EMCF-18-F14

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    MATH 3321 Quiz 18 11/19/14

    1. The linear differential system equivalent to the differential equation

    y 2y 8y= 2e3t

    is:

    (a)

    x1x2

    =

    0 18 2

    x1x2

    +

    0

    2e3t

    (b)

    x1x2

    =

    0 18 2

    x1x2

    +

    2e3t

    0

    (c)

    x1x2

    =

    0 18 2

    x1x2

    +

    0

    2e3t

    (d)

    x1x2

    =

    0 18 2

    x1x2

    +

    2e3t

    0

    (e) None of the above.

    2. The linear differential system equivalent to the differential equation

    y 4

    ty +

    6

    t2y= 2t2

    is:

    (a)

    x1x2

    =

    0 16/t2 4/t

    x1x2

    +

    02t2

    (b)

    x1x2

    =

    0 16/t2 4/t

    x1x2

    +

    2t2

    0

    (c)

    x1x2

    =

    0 16/t2 4/t

    x1x2

    +

    02t2

    (d) x1x2

    = 0 16/t

    2

    4/t x1

    x2+ 2t

    2

    0

    (e) None of the above.

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    3. Find a fundamental set of solutions of x =

    0 110 3

    x. Hint: This system is equivalent

    to a second order homogeneous equation.

    (a) x1=

    e5t

    5e5t

    , x2=

    e2t

    2e2t

    (b) x1=

    e5t

    5e5t, x2=

    e

    2t

    2e2t

    (c) x1=

    e5t

    e5t

    , x2=

    e2t

    e2t

    (d) x1=

    e5t

    5e5t

    , x2=

    e2t

    2e2t

    (e) None of the above.

    4. Find a fundamental set of solutions of x = 0 1

    12/t

    2

    6/tx. Hint: This system is

    equivalent to a second order homogeneous equation.

    (a) x1=

    t3

    t2

    , x2=

    t4

    t3

    (b) x1=

    t3

    3t4

    , x2=

    t4

    4t5

    (c) x1=

    t3

    3t2

    , x2=

    t4

    4t3

    (d) x1= t3

    3t2, x2=

    t4

    4t5

    (e) None of the above.

    5. The general solution of x =

    0 16 1

    x+

    0

    2e2t

    is:

    (a) x= C1e3t

    13

    +C2e2

    t

    12

    +

    0

    1

    2e2t

    (b) x= C1e3t 1

    3+C2e2t 1

    2+

    1

    2e2t

    e2t

    (c) x= C1e3t

    13

    +C2e

    2t

    12

    +

    e2t

    0

    (d) x= C1e3t

    13

    +C2e

    2t

    12

    +

    e2t

    2e2t

    (e) None of the above.

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    6. The general solution of x =

    0 1 00 0 1

    4 4 1

    x is: Hint: This system is equivalent to a

    third order homogeneous equation.

    (a) x= C1e2t

    124+C2e2t

    12

    4 +C3et

    11

    1

    (b) x= C1e2t

    12

    4

    +C2e2t

    12

    4

    +C3et

    11

    1

    (c) x= C1e2t

    12

    4

    +C2e2t

    12

    4

    +C3et

    10

    1

    (d) x= C1e2t

    12

    4

    +C2e2t

    12

    4

    +C3et

    11

    1

    (e) None of the above.

    7. A fundamental set of solutions of x =

    3 2

    1 2

    x is:

    (a) x1= e4t

    21

    , x2= e

    t

    11

    (b) x1= e4t

    21

    , x2= e

    t

    11

    (c) x1= e4t

    21

    , x2= e

    t

    11

    (d) x1= e4t

    21

    , x2= e

    t

    11

    (e) None of the above.

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    8. The solution of the initial-value problem x =

    1 1

    4 2

    x, x(0) =

    2

    5

    is:

    (a) x= 35e3t

    14

    + 13

    5e2t

    11

    (b) x=

    3

    5e3t 1

    4 13

    5e2t 1

    1

    (c) x= 35e3t

    1

    4

    13

    5e2t

    11

    (d) x= 35e3t

    14

    13

    5e2t

    11

    (e) None of the above.

    9. A fundamental set of solutions of x =

    3 2 23 1 3

    1 2 0

    x is:

    (a) x1= e2t

    011

    , x2= et

    11

    1

    , x3= et

    101

    (b) x1= e2t

    10

    1

    , x2=et

    11

    1

    , x3= et

    12

    1

    (c) x1= e2t

    02

    1

    , x2= et

    11

    3

    , x3= et

    10

    1

    (d) x1= e2t

    01

    1

    , x2=et

    11

    1

    , x3=et

    10

    1

    (e) None of the above.

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    10. The general solution of x =

    1 3 11 1 1

    3 3 1

    x is

    (a) x= C1e2t

    3

    2

    3

    +C2 e2

    t

    11

    1

    +C3e

    t

    31

    3

    (b) x= C1e

    2t

    32

    3

    +C2 e2t

    10

    1

    +C3et

    31

    3

    (c) x= C1e2t

    323

    +C2 e2t

    10

    1

    +C3et

    313

    (d) x= C1e2t

    32

    3

    +C2 e

    2t

    1

    10

    +C3e

    t

    3

    13

    (e) None of the above.

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