Electroneumatic 100 148
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Transcript of Electroneumatic 100 148
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8/14/2019 Electroneumatic 100 148
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TP201 Festo Didactic
C-36
Solution 9
By pressing the pushbutton switch S1 the electric circuit for the solenoidcoil 1Y1is closed and the 5/2-way double solenoid valve is reversed. Thepiston rod of the single-acting (double-acting) cylinder advances to itsforward end position. When the pushbutton switch S1 is released theelectric circuit for the solenoid coil 1Y1 is opened.
By pressing the pushbutton switch S2 the electric circuit for the solenoidcoil 1Y2 is closed and the 5/2-way double solenoid valve is switchedback to its initial position. The piston rod of the single-acting (double-acting) cylinder returns to its retracted end position. After releasingpushbutton switch S2 the electric circuit for the solenoid coil 1Y2 is
opened.
1 1
4 2
3 35 5
1Y1 1Y2
4 2
1Y1 1Y2
1 2
3
0Z2
1 2
3
0Z2
1A 1A
0Z10Z1
Solution description
Fig. 9/4:Circuit design, pneumatic
p = 400 ... 600 kPa (4 ... 6 bar) p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 9
Quantity Description
1 Single-acting cylinder
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 5/2-way double solenoid valve
1 2
S1 S2
1Y1 1Y2
14
13
14
13
24 V-4,5 A
Quantity Description
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Components list
Fig. 9/5:Circuit design, electrical
Components list
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Solution 9
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Solution 10
Hopper control
1Y1 1Y21Y1 1Y2
1 32 4
S1 K1S2 K2
K1 1Y1K2 1Y2
43
Fig. 10/2:Circuit diagram, pneumatic
Fig. 10/3:Circuit diagram, electrical
Representation without manifold
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Solution 10
By pressing the pushbutton switch S1 the electric circuit for the relay K1is closed and the contact K1 is made. The electric circuit for the solenoidcoil 1Y1 is closed and the 5/2-way double solenoid valve is reversed.The piston rod of the single-acting (double-acting) cylinder advances tothe forward end position. After releasing pushbutton switch S1 theelectric circuit for the relay K1 is opened and the contact K1 is broughtinto the normal position thereby opening the electric circuit for the sole-noid coil 1Y1.
By pressing the pushbutton switch S2 the electric circuit for the relay K2is closed and the contact K2 is made. The electric circuit for the solenoid
coil 1Y2 is closed and the 5/2-way double solenoid valve is switchedback to its initial position. The piston rod of the single-acting (double-acting) cylinder returns to the retracted end position. After releasing thepushbutton switch S2 the electric circuit for the relay K2 is opened andthe contact K2 is brought into the normal position opening the electriccircuit for the solenoid coil 1Y2
1 1
4 2
3 35 5
1Y1 1Y2
4 2
1Y1 1Y2
1 2
3
0Z2
1 2
3
0Z2
1A 1A
0Z10Z1
Solution description
Fig. 10/4:Circuit design, pneumatic
p = 400 ... 600 kPa (4 ... 6 bar)p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 10
Quantity Description
1 Single-acting cylinder
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 5/2-way double solenoid valve
1 32 4
S1 K1S2 K2
K1 1Y1K2 1Y2
14
A1
A2
14
13 13
14
A1
A2
14
13 13
24 V-5 A4,
3 4
Quantity Description
1 Relay, 3-off
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Components list
Fig. 10/5:Circuit design, electrical
Components list
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Solution 10
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Solution 11
By pressing the pushbutton switch S1 the electric circuit for the solenoidcoil 1Y1 is closed and the 5/2-way double solenoid valve is reversed.The piston rod of the double-acting cylinder advances to the forward endposition. When the pushbutton switch S1 is released the electric circuitfor the solenoid coil 1Y1 is opened.
The piston rod of the double-acting cylinder advances to the forward endposition and actuates limit switch 1S. The electric circuit for the solenoidcoil 1Y2 is closed and the 5/2-way double solenoid valve is switchedback to its initial position. The piston rod of the double-acting cylinderreturns to its rear end position. When the limit switch 1S is released the
electric circuit for the solenoid coil 1Y2 is opened.
1S
4 2
15 3
1Y1 1Y2
1 2
3
0Z2
1A
0Z1
Solution description
Fig. 11/4:Circuit design, pneumatic
p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 11
Quantity Description
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 5/2-way double solenoid valve
1 2
S1
1Y1 1Y2
14
13
42
1
24 V-
5 A4,
1S
Quantity Description
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Limit switch, electrical, actuated from the left
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Components list
Fig. 11/5:
Circuit design, electrical
Components list
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Solution 11
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Solution 12
Multi-track gravity feed magazine
1S
1Y1 1Y2
1 32 4
S1 K11S K2
K1 1Y1K2 1Y2
43
Fig. 12/2:Circuit diagram, pneumatic
Fig. 12/3:Circuit diagram, electrical
Representation without manifold
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Solution 12
By pressing the pushbutton switch S1 the electric circuit for the relay K1is closed and the contact K1 is made. The electric circuit for the solenoidcoil 1Y1 is closed and the 5/2-way double solenoid valve is reversed.The piston rod of the double-acting cylinder advances to the forward endposition. When the pushbutton switch S1 is released the electric circuitfor the relay K1 is opened and the contact K1 is brought to the normalposition. The electric circuit for the solenoid coil 1Y1 is opened.
The piston rod of the double-acting cylinder advances to the forward endposition and actuates limit switch 1S. The electric circuit for the relay K2is closed and the 5/2-way double solenoid valve is switched back to its
initial position. The piston rod of the double-acting cylinder returns to itsrear end position. The electric circuit for the relay K2 is opened and thecontact K2 is brought into the normal position. The electric circuit for thesolenoid coil 1Y2 is opened.
1S
4 2
15 3
1Y1 1Y2
1 2
3
0Z2
1A
0Z1
Solution description
Fig. 12/4:Circuit design, pneumatic
p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 12
Quantity Description
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 5/2-way double solenoid valve
1 32 4
S1 K11S K2
K1 1Y1K2 1Y2
14
A1
A2
14
13 13
42
A1
A2
14
1 13
24 V-
5 A4,
43
Quantity Description
1 Relay, 3-off
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Limit switch, electrical, actuated from the left
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Components list
Fig. 12/5:
Circuit design, electrical
Components list
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Solution 12
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Solution 13
Conveyor belt control
1S21S1
1Y1 1Y2
1 2
1Y1 1Y2
S1 1S2
1S1
Fig. 13/2:Circuit diagram, pneumatic
Fig. 13/3:Circuit diagram, electrical
Representation without manifold
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Solution 13
When latching pushbutton switch S1 is pressed the electric circuit for thesolenoid coil 1Y1 is closed and the 5/2-way double solenoid valve isreversed. The piston rod of the double-acting cylinder advances to theforward end position and switches limit switch 1S2. After leaving the rearend position, the electric circuit for the solenoid coil 1Y1 is opened vialimit switch 1S1.
The electric circuit for the solenoid coil 1Y2 is closed via limit switch 1S2and the 5/2-way double solenoid valve is switched back to its initialposition. The piston rod of the double-acting cylinder returns to its re-tracted end position and switches limit switch 1S1. After leaving the
forward end position, the electric circuit for the solenoid coil 1Y1 isclosed by means of limit switch 1S1 via the actuated latching pushbuttonswitch S1. The piston rod of the double-acting cylinder advances againto the forward end position.
1S21S1
4 2
15 3
1Y1 1Y2
1 2
3
0Z2
1A
0Z1
Solution description
Fig. 13/4:Circuit design, pneumatic
p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 13
Quantity Description
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 5/2-way double solenoid valve
1 2
1Y1 1Y2
141
13
42
1
24 V-
4,5 A
S1
1S1
1S2
42
Quantity Description
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Limit switch, electrical, actuated from the left
1 Limit switch, electrical, actuated from the right
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Components list
Fig. 13/5:
Circuit design, electrical
Components list
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Solution 13
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Solution 14
Rotary indexing table
1S21S1
1Y1 1Y2
1 2
K2
S1
1S1
1S2
3 4
K1 K2
1Y1 1Y2
3 4
1S1
K1
Fig. 14/2:Circuit diagram, pneumatic
Fig. 14/3:Circuit diagram, electrical
Representation without manifold
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Solution 14
By pressing the latching pushbutton switch S1 the electric circuit for therelay K1 is closed and the contact K1 is made. The electric circuit for thesolenoid coil 1Y1 is closed and the 5/2-way double solenoid valve isreversed. The piston rod of the double-acting cylinder advances to theforward end position and switches limit switch 1S2. After leaving theretracted end position, the electric circuit for the relay K1 is opened vialimit switch 1S1 and the contact K1 is brought into the normal position.
The electric circuit for the relay K2 is closed by means of limit switch 1S2and the contact K2 is made. The electric circuit for the solenoid coil 1Y2is closed and the 5/2-way double solenoid valve is switched back to its
initial position. The piston rod of the double-acting cylinder returns to theretracted end position and switches limit switch 1S1. After leaving theforward end position the electric circuit for the solenoid coil 1Y2 isopened by means of limit switch 1S2.
The electric circuit for the relay K1 is again closed via the limit switch1S1 by means of the latchedpushbutton switch S1 and the contact K1is made. The electric circuit for the solenoid coil 1Y1 is closed and the5/2-way double solenoid valve is reversed. The piston rod of the double-acting cylinder advances again to the forward end position.
Solution description
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Solution 14
1S21S1
4 2
15 3
1Y1 1Y2
1 2
3
0Z2
1A
0Z1
Quantity Description
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 5/2-way double solenoid valve
Fig. 14/4:Circuit design, pneumatic
Components list
p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 14
1 2
K1 K2
141
13
42
1
24 V-5 A4,
S1
1S1
1S2
4A1 A1
A2 A2
2
3 4
K1 K2
1Y1 1Y2
14 14
13 13
43
Quantity Description
1 Relay, 3-off
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Limit switch, electrical, actuated from the left
1 Limit switch, electrical, actuated from the right
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Fig. 14/5:Circuit design, electrical
Components list
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Solution 15
Sliding table
1Y1Y
S1
S2
K1 K1
K1 1Y
1 32
23
Fig. 15/2:Circuit diagram, pneumatic
Fig. 15/3:Circuit diagram, electrical
Representation without manifold
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Solution 15
By pressing the pushbutton switch S1 (ON) the electric circuit for therelay K1 is closed via the unactuatedpushbutton switch S2 (OFF) andthe bank of contacts is made. The latching circuit with contact K1(13, 14) keeps the electric circuit closed for the relay K1 after the releaseof the pushbutton switch S1 (ON). The electric circuit for the solenoidcoil 1Y is closed with contact K1 (23, 24) and the 3/2- (5/2-) way sole-noid valve is reversed. The piston rod of the single-acting (double-acting) cylinder advances to the forward end position.
By pressing the pushbutton switch S2 (OFF) the electric circuit for therelay K1 is opened and the bank of contacts is brought to the normal
position. The electric circuit for the solenoid coil 1Y is opened and the3/2- (5/2-) way solenoid valve is reversed. The piston rod of the single-acting (double-acting) cylinder returns to the retracted end position.
1
2
3
1Y
4 2
15 3
1Y
1 2
3
1 2
3
1A1A
0Z2
0Z1
0Z2
0Z1
Solution description
Fig. 15/4:Circuit design, pneumatic
p = 400 ... 600 kPa (4 ... 6 bar)p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 15
Quantity Description
1 Single-acting cylinder
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 3/2-way single solenoid valve, normally closed
1 5/2-way single solenoid valve
24
23
24 V-5 A4,
14 14
13
32A1
A2
13
31
S1
S2
K1 K1
K1 1Y
1 32
23
Quantity Description
1 Relay, 3-off
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Components list
Fig. 15/5:Circuit design, electrical
Components list
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Solution 15
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Solution 16
Clamping device
1Y1Y
S1
S2
K1 K1
K1 1Y
1 32
23
Fig. 16/2:Circuit diagram, pneumatic
Fig. 16/3:Circuit diagram, electrical
Representation without manifold
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Solution 16
By pressing the pushbutton switch S1 (ON) the electric circuit for therelay K1 is closed and the bank of contacts is made. The latching circuitwith contact K1 (13, 14) via the unactuatedpushbutton switch S2 (OFF)keeps the electric circuit closed for the relay K1 after the release of thepushbutton switch S1 (ON). The electric circuit for the solenoid coil 1Y isclosed via the contact K1 (23, 24) and the 3/2- (5/2-) way solenoid valveis reversed. The piston rod of the single-acting (double-acting) cylinderadvances to the forward end position.
By pressing the pushbutton switch S2 (OFF) the electric circuit for therelay K1 is opened and the bank of contacts is brought into the normal
position. The electric circuit for the solenoid coil 1Y is opened and the3/2- (5/2-) way solenoid valve is switched back to its initial position. Thepiston rod of the single-acting (double-acting) cylinder returns to theretracted end position.
1
2
3
1Y
4 2
15 3
1Y
1 2
3
1 2
3
1A1A
0Z2
0Z1
0Z2
0Z1
Solution description
Fig. 16/4:Circuit design, pneumatic
p = 400 ... 600 kPa (4 ... 6 bar)p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 16
Quantity Description
1 Single-acting cylinder
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 3/2-way single solenoid valve, normally closed
1 5/2-way single solenoid valve
24
23
24 V-5 A4,
14 14
13
A1
A2
13
31
32
S1
S2
K1 K1
K1 1Y
1 32
23
Quantity Description
1 Relay, 3-off
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Components list
Fig. 16/5:Circuit design, electrical
Components list
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Solution 16
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Solution 17
Diverting device
1B1 1B2
1Y11Y2
1 2
3
42 7 8
S1
S2
K1
K1 K2 K3
1 3 4 52
1B2
6 7 8
K2 K3
1Y1 1Y2
K1
1B1
Fig. 17/2:Circuit diagram, pneumatic
Fig. 17/3:Circuit diagram, electrical
Representation without manifold
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Solution 17
By pressing the pushbutton switch S1 (ON) the electric circuit is closedfor relay K1 via the unactuated pushbutton switch S2 (OFF) and thebank of contacts is made. After releasing pushbutton switch S1 (ON) theelectric circuit for the relay K1 is kept closed via the latching circuit withcontact K1 (13, 14). The electric circuit for the relay K2 is closed withcontact K1 (23, 24) and the contact K2 is actuated. The electric circuitfor the solenoid coil 1Y1 is closed and the 5/2-way double solenoid valveis reversed. The piston rod of the double-acting cylinder advances to theforward end position actuating sensor 1B2. After leaving the rear endposition, the electric circuit for the relay K2 is opened via sensor 1B1and the contact K2 is brought to the normal position.
The electric circuit for the relay K3 is closed via sensor 1B2 and thecontact K3 is made. The electric circuit for the solenoid coil 1Y2 isclosed and the 5/2-way double solenoid valve is switched back to itsinitial position. The piston rod returns to the rear end position and actu-ates the sensor 1B1. After leaving the forward end position the electriccircuit for relay K3 is opened via sensor 1B2 and the contact K3 isbrought to the normal position.
1The electric circuit for the relay K2 is closed via sensor 1B1 and thecontact K2 is made. The electric circuit for the solenoid coil 1Y1 isclosed and the 5/2-way double solenoid valve is reversed. The pistonrod of the double-acting cylinder advances again to the forward endposition.
By pressing the pushbutton switch S2 (OFF), the electric circuit for therelay K1 is opened and the bank of contacts is brought to the normalposition.
Solution description
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Solution 17
4 2
1
1B1 1B2
5 3
1Y1 1Y2
1 2
3
0Z2
1A
0Z1
Quantity Description
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 5/2-way double solenoid valve
Fig. 17/4:Circuit design, pneumatic
Components list
p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 17
42 7 8
BN BN
24 V-5 A4,
32A1 A1 A1
A2 A2 A2
31
S1
S2
K1
K1 K2 K3
1 3 4 52
BK BK1B2
14 14
13 13
BU BU
6 7 8
K2
K1
K3
1Y1 1Y2
14
24
14
13
23
13
1B1
Quantity Description
1 Relay, 3-off1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
2 Proximity switch with cylinder mouting
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Fig. 17/5:Circuit design, electrical
Components list
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C-71
Solution 18
Stamping device
pp1
p21B 1Y1 1Y2
4 51
S1
S2
K1 K2
1 2 3
13
4 5
K1 K2
1Y1 1Y2
1B
K2
Fig. 18/2:Circuit diagram, pneumatic
Fig. 18/3:Circuit diagram, electrical
Representation without manifold
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Solution 18
By pressing the pushbutton switches S1 andS2 the electric circuit forthe relay K1 is closed and the bank of contacts is made. The electriccircuit for the solenoid coil 1Y1 is closed with contact K1 (13, 14) and the5/2-way double solenoid valve is reversed. The piston rod of the double-acting cylinder advances to the forward end position.
When the pre-set switching pressure has been achieved in the supplyline of the double-acting cylinder, the pressure switch 1B is actuated.The electric circuit for the relay K2 is closed and the bank of contacts isactuated. The electric circuit for the relay K1 is opened with contact K2(41, 42) and the bank of contacts is brought to the normal position. The
electric circuit for the solenoid coil 1Y1 is opened. At the same time theelectric circuit for the solenoid coil1 Y2 is closed with contact K2 (13, 14)and the 5/2-way double solenoid valve is switched back to its initialposition. The piston rod of the double-acting cylinder returns to theretracted end position.
When the switching pressure has dropped the pressure switch 1B isreturned to its initial position by means of a reset spring. The electriccircuit for the relay K2 is opened and the bank of contacts is brought tothe normal position. The electric circuit for the solenoid coil 1Y2 isopened.
The solution shown above is an AND-function, not a two-hand safetycontrol..
Solution description
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Solution 18
1
4 2
5 3
1Y1 1Y2pp1
p21B
1 2
3
0Z2
1A
0Z1
Quantity Description
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold1 Pneumatic-electrical converter
1 5/2-way double solenoid valve
Fig. 18/4:Circuit design, pneumatic
Components list
p > 400 kPa (4 bar)
p = 400 ... 600 kPa (4 ... 6 bar)
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C-74
Solution 18
4 51
RD
24 V-5 A4,
14
A1 A1
A2 A2
13
S1
S2
K1 K2
1 2 3
BK14
13
BU
4 5
K1 K2
1Y1 1Y2
14 14
13 131B
K2
42
41
p1
p2
Quantity Description
1 Relay, 3-off
1 Signal input plate, electrical
1 Indicator and distributor plate, electrical
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Fig. 18/5:Circuit design, electrical
Components list
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Solution 19
Heat sealing device
1Y1 1Y2
1B21B1
pp1
p21B3
5
K2
1B3
79
28
S1 K1
K1 K3 H1
1 3 4 52
1B2
6 7 8 9
1Y1 1Y2
K2 K3 K1 K3
1B1
Fig. 19/2:Circuit diagram, pneumatic
Fig. 19/3:Circuit diagram, electrical
Representation without manifold
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Solution 19
1
4 2
5 3
1Y1 1Y2
1B1 1B2
pp1
p21B3
1 2
3
0Z2
1A
0Z1
Quantity Description
1 Double-acting cylinder
1 Service unit with on-off valve
1 Manifold
1 Pneumatic-electrical converter
1 5/2-way double solenoid valve
Fig. 19/4:Circuit design, pneumatic
Components list
p > 400 kPa (4 bar)
p = 400 ... 600 kPa (4 ... 6 bar)
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Solution 20
S1
10
K3
938
S2
K1 K2
1B2
2Y11Y 2Y2
K1K1 K2 K31B1
H1
1 2 3 94 105 6 7 8
2S1 2S2
When carrying out the practical circuit construction, the limit switch S1 isreplaced by the latching pushbutton switch on the electrical signal inputplate.
Empty magazineWhen the latching pushbutton switch S1 is unactuated the electriccircuit for the audible indicator H1 is closed via contact S1 (31, 32). Theelectric current supply for the main circuit is switched off via contact S1(13, 14).
Full magazineWhen the latching pushbutton switch S1 is actuatedthe electric circuit
for the audible indicator H1 is opened via contact S1 (31, 32). Theelectric current supply for the main circuit is switched on via contact S1(13, 14).
Step 1By pressing the pushbutton switch S2 the electric circuit for the relay K1is closed and the bank of contacts made. When the pushbutton switchS2 is released, the electric circuit for the relay K1 remains closed via thelatching circuit with K1 (13, 14). The electric circuit for the solenoid coil1Y1 is closed with contact K1 (23, 24) and the 5/2-way solenoid valve isreversed. The piston rod of cylinder 1A advances to the forward endposition and actuates sensor 1B2.
Fig. 20/4:Circuit diagram, electrical
Solution description
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8/14/2019 Electroneumatic 100 148
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8/14/2019 Electroneumatic 100 148
48/49
TP201 Festo Didactic
C-83
Solution 20
S1
2S2
10
BN
A2
K3
BK
BK
BU
938
BN
24 V-4,5 A
A14 42 2
A1 A1
A2 A2
S2
K1 K2
1B2
14 14
13
1313
1432
13
BU
2Y11Y 2Y2
K1
24
23
K1 K2
14
13
K3
14
13
1B1
2S1
1
H1
1 2 3 94 105 6 7 8
Quantity Description
1 Relay, 3-off
1 Signal input plate, electrical
2 Indicator and distributor plate, electrical
2 Proximity switch with cylinder mouting
1 Limit switch, electrical, actuated from the left
1 Limit switch, electrical, actuated from the right
1 Cabel set, universal
1 Electrical power supply unit, 24 V
Fig. 20/6:Circuit design, electrical
Components list
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C-84
Solution 20