E205 Salazar (1)

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Mapua Institute of Technology Department of Physics Name: Salazar, Abigail B. Program/Year: CE-2 Course Code/ Section: PHY11L/A1 Student No.: 2012101116 Group no.: 03 Seat No.: 15 Date of Performance: November 17, 2014 Date of Submission: Novermber 24, 2014 Ramil R. Jimenez Experiment 205 HOOKE’S LAW GRADE

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Transcript of E205 Salazar (1)

Mapua Institute of TechnologyDepartment of Physics

Experiment 205HOOKES LAW

Name: Salazar, Abigail B.

GRADEProgram/Year: CE-2Course Code/ Section: PHY11L/A1Student No.: 2012101116Group no.: 03 Seat No.: 15Date of Performance: November 17, 2014Date of Submission: Novermber 24, 2014

Ramil R. JimenezInstructor

DATA and OBSERVATIONSTABLE 1A. Determining the Force Constant of the Spring

TRIAL Mass (kg)Force (N)Displace-ment(m)Force Constant(N/m)

10.015kg0.147 N0.027m5.444 N/m

20.025kg0.245N0.046m5.326 N/m

30.035kg0.343N0.064m5.359 N/m

40.045kg0.441N0.084m5.250 N/m

average5.345

slope of the line5.250 N/m

% difference1.793 %

TABLE 1B. Determining the Force Constant of the Spring

TRIAL Mass (kg)Force (N)Displace-ment(m)Force Constant(N/m)

10.015kg0.147 N0.014m10.500 N/m

20.025kg0.245N0.023m10.652 N/m

30.035kg0.343N0.030m11.430 N/m

40.045kg0.441N0.042m10.500 N/m

average10.771

slope of the line10.500 N/m

% difference2.548 %

TABLE 2. Determining the Work Done on the Spring

TRIALFinalDisplacement (m)Average force constant (N/m)Work(Joule)

Table1A0.084 m5.250 (N/m)0.019J

Table 1B0.042 m10.500(N/m)0.009J

TRIALArea under the graph F vs. x graph% difference

Table1A0.019J0.00 %

Table 1B0.009 J0.00 %

Sample ComputationTable 1A. Determining the Force Constant of the SpringTrial 1

m = 0.015 kg Displacement (x) = 0.027 mForce constant = K = F/x F = 0.147 N

K= 5.444 N/m

Average Force Constant

Average Force Constant = 5.345 N/mSlope of Line

Slope of line = 5.250 N/m

Table 1B. Determining the Force Constant of the SpringTrial 1

m = 0.015 kg Displacement (x) = 0.014 mForce constant = K = F/x F = 0.147 N

K= 10.500 N/m

Average Force Constant

Average Force Constant = 10.771 N/mSlope of Line

Slope of line = 10.500 N/m

Table 2. Determining the work done on the springTable 1AFinal Displacement = 0.084 mAve. Force constant = 5.25 N/m

Work = 0.019 J

Area under the graph = 0.019

Table 2BFinal Displacement = 0.042 mAve. Force constant = 10.500 N/m

Work = 0.009 J

Area under the graph = 0.009

ANALYSIS1. Which method (ballistic method or trajectory method) is more accurate in determining the initial speed of the ball? Defend your answer.

In determining the initial speed of the ball, I can say that the ballistic method is more accurate than the trajectory method. In ballistic method, we only need to determine the increase in the height of the pendulum and then compute the initial velocity and that it will give us a more accurate result unlike the trajectory method where we can have errors in finding the horizontal displacement since we are only using a meter stick.

2. In Part 1 of the experiment, is the total momentum of the system conserved? Explain.Yes, the total momentum of the system is conserved.In part 1, the ballistic method is an example of an inelastic collision. The law of conservation states that in an inelastic collision, the total momentum of the system is always conserved.

3. In Part 1 of the experiment, when is the total energy of the system not conserved? When is the total energy of the system conserved?

The total energy of the system is conserved during the collision. The total momentum before an inelastic collision is the same as after the collision. Since what is asked is the total energy not the total kinetic energy, the total energy is conserved because the total kinetic energy before and after the inelastic collision is different. Of course this does not mean that total energy has not been conserved, rather the energy has been transformed into another type of energy.

CONCLUSION:

1. What causes the total momentum of the system to change?The law of conservation of momentum is very useful in the analysis of collisions and explosions as it can be used to calculate the velocities of a body or bodies before and after the collision. Since momentum is a conserved quantity,external forcessuch as air resistance are the one that causes the total momentum of a system to change.

2. When the total momentum of the system is conserved, is the total energy of the system conserved as well? Explain.

Yes, both the energy and the momentum of the system are conserved. In an elastic collision, both kinetic energy and momentum is conserved. In an inelastic collision, the total momentum is also conserved but the totalkinetic energy is not.An inelastic collision is usually accompanied by deformation of one or both bodies. This requires energy thus; the total energy is conserved but not necessarily the kinetic energy.3. Is the total momentum of the system conserved in all kinds of collisions? Explain.

Yes, the total momentum of the system in all kinds of collisions is conserved. The law of conservation of momentum states that the total momentum of the system before collision is equal to the total momentum of the system after collision. Also, it states that in an elastic collision, both energy and momentum is conserved. In an inelastic collision, the total momentum is conserved but total kinetic energy is not conserved the kinetic energy is transformed into other kinds of energy.

RESEARCH/APPLICATIONS:

1. Excepting very small losses due tofriction andheat transfer, momentum isconserved incue sportsuch aspool(break-off shot). When oneball hits another and is stopped, all its momentumhas, in effect, been transferred to the other ball. If,however, it is deflected rather than stopped, its momentum is shared between the two balls.

2. Using the impulse-momentum theorem: When collision happens, people in the car will have a amount of momentum to make sure their bodieswant to keep moving forward. In order to stop them from getting harm, air bags are used to extendthe time required to get the enough amount ff impulse to reduce the momentum for a stop

3. The conservation oflinearmomentumis reflected in operations as simple as therecoilof a rifle when it is fired, and in those as complex as the propulsion of a rocket through space. In accordance with the conservation of momentum, the momentum of a system must be the same after it undergoes an operation as it was before the process began. Before firing, the momentum of a rifle and bullet is zero, and therefore, the rifle-bullet system must return to that same zero-level of momentum after it is fired. Thus, the momentum of the bullet must be matchedand "cancelled" within the system under studyby a corresponding backward momentum.

http://www.scienceclarified.com/everyday/Real-Life-Chemistry-Vol-3-Physics-Vol-1/Momentum-Real-life-applications.html

http://en.wikipedia.org/wiki/Momentum

http://www.scienceclarified.com/everyday/Real-Life-Chemistry-Vol-3-Physics-Vol-1/Conservation-Laws-Real-life-applications.html