economy Chapter6 2011_by louy Al hami
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Transcript of economy Chapter6 2011_by louy Al hami
The objective of chapter 6 is
to evaluate correctly capital
investment alternatives when
the time value of money is a
key influence.
Making decisions means
comparing alternatives.
In this chapter we examine feasible design
alternatives.
The decisions considered are those selecting
from among a set of mutually exclusive
alternatives (when selecting one excludes the
choice of any of the others).
Principle 2 from Chapter 1. The alternative that requires the minimum investment of
capital and produces satisfactory functional results will be
chosen(the base alternative)
unless the incremental capital associated with an alternative
having a larger investment can be justified with respect to its
incremental benefits.
The alternative requiring the least investment is the base alternative.
For alternatives that have a larger
investment than the base…
If the extra benefits obtained by investing additional
capital are better than those that could be obtained from
investment of the same capital elsewhere in the
company at the MARR, the investment should be made.
(Please note that there are some cautions when
considering more than two alternatives, which will be
examined later.)
Types of Alternatives Investment alternatives (capital & Revenue)
Cost alternatives (Negative & salvage value) same expected revenue
Ensuring Comparable Basis
Rule 1. When revenues and other economic benefits are present(Investment alternatives ), select alternative that has greatest positive equivalent worth at i %= MARR% and satisfies project requirements.
Rule 2. When revenues and economic benefits are not present(Cost alternatives ), select alternative that minimizes cost.
In Other Words:
Select the alternative that gives you
the most money!
For investment alternatives the PW of all cash flows must be positive, at the MARR, to be attractive. Select the alternative with the largest PW.
For cost alternatives the PW of all cash flows will be negative. Select the alternative with the largest (smallest in absolute value) PW.
Example: Investment Alternative
Use a MARR of 10% and useful life of 5 years to select
between the investment alternatives below.
Alternative
A B
Capital investment -$100,000 -$125,000
Annual revenues less expenses $34,000 $41,000
Both alternatives are attractive, but Alternative B provides
a greater present worth, so is better economically.
Cost alternative example
Use a MARR of 12% and useful life of 4 years to select
between the cost alternatives below.
Alternative
C D
Capital investment -$80,000 -$60,000
Annual expenses -$25,000 -$30,000
Alternative D costs less than Alternative C, it has a greater
PW, so is better economically.
Determining the study period.
A study period (or planning horizon) is the time period over which mutually exclusive alternatives are compared, and it must be appropriate for the decision situation.
mutually exclusive alternatives can have equal lives (in which case the study period used is these equal lives), or they can have unequal lives, and at least one does not match the study period.
The equal life case is straightforward.
Useful Lives of all Alternatives is Equal to the Study Period
1. Equivalent worth methods
2. Rate of return methods
1.Equivalent Worth Methods
If : PWA (i) < PWB (i)
Then
AWA (i) < AWB (i)
and
FWA (i) < FWB (i)
Select Alternative B
Example: When lives are equal adjustments to cash flows are not
required. The MEAs can be compared by directly comparing
their equivalent worth (PW, FW, or AW) calculated using the
MARR. The decision will be the same regardless of the
equivalent worth method you use. For a MARR of 12%, select
from among the MEAs below.
Alternatives
A B C D
Capital investment -$150,000 -$85,000 -$75,000 -$120,000
Annual revenues $28,000 $16,000 $15,000 $22,000
Annual expenses -$1,000 -$550 -$500 -$700
Market Value
(EOL)
$20,000 $10,000 $6,000 $11,000
Life (years) 10 10 10 10
Selecting the best alternative.
Present worth analysis select Alternative A (but C is close).
Annual worth analysis—the decision is the same.
The return on investment (rate of return) is a popular
measure of investment performance.
Selecting the alternative with the largest rate of return
can lead to incorrect decisions do not compare the
IRR of one alternative to the IRR of another
alternative.
Remember, the base alternative must be attractive
(rate of return greater than the MARR), and the
additional investment in other alternatives must itself
make a satisfactory rate of return on that increment.
The Incremental Investment
Analysis Procedure. Arrange (rank order) the feasible alternatives based on
increasing capital investment.
Establish a base alternative.
Cost alternatives the first alternative is the base.
Investment alternatives the first acceptable alternative
(IRR>MARR) is the base.
Iteratively evaluate differences (incremental cash flows) between alternatives until all have been considered.
a. If incremental cash flow between next alternative and current alternative is acceptable, choose the next.
b. Repeat, and select as the preferred alternative the last one for which the incremental cash flow was acceptable
Example 6-4 A B C D E F
Capital 900 1,500 2,500 4,000 5,000 7,000
Annual R – Annual E
150 276 400 925 1,125 1,425
IRR 10.6% 13% 9.6% 19.1% 18.3% 15.6%
The alternative is arranged based on increasing capital investment.
IRR for alternative (C) 9.6<MARR(10%)
Then C is rejected
A is the base alternative then we will compare A with B
A Δ(B-A) Δ(D-B)
Δ(E-D)
Δ(F-E)
ΔCapital
900
Δ(Annual R – Annual E)
150
IRRΔ 10.6%
Is increment justified
Yes
B is better then A because the additional capital investment gives IRR >MARR(16.4%>10%)
Then we will compare B with D since C is rejected from the beginning
A Δ(B-A) Δ(D-B)
Δ(E-D)
Δ(F-E)
ΔCapital
900 600
Δ(Annual R – Annual E)
150 126
IRRΔ 10.6% 16.4%
Is increment justified
Yes Yes
D is better then B because the additional capital investment gives IRR >MARR(22.6%>10%)
Then we will compare D with E
A Δ(B-A) Δ(D-B)
Δ(E-D)
Δ(F-E)
ΔCapital
900 600 2,500
Δ(Annual R – Annual E)
150 126 649
IRRΔ 10.6% 16.4% 22.6%
Is increment justified
Yes Yes Yes
E is better then D because the additional capital investment gives IRR >MARR(15.1%>10%)
Then we will compare E with F
A Δ(B-A) Δ(D-B)
Δ(E-D)
Δ(F-E)
ΔCapital
900 600 2,500 1,000
Δ(Annual R – Annual E)
150 126 649 200
IRRΔ 10.6% 16.4% 22.6% 15.1%
Is increment justified
Yes Yes Yes Yes
F is NOT better then E because the additional capital investment gives IRR < MARR(8.1%>10%)
Then E is the best alternative
A Δ(B-A) Δ(D-B)
Δ(E-D)
Δ(F-E)
ΔCapital
900 600 2,500 1,000 2,000
Δ(Annual R – Annual E)
150 126 649 200 300
IRRΔ 10.6% 16.4% 22.6% 15.1% 8.1%
Is increment justified
Yes Yes Yes Yes No
Three Errors Common To Incremental Investment Analysis Procedure Applied To IRR
Choosing the feasible Alternative with:
1. the highest overall IRR on total cash flow (choose D)
A B C D E F
Capital 900 1,500 2,500 4,000 5,000 7,000
Annual R – Annual E
150 276 400 925 1,125 1,425
IRR 10.6% 13% 9.6% 19.1% 18.3% 15.6%
Three Errors Common To Incremental Investment Analysis Procedure Applied To IRR
Choosing the feasible Alternative with: 2.the highest IRR on an incremental capital investment(choose
D-B instead of E-D)
A Δ(B-A) Δ(D-B)
Δ(E-D)
Δ(F-E)
ΔCapital
900 600 2,500 1,000 2,000
Δ(Annual R – Annual E)
150 126 649 200 300
IRRΔ 10.6% 16.4% 22.6% 15.1% 8.1%
Is increment justified
Yes Yes Yes Yes No
Three Errors Common To Incremental Investment Analysis Procedure Applied To IRR
3.the largest capital investment that has an IRR greater than or equal to the MARR (choose F)
A B C D E F
Capital 900 1,500 2,500 4,000 5,000 7,000
Annual R – Annual E
150 276 400 925 1,125 1,425
IRR 10.6% 13% 9.6% 19.1% 18.3% 15.6%
Incremental analysis must be used with rate of return methods to ensure the best alternative is selected
Rate of Return with unequal lifes A B
Capital investment $3,500 $5,00
Annual cash flow 1,255 1,480
Useful life 4 6
When the repeatability applies 1.we need to find the AW of each alternative over it’s own useful life 2.Find the interest rate that make them equal AW A(i*%) = AW B(i*%) -3,500(A/i*%,4) +1,255 = -5,000(A/i*%,6) +1,480 Trail and error i= 26% >MARR (10%) the increment is justified and B is preferred
Useful life > Study period
The imputed Market Value Technique
i. e find the estimated market value at any year that is before the end of the useful life
MVT = PW at EOY T of remaining CR amounts + PW at EOY T of original market value at end of useful life
Example
If the capital investment is 47,600 useful life = 9 years market value at the end of 9 years = $5,000 find the market value et the end of 5 years if MARR = 20%
Step 1 : CR = 47,000 (A/P,20%,9) – 5,000(A/F,20%,9)
Step 2 : PW at EOY 5 of the remaining CR
PW(20%) CR = CR (P/A, 20%,4) = $29,949
Step 3 : PW at EOY 5 of MV 9
PW(20%) MV = 5,000 (P/F, 20%,4) = $2,412
The estimated market value at EOY 5 =
MV 5 = PW(20%) CR + PW(20%) MV = 29,949 + 2,412 = 32,361