Drill: Determine the Ksp for Mn 2 S 3 when the solubility is 1 x 10 -20.
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Transcript of Drill: Determine the Ksp for Mn 2 S 3 when the solubility is 1 x 10 -20.
![Page 1: Drill: Determine the Ksp for Mn 2 S 3 when the solubility is 1 x 10 -20.](https://reader036.fdocuments.us/reader036/viewer/2022062409/5697bf861a28abf838c88148/html5/thumbnails/1.jpg)
Drill: •Determine the Ksp for Mn2S3 when the solubility is 1 x 10-20
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Complex Ions
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Complex Ion•An ion formed when a positive central element binds with multiple ions
or polar molecules
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Complex Ion•The central
element is almost always a positively
charged metal
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Describe or define a
Complex Ion
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Anion•Negatively charged ion
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Cation
•Positively charged ion
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Metal Ion Examples Cu+2 Cu+ Au+
Ag+ Zn+2 Ni+2
Pt+2 Co+2 Al+3
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Ligands•The negative ions or polar molecules bound by the central element
in a complex ion
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Ligand Examples
•Cl- F- H2O
•NH3 CN- Br-
•NO O2 OH-
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Polydentate Ligands
• Ligands that can bind to more than
one point
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Bidentate Ligands
•Ligands that can bind to two points in a complex ion
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Bidentate Examples
H2N-CH2-CH2-NH2
-OOC-COO-
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Tridentate Ligands
•Ligands that can bind to three points
in a complex ion
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Tridentate Examples
H2-C-COO-
HO-C-COO-
H2-C-COO-
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Chelates•Polydentate ligands
that bind to metal ions in solution
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Coordination Number
•The number of points in which ligands bind to the central element
in a complex ion
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Coordinate Covalent Bond•Covalent bonds in which both electrons involved are donated
by one atom
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Drill:•Define:
–Complex ion
–Ligand
–Coordination number
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Complex Ions•The bonds formed in a
complex ion are coordinate covalent
bonds
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Coordination Complex
•A complex ion and its counter ion
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Complex Ions•The bonds formed in a
complex ion are coordinate covalent
bonds
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Complex Ion•Because of the type
bonding, they are sometimes called
coordinate complexes
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AP CHM HW•Read: Chapter 15
•Problems: 3 & 5
•Page: 445
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1) Name cations before anions
Naming Complexes
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Naming Complexes
2) Name ligands before metal in the
complex ion
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2) Naming Ligands
a) give neutral compds normal names except:
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H2O aqua
NH3 amine
CO carbonyl
NO nitrosyl
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2) Naming Ligands
b) change -ide endings to -o for
all anions
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2) Naming Ligands
c) name ligands alphabetically
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2) Naming Ligands d) use geometric
prefixes for monodentate
ligands
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2) Naming Ligands e) use bis- for 2 &
tris- for 3 polydentate ligands
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3) Naming Metal a) use the normal
name if the complex ion is (+)
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3) Naming Metal b) make the metal
ending -ate if the complex ion is (-)
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3) Naming Metal d) use Roman numerals in () to
indicate metal ox #
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Name the Following:
[Pt(NH3)4]Cl2
[Co(H2O)2Cl4]-2
[Cu(H2O)2(en)2]I2
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AP CHM HW•Read: Chapter 15•Name each in Problem 5
•Page: 445
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Predict # of isomers of each:
[Pt(NH3)4 Cl2]
[Co(H2O)3Cl3]
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Drill: Name each
[Pt (H2O)2(en)2]+2
[Co(H2O)2F2I2]-2
[ZnNH3ClFI]-1
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Complex Ion Shapes
2-linear 4-tetrahedral or sq pl
6-octahedral
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Geometric Isomers
Square planar vs tetrahedral
cis vs trans
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Geometric IsomersTetra vs Sq Pl
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Geometric IsomersSquare Planer
X
Y
X
Y
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Geometric Isomers
Bunched octa-
T-shaped octa-
bis: cis vs trans
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T-Shaped vs Bunched
X
X
X
X
X
X
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Optical Isomers Tri-bis mirror
images
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Cis vs trans
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Optical isomers
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Predict isomer #
[Pt (H2O)2(en)2]+2
[Co(H2O)2F2I2]-2
[ZnNH3ClFI]-1
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Name & Predict isomer #
[FeNH3Cl2I]-1
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AP CHM HW•Read: Chapter 15
•Problem: 13
•Page: 445
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Field Strength
CN- > NO2- > en >
NH3 > NCS- > H2O > F- > Cl-
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Field Strength CN- is strong field
Cl- is weak field
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Field Strength Determines d-level
splitting or o(splitting energy)
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dlevel
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dlevel
Low field strength (small splitting)
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dlevel
High field strength (large splitting)
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dlevel
Low spin High spin
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Field Strength Largeo yields low spin or diamagnetic
compds
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Field Strength Smallo yields high spin or paramagnetic
compds
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[Pt(NH3)2I4]-2
Determine:
Name, shape, & possible isomerism
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Drill: Determine the name, shape &
isomers of:
[Co(H2O)3Cl3]-1
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Determine the name, shape &
isomers of:
[Cu(NH3)2F2I2]-2
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Determine the name, shape &
isomers of:
[ZnBr2Cl2]-2
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[Co(NH3)6]+3 yellow[Co(NH3)5NCS]+2 orange[Co(NH3)5H2O]+2 red[Co(NH3)5Cl]+2 purplet-[Co(NH3)4Cl2]+1 green
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Complex Ion Equilibria
Cu+2 + 4 NH3 [Cu(NH3)4]+2
[[Cu(NH3)4]+2][Cu+2][NH3]4Kf =
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Calculate the ratio of [Cu+2]/ [Cu(NH3)4]+2 when Cu+2 is added to a 0.10 M
NH3 solution:Kf = 2.0 x 1012
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AP CHM HW•Read: Chapter 15
•Problem: 37
•Page: 446
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Common Ion Equilibria
•The larger the Kf, the more likely the complex will form
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Common Ion Equilibria
•Kf for [Ag(NH3)2]+1
= 1.7 x 107
•Kf for [Ag(CN)2]-1
= 2.0 x 1020
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Common Ion Equilibria
CN- will replaceNH3 in the
complex with silver
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Common Ion Equilibria
•Kf for [M(NH3)2]+2
= 1.7 x 1011
•Kf for [M(CN)4]-2
= 2.0 x 1020
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Calculate: a) coordination #
b) number of isomersc) oxidation # of metal
[Zn(NH3)2H2OF]+1
[Co(NH3)3ClFI]-1