ENSC380 Signals and Systems Fourier AnalysisBode Plot (Cont.) • We know that any LTI system is...
Transcript of ENSC380 Signals and Systems Fourier AnalysisBode Plot (Cont.) • We know that any LTI system is...
ENSC380Lecture 22
Objectives:
• Signals and Systems Fourier Analysis:• Power Spectrum• Log-Magnitude response plots• Bode plots
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Power Spectrum
• Power spectrum of a signal refers to the amount of power a signal contains ina very narrow band around each frequency.
• To find the power spectrum of a signal, x(t), the following system is used. Thisis an example of the application of BPFs.
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Noise Removal
• An important application of filters (usually LPF or BPF) is to reduce the noisecontents of a signal.
• Noise is an undesirable signal which inevitably adds to signal when they arestored, transmitted, filtered, . . . .
• Practical signals usually have a limited bandwidth, whereas noise usually hasunlimited or very large bandwidth.
• The idea is to remove the noise in the frequency range that the desired signaldoes not exist.
• The ratio of the desired signal power to the noise power is called the signal tonoise ratio (SNR). The goal of a noise reduction system is to increase SNR asmuch as possible.
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Log-Magnitude Plot
• Sometimes instead of plotting the magnitude of a frequency response of asystem versus frequency, we plot the logarithm of the magnitude.
• The reason is that logarithm de-emphasizes large values and emphasizessmall values. This helps see the subtle differences between the magnituderesponse of two systems more clearly.
H1(f) =1
1 + j2πfH2(f) =
30
30 − 4π2f2 + j62πf
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Bode Plot
• A more common practice is to plot the logarithm of the magnitude of thefrequency response (H(f) or H(jω)) against a logarithmic scale of thefrequency. This is called a Bode diagram or a Bode Plot.
• In a Bode plot the magnitude of H(jω) is converted into a logarithmic scalecalled decibel (dB). The unit Bel is named after Alexander Graham Bell, and isdefined as the base 10 logarithm of the ratio of two powers. Decibel is atenth of a Bel.
• If the input and output signals of a system are x(t) and y(t), with powers Px
and Py respectively, then, the ratio of their powers in Bel and Decibel is:
• On the other hand we know that Px is proportional to |X(f)|2 and Py to|Y (f)|2. Thus we can write:
log10(Py
Px
) =
• Finally, the conversion of |H(f)| to it’s decibel unit can be written as:
HdB(f) =
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Bode Plot (Cont.)
• The bode plots of the previous systems H1(f) and H2(f):
Note: The phase of H(f) should also be plotted against the logarithmic scaleof frequency.
• In the following slides, we replace H(f) with H(jω) for simplicity in theformulas. H(jω) is the same as H(f) when 2πf is replaced with ω.
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Bode Plot (Cont.)
• We know that any LTI system is defined by a linear constant-coefficientdifferential equation:
• Hence, its transfer function (frequency response) has the form:
• If we find the roots of the numerator and denominator of H(jω) and show themwith zi and pi respectively, we can write:
H(jω) = A
(
1 − jω
z1
) (
1 − jω
z2
)
. . .(
1 − jω
zN
)
(
1 − jω
p1
) (
1 − jω
p2
)
. . .(
1 − jω
pD
)
• zi’s are called the “zeros” and pi’s the poles of the transfer function. H(jω) isequal to zero at ω = zi and goes to infinity for ω = pi.
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Bode Plot (Cont.)
• The above system, can be viewed as a cascade of N + D simplersub-systems:
• The transfer function of each subsystem (Hl(jω)) has a magnitude and phase:|Hl(jω)| and ∠Hl(jω)
• The Bode plot for the over all system (H(jω) or (H(f)) is the sum of the bodeplots for each sub-system (both for the magnitude and phase).
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Component Diagrams
• The bode plot for each sub-system is called a “component diagram”.subsystems can have different forms:
• Sub-systems with a real (non-zero)zero:
• Sub-systems with a real (non-zero)pole:
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Component Diagrams (Cont).
• Subsystem with a zero at 0(Differentiator):
• Subsystem with a pole at 0(Integrator):
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Component Diagrams (Cont).
Subsystem with complex zero pair
H(jω) =
(
1 −jω
z1
) (
1 −jω
z2
)
where z2 = z1∗
Let
ω0 = |z1|2 ζ = −
Re(z1)
ω0
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Component Diagrams (Cont).
Subsystem with complex pole pair
H(jω) =1
(
1 − jω
p1
) (
1 − jω
p2
) where p2 = p1∗
Let
ω0 = |p1|2 ζ = −
Re(p1)
ω0
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Example
Plot the Bode diagram for the given circuit, with C1 = 1 F, C2 = 2 F, Rs = 4Ω,R1 = 2Ω, R2 = 3Ω
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Example(Cont.) 14/14
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