Draw that shape. Draw that shape 1 - solutions Shape 1 Card 11 Shape 2 Card 13 Shape 3 Card 15...

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Draw that shape

Transcript of Draw that shape. Draw that shape 1 - solutions Shape 1 Card 11 Shape 2 Card 13 Shape 3 Card 15...

Draw that shape

Draw that shape 1 - solutionsShape 1 Card 11

Shape 2 Card 13

Shape 3 Card 15

Shape 4 Card 1

Shape 5 Card 9

Shape 6 Card 12

Shape 7 Card 6

Shape 8 Card 7

Shape 9 Card 2

Shape 10 Card 14

Shape 11 Card 4

Shape 12 Card 10

Shape 13 Card 8

Shape 14 Card 5

Shape 15 Card 3

Draw that shape 1 - solutionsCard 1 Shape 4

Card 2 Shape 9

Card 3 Shape 15

Card 4 Shape 11

Card 5 Shape 14

Card 6 Shape 7

Card 7 Shape 8

Card 8 Shape 13

Card 9 Shape 5

Card 10 Shape 12

Card 11 Shape 1

Card 12 Shape 6

Card 13 Shape 2

Card 14 Shape 10

Card 15 Shape 3

Draw that shape 2 - solutionsShape 1 octagon – 3 right angles – 1 reflex angle

Shape 2 hexagon – 2 right angles – 4 obtuse angles

Shape 3 hexagon – 4 acute angles – 2 reflex angles

Shape 4 pentagon – 3 right angles – 2 obtuse angles

Shape 5 rectangle – 4 right angles – perimeter = 6cm

Shape 6 quadrilateral – 4 right angles – area = 6cm²

Shape 7 pentagon – 2 right angles – 1 reflex angle

Shape 8 octagon – 4 right angles – 2 reflex angles

Draw that shape 3 - solutionsShape 1

I am a pentagon

2 acute angles

0 obtuse angles

1 reflex angle

2 right angles

3 sides of length 2 cm

perimeter is 14 cm

area = 6 cm²

0 lines of reflection

rotation order 0

Draw that shape 3 - solutionsShape 2

I am a hexagon

6 acute angles

0 obtuse angles

0 reflex angle

0 right angles

2 sides of length 1 cm

perimeter is 9·3 cm

area = 6 cm²

0 lines of reflection

rotation order 2

Draw that shape 3 - solutionsShape 3

I am a square

0 acute angles

0 obtuse angles

0 reflex angle

4 right angles

4 sides of length 2·2 cm

perimeter is 9 cm

area = 5 cm²

4 lines of reflection

rotation order 4

Draw that shape 3 - solutionsShape 4

I am a octagon

0 acute angles

0 obtuse angles

2 reflex angle

6 right angles

5 sides of length 1 cm2 sides of length 2 cm

perimeter is 12 cm

area = 5 cm²

1 line of reflection

rotation order 0

Draw that shape 3 - solutionsShape 5

I am a triangle

2 acute angles

0 obtuse angles

0 reflex angle

1 right angle

2 sides of length 2 cm

perimeter is 10·3 cm

area = 4·5 cm²

1 line of reflection

rotation order 0

Draw that shape 3 - solutionsShape 6

I am a octagon

4 acute angles

0 obtuse angles

4 reflex angles

0 right angles

2 sides of length 1 cm2 sides of length 3 cm

perimeter is 13·7 cm

area = 5 cm²

2 lines of reflection

rotation order 2

Draw that shape 3 - solutionsShape 7

I am a hexagon

2 acute angles

2 obtuse angles

2 reflex angles

0 right angles

2 sides of length 1 cm

perimeter is 11·2 cm

area = 4 cm²

1 line of reflection

rotation order 0

Draw that shape 3 - solutionsShape 8

I am a pentagon

0 acute angles

4 obtuse angles

0 reflex angles

1 right angle

2 sides of length 2 cm

perimeter is 9·9 cm

area = 6·5 cm²

1 line of reflection

rotation order 0

Draw that shape 4 - solutionsShape 1

Draw that shape 4 - solutionsShape 2

Draw that shape 4 - solutionsShape 3

Draw that shape 4 - solutionsShape 4

Draw that shape 4 - solutionsShape 5

Draw that shape 4 - solutionsShape 6

Draw that shape 4 - solutionsShape 7

Draw that shape 4 - solutionsShape 8

Draw that shape 5 - solutionsShape 1

I am a hexagon

1 line of reflection

rotation order 3

?

0 acute angles

6 obtuse angles

0 reflex angles

0 right angles

Draw that shape 5 - solutionsShape 2

I am a triangle

3 lines of reflection

rotation order 3

? equilateral

3 acute angles

0 obtuse angles

0 reflex angles

0 right angles

Draw that shape 5 - solutionsShape 3

I am a hexagon

1 line of reflection

rotation order 0

?

0 acute angles

4 obtuse angles

0 reflex angles

2 right angles

Draw that shape 5 - solutionsShape 4

I am a trapezium

1 line of reflection

rotation order 0

?

2 acute angles

2 obtuse angles

0 reflex angles

0 right angles

Draw that shape 5 - solutionsShape 5

I am a duodecagon

2 lines of reflection

rotation order 2

?

4 acute angles

4 obtuse angles

4 reflex angles

0 right angles

Draw that shape 5 - solutionsShape 6

I am a octagon

2 lines of reflection

rotation order 2

?

4 acute angles

2 obtuse angles

2 reflex angles

0 right angles

Draw that shape 5 - solutionsShape 7

I am a heptagon

1 line of reflection

rotation order 0

?

2 acute angles

3 obtuse angles

2 reflex angles

0 right angles

Draw that shape 5 - solutionsShape 8

I am a kite

1 line of reflection

rotation order 0

?

1 acute angle

3 obtuse angles

0 reflex angles

0 right angles

Draw that shape 6 - solutionsShape 1

Draw that shape 6 - solutionsShape 2

Draw that shape 6 - solutionsShape 3

Draw that shape 6 - solutionsShape 4

Draw that shape 6 - solutionsShape 5

Draw that shape 6 - solutionsShape 6

Draw that shape 6 - solutionsShape 7

Draw that shape 6 - solutionsShape 8

Draw that shape 7I’ll draw that shape in…

You will get 4 sentences.

They will be revealed one by one.

Predict the number of sentences you think you will need to be able to draw the correct shape, and show your number.

If you say 2, you must draw and show a shape after 2 sentences.

Draw that shape 7Shape 1

I am an arrowhead.

I have 1 line of symmetry.

2 of my sides are 1 cm long.

I have 1 internal dot.

Draw that shape 7Shape 2

I am an octagon.

1 of my sides is 2 cm long, the rest are 1 cm long.

I have 1 line of symmetry.

I have no internal dots.

Draw that shape 7Shape 3

I have 2 sets of equal parallel sides.

I have rotation symmetry but no reflection symmetry.

I have 2 internal dots.

There are 4 dots at the vertices but no other dots on the sides.

Draw that shape 7Shape 4

I have 1 set of parallel sides.

I have no reflection or rotation symmetry.

2 adjacent sides are 1 cm long.

The longest side is horizontal.

internal angle

÷ by 6 full turn = 360°, 6 equal angles

internal angle is double the base angle

angles in a triangle = 180°

180° - 60° = 120° isosceles triangle so the base angles equal ÷ by 2 = 60°

60° × 2 = 120° external angle

angles on a straight line = 180°

180° - 120° = 60°