Domestic Demand:

#JElevation ( m )

Domestic

AreaDensityPopulation

Q

(m²( (m3/d(

J134.033256.820.05162.8432.98

J229.066493.580.05324.6865.75

J325.305778.820.05288.9458.51

J425.206637.210.05331.8667.20

J526.704675.620.05233.7847.34

For the 1st junction :P domestic = Area*Population Density

= 3256.82* 0.05= 163 Q domestic = P domestic*150 *1.35 /1000 = 32.98 m³/d Average Demand for capita / day =150 L/c/dThe value 1.35 = 25% loses in the network

and the equivalent commercial demand which was taken 10% domestic demand.

Domestic Demand:

For public demand:

Average Demand for capita / day = 40 L/c/d

Q public = # employee * 40 * 1.25 (25%

UFW)

Public Demand:

Public Demand:

#J

Public

Area #Employees

Q

(m²( (m3/d(

J10 00

J20 00

J30 00

J4548.38109.685.5

J51922.40384.4819

For junction 4 which has a public demand,

Area = 548.38 m² ,

Let # of employee = 0.2*Area =109.68 =110

person

Q public =110*40*1.25/1000 = 5.5 m³ /day

Public Demand:

Commercial Demand:

For junction which has a commercial demand,

Let # of = 1200 person/day

Average Demand for capita / day = 30 L/c/d

Q Commercial = 1200*30*1.25/1000 = 45 m³ /day

(25% UFW)

Industrial Demand:

For junction which has an industrial demand,

Let # of workers = 850 person

Average Demand for capita / day = 30 L/c/d

Add 30% for cleaning works.. etc

Q Industrial = 850*30*1.55/1000 = 40 m³ /day

(25% UFW, 30% Others)

School Demand:

For junction which has a school demand,

# of pupils/school = 1200 pupil

Average Demand for capita / day = 10 L/c/d

Q school = 1200*10*1.25/1000 = 15 m³ /day

(25% UFW)

Hospital Demand:

For junction which has a hospital demand,

Let # of beds = 160

Average Demand for capita / day = 300 L/c/d

Q Hospital = 160*300*1.25/1000 = 60 m³ /day

(25% UFW)

Mosque Demand:

For junction which has a mosque demand,

# of prayers/day =500 person

Average Demand for capita / day = 25 L/c/d

Q Mosque = 500*25*1.25/1000 = 15.7 m³ /day

(25% UFW)

Agricultural Demand:

For junction which has a agricultural demand,

Agricultural demand varies according to the

type of trees.

Demand for Green areas = 5

m3/Donum/Week

Average Demand / day = ??? m3/d

Don’t Forget (25% UFW)

Tourist Demand:

For junction which has a tourist demand,

Demand for Hotels = 180 L/C/d

Average Demand / day = ??? m3/d

Don’t Forget (25% UFW)

Total Demand:

Qtotal of network = ∑ Qnodes m3/day

Average Demand:

For each type of demand

Qavg_i = ∑ Qnodes / 24 m3/hr

Where (i) is the type of demand

Qtotal of network (m3/day)

Example..

Questions