Eng. Khalid Stair-Design
Transcript of Eng. Khalid Stair-Design
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Stair Design
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Stair Types
Straight stairs
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Stair Type based on the structural
loading type
Simply supported stair
(transversely supported)Longitudinally supported stair
Cantilever stair
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Simply supported stair
Design a straight flight stair in a residential building supported onreinforced concrete wall 1.5 m )(center to center)
L.L = 3kN/m2
Covering Material = 0.5kN/m
The riser are 16cm and goings are 30 cm
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Loads and Analysis
cmh
cml
h
ave5.16
5.78
cos
5.78
5.720150
20
22 1630
16
min
D.L(O.W) =0.34*0.075*25 + 0.5*0.16*0.3*25=1.24 kN/mD.L (covering material) = 0.5 kN/m
D.L (total) = 1.74 kN/m
L.L =3*(0.3) =0.9 kN/m
0.30.16
0.34
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Design for moment
stepeachfor121
9.01.89165*300*0018.0
0005.0139003259.085.0
1102
11420
2585.0
9.0
30030
1399.136.025.16
.1
22
min
min2
6
lim
use
cmmmAs
assume
mmcmb
mmcmd
mkNM
w
u
uCVkNV 261000/300139
6
2575.0
Design for shear
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LongitudinalSupported stairs
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Design a U- stair in a residential building L.L = 3 kN/m2Covering Material = 2 kN/m2
The riser are 16 cm and goings are 30 cm
LongitudinalSupported stairs (Example)
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Loads and Analysis
cml
h 2220
525
2085.0min
D.L (slab) = 0.22*25 =5kN/m2
D.L (step) = 0.5*0.16*25=2 kN/m2D.L (covering material) = 2 kN/m2
D.L (flight) = 9 kN/m2
D.L (landing) = 7 kN/m2
L.L =3 kN/m2
Wu(flight) = 1.2(9)+1.6(3)=15.6kN/m
Wu(landing) = 1.2(7)+1.6(3)=13.2kN/m
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Design for moment
128
33.732.733194*1050*0036.0
0036.01940501259.085.0
2.52102
11420
2585.0
9.0
1050105
1944.196.0222
.2.52
22
min
2
6
lim
use
cmmmAs
assume
mmcmb
mmcmd
mkNM
w
u
uCVkNV 3.1271000/1050194
6
2575.0
Design for shear
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Reinforcement Notes
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Cantilever Stair
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Cantilever stairs (Example)
Design a cantilever straight flight stair in a residential buildingL.L = 3kN/m2
Covering Material = 0.5kN/m
The riser are 16cm and goings are 30 cm
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cm
l
h 1510
150
10min
D.L(O.W) =0.15*0.075*25 + 0.15*0.075*25=0.6 kN/m
D.L (covering material) = 0.5 kN/m
D.L (total) = 1.1 kN/m
L.L =3*(0.3) =0.9 kN/m
Wu = 1.2(1.1)+1.6(0.9) = 2.76 kN/m
Vu = 2.76(1.5) = 4.14 kN
Mu = WuL2/2 = 3.1 kN.m 15
15
7.5
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Design for moment
102
72.061.71124*75*0077.0
0077.012457259.085.0
1.3102
11420
2585.0
9.0
755.7
1944.126.0215
.1.3
22
min
2
6
lim
use
cmmmAs
assume
mmcmb
mmcmd
mkNM
w
u
uCVkNV 8.51000/75124
6
2575.0
Design for shear
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LongitudinalSupported stairswell stairs-Open
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General Example