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The cost of fuel in running of an engine is proportional to the square of the speed and is Rs 48 per hour for?The cost of fuel in running of an engine is proportional to the square of the speed and is Rs 48 per hour for speed of 16 kilometers per hour. Other expenses amount to Rs 300 per...show moreBest Answer

Encyclopediaanswered2 years ago Based on the above statement, the formula for cost isC = k*v2 + 300.So, for 48 rs per hour cost at 16 per hour speed,48 = k*16*16 + 30048 = k*256 + 300k = -252/256

now for the most economical speed, differentiate the function. This gives2kv + 300 = 0.v = -150*256/-252v = 152.38 km/hr. 00 CommentOther Answers (2)Relevance Ganswered1 year agofuel cost per hour = k speed^248 = k 16^2k = 48/256 = 3/16

distance = speed * timefor a given distance and speed, time = distance/speedfuel cost in that time = fuel cost per hour * time= fuel cost per hour * distance/speed= k * speed * distanceadditional cost = 300 per hour = 300 * distance/speedtotal cost = (3/16)*speed*distance + 300*distance/speedtotal cost per km = (3/16)*speed + 300/speedd/dspeed = (3/16) - 300/speed^2 = 0 at an extremum of cost.speed = 40 kmph 00 Comment Seedpotatoanswered2 years agoare youleaving part of this out? I don't seem to follow, do we need one more speed and cost? 00 CommentThe cost of fuel in running of an engine is proportional to the square of the speed and is Rs 48 per hour for?

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