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JNTU ONLINE EXAMINATIONS [Mid 2 - EMTL]

1.The ideal conducting boundary is analogous toa. The transmission line terminated with itscharacteristic impedanceb. Open circuit on the transmission linec. Short circuit on the transmission lined. The transmission line terminated with any load.

2.For normal incidence of the wave on perfectconductora. Surface current doesn't existb. Surface current existc. Conduction current existd. Free charge exists on the surface3.At the dielectric conductor interface the wavea. Complete transmission takes placeb. Complete reflection takes placec. Both reflection and transmission takes placed. No transmission and no reflection take place.4.At the dielectric conductor interfacea. The H is double of the incident fieldb. The E is double of the incident field

c. The H is half of the incident fieldd. The E is half of the incident field5.The magnitude of the E at the dielectric-conductor interfacea. Zerob. Infinityc. Twice to that of the incident field

d. Half to that of the incident field6.The conductivity of an ideal conductor isa. Zerob. Unityc. Infinityd. Two7.For normal incidence of a wave on dielectric-conductor interface the magnitude ofreflection coefficient isa. Unityb. Zeroc. Infinityd. In between 0 and 1

8.The electric field within a conductor isa. Infinityb. Zeroc. Unityd. Equal to surface current9.A standing wavea. Progresses with less than light velocity

b. Progresses with more than light velocityc. Progresses with light velocityd. Does not progress10. The unit for surface currenta. Ampereb. Ampere/mc. Ampere/m2d. ampere/m311. For normal incidence ,the angle of incidenceisa.b.c.

d.12. In the case of perpendicular polarizationa. The H is perpendicular to the plane of incidence andparallel to the reflecting surfaceb. The E is perpendicular to the plane ofincidence and parallel to the reflecting

surfacec. The H is Parallel to the plane of incidence andperpendicular to the reflecting surfaced. The E is parallel to the plane of incidence andperpendicular to the reflecting surface13. The expression for snells law isa. Sin /Sin = Sqrt( )b. Sin /Sin = Sqrt( )c. Sin /Sin = Sqrt( ))d. Sin /Sin = Sqrt( ))14. The refractive index of a dielectric materiala. Sqrt( )b. Sqrt( )c. Sqrt( )

d. Sqrt( )15.As per the boundary conditiona. The normal components of E is continuous acrossthe boundary.b. The tangential components of E is continuousacross the boundary.c. The tangential components of D is continuous across

the boundary.d. The normal components of H is continuous acrossthe boundary16. The absorption of power in propagationthrough the dielectric isa. Highb. Lowc. Zerod. Infinity17. The dimension of a reflection coefficient isa. A/mb. V/mc. No unit

d. V/A18. Expression for reflection coefficient in termsof SWR(s)a. l l =(s2+1)/(s2-1)b. l l =(s+1)/(s-1)c. l l =(s2-1)/(s2+1)d. l l =(s-1)/(s+1)19. The range of reflection coefficient isa. 0 to 1b. -1 to 1c. 0 to infinity

d. - infinity to + infinity20. Ifis reflection coefficient and istransmission coefficient thena. = 1+b. l l = 1+c. = 1-l ld. ll = 1-

21. The another name of Brewster angle isa. Angle of reflection
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b. Polarizing anglec. Angle of transmissiond. Non polarizing angle22.During total internal reflection wave undergoesa. A phase changeb. Polarization change

c. Magnitude changed. No change in the phase

23. The Total internal reflection can takes placea. If the wave travels from Rarer to Denser mediumb. If the wave travels from Denser to Rarermediumc. If the wave travels from Denser to Denser mediumd. If the wave travels from Rarer to Rarer medium24.Under total internal reflection the reflectioncoefficient for both polarizations isa. A real quantityb. An imaginary quantityc. A complex quantity

d. May be real or imaginary quantity25. For total internal reflection the fields in thesecond medium

a. Vanish completelyb. Do not vanishc. No change with angle of incidenced. Infinite at the interface26.When incident angle is Brewster angle thena. Complete reflection takes placeb. No reflection takes placec. Partial reflection only takes placed. Partial transmission only takes place27. Brewster angle is given bya. Tan=Sqrt( )

b. Tan=Sqrt( )c. Tan=Sqrt( )d. Tan=Sqrt( )

28. Brewster angle concept is applicable fora. Elliptical polarizationb. Perpendicular polarizationc. Parallel polarizationd. Linear polarization29. The gas laser usesa. Brewster effect

b. Total internal reflection conceptc. Critical angle conceptd. Both Brewster effect and total internal reflectionconcept30. Surface impedance is a useful parameter incomputinga. Poynting vector

b. Dielectric lossesc. Conductor lossesd. Magnitude of electric field31. The surface resistancea. Increases with frequencyb. Decreases with frequency

c. Increases with conductivityd. Decreases with frequency and Increases withconductivity32. Electric and magnetic fields which areparallela. Constitute a power flow

b. Constitute infinite power flowc. Do not constitute any power flowd. Constitute unit magnitude power flow33. The surface impedance is defined asa.b.c.

d.34.At very high frequency the amount of power

penetration into the conductingmediuma. Very highb. Highc. Lowd. Very low35. The unit for pointing vector isa. Watts/mb. Watts/m2c. Watts/m3d. Watts

36. The pointing vector givesa. The direction of E fieldb. The direction of H field

c. The direction of wave propagationd. The direction of both E and H fields37. The pointing vector in free space is given bya.b.c.d.38. The average power density is given bya. 1/2 Re (E X H)b. 1/2 Re (E X H *)c. 1/2 Re (E* X H )d. 1/2 Re (E* X H* )39. Poynting theorem is strictly valid fora. Free space

b. Open surface onlyc. Spherical surface onlyd. Any closed surface40.A uniform plane wave traveling in a dielectricof refractive index 2 is incident at thedielectric air surface. Then the critical angle atthe interface isa. Sinb. Sinc. Sind. Tan41. In a region E= 100( ) e and H=( ) e . Thenaverage power flowdensity is

a.b.c.

d.42.A uniform plane wave traveling in air with apower density of 2W/m2. Then theelectric field strength of the wave isa.b.c.d.
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c. Any X-Y planed. Z=0 plane only63. For a z directed guided wave betweenparallel conducting planes, the standingwave distribution across the guide ina. Z - directionb. Y -direction

c. X - directiond. Y and Z directions

64. For a z directed TE wavea. Hz = 0b. Ez = 0c. Hz = Ez = 0d. E = 065. If frequency is less than critical frequencythen the guided wave between parallelconducting planesa. Progresses without any attenuationb. Attenuates linearlyc. Attenuates exponentially

d. Have value for phase constant66. The frequency at which, wave motion ceasesis called

a. Lower 3-db frequencyb. Cut-off frequencyc. upper 3-db frequencyd. Maximum frequency67. Other name of TE wave isa. E waveb. H wavec. E & H waved. Uniform plane wave68. For a TEm0 mode of propagation of guidedwaves , the minimum value of m isa. Zerob. Onec. two

d. Three69. Cut-off frequency is a frequency below whicha.b.c.d.70. The propagation constant between parallelplates isa.b.c.d.71. The velocity of propagation of equiphasesurfaces along the guide is

a. Guide velocityb. Light velocityc. Phase velocity

d. Group velocity72. In TMm0 mode of propagation of guidedwaves , the minimum value of m isa. Oneb. twoc. Zerod. Three73. The dominant mode hasa. Highest cut-off frequency

b. Average cut-off frequencyc. Lowest cut-off frequencyd. Any cut-off frequency74. For a z directed TM wavea.b.c.

d. H = 075. Other name of TM wave is

a. E waveb. H wavec. E & H waved. Uniform plane wave76.When a wave of 6 G Hz propagating in parallelconducting planes separated by'd'cm. then the cutoff wavelength isa. 2d cmb. 1.5 d cmc. d cmd. 0.5 d cm

77. If operating frequency is greater than thecutoff wavelength, thena. = infinity

b. = Zeroc.d.78. Group velocity , phase velocity and free spacevelocity are related bya.b.c.d.79. TEM mode is equal toa. TEb. TEc. TMd. TM

80.Attenuation factor for a TEM wave isproportional toa. Frequencyb. Sqrt( Frequency )c. Conductivityd.81. The attenuation constant for a TEM mode ofpropagation isa. Lowb. Highc. Infinityd. Zero82. The velocity of TEM wavea. Depends on frequency

b. Depends on the mediumc. Depends on the conductivityd. Independent of the frequency

83.Across a cross section normal to the directionof propagation, the amplitudes offields of a TEM wavea. Constantb. Increases linearlyc. Increases exponentiallyd. Decreases exponentially84. For a TEM wavea.
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b.c.d.85. TEM wave exists ina. Between parallel platesb. A hollow wave guidec. A dielectric filled wave guide

d. A micro strip86. Cut-off frequency for a TEM wave is

a. Infinityb. Zeroc. 2 G Hzd. 3 G Hz87.A mode which does not propagate isa. Principal waveb. Evanescent modec. Dominant moded. TE mode88. The cut-off wave length for a TEM wave isa. Zero

b. Infinityc. Lowd. High

89. The wave impedance for a z directed TMwave isa.b.c.d.90.When frequency approaching infinity, thewave impedance of TE and TM wavesbetween parallel conducting platesa.b.c. Approaches infinityd. Approaches zero91. For TM waves the attenuation is minimum at

a.b.c.d. f = fc92. The wave impedance over the cross sectionof the guide isa. Constantb. Increases with frequencyc. Decreases with frequencyd. Increases exponentially93. The free space wavelength of a wavepropagation at 6 G Hz isa. 3 cmb. 4 cm

c. 5 cmd. 6 cm94. For a TEM wave , the wave impedance is

a.b.c.d.95.When a wave is traveling in Z direction , thenits impedance is given bya.b.c.

d.96. Consider a wave of 3 G Hz propagating inparallel conducting plates separated by 3cm. Then the lambda c isa. 3 cmb. 1.5 cmc. 6 cm

d. 1/3 cm97. Consider a wave propagating in parallel

conducting plates separated with = 6times 108 m/s. Then isa.b.c.d.98. If a dielectric of = 4 is filled in betweenparallel plate waveguide then thevelocity of wave propagation isa.b.

c.d.99. In a coaxial transmission line electric and

magnetic fields area. Confined to a dielectric mediumb. Confined to the inner conductorc. Confined to the outer conductord. Not Confined to dielectric medium100. Parallel plate transmission line fabricatedon a dielectric substrate usingprinted circuit technology often called asa. Integrated circuitb. Strip linec. Wave guided. Resonator101. In a transmission line parametersa. G=1/R

b.c. RG=1d. R/G=1102. The electrical length of the transmission lineis equal toa. Physical lengthb.c.d.103. The line parameters R, L, G, C area. Discreteb. Lumpedc. Uniformly distributedd. Non uniformly distributed

104. The ratio of positively traveling voltagewave to positively traveling currentwave at any point on the transmission line is

known asa. Load impedanceb. Characteristic impedancec. Line impedanced. Source impedance105. A two conductor transmission line supportsa. TE mode wave onlyb. TM mode wave onlyc. Both TE and TM mode waves
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d. TEM mode wave106. In solving transmission line problems weuse the following circuit quantitiesa. E and Hb. D and Bc. V and Id. J and E

107. Two wire transmission lines consists of apair of parallel conducting wires

separated bya. Non uniform distanceb. Zero distancec. Uniform distanced. Infinite distance108. In a TEM mode of propagationa. E is transverse to the direction of propagationb. H is transverse to the direction of propagationc. Both E and H are transverse to the direction ofpropagationd. Neither E nor H are transverse to the direction of

propagation109. For a two wire transmission line atmicrowave frequencies

a.b.c.d.110. In a transmission line the voltage andcurrent standing waves area. 1800 out of phase along the lineb. 00 out of phase along the linec. 900 out of phase along the lined. 2700 out of phase along the line111. The unit for electrical length of the line isa. Radiansb. Metersc. Feet

d. Degrees112. When the dielectric of a lossy microwavetransmission line is not air, then thephase velocitya. Smaller than velocity of light in vacuumb. Greater than velocity of light in vacuumc. Equal to the velocity of light in vacuumd. Inversely proportional to the velocity of light invacuum113. When a line is called as a flat line thenstanding wave ratio isa. Unityb. Zeroc. Infinity

d. Two114. The unit for attenuation constant isa. dB/m

b. Radian / mc. Volt/md. Amp./m115. The phase velocity of transmission line isa.b.c.d.

116. In a transmission line when terminationimpedance is equal to characteristicimpedance of that line then the reflectioncoefficient isa. Unityb. Infinityc. Zero

d. Equal to transmission coefficient117. In a transmission line the distance between

two successive minima isa.b.c. d.118. The expression for group velocity isa.b.c.d.119. For a low loss line the phase velocity is

a. Increases with frequencyb. Decreases with frequencyc. Approximately constant

d. Increases with square of frequency120. For minimum attenuationa. C=LG/Rb. C=LR/Gc. C=G/LRd. C=R/LG121. For a low loss line phase constanta.b.c.d.122. A lossy transmission linea. Non Dispersiveb. Dispersive

c. Have infinite lossd. It must be a distortion less line123. For a lossless line if , the impedance at anypoint on the line isa.b.c.d.124. For a loss less linea. R/L = G/Cb. R = Gc. R=G=0d. RL = GC125. For a lossless line the characteristic

impedance isa.b.

c.d.126. The condition for a distortion less line isa. L/R = G/Cb. RL = GCc. R/L = C/Gd. R/L = G/C127. For a lossless line the normalizedimpedance inverts for every
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a.b.c.d. 128. For a lossless line the line characteristicsrepeat for everya.

b.c.

d. 129. A lumped loaded lines behaves as aa. High pass filterb. Band pass filterc. Band reject filterd. Low pass filter130. Effect of loading of a transmission line uponits characteristic impedance isa. Z0 increasesb. Z0 decreasesc. Z0 becomes constant

d. No change131. The loading coils area. Lumped inductors

b. Lumped capacitorsc. Distributed inductord. Distributed capacitor132. The loading practice generally restricted toa. Open wires onlyb. cables onlyc. strip linesd. wave guides133. If and are the total inductance and totalcapacitance of the lineincluding the loading coils , then its cutofffrequency is given bya.b.

c.d.134. By inserting inductance in series with theline to increase the inductance iscalleda. Unloadingb. Loadingc. Feedbackd. Open circuit135. For a loaded line the alteration for delta > fca. Decreases rapidlyb. Rises rapidlyc. No changed. Zero

136. For ocean cables the type of loading used isa. Lumped loadingb. Continuous loading

c. Patch loadingd. Unmatched loading137. Hysteresis and eddy current losses inloading coils leads toa. Increase in Lb. Decrease in Lc. Increase in Rd. Decrease in R138. In a continuously loaded cable

a. increases uniformly with increase infrequencyb. decreases uniformly with increase in frequencyc. increases uniformly with decrease in frequencyd. decreases uniformly with decrease in frequency139. For a lossless line if = 50 ohms and = 2.5 xm/s then theinductance of the line isa.

b.c.d.140. A lossless line has = 100 ohms and = 10rad/m operating at 100 M Hz.

Then the capacitance of the line per meter isa. 1.0 pF /mb. 1.0 micro farad/mc. 100 farads/md. 1.0 nano farad/m141. A low loss transmission line operating at

100 M Hz has L=0.25 micro henry/m, C= 100pF/m. Then the phase constant isa.

b. c.d.142. If 100 meter length transmission line has = 0.05Np/m , the attenuation atthe end of the linea. 43.4 dBb. 5 dBc. 50 dBd. 34.3 dB143. A transmission line operating at 100 M Hzhas= rad/m . Then the phasevelocity isa.

b.c.d.144. high frequency line has L= 0.1 mH/Km, C=0.1 micro farads/Km . If R & G arenegligible , then characteristic impedance isa. 50 Ohmsb. 100 Ohmsc. 200 Ohmsd. 400 Ohms145. A transmission line operating at 1 G Hz hasL=1 micro henry/m , C= 1pF/m,R= G=0. Then its characteristic admittance isa. 10 mhos

b. 0.01 mhosc. 0.001 mhosd. 0.1 mhos146. If the phase velocity is 4.5 x m/s then thegroup velocity isa.b.c.d.147. A transmission line operating at 2 M Hz hasvoltage reflection coefficient of0.5 . then VSWR is
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a. 1b. 2c. 3d. 4148. One neper is equal toa. 6.86 dBb. 8.86 dB

c. 8.68 dBd. 10 dB

149. If a transmission line is terminated with ashort circuit then the I/Pimpedance of the line isa.b.c.d.150. Input impedance of a short circuitedtransmission line becomesa. Pure resistiveb. Pure reactive

c. complex quantityd. Zero151. If , the input impedance of a open circuited

line will bea. Inductiveb. Capacitivec. Resistived. Complex quantity152. If , the input impedance of short circuitedline will bea. Capacitiveb. Inductivec. Resistived. Complex quantity153. the reflection coefficient for a shortcircuited transmission line isa. Zero

b. Infinityc. +1d. -1154. The SWR of a open circuited transmissionline isa. Zerob. Infinityc. 1d. 2155. The relation between and is given bya.b.c.d.

156. The SWR of a transmission line which isterminated with its characteristicimpedances given by

a. 1b. 2c. zerod. infinity157. The incident power is fully absorbed by theload ifa.b.c.

d.158. The maximum power transfer is possiblewhena. Transmission line is open circuitedb. Transmission line is matched with the loadc. Transmission line is short circuitedd. Transmission line is connected to a load which is not

equal to159. Quarter wave transformer is

a. Voltage sensitive deviceb. Current sensitive devicec. Frequency sensitive deviced. Power sensitive device160. A short circuited /4 line can be used as

a. A conductorb. An insulatorc. A capacitord. An inductor161. The range of UHF isa. 30 M Hz to 300 M Hzb. 300M Hz to 3 G Hzc. 3 M Hz to 30 M Hzd. 3 G Hz to 30 G Hz

162. At the input terminals a short circuited lineappears asa. Matched terminationb. Short circuitc. Open circuitd. Improper terminator163. A line may be used to transform anyresistance to an impedance with amagnitude equal toa. R0 of the lineb. Z0 of the linec. 1/R0 of the lined. 1/Z0 of the line164. A half wave lossless line transfers the load

impedance to the input terminalsasa.b.c.d.165. when the length of a line is an integralmultiples of/2 then Tan l is equaltoa. Unityb. Zeroc. Infinityd. Two166. Which of the following is a one to one

transformera.b.c.d.167. A /4 line may be considered as

a. Voltage inverterb. Current inverterc. Impedance inverterd. Power inverter168. An equation applies toa. line
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b. linec. lined. line169. The center of the smith chart representsa. matched load impedanceb. Source impedancec. Line impedance

d. Reactive load impedance170. On a smith chart real axis represents

a. Any impedanceb. Purely resistive impedancec. Purely reactive impedanced. Any admittance171. On a transmission line are separated by thedistance ofa. /4

b. /8c. /2d. 172. In a transmission line at a point of there is a

a.b.c.

d.173. On a smith chart for x=0 circles the centeris ata. (1,0)

b. (1,1)c.d.174. A complete revolution around the smithchart represents a distance ofa. on the lineb. on the linec. on the lined. on the line175. The smith chart can be used as

a. Impedance chart onlyb. Admittance chart onlyc. Impedance chart as well as Admittance chart

d. Normalized admittance chart only176. The constant r and constant x circles allpass through the pointa.b.c.d.177. The upper half of the smith chart representsa.b. +jxc.

d.178. When a transmission line is shorted , thefirst voltage minimum occurs ata. Sourceb. A distance of/2 from the loadc. Loadd. A distance of/4 from the load179. The stub length to be adjusteda. To neutralize the susceptance of the loadb. Not to change the susceptance of the load

c. To increase the susceptance of the loadd. To decrease the susceptance of the load

180. In the single stub matching the location ofthe stub changes witha. Load impedanceb. Source impedancec. Characteristic impedanced. Frequency181. A stub with a short circuited load offers

a. Capacitive reactanceb. Inductive reactance

c. Pure resistanced. Impedance182. By connecting the stub at the load pointa. Matching cannot be obtainedb. Matching can be obtainedc. Matching can be obtained for a particular frequencyd. Matching can not be obtained for a particularfrequency183. In a double stub tuner, the spacing betweenthe stubs isa. b. /4c. /2d. 2

184. The impedance seen beyond the stub isequal toa. Load impedanceb. Source impedancec. Characteristic impedanced. Reciprocal of characteristic impedance185. In a stub matching it is more convenient tosolve the problem usinga. Admittanceb. Impedancec. Resistanced. Reactance186. Stub is to be used to neutralize thea. Resistance of the load

b. Impedance of the loadc. Susceptance of the loadd. Admittance of the load187. A short circuited stub is ordinarily preferredto an open circuited stubbecausea. It has lower loss of energy due to radiation

b. It has higher loss of energy due to radiationc. It has complete loss of energy due to radiationd. Its length is small.188. A single stub matching is aa. Narrow band systemb. Broad band systemc. Pass band system

d. Band reject system189. A certain low loss line has = 400 ohms. For= 200 ohms, the SWR isa.b. 1/3c. 2

d. 4190. Two very long lossless cables ofcharacteristic impedances of 36 ohms and100 ohms respectively are to be joined forreflection less transmission. The ofa matching transformer is
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a. 36 ohmsb. 100 ohmsc. 60 ohmsd. 1/36 ohms191. In a transmission line if the distancebetween two successive minima's is 5meters. Then the operating frequency of the

signal impressed on it isa. 3 K Hz

b. 3 M Hzc. 3 G Hzd. 30 G Hz192. If the phase constant on the line is 2rad/m, the distance between twosuccessive maxima isa. 20 cmb. 30 cmc. 40 cmd. 50 cm193. Consider a 5m length transmission line isproperly terminated with 50 ohmsLoad Then the input impedance at 3m fromsource end is

a. 25 ohmsb. 50 ohmsc. 75 ohmsd. 100 ohms194. A transmission line operating at 1.6 G Hzhas Zoc= ohms anda.b.c.d.195. A loss less line has = 50 ohms. If it isconnected to a load of =(50/(2+j2)) ohms. Then the normalizedadmittance is

a. (2+j2)b. (2-j2)c. 1/(2+j2)d. 1/(2-j2)196. If SWR = 1 then the reflection coefficient isa. Zerob. One

c. Twod. Infinity197. A transmission line has = 50 ohms, and =100 ohms. Then isa. 200 ohmsb. 75 ohmsc. 50 ohms

d. 25 ohms198. For a quarter wave transformer l is equal toa. /4b. /2c. d. 2
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EMWT MID2 [UandiStar.org]

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