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    V.M.K.V. ENGINEERING COLLEGE

    DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING

    ELECTRONIC DEVICES MATERIALBy

    P.LOGANATHAN M.E.,AP / EEE,

    DEPARTMENT OF ELCTRICAL AND ELECTRONICS ENGINEERING.

    V.M.K.V. ENGINEERING COLLEGE,PERIYA SEERAGAPADI, SALEM 636 308.

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    + + + + + + +

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    A

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    Vd

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    UNIT-I: BASICS OF SEMICONDUCTORS

    (2 MARKS)

    1. What is the path taken by the electron when it enters a uniform electric field?

    When the charged particle (q Charge) moves in the direction of electric field (Eintensity), A force F=q*E .the path will be straight line. An electron placed at plate A will

    be attracted towards the positively charged plate B. The tracing path of electron is straightline.

    2. What is the path taken by the electron when it is placed in a uniform magneticfield with zero initial velocity?

    When a charge particle moves in a magnetic field, it experience a force whose

    direction is perpendicular both to the direction of motion of the particle and to the direction

    of the field.

    3. What is the path taken by the electron when it enters a uniform magnetic fieldwith an initial velocity at an angle with the direction of the field?

    An electron is injected with an initial velocity of v m/sec at a small angle to thedirection of a magnetic field of flux density B wb/m2 as a result of these concurrent motions,

    the electron traces a helical path.

    X X X X

    X X X X

    X X X X

    X X X X

    X

    X

    CIRCULAR PATH

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    4. What is the path taken by the electron when it is placed in perpendicular electric

    and magnetic fields with zero initial velocity?

    Let electric and magnetic fields align along y-direction and velocity vector is aligned

    along positive x-direction. Let the charge be positive and initial velocity be vo In this case,velocity and magnetic field vectors are perpendicular to each other. Applying Right hand vector

    cross product rule, we determine that magnetic force is acting in positive z-direction. If electric

    field is not present, then the particle revolves along a circle in xz plane as shown in the figure

    below. Motion of a charged particle in electric and magnetic fields

    The radius of each of the circular element and other periodic attributes like time period,

    frequency and angular frequency are same as for the case of circular motion of charged particle

    in perpendicular to magnetic field

    R = v / B ; T = 2 / B ; = B / 2 ; = B

    5. An electron is accelerated through a potential of 40 V before it enters a magnetic

    field density of 0.91 Wb/m2

    at an angle of 30 degrees with the field. Find the

    position of the electron after which it has completed one revolution in the field.

    The velocity of electron is = 2qva/ m = 3.68 x 106 m / s.

    The time taken for one revolution is T = 2m / Bq = 4 x 10-11 s.

    The pitch = T v cos = 1.27 x 10-4 m.

    Thus the electron has traveled the position after completed one revolution in the field is

    1.27 x 10-4 m.

    6. Differentiate intrinsic and extrinsic semiconductors.S.NO Intrinsic Semiconductor Extrinsic Semiconductor

    1 It is a pure form of semiconductor An impurity of doping agent is addedin the pure semiconductor formsextrinsic semiconductor.

    2 Number of electrons and holesare equal Number of electrons and holes arenot equal because of doping3 Conductivity is poor Conductivity is improved

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    7. Differentiate P-type and N-type semiconductors.S.NO P - type Semiconductor N - type Semiconductor

    1 An trivalent impurities is added topure Si or Ge to form P type

    Semiconductor

    Pentavalent impurities are added topure Si or Ge to form N type

    Semiconductor.2 Doping agents : gallium, indium

    etc,Doping agents : Arsenic, Antimonyetc,

    3 Holes are majority carriers:Electrons are minority carriers

    Electrons are majority carriers: areHoles minority carriers

    8. Draw the energy band diagram of a semiconductor.

    9. Define Fermi Level in semiconductor.The Fermi level is defined as the maximum energy level, which is occupied by an

    electron at absolute zero temperature.

    10. Illustrate the Fermi level of a P type semiconductor.

    DISTANCE

    FERMI LEVEL

    ENERGYL

    EV

    EL

    FORBIDDEN ENERGY GAP = 1.1 eV

    CONDUCTION BAND

    VALANCE BAND

    D

    E

    DISTANCE

    FERMI LEVEL

    ENERGYL

    EVEL

    FORBIDDEN ENERGY GAP

    CONDUCTION BAND

    VALANCE BAND

    D

    E

    E

    EC

    EA

    E VALANCE BAND

    DISTANCE

    FERMI LEVEL

    ENERGY LEVEL

    FORBIDDEN ENERGY GAP

    CONDUCTION BAND

    D

    Excess Holes

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    ED

    E

    RS

    E VALANCE BAND

    DISTANCE

    FERMI LEVEL

    ENERGY LEVEL

    FORBIDDEN ENERGY GAP

    CONDUCTION BAND

    D

    Excess Electrons

    Where EA = Acceptor Energy Level

    EV = Valance band energy Level

    EC = Conduction band energy Level

    11. Illustrate the Fermi level of an N type semiconductor.

    12. What is the effect of temperature on position of Fermi level?

    In an N type semi conductor, as temperature T increases, more number ofElectrons hole pairs are formed. At very high temperature T, the concentration ofthermally generated electrons in conduction band will be far greater than theconcentration of donor electrons. In such case, as concentration of holes and electrons

    become equal, the semi conductor becomes essentially intrinsic and EF returns to themiddle of the forbidden energy gap, hence it is concluded that as the temperature of P

    and N type semiconductor increases, EF progressively moves towards the middle of theforbiddenenergygap.

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    13. In a P-type semiconductor, the Fermi level is 0.3eV above the valence bandat a room temperature of 300 K. Determine the new position of the Fermi level for

    a temperature of 400 K.

    The Fermi level in a P Type material is given by

    EF =EV + kTln NV / NA

    Therefore, (EF EV) = kTlnNV / NA

    At T = 300k, 0.3 = 300 k lnNV / NA

    (a) At T = 350k, (EF1 EV) = 350k lnNV/ NA

    Hence, from the above equation,

    EF1 EV / 0.3 = 350 / 300

    Therefore, EF1 EV = 350 / 300 x 0.3 = 0.35 eV

    (b) At T = 400k, (EF2 EV) = 400k lnNV/ NA

    Hence, from the above equation,

    EF2 EV / 0.3 = 400 / 300

    Therefore, EF2 EV = 400 / 300 x 0.3 = 0.4 eV

    14.What is Drift current?It is a current when an electric field is applied across the semiconductor, the holes move

    towards the negative terminal of the battery and electrons move towards the positive of the battery. This combined effect causes a current flow in the circuit. This current is called drift

    current.

    15.What is Diffusion current?A concentration gradient exists, if the number of either electrons or holes is greater in one

    region of a semi conductor as compared to the rest of the region. The holes and electrons then

    tend to move from region of higher concentration gradient to the region of lower concentration.

    This process is called diffusion and the electric current produced due to this process is known asdiffusion current.

    16.Define diffusion lengthThe minority carrier densities decay exponentially with the distance from the junction,

    with a characteristics decay length of LP for holes and LN for electrons. It can be shown that the

    average distance a hole diffuses before recombining is equal to LP so that it is called the diffusion

    length.Where

    LP = DP TP called the hole diffusion LengthLN = DN TN is called the electron diffusion length.

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    UNIT-II: CHARACTERISTICS OF DIODES

    (2 MARKS)

    1. Define breakdown voltage and cut-in voltage of a PN junction diodeBreakdown Voltage :

    It is a reverse biased voltage; in a PN junction diode anode is negative with respect

    to cathode, when the voltage is increased (VR) at which the PN junction breakdown is

    occur. This reverse voltage is called as breakdown voltage.

    Cut - in Voltage :

    It is a forward biased voltage; in a PN junction diode anode is positive with

    respect to cathode, when the voltage is increased (VF) at which the current flow through

    the PN junction starts increasing rapidly is known as cut-in voltage. It is also called asknee voltage or threshold voltage.

    2. Define PIV of a PN junction diodePIV is a Peak Inverse Voltage. It is the maximum allowable voltage applied across

    the diode when it is connected in reverse bias without destroying the device.

    3. Give the diode current equation

    WhereI is the diode current,IS is a scale factor called the saturation current,VD is the voltage across the diode,VT is the thermal voltage,

    And n is the emission coefficient, also known as the ideality factor. The emission

    coefficient n varies from about 1 to 2 depending on the fabrication process and semiconductor

    material and in many cases is assumed to be approximately equal to 1 (thus the notation n is

    omitted). The thermal voltage VT is approximately 25.85 mV at 300 K, a temperature close to

    room temperature commonly used in device simulation software. At any temperature it is a

    known constant defined by:

    where

    q is the magnitude of charge on an electronk is Boltzmanns constant,T is the absolute temperature of the p-n junction in kelvins

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    4. Give the circuit symbol of a varactor diode

    Equivalent circuit

    5. Give the applications of tunnel diodes

    1. Tunnel diode is used as mixers.

    2. Being high speed devices, tunnel diode also lend than themselves to high speed

    switching and logic operations as flip flop and gate.

    3. They are used as low power oscillator up to 1000GHz, because of their simplicity,

    frequency stability and immunity to radiation.

    4. It may be used throughout microwave range as moderate to low noise pre amplifiers in

    all kind of receivers.

    6. Give the advantages of tunnel diodes.

    1. Low Cost

    2. Simplicity construction

    3. High speed operation

    4. Low temperature sensitivity, low noise and low power

    5. Environmental Immunity.

    7. Compare avalanche breakdown and zener breakdown?

    S.NO Avalanche breakdown Zener breakdown

    1 This occurs in lightly doped diode This occurs in heavily doped diode

    2 These depletion region is very wide This depletion region is very small

    3 Electric field is low electric field is strong.

    4 It has sufficient kinetic energy and

    disrupts covalent bond in crystal andreleasing the valance electron.

    It break covalent bond and create

    new electron hole pair.

    C

    RRRS

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    8. Give the structure of a PIN diode.

    9. What is the advantage of a PIN diode over an ordinary PN junction diode?

    PIN diode is a high speed switching device, because its, highly improved

    switching time compare with PN diode and it have high resistivity intrinsic layer is

    sandwiched between the heavily doped P and N layer. It used as MPST switch.

    10. What are multi junction photodiodes?

    The multijunction diode is a high-impedance source and provides a negative biased

    signal. To actuate a conventional low-impedance meter movement, an impedance transformation

    device would be used. Such devices are within the current state of the art. Operational amplifiers

    of unity gain may be employed. If has been found that the multi junction diode of this invention,

    under open circuit conditions, has an output independent of the junction area. This permits the

    use of extremely small units. For example, the device whose response is shown above is about

    one-third of the area of the 1/16 th by 1/8 th inch hole normally used in tabulating cards.

    11. What is a photovoltaic cell?

    Photovoltaic cell is called as solar cell. It works on the principle of photovoltaic effect.

    Which is the light energy is converted to electrical energy, and it is a self generating device,

    when the light signal is strikes the device voltage is generated.

    12. What are the advantages and disadvantages of LEDs? Advantage:

    1. Less power consumption

    2.

    Very small size and weight3. Operating voltage and Current is less4. Variety of Spectral output colors

    IP N

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    5. Very fast action and Long life Disadvantage:

    1. Very sensitive device, (it damage by over voltage and over current)2. Radiated output power is temperature dependent.3. Low efficiency.

    13. What are the advantages and disadvantages of LCDs? Advantage:

    1. Power consumption is very small compared with LED2. It is used in Watches, pocket calculators, portable instrument displays3. contrast is high4. very small size and weight Disadvantage:

    1. The life time is Very less compare with LED

    2. The response time is more than LED3. Operates slowly.

    14. What are thermistors?

    A temperature-sensitive resistor is called a Thermistor. The resistance of most commontypes of thermistor decreases as the temperature rises. It is a bulk semi conductor devicehaving negative temperature coefficient of resistivity. These are frequently used astemperature sensors in the range of - 100 to 300. The resistance decreasingexponentially with increasing temperature. They are called negative temperaturecoefficient, or NTC, thermistors. As the temperature rises, more charge carriers become

    available and the resistance falls. Although less often used, it is possible to manufacture positivetemperature coefficient, orPTC, thermistors. These are made of different materials and showan increase in resistance with temperature.

    15. Give the applications of thermistors.1. In electronic circuit used as temperature compensating devices2. as a temperature sensor in electronic thermometers.

    3. as a sensing element in microwave power measuring equipment.4. as thermal delay.5. in control devices actuated by charges in temperature.

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    UNIT III-BIPOLAR JUNCTION TRANSISTORS

    (2 MARKS)

    1. Give the circuit representation of a PNP type transistor.The name transistor is derived from the words transfer and resistor. It has 3 terminal 3

    layer device as shown in figure,

    2. Give the circuit representation of an NPN type transistor.

    3. Define emitter efficiencyEmitter injection ratio or emitter efficiency is the ratio of the electron current to the total

    current

    The emitter efficiency is obtained from:

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    4. Define transport factorBase transportation factor is the ratio of number of electrons arriving at the collector to the

    number of injected electrons.

    The base transport factor equals:

    5. Define large signal current gainThe large signal current gain of a common base transistor is defined as the ratio of the

    negative of the collector current increment to the emitter current change from cutoff (IE = 0) to IE

    = - (Ic ICBO) / IE 0

    Where ICBO is the reverse saturation current flowing through the reverse biased collector

    base junction. As a magnitude of ICBO is negligible when compared to IE the above term canexpress as = Ic / IE

    Since Ic and IE are flowing in opposite directions, is always positive. Typical value of range from 0.90 to 0.955. Also is not a constant but varies with IE collector voltage VCB andtemperature.

    6. Give the relation between large signal current gain, emitter efficiency andtransport factor.

    Any of three basic configurations, there is a definite relationship, as pointed out earlier,

    between alpha (), beta (), and gamma (). These relationships are listed as below

    7.

    Give the circuit representation of a CB transistor configuration

    The above figure represents the circuit diagram of common base configuration

    transistor. Base terminal is common to both input characteristics and outputcharacteristics.

    (OR

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    8. Give the circuit representation of a CC transistor configuration

    9. Give the circuit representation of a CE transistor configuration

    10.Define early effectIt is defined as the variation of effective base with by collector base voltage is

    known as base width modulation or early effect. When the collector to base voltage is

    made to increase, it increases the depletion region across the collector base junction. With

    the result the effective width of base layer is decrease. It is called as early effect.

    11.Define alpha and beta of a transistor.Current amplification factor ():

    The ratio of change in collector current IC to the change in Emitter current IE at

    constant collector base voltage VCB is known as current amplification factor () = IC / IE at constant VCB

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    Base Current amplification factor ():

    It is defined as the ratio between change in collector current IC to the change in

    Base current IB

    = IC / IB

    12.Write the h parameter equations for CB configuration.

    13.Write the h parameter equations for CC configuration.

    14.Write the h parameter equations for CE configuration.

    15.How a transistor can be used as a switch?When used as an AC signal amplifier, the transistors Base biasing voltage is applied so

    that it operates within its "Active" region and the linear part of the output characteristics curves

    are used. However, both the NPN & PNP type bipolar transistors can be made to operate as an

    "ON/OFF" type solid state switch for controlling high power devices such as motors, solenoids

    or lamps. If the circuit uses the Transistor as a Switch, then the biasing is arranged to operate in

    the output characteristics curves seen previously in the areas known as the "Saturation" and

    "Cut-off" regions as shown below.

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    16.What are RF transistors?The RF bipolar transistor is planner in the form and mostly Si, NPN type operating

    up to 5db. At high frequency (RF) the reactance due to junction capacitance depend onthe depletion width and bias voltage etc., RF current handling capability, high power gain,

    low base resistance, and low output capacitance. This device is intended for Class A, B, or C

    amplifier, oscillator, or frequency multiplier circuits and is specifically designed for operation in

    the VHF-UHF region.

    17.What are power transistors?Power transistor is a semiconductor and widely used in electronic devices as an amplifier or a

    switch. It handles high voltage and high current rating. These transistors are mostly used in

    switching mode. A heavy-duty transistor designed for power-amplifier and power-control

    service. It has following specification

    1) High current capability2) Small reverse leak current3) High reliability4) High quality and low price

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    UNIT IV-FET AND UJT

    (2 MARKS)

    1. Why a Field Effect Transistor is called so?The field-effect transistor (FET) controls the current between two points but does so

    differently than the bipolar transistor. The FET operates by the effects of an electric field on the

    flow of electrons through a single type of semiconductor material. This is why the device is

    called as field effect transistor. It is sometimes called a unipolar transistor.

    2. What are the types of FET?Field-effect transistors exist in two major classifications.

    1. Junction FET (JFET)and2. Metal-Oxide- Semiconductor FET (MOSFET).

    I. Depletion and Enhancement MOSFET (DE MOSFET)

    II. Enhancement only MOSFET or E only MOSFET

    3. Define pinch off voltage of a JFETIt is the minimum drain source voltage at which the drain current essentially

    become constant. When a voltage is applied between drain and source (VDS) current flows and

    the silicon channel acts rather like a conventional resistor. Now if VDS is increased (with VGS

    held at zero volts) towards what is called the pinch off value VP, the drain current ID also at first,

    increases. The transistor is working in the "ohmic region" as shown in Fig

    4. List the advantages and disadvantages of JFET.Advantage:

    1. it has a very high input impedance ( in the order of 100M)2. The operation of JFET is depends upon the bulk material current carriers that do

    not cross the junctions. There for inherent noise is absent.3. It has negative temperature co efficient of resistance4. It has very power gain, small in size, long life and high efficiency.

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    Disadvantage:

    1. High leakage current. Low input impedance than MOSFET.2. Less transconductance.3. Amplification factor is not sufficient.

    4. Define Tran conductance of JFET.It is the ratio of change in drain current (ID) to the change in gate source

    voltage (VGS) at constant drain source voltage (VDS).

    Trans conductance gfs = ID / VGS at constant VDS in mA or micromho

    5. Define drain resistance of JFET.It is the ratio of change in drain source voltage (VDS) to the change in drain

    current (ID) at constant gate source voltage VGS

    Drain resistance rD = VDS / ID at constant VGS

    6. Define amplification factor of JFET.It is the ratio of change in drain source voltage (VDS) to the change in gate

    source voltage VGS (VGS) at constant drain current ID

    Amplification factor = VDS / VGS at constant ID

    7. List the applications of JFETa. The JFET Differential Amplifier

    b. A Low-Noise Amplifier

    c. The JFET Constant Current Source

    d. The JFET Analog Switch

    e. The JFET Voltage Controlled Resistor

    8. State the principle of operation of MOSFETs.The basic principle of the device is a voltage on the oxide-insulated gate electrode (G)

    can induce a conducting channel between the two other contacts called source (S) and drain (D).

    The channel can be of n-type or p-type, and is accordingly called an nMOSFET or a pMOSFET

    the gate terminal is formed as a small capacitor. One plate of this capacitor is the gate and the

    other plate is the channel with metal oxide as the dielectric. When the negative voltage isapplied on the gate, electrons accumulate on it. These electrons repel the conduction band

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    electrons in the n-channel therefore less number of conduction electrons are made available for

    current conduction through the channel. The greater negative voltage on the gate, the lesser is

    the current conduction from source to drain. If the gate is positive more electrons are made

    available in n-channel. Consequently current from source to drain.

    9. Give the circuit symbol of a P-channel enhancement MOSFET

    10. Give the circuit symbol of a P-channel depletion MOSFET

    11.Compare N channel and P Channel MOSFETsS.NO N channelMOSFET P channelMOSFET

    1 ON resistance is smaller thanPMOS, thus it is smaller in timeand occupies space.

    The mobility of electron in silicon atnormal electric field is about 2.5 times thatof holes thus its on resistance is highhence it occupies more space in ICfabrication.

    2 Size is small as well as itsjunction capacitance also smallresult in which very fast

    operation.

    Size is greater than NMOS, the internalcapacitance reduces the speed ofoperation.

    3 It require positive gate drainsupply,

    It require negative gate drain supply.

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    12. Define threshold voltage.Threshold voltage is defined as the minimum voltage that required making the transistor ON.

    Transistor may be either NMOS or PMOS. For NMOS the value of threshold voltage is positive

    value and for PMOS the value of threshold voltage is negative value.

    13. What is Gate capacitance?The gate electrode forms a parallel plate capacitor with the channel, where Sio2 layer act

    as dielectric. This formation of gate is called as gate capacitance. The gate definition spacer

    defines the walls of a second etched trench that is used to remove a portion of the p-n junction,

    thereby further reducing the junction capacitance

    14.What are the applications of CCD?Charge-coupled devices (CCDs) have made possible a revolution in image processing

    They consist of a series of light-sensitive elements, called pixels, arranged in a square or

    rectangular array. When CCDs are exposed to light, an image of the object being observed is

    formed; this image can be extracted from the CCD and stored on a computer for later analysis.

    CCDs are used in a variety of modern instruments, ranging from scanners and photocopiers to

    video cameras and digital still cameras. They have transformed the way scientists measure and

    chart the universe. Because CCDs are available in a wide price range, they are accessible to

    amateurs as well as professionals, and enable both to make significant contributions to modern

    astronomy.

    The potential of the charge-coupling concept for digital memory has been recognized.

    Applications to image sensing and signal processing requirements have, however, preceded the

    application of CCD to memory. This occurred because relatively simple charge-coupled devices

    offered new performance potentials for image sensing and signal processing. Nonetheless, the

    basic shift-register nature of CCD implies that its greatest opportunity for widespread application

    lies in the highly competitive area of high density semiconductor memory. Today, sophisticated

    CCD memory components are emerging.

    15. What are BBDs?The BBD consists of series MOSFET switches with capacitor connected at their nodes

    sampled values of input signal are stored as charge on the capacitor. It can be transferred from

    one stage to next by controlling the switches using a clock pulses.

    http://science.jrank.org/pages/1374/Charge-Coupled-Device.htmlhttp://science.jrank.org/pages/6419/Square.htmlhttp://science.jrank.org/pages/3929/Light.htmlhttp://science.jrank.org/pages/1374/Charge-Coupled-Device.htmlhttp://science.jrank.org/pages/1374/Charge-Coupled-Device.htmlhttp://science.jrank.org/pages/583/Astronomy.htmlhttp://science.jrank.org/pages/583/Astronomy.htmlhttp://science.jrank.org/pages/1374/Charge-Coupled-Device.htmlhttp://science.jrank.org/pages/1374/Charge-Coupled-Device.htmlhttp://science.jrank.org/pages/3929/Light.htmlhttp://science.jrank.org/pages/6419/Square.htmlhttp://science.jrank.org/pages/1374/Charge-Coupled-Device.html
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    A capacitive delay device comprising a sequence of capacitances, in which information is

    transferred by charge transfer. The device is provided with at least one auxiliary store which has

    been connected between a first and a second capacitance, whilst after a charge transfer between

    the capacitances a residual charge transfer takes place between the first capacitance and the

    auxiliary store, after which the charge stored in the auxiliary store and in the second capacitance

    is transferred to a capacitance succeeding the second capacitance.

    16. What is the difference between a UJT and a BJT?S.NO UJT BJT

    1 It is 2 layer 3 terminal device It is 3 layer 3 terminal device

    2 It has no ability to amplify the

    signal.

    It has the ability to amplify the signal

    3 Current conduction is only dueto one type of charge carriers.Majority charge carriers

    Current conduction is both types of chargecarriers. In electron and holes.

    4 It is used as oscillator It is used as amplifier

    17. Define intrinsic ratio-off ratio of a UJT.The intrinsic standoff ratio is the ratio of voltage drop across RB1 (VA) to the battery

    voltage RBBO (VBB). It varies from 0.4 to 0.8 for different devices. The schematic symbol is

    Figure below

    Intrinsic standoff ratio = VA / VBB

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    UNIT 5: SCR AND PRINCIPLES OF IC

    (2 MARKS)

    1. Give the basic structure and circuit symbol of an SCR

    (OR)

    2. Draw the two transistor version of SCR.

    3. Define latching current of an SCR

    It is the minimum current flowing from anode to cathode when SCR goes from OFF state

    to ON state and remains in ON state even after gate bias is removed. It is greater than but very

    close to Holding current.

    4. Define holding current of an SCR

    It is that value of current below which the SCR switches from the conduction state (ONstate) to the forward blocking state.

    5. Define forward current rating and breakdown voltage of SCR.

    Forward current rating of SCRis defined as that the maximum anode current that it

    can handle without destruction.

    Break down voltage is the reverse voltage in which the breakdown occurs, and

    breakings happened in junction J1

    and unction3when Anode is negative with respect to cathode.

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    6. Why an SCR is operated only in forward biased condition?

    The reverse bias condition is represented by -V. A reverse bias exists when the potential

    applied across the SCR results in the cathode being more positive than the anode. In this

    condition the SCR is non-conducting and the application of a trigger voltage will have no effect

    on the device. In the reverse bias mode, the knee of the curve is known as the Peak Inverse

    Voltage PIV (or Peak Reverse Voltage - PRV) and this value cannot be exceeded or the device

    will break-down and be destroyed. A good Rule-of -Thumb is to select a device with a PIV of at

    least three times the RMS value of the applied voltage. Therefore current conduction in reverse

    bias is negligible. This is a fact that SCR operated only in forward bias.

    7. Give the basic structure and circuit symbol of a TRIAC

    8. Give the two SCR version of a TRIACThe SCR will only operate when the anode is positive to the cathode. Two SCR's can be

    placed back-to-back in order to operate with positive and negative voltages. A Triac is equivalent

    to two SCR's back-to-back.

    9. Give the basic structure and circuit symbol of a DIAC

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    10. Give the two transistor analogy of GTO

    11. What is meant by epitaxial layer?

    In the Monolithic IC manufacturing process is consider the layer preparation. The second

    layer of N type material which is grown as a single crystal extension on the substrate. For this

    purpose the wafer put in diffusion furnace. A gas mixture of silicon atoms and pentavalent atoms

    is passed over the wafers. This form a thin layer of n type semiconductor on heated surface of

    the substrate. This thin layer is called epitaxial layer.

    12. How electrical isolation is provided between the different components fabricated

    in an IC?

    Si02 layer is removed from the desired areas to penetrate into the N-type epitaxial layer

    through the openings in Si02 layer and ultimately reach the P-type substrate. The temperature and

    time period of diffusion are required to be carefully controlled. The process results in formation

    of N-type regions, called the isolation islands. The name is given as they are separated by back-

    to-back P-N junctions. Their purpose is to permit electrical isolation between various

    components of IC. Each electrical element is later on formed in a separate isolation island. The

    bottom of the N-type isolation island ultimately forms the collector of an N-P-N transistor.

    13. What is the use of photolithography in IC manufacturing?

    Photolithographic process is used to remove the Sio2 layer from selective area in which

    impurities required the diffusion process.

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    14. Why buried layer is needed in collector region?

    The presence of a buried layer may cause the value of the collector breakdown voltages,

    BVCES andBVCBO, to be considerably less than existing theory predicts. A method for forming a

    buried layer below the collector region of a transistor of an integrated circuit uses a second

    doping agent (Phosphorus) in addition to a main doping agent (antimony). The use of the second

    doping agent solves the problem of undesired intermediate or phantom layers caused by the

    external diffusion (out-diffusion) of the doping agent in a P-type doped isolation layer below the

    buried layer. The use of the second doping agent also solves the problem of providing a collector

    region for transistors of the integrated circuit with a concentration of impurities which is

    typically 10 times higher than that of the collector region of a power transistor integrated

    monolithically on the same chip. The use of the second doping agent finally makes it possible to

    achieve collector regions for the transistors of the integrated circuit with a concentration of

    impurities which differs from transistor to transistor in accordance with the circuit functions to

    be carried out.

    14.What is the advantage of CMOS over NMOS?The most important advantage of CMOS is the very low static power consumption in

    compare with NMOS technology. Two important characteristics of CMOS devices are high

    noise immunity and low static power consumption. On the other hand, CMOS technology is

    more complex to fabricate then NMOS technology, so it is more expensive. However, almost

    every todays digital circuits are CMOS. You want to use NMOS only when you want to

    fabricate fast and low-cost a simple circuit.

    16. What are the advantages of thick film hybrid circuits?

    Advantage:

    1. Relatively simple processing assembly techniques.

    2. Low development cost and high reliable

    3. Higher frequency performance

    4. Reduced size leading to reduced weight and high density

    5. High thermal conductivity of substrates.