Normal
Stresses(indicate
subscript)
Total Shear
Stresses
(indicatesubscripts)
Stress Tensor
PrincipalStresses
Angles for the
principal
stresses
DET Theory
Von Mises
Stress and
Safety factor
y
z
x
y
z
x
y
z
x
y
z
x
y
z
x
y
z
x
y
z
x
y
z
x
y
z
x
y
z
x
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MSS Theory,
Maximum
Shear Stress
and Safety
Factor
Draw Mohr
Circle for
stresses
Was thecomponent
properly
designed
Compliance
Matrix
Calculated
Strains
Strain Tensor
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Principal
strains
Angles for the
principal strain
Mohr!s Circle
for strains
Strain in the
strain gauges a,
b and c ( for
the point K
change the y-
direction for a
z-direction in
the figure)
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2. (30 points) The figure below shows a 60oangle (angle between the x-axis and the direction 1
of the fibers) graphite/epoxy lamina which is subjected to the following stresses: !x = 2MPa ,
!y = -3MPa and "xy = 4MPa. What will be the strains associated with a delta rosette strain gaugeattached to the surface of the lamina? Data: E1=181GPa , E2=10.3GPa , #12=0.28 , #23=0.6 ,
#13=0.27 , G12=7.17GPa , G23=3.0GPa , G31=7.00GPa
#21
transformationmatrix
Stresses at 1-2coordinate
system
Reduced
Compliance
matrix
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$1
$2
%12
Transformation
Matrix
$x$y
%xy
$a$b
$c
Principal Stresses
Angle for
Principal Stresses
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Principal Strains
Angle for
Principal Strains