Equations are more important to me, because politics is for the present, but an equation is something for eternity.

Albert Einstein

Today:◦Multiple Choice

Practice◦12.6 Instruction◦Practice

Objectives:Find the volume of a SphereFind the volume of a Composite

Figures

Vocabulary:: None

Surface Area

Prism S = 2B + Ph

Cylinder S = 2B + Ch

Pyramid S = B + ½Pl

Cone S = B + ½Cl

Sphere S = ?

Volume

Prism V = Bh

Cylinder V = Bh

Pyramid V = 1/3Bh

Cone V = 1/3Bh

Sphere V = ?

Sphere – the locus of points in space that

are equal distance from a point.

Has no base, but can be cut into circles.

Circle at center point called great circle.

SA of Sphere = 4r2 where r = radius.

Find the surface area of a sphere with radius of 2”.

16in2

50.24 in2

2”

Find the surface area of the hemisphere of the above figure.Cut in half? 8in2?

12in2

37.68 in2

Find the surface area of the figure. Round answer to nearest tenth. Include units!

cmcm

36cm3

113.10 cm3

Find the volume of the sphere if r = 3 cm.

r34

Volume of a SphereThe volume, V, of a sphere is V = 4/3r3, where r = radius.

What is the radius to the nearest hundredth of a sphere molded from the cylinder of modeling clay shown?

3.63 cm

2 cm

16 cm

A rectangular pyramid fits exactly on top of a rectangular prism. The prism has length 15 cm, width 5 cm, and height 7 cm, and the pyramid has height 13 cm. Find the volume of the composite figure.

Surface Area

Prism S = 2B + Ph

Cylinder S = 2B + Ch

Pyramid S = B + ½Pl

Cone S = B + ½Cl

Sphere S = 4r2

Volume

Prism V = Bh

Cylinder V = Bh

Pyramid V = 1/3Bh

Cone V = 1/3Bh

Sphere V = 4/3r3

Equations are more important to me, because politics is for the present, but an equation is something for eternity.

Albert Einstein

Assignment: Worksheet Project Work

Tomorrow Test Tuesday