Electric Currents What is an electric current? What makes current flow?
Electric circuits, Current, and resistance (Chapter 22 and 23) › ... › Resistor.pdf · An...
Transcript of Electric circuits, Current, and resistance (Chapter 22 and 23) › ... › Resistor.pdf · An...
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Dr. Mangala Singh, 1P22/92 Brock University
Electric circuits, Current, and resistance(Chapter 22 and 23)
Acknowledgements: Several Images and excerpts are taken from College Physics: A strategic approach, Pearson Education Inc
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Dr. Mangala Singh, 1P22/92 Brock University
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Dr. Mangala Singh, 1P22/92 Brock University
Current
QI
t
∆=
∆
If electric charge (e.g. electron) moves, we will say an electric current, I, is set to exist.
An electric current, I, is the rate at which net charge (∆Q)flows through a surface area A
Current’s units = C/S and often written as A (Ampere)
Although current carriers (i.e., charges) could be “+” or “-”, the direction of current will be in the direction of a “+”charge flow (i.e., clockwise)
AI +
Electrons are actual current carriers in metals. They flow opposite to the direction of electric field or current
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Dr. Mangala Singh, 1P22/92 Brock University
Current and Current density
n = number of mobile charges per unit volume
q = charge on each current carriers
∆x = distance they move in a time interval ∆t
vd= speed (called drift velocity )
J = current density
Drift velocity vd ?
AI +
( )
( )
d
d
d
d
x v t
Q nA x q
nAv t q
QI nqv A
t
IJ nqv
A
∆ = ∆
∆ = ∆
= ∆
∆= =
∆
= =
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Dr. Mangala Singh, 1P22/92 Brock University
Multiple choice questions1. The charge carriers in metals are
A. electrons.
B. positrons.
C. protons.
D. a mix of protons and electrons.
2. A battery is connected to a resistor. Increasing the resistance of the resistor will
A. increase the current in the circuit.
B. decrease the current in the circuit.
C. not affect the current in the circuit.
3. A battery is connected to a resistor. As charge flows, the chemical energy of the battery is dissipated as
A. current.
B. voltage.
C. charge.
D. thermal energy.
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Dr. Mangala Singh, 1P22/92 Brock University
Problem: The discharge of the electric eel can transfer a charge of 2.0 mC in a time of 2.0 ms. What current, in A, does this correspond to?
Solution: Step 1: To solve a problem, note each and every quantities mentioned in your problem. In this problemQ = 2.0 x10-3 CTime = 2.0 x10-3 sCurrent = ?Step 2: Identify relationship between these quantitiesStep 3: Rearrange your equation to find out the unknown quantityAdd each and every numbers and compute.Warning: Calculator does what you ask for….If you insert wrong numbers or in a wrong manner, you will get a wrong answer!!! You must learn how to use your calculator properly
I = Q/t = 2.0x10-3C/2.0x10-3s = 1A
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Dr. Mangala Singh, 1P22/92 Brock University
BatteriesThe potential difference between the terminals of a battery, often called the terminal voltage is often called battery’s electromotive force (emf)
chem
bat
WV ξ
q∆ = =
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Dr. Mangala Singh, 1P22/92 Brock University
Simple CircuitsThe current is determined by the potential difference and the resistance of the wire:
wireVI
R
∆=
battery
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Dr. Mangala Singh, 1P22/92 Brock University
Ohm’s law and resistanceA current density J & the electric field E are established in a conductor when a potential difference (Vb-Va) is maintained across the conductor
J = σE ------- Ohm’s Lawσ is called electrical conductivity of the materials
Ohmic materials: In these materials the ratio of J and E is a constant “σ”. In other words, it is J varies linearly with E
Value of conductivity of the materials are different for different materials
LR
A
ρ=
b aV V V
VE V El
l
VJ E
l
lV I V RI
A
lR
A
σ σ
σ
σ
= −
= ⇒ =
= =
= ⇒ =
=
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Dr. Mangala Singh, 1P22/92 Brock University
Resistance & ResistivityThe resistance of a wire depends on its dimensions (length L & Cross sectional area A) and the resistivity of its material.
Every material has a characteristic resistivity that only depends on the properties and composition of the material.
Value of resistivity of the materials are different for different materials
resistivity of the metal increase as temperature increase
resistivity of semiconductors and insulators decreases as temperature increases
LR
A
ρ=
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Dr. Mangala Singh, 1P22/92 Brock University
Multiple choiceA battery is connected to a wire, and makes a current in the wire. Which of the following changes would increase the current? (1) Increasing the length of the wire; (2) keeping the wire the same length, but making it thicker; (3) using a battery with a higher-rated voltage; (4) making the wire into a coil, but keeping its dimensions the same; (5) increasing the temperature of the wire.
A. All of the aboveB. 1 and 5C. 1, 4, and 5D. 2 and 3E. None of the above
Problem 1:
A wire has resistance of 21 ohm. It is melted down and from the same volume of metal a new wire is made, that is three times longer than the original one. What is the resistance of new wire
Problem 2: The filament of a 100-W bulb carries a current of 0.83 A at the normal operating voltage of 120 V.
A. What is the resistance of the filament?B. If the filament is made of tungsten wire of diameter 0.035 mm, how long is the filament?
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Dr. Mangala Singh, 1P22/92 Brock University
Power in Circuits
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Dr. Mangala Singh, 1P22/92 Brock University
Energy and Power in Resistors
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Dr. Mangala Singh, 1P22/92 Brock University
A resistor is connected to a 3.0 V battery; the power dissipated in the resistor is 1.0 W. The battery is traded for a 6.0 V battery. The power dissipated by the resistor is now
A. 1.0 WB. 2.0 WC. 3.0 WD. 4.0 W
Multiple choice
Problem 1: An electric blanket has a wire that runs through the interior. A current causes energy to be dissipated in the wire, warming the blanket. A new, low-voltage electric blanket is rated to be used at 18 V. It dissipates a power of 82 W. What is the resistance of the wire that runs through the blanket?
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Dr. Mangala Singh, 1P22/92 Brock University
An electric blanket has a wire that runs through the interior. A current causes energy to be dissipated in the wire, warming the blanket. A new, low-voltage electric blanket is rated to be used at 18 V. It dissipates a power of 82 W. What is the resistance of the wire that runs through the blanket?
Example Problem
Summary
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Dr. Mangala Singh, 1P22/92 Brock University
Conservation of Current
in outI I∑ = ∑
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Dr. Mangala Singh, 1P22/92 Brock University
1. Rank the bulbs in the following circuit according to their brightness, from brightest to dimmest.
A. A > B = C > D
B. A = B = C = D
C. A = D > B = C
D. B = C > A > D
Multiple choice questions
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Dr. Mangala Singh, 1P22/92 Brock University
Drawing Circuit Diagrams
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Dr. Mangala Singh, 1P22/92 Brock University
Kirchhoff’s Law
in outI I∑ = ∑
0loop i
V V∆ = ∑ =
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Dr. Mangala Singh, 1P22/92 Brock University
Using Kirchhoff’s Laws
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Dr. Mangala Singh, 1P22/92 Brock University
1. The diagram below shows a segment of a circuit. What is the current in the 200Ω resistor?
A. 0.5 AB. 1.0 AC. 1.5 AD. 2.0 AE. There is not enough information to decide.
Multiple choice questions
2. The diagram below shows a circuit with two batteries and three resistors. What is the potential difference across the 200Ω resistor?
A. 2.0 VB. 3.0 VC. 4.5 VD. 7.5 VE. There is not enough information to decide.
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Dr. Mangala Singh, 1P22/92 Brock University
Series Resistors
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Dr. Mangala Singh, 1P22/92 Brock University
Parallel Resistors
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Dr. Mangala Singh, 1P22/92 Brock University
1. There is a current of 1.0 A in the circuit below. What is theresistance of the unknown circuit element?
2. What is the current out of the battery?
Problems
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Dr. Mangala Singh, 1P22/92 Brock University
Analyzing Complex Circuits
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Dr. Mangala Singh, 1P22/92 Brock University
Problems
1. In the circuit shown below:
A. Rank in order, from most to least bright, the brightness of bulbs A–D. Explain.
B. Describe what, if anything, happens to the brightness of bulbs A, B, and D if bulb C is removed from its socket. Explain.
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Dr. Mangala Singh, 1P22/92 Brock University
In the circuit shown below:A. How much power is dissipated by the 12 Ω resistor?
B. What is the value of the potential at points a, b, c, and d?
Problems
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Dr. Mangala Singh, 1P22/92 Brock University
Battery and its internal resistance (r)
As the charges passes through from – to + terminal of the battery its potential energy increases
Due to internal resistance of the battery, its potential decreases by Ir, wherein I is the current.
Terminal voltage of the battery = V+-V- = ξ-Ir
Note: Terminal voltage may exceed the emfby an amount Ir – when the current is opposite the emf as in the case of charging a battery with another source of emf.
IR r
ξ=
+
22
2( )P I R R
R r
ξ= =
+
The current in the circuit
-Depends both external resistance to the battery
-And its internal resistance
Power dissipated, P, in the load resistance R
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Dr. Mangala Singh, 1P22/92 Brock University
Problems:
1. Show that maximum power lost in the load resistor R occurs when R =r, i.e., when the value of load resistance matches the internal resistance of the battery.