Exam Eng. Sc. 2

12
Confidential ENGINEERING SCIENCE 2 (SSD 12103) / Session June 2013 :EQUATIONS: 1

description

exam paper for engineering science 2

Transcript of Exam Eng. Sc. 2

Section A: SELECTION TYPE

Confidential ENGINEERING SCIENCE 2 (SSD 12103) / Session June 2013

:EQUATIONS: Fluid & Pressure

= m

v

P = F A

PA= PB

n = F L v A

Qv = v A

Qm = v A

Heat & Temperature

TF = 9 TC + 32

5

TK = TC + 273.15

Q = m c ( T1 T0 )

Qf = m Hf

Qv = m Hv

Q = k A ( T ) t L

Q = e A T4 t

L = Lo ( T )

V = Vo ( T )

Waves

f = 1 T

y = A .. ( t )

= 2 f

v = f

f = n fs

L = n ( / 2 )

I = P / A

I a = ( r b )2

I b ( r a )2

f beats = f a f b

Q = ne Qe + np Qp

F = k q1 q2

r2

E = k Q E = F / q

r2

* Qe = -1.602 x 10-19 C

* Qp = +1.602 x 10-19 C

Gauss Law & Electric Potential Energy

= E A cos

E . dA = Q / o

= Q / L = Q / A

E = / 2 o r E = / 2 o

W = q E d

V = E d

Capacitance

C = Q / V

C = o A / d

Energy = C V2

Cdie = K C

C TOTAL = C1 + C2 + C3 { parallel }

1 = 1 + 1 + 1 { series }C TOTAL C1 C2 C3

Current & Resistance

I = q / t

V = I R

R = L A

R = Ro ( T )

P = V I = I2 R = V2 / R

Direct Current Circuit

VT = - I r

1 = 1 + 1 + 1 { parallel }R TOTAL R1 R2 R3

R TOTAL = R1 + R2 + R3 { series }

I in = I out

V loop = 0

Magnetism

= B A cos

F = B I L sin

F = q v B sin

Electromagnetic Induction

emf = N ( ) t

emf = B L v

* k = 9 x 109 Nm2 / C2

* o = 8.85 x 1012 C2 / N m2

Answer only eight (8) questions. Each question carries 10 marks.1.a} Show the difference between Laminar flow and Turbulent flow with diagrams.b} Calculate the area, A in each pipe system using the Principle of Continuity.

i.

0.3m2

5m/s

0.3m2

7m/s

A 8m/s 9m/s

0.2m2c}Based on the hydraulic press system here;

Fi

Fo = 1.5 x 106 N

Ai = r 2

Ao = 4.5m2

Input Piston Output Piston

i) How much is the pressure on the output piston?

ii) Calculate the cross-sectional area (Ai) of the input piston if its radius is 0.025m.

iii) What was force applied to the input piston, Fi?

2.The data below shows the temperature values of some quantities in three different temperature scales.

TC

TF

TK

Boiling Point of Water

100

212

373.15

Melting Point of Water

0

32

273.15

Normal Human Body

36.9

X

310.05

At the North Pole

Y -85.1

Z

a) Explain the difference between the Tc and TF scales.b) Calculate the missing temperature values X , Y and Z. c) At what temperature will the value be the same on Celsius scale and Fahrenheit scale ?

3.a) A Bigfoots favourite pastime is to swing from the twines hanging from trees. The

sinusoidal wave equation for the swinging Bigfoot is;

y = 7.7 cos ( 1.57 t ) m

Determine the:

i) period of the motion.

ii) displacement at 0.6 seconds.

iii) sketch & label the sinusoidal displacement{y} vs. time{t} graph.

b) A clothesline wire is 7.5m long. It vibrates at the 4th Harmonics when specific waves of 420m/s velocity are supplied to it.

i) Sketch the standing wave pattern.

ii) Calculate the wavelength.

iii) Find the frequency of the wave.4. a) i. Explain the concept of Electric field.

ii. Sketch the electric field lines between these charges.b)A butterfly contains 2.2 x 1014 electrons and 3.5 x 1014 protons. It is attracted to a beautiful but smelly Tahi Ayam flower which has a total charge of -15 x 10-6 C.Calculate the: i} total charge of the butterfly.

ii} magnitude & direction of the flowers electric field at point P. iii} magnitude & direction of electrostatic force between the flower and the butterfly.

P

30m

44m * Assume both objects are point charges

5. a)The steps below shows how Gauss Law is used to obtain the Electric field equation of a cylindrical charge. Complete the missing steps. step 1 : type of charge distribution = .step 2 : total charge, Q = step 3 : electric field shape = open-ended cylinder step 4 : Area of electric field shape, A = step 5 : insert into Gauss Law

E . dA = Q / o

L

E {..}= {}/ o

r

E = / 2 o rb) A flat circular loop of copper wire with a radius of 0.24m is placed in an electric field

of 35N/C in various position shown. Calculate the; i) area of the wire loop

ii) electric flux for each position.

Position A Position B

60E = 35N/C6.a)State all the three(3) factors that affects the capacitance of a capacitor.b)The circuits below contain capacitors. Calculate the total capacitance of each circuit.

i.

3F

ii.

24F

5F

5F

9F

4F 12F

7F

6F

8Fc) A capacitor is made of two circular plates separated by a 0.25mm of petroleum jelly dielectric. The area of the plates is 0.07m2. Determine the capacitance with dielectric.

{Kpetroleum jelly = 2.2}

7.a)Explain the concept of resistance. Sketch on this diagram to show resistance.

.

b) Two resistors, 15 and 21 are connected parallel in a circuit containing a 6V battery. Determine;i) drawing of the circuit.

ii) total equivalent resistance.

Hah! Asyik Tido saja!

iii) current at each resistor.

15 iv) power dissipated at the 15 resistor.

21 8. a) Sketch the magnetic field of each object.

i.

ii. N

I

Sb)The lines of a uniform magnetic field of 0.15T points west. Find the magnitude and direction of the magnetic force on a;

I

0.15T

50

i) -75C charged eagle an eagle flying straight up at 34m/s.

ii) angled 1.2m wire with 3.75A current. c)Explain the Faraday Law of Magnetic Induction. Sketch a diagram showing this.9.a) The calorimetry graph gives the relation between temperature & heat.

TEMP

HEAT

i) Label; melting point, boiling point, fusion phase and vaporization phase.

ii) Explain; fusion phase and vaporization phase.

b)An aquarium contains an exotic fish that is spherical in shape with a radius of 9cm. Suddenly, the temperature of the water in the aquarium increases by 34oC. Calculate the; i. initial volume of the fish in cm3.ii. change of volume of the fishs body.

10. a) Amy Search the rock-star likes to tie his hair into a ponytail {tocang}. The length of his ponytail is 0.72m while the c/s area is 5 x 10-6m2. { hair = 7.15 x 10-4 .m.} { hair = 0.002}

Find the: i} ponytails resistance at standard temperature (20 oC). ii} ponytails resistance at 75oC.

c)Use the Kirchhoffs Rules to determine the values of current I, battery V1 and battery V2 in this electric circuit. . 0.6A V1

I

5

10 V2 10

:- End of Examination Paper -:+

+

{ tissue = 120 x 10-6 }

{ Volume = 4 r3 }

3

5V

0.2A

PAGE 1