Distribution From A Physiologic Perspective Problems / Questions Related to Introduction...
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DistributionFrom A Physiologic Perspective
•Problems / Questions Related to Introduction
• Distribution From A Physiologic Perspective]
• Five “Distribution Problems” are provided starting at slide 21. Not all of these problems will be completed in class … but you are expected to work through them on your own.
Objectives
Opening Question:Mr. JR receives 500 mg of Levofloxacin by intravenous bolus (over 1 minute) and the serum concentration is measured immediately and found to be 5.0 mg/L.
What is the apparent volume of distribution?What percent of drug is located in serum?
Distribution
Where does drug go?
ObjectiveReview Basic Principles related to
drug & chemical / metabolite distribution in the body
Develop a definition forVolume of Distribution
Where does the drug go?
Is it confined to bloodor
is it mostly in the blood or
is it largely confined to tissues?
Facts and Figures
Body WeightsActual vs Ideal (IBW)
Male: 50 kg + (2.5 kg/inch over 5 ft)Female: 45.5 kg + (2.3 kg / inch over 5 ft)
Blood Volume (L) ~ 8% of IBWBody water (L)~60% of IBW
Barriers to Distribution1. GI Tract
Intestinal wall prevents absorption… not all drugs are absorbed
2. Vascular wallslimits “escape” from serum / blood
3. Cellular walls limits “free” movement within the body
Extra-cellularWater~ 15 L
Intra-cellular Water~ 25 L
RBC’s, ~ 45% of whole bloodPlasma or Serum ~ 55%
Whole Blood ~ 5 L
Body Water1
1. Skelton, H. Arch Int. Med 1927; 40: 140.
Tissue % Water %Weight Waterper 70 kg ( L )
Skin 72 18 9.1Muscle 75 42 22.1Brain 75 2 1.1Skelton 22 16 2.5Adipose 10 ~10 0.7Other 12 6.5Total 100 42
General Principles of Distribution
10 L
1000 mg If you add 1000 mg of a drug to 10 L of water,
what is the final concentration?
Following complete mixingConcentration (C) = 1000 mg/ 10L= 100 mg/L
C = Amount / volumeVolume = Amount / C
General Principles of Distribution
10 L
1000 mgIf you add 1000 mg of a drug
to 10 L of water, what is the final concentration?
Could the concentration change as a function of time after addition?
C = Amount / volumeVolume = Amount / C
If you knew that you had added 1000 mg of drug and then drew a sample from a corner of the vessel before complete mixing occurred, what would you conclude?
General Principles of Distribution
10 L
1000 mgAgain you add 1000 mg of a drug
to 10 L of water, but now there is some charcoal in the water
that may bind the drug.The observed concentration
after complete mixing is 50 mg/L
SinceVolume = Amount / C
then the apparent volume of distribution is:
= 1000 mg/50 mg/L= 20L …???
BUT The real volume is 10L
Charcoal
General Principles of Distribution
10 L
1000 mgAgain you add 1000 mg of a drug
but this time in addition to the charcoal and 10L of water there is 1 L of oil.
You measure the concentration in the oil (150 mg/L)
and in the water (25 mg/L).
Now calculate the volume:
Based on the concentration in the waterVolume = Amount / C
then the apparent volume of distribution is:
= 1000 mg/25 mg/L= 40L
Charcoal
1L
Again you add 1000 mg of a drug but this time in addition to the charcoal
and 10L of water there is 1 L of oil.
You measure the concentration in the oil (150 mg/L)
and in the water (25 mg/L).
General Principles of Distribution
10 L
1000 mg
Now calculate the volume:
Based on the concentration in the oilVolume = Amount / C
then the apparent volume of distribution is:
= 1000 mg/150 mg/L= 6.66 L
Charcoal
1L
Mass Balance
Water:Concentration 25 mg/L
True Volume: 10LAmount of Drug = 250 mgApparent Volume = 40L
Oil:Concentration 150 mg/L
True Volume: 1LAmount of Drug = 150 mgApparent Volume = 6.66 L
Charcoal: (therefore)Amount = 600 mg
General Principles of Distribution
10 L
1000 mg
Charcoal
1L
Conclusions
1. The calculated Apparent Volume depends on the fluid being sampled.
2. The volume depends on the host, and the physical/chemical properties of the drug or metabolite
3. The calculated Apparent Volume rarely reflects a real physiologic volume.
General Principles of Distribution
10 L
1000 mg
Charcoal
1L
…so what is the Apparent Volume of Distribution?
… it is the volume of sampled fluid need to account for the total amount of drug in the body … at distribution equilibrium … (following complete mixing).
The volume is not associated with a particular space or anatomical area or tissue.
It is a proportionality constant relating concentration and amount in the body.
General Principles of Distribution
10 L
1000 mg
Charcoal
1L
…so, if it is not real, how useful is it?
Uses:
• It tells us how much drug must be added to the body so as to achieve a specified concentration in the sampled fluid.
• In a general way it tells us where the drug is stored in the body or where it might be found.
General Principles of Distribution
10 L
1000 mg
Charcoal
1L
L/70 kg50,000
20,000
10,000
5,000
1,000
500
100
50
10
5
General Principles of Distribution
Quinacrine
Chloroquine
NortriptylineDigoxin
PropranololQuinidineQuinolones (1- 2 L/kg), TetracyclinePhenobarbitalPhenytoinTheophylline (0.45 L/kg)Aminoglycodises (0.25 L/kg)ASAWarfarin
Question:If the drug is distributing to total body water, why are there large differences in the volume for different drugs?
General Principles of Distribution
Physical Chemical properties of the drugHigh molecular weight (mabs) and even ICG (MW = 775) are confined to plasma volume.
Ions (Cl-, Br-) rapidly distribute throughout extra-cellular fluid but do not easily cross cell membranes.
Other Ions (K+, Ca2+) are actively transported across membranes. Potassium is predominately intra-cellular.
Protein Binding
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
In blood, drugs often bind to albumin.
The unbound (free) drug can diffuse out of the
blood, into the extra-cellular water and often into cells (intra-cellular water).
Equilibrium is established
General Principles of Distribution
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
The equilibrium between
Bound & Free remains in place.
It is also assumed that at equilibrium
the free concentration is equal in all tissues
General Principles of Distribution
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
If a drug is highly bound within tissues, the equilibrium
established betweenbound and free
will find the majority of the drug in tissues,
(based on binding and mass).
General Principles of Distribution
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
Protein binding in blood will <effectively>
keep drug in blood.
However, since tissue mass
exceeds blood volume,any binding in tissues
will shift the equilibrium toward drug in tissues.
General Principles of Distribution
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues. The volume of distribution
of a drug can be viewed as a relationship between
tissue binding and binding to protein within the blood.
If a drug is highly protein bound within blood but has little tissue binding,
the volume of distribution will be small
(~10L – e.g. warfarin).
General Principles of Distribution
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
Even if a drug is highly protein bound
within blood but also has high tissue binding,
the volume of distribution will be large.
General Principles of Distribution
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
The volume of distribution of a drug can be viewed as
a relationship between tissue binding and binding to protein within the blood.
General Principles of Distribution
VdTOTAL = VB + VT (fB/fT)
Where VB is blood volume ~ 5L and VT is body water (between 30-50 L).
fB and fT is the fraction unbound in tissue and in blood
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
The volume of distribution of a drug can be viewed as
a relationship between tissue binding and binding to protein within the blood.
General Principles of Distribution
VdTOTAL = VB + VT (fB/fT)
Where VB is blood volume ~ 5L and VT is body water (between 30-50 L).
If fB is 5% (free in blood or plasma)and fT is 100%
(free in issues – no binding)The final volume
is 5L of blood volume plus ~2.5L of tissue volume.
7.5L total.
Protein Binding:Unless a drug is actively transported into cells, it is generally assumed that only free drug can distribute to tissues.
The volume of distribution of a drug can be viewed as
a relationship between tissue binding and binding to protein within the blood.
General Principles of Distribution
VdTOTAL = VB + VT (fB/fT)
Where VB is blood volume ~ 5L and VT is body water (between 30-50 L).
If fB is 5% (free in blood or plasma)But fT is 1%
(free in issues – 99% binding)The final volume
is 5L of blood volume plus ~250 L of tissue volume.
255L total.
VdTOTAL = VB + VT (fB/fT)
This makes the assumption that
the drug may distribute to all
places in the body where water exists and this may not be true if there is active transport
in or out of a particular
tissue. eg. BBB etc.
Effect of Protein Binding on Volume of Distribution
General Principles of Distribution
Observe the Effect of Protein Binding on Volume of Distribution of Propranolol
For propranololas the free fraction
increases from ~5% to ~30%Volume (Vd) increases from
~125 L to ~800 L.
6-fold increases in both FF and Vd.
Open circles – Liver disease patients
General Principles of Distribution
L/70 kg50,000
20,000
10,000
5,000
1,000
500
100
50
10
5
General Principles of Distribution
Quinacrine
Chloroquine
NortriptylineDigoxin
PropranololQuinidineQuinolones (1- 2 L/kg), TetracyclinePhenobarbitalPhenytoinTheophylline (0.45 L/kg)Aminoglycodises (0.25 L/kg)ASAWarfarin
Five Examples:Example 5: Cyclosporin … 3000L Example 2: Ciprofloxacin … 120LExample 1: Levofloxacin … 100LExample 4: Levofloxacin … 83.3LExample 3: Theophylline … 36L
Notice that the
Volume of distributionis different
for all drugs and will also be different
for each patient (levo).
Distribution ProblemsFive Examples:Example 1: Levofloxacin
Calculate Volume
Example 2: CiprofloxacinGiven Volume, Calculate Concentration
Example 3: TheophyllineCalculate Volume…then predict new dose
Example 4: Levofloxacin Example 5: Cyclosporin
Male Acute Community Acquired Pneumonia
General Principles of Distribution
Summary1. The calculated apparent Volume depends
on the fluid being sampled.
2. Drugs can go anywhere (phys.-chem. prop.) leaving extra-cellular water to distribute into bone, fat or … anywhere, any tissue.
3. The apparent Volume depends on the host, and the physical/chemical properties of the drug or metabolite.
4. The calculated apparent Volume rarely reflects a real physiologic volume.
5. The minimum volume* of distribution is vascular volume (8% IBW: 6’ ♂ = 6.4L).
6. There is no maximum volume*.
Volume of Distribution
Blood
Liver
Kidney
GI TractOralDose
IVDose
First Example: Levofloxacin
Distribution Problem 1Calculate Volume
Male with PneumoniaAge: 45 yrWeight: 80 kgDrug: Levofloxacin
Observe: Serum levofloxacin concentration followingi.v. bolus of 500 mg
5 g/mL (mg/L)
Additional Information:Blood Volume: 8% of body weightHematocrit: 0.45
Male Acute Community Acquired Pneumonia
Distribution Problem 1
Questions
1. What is the Volume of distribution of levo?
2. Where in the body does levo appear to be located? What percent is located in the Serum?
3. If the serum levo concentration is at the mid-point of target…3 g/mL
(a) how much drug is in the serum?(b) what is the total amount of drug in
your patient (MAC)?
Male Acute Community Acquired Pneumonia
Distribution Problem 1
Answers.
1. What is the Volume of distribution of levo? Dose = Initial [ ] = Levo Volume: =
2. Proportion in Serum: =
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 1
Answers.
1. What is the Volume of distribution of levo? Dose = 500 mgInitial [ ] = 5 g/mL (mg/L)
Levo Volume: = Dose / Conc= 500 / 5= 100 L
2. Proportion in Serum: =
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 1
Answers.
2. Proportion in Serum:Weight : 80 kgLevo Volume: 500 mg/ 5 mg/L Blood Volume: 8% of body weightHematocrit: 0.45
Blood volume: = Serum (55%): =Levo Volume: =
Proportion in Serum: =
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 1
Answers.
2. Proportion in Serum:Weight : 80 kgLevo Volume: 500 mg/ 5 mg/L Blood Volume: 8% of body weightHematocrit: 0.45
Blood volume: = 0.08 x 80 kg = 6.4 LSerum (55%): =6.4 x 0.55 = 3.5 LLevo Volume: = 500 mg/ 5 mg/L = 100 L
Proportion in Serum: =
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 1
Answers.
2. Proportion in Serum:Weight : 80 kgLevo Volume: 500 mg/ 5 mg/L Blood Volume: 8% of body weightHematocrit: 0.45
Blood volume: = 0.8 x 80 kg = 6.4 LSerum (55%): =6.4 x 0.55 = 3.5 LLevo Volume: = 500 mg/ 5 mg/L = 100 L
Proportion in Serum: = 3.5 L/100.0 L= 3.5%
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 1
Answers.
3. If the serum levofloxacin concentration is at the mid-point of target … ~ 3mg/L …
(a) how much drug is in the serum?(b) what is the total amount of drug in MAC?
Therapeutic Range: 5 - 1 g/mL = mg/Lmid point: 3 mg/L
Amount in body at equilibrium:=
Amount in serum:=
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 1
Answers.
3. If the serum levofloxacin concentration is at the mid-point of target … ~ 3mg/L …
(a) how much drug is in the serum?(b) what is the total amount of drug in MAC?
Therapeutic Range: 5 - 1 g/mL = mg/Lmid point: 3 mg/L
Amount in body at equilibrium:= 3 mg/L x 100.0 L = 300 mg
Amount in serum:= 3 mg/L x 3.5 L = 10.5 mg
Percent in serum: = 10.5 mg/ 300 mg= 3.5%
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Levofloxacin Distribution Problem 1 Review
Answers.Body Weight: 80 kgBlood Volume: 8% of body weight
Serum is 55% of Blood
Serum = (0.08) x (0.55) x (80) = 3.52 L
Serum conc. = 3 g/mL= 3 mg/L
Amount in Serum:= (3.5 L) x 3 mg/L)= 10.5 mg
Amount in Body, based on volume of 100 L= (3) x (100) = 300 mg
Percent in Serum: 10.5 mg / 300 mg = 3.5%
Volume100 L
100 L/80kg= 1.2 L/kg
Recall Levo monograph
indicated volume was
between 74 & 112 L.
Volume of Distribution
Blood
Liver
Kidney
GI TractOralDose
IVDose
Second Example: Ciprofloxacin
Distribution Problem 2This time … given Volume
Male with PneumoniaAge: 45 yrWeight: 80 kgDrug: Ciprofloxacin
Goal: Serum ciprofloxacin concentrations ranging
3 - 4 g/mL (target)
Additional Information:Cipro Volume: 1.5 L/kgBlood Volume: 8% of body weightHematocrit: 0.45
Male Acute Community Acquired Pneumonia
Distribution Problem 2
Questions
1. What dose should be given to MAC to achieve a peak concentration of between 3 and 4 g/mL?
2. What percent is located in the Serum?
3. If the serum cipro concentration is at the mid-point of target…3.5 g/mL
(a) how much drug is in the serum?(b) what is the total amount of drug in MAC?
Male Acute Community Acquired Pneumonia
Distribution Problem 2
Answers.
1. What dose should be given to MAC to achieve a peak concentration of between 3 and 4 g/mL?
Cipro Volume: 1.5 L/kgPt weight: 80 kg6.4 x 0.55 = 3.5 LCipro Volume (L): =
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 2
Answers.
1. What dose should be given to MAC to achieve a peak concentration of between 3 and 4 g/mL ?
Cipro Volume: 1.5 L/kgPt weight: 80 kg6.4 x 0.55 = 3.5 LCipro Volume (L): = 1.5 L/kg x 80 kg
= 120.0 L
Peak target [ ] mg/L = 3 g/mLReq. Cipro Dose =
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 2
Answers.
1. What dose should be given to MAC to achieve a peak concentration of between 3 and 4 g/mL?
Cipro Volume: 1.5 L/kgPt weight: 80 kg6.4 x 0.55 = 3.5 LCipro Volume (L): = 1.5 L/kg x 80 kg
= 120.0 L
Peak target [ ] mg/L = 3 g/mL (mg/L)Req. Cipro Dose = 3 mg/L x 120 L
= 360 mg
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 2
Answers.
1. What dose should be given to MAC to achieve a peak concentration of between 3 and 4 g/mL?
Cipro Volume: 1.5 L/kgPt weight: 80 kg6.4 x 0.55 = 3.5 LCipro Volume (L): = 1.5 L/kg x 80 kg
= 120.0 L
Peak target [ ] mg/L = 4 g/mL (mg/L)Req. Cipro Dose = 4 mg/L x 120 L
= 480 mg
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 2
Answers.
1. What dose should be given to MAC to achieve a peak concentration of between 3 and 4 g/mL?
Peak target 3 mg/L = Dose = 360mg
Peak target 4 mg/L = Dose = 480mg
Common dose of Cipro IV?
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 2
Answers.
1. What dose should be given to MAC to achieve a peak concentration of between 3 and 4 g/mL?
Peak target 3 mg/L = Dose = 360mg
Peak target 4 mg/L = Dose = 480mg
Common dose of Cipro IV?
400 mg
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 2
Answers.
2. What percent is located in the Serum?Weight : 80 kgCipro Volume: 1.5 L/kgBlood Volume: 8% of body weightHematocrit: 0.45
Blood volume: 0.8 x 80 kg = 6.4 LSerum vol. (55%): 6.4 x 0.55 = 3.5 LCipro Volume: 1.75 L/kg x 80 kg
140.0 LProportion in Serum: 3.5 L/140.0 L = 2.5%
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 2
Answers.
2. What percent is located in the Serum?Weight : 80 kgCipro Volume: 1.5 L/kgBlood Volume: 8% of body weightHematocrit: 0.45
Blood volume: 0.08 x 80 kg = 6.4 LSerum vol. (55%): 6.4 x 0.55 = 3.5 LCipro Volume: 1.5 L/kg x 80 kg
120.0 LProportion in Serum: 3.5 L/120.0 L = 2.9%
Male Acute Community Acquired Pneumonia
Equations
Conc = Dose / V
V = Dose/Conc
Ciprofloxacin Distribution Problem 2 ReviewAnswers.Body Weight: 80 kgBlood Volume: 8% of body weight
Serum is 55% of BloodSerum = (0.08) x (0.55) x (80) = 3.52 L
Serum conc. = 3 g/mL= 3 mg/L
Amount in Serum:= (3.5 L) x 3 mg/L)= 10.5 mg
Amount in Body, based on volume of 120 L= (3) x (120) = 360 mg
(Dose = 400 mg)
Percent in Serum: 10.5 mg / 360 mg = 2.9%
Volume1.5 L/kg
120.0 L
Volume of Distribution
Blood
Liver
Kidney
GI TractOralDose
IVDose
Third Example: Theophylline
Distribution Problem 3
Male AsthmaticAge: 45 yrWeight: 80 kgDrug: Theophylline
Goal: Serum theophylline in the therapeutic range
10 – 20 g/mL
Additional Information:Initial Theophylline Dose of 300 mg produces a peak following a bolus iv dose of 8.33 mg/L.
Severe Asthmatic Male
Distribution Problem 3
Questions
1. What is the volume of distributionof theophylline?
2. What percent is located in the Serum?
3. If we need to produce a peak serum theophylline concentration near the mid-point of target… (~15 mg/L), what should the dose be?
Severe Asthmatic Male
Distribution Problem 3
Answers.
1. What is the volume of distributionof theophylline?
Theophylline Dose = 300 mg Peak [ ] mg/L = 8.33 mg/L.0.55 = 3.5 LTheophylline Volume: =
Vol. Expressed as L/kg: =
Severe Asthmatic Male
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 3
Answers.
1. What is the volume of distributionof theophylline?
Theophylline Dose = 300 mg Peak [ ] mg/L = 8.33 mg/L.0.55 = 3.5 LTheophylline Volume: = 300 mg / 8.33 mg/L
= 36 LExpressed as L/kg: = 36 L / 80 kg
= 0.45 L/kg
Severe Asthmatic Male
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 3
Answers.
2. Proportion in Serum?Weight : 80 kgTheophylline Volume: 0.45 L/kgBlood Volume: 8% of body weightHematocrit: 0.45
Blood volume: 0.8 x 80 kg = 6.4 LSerum (55%): 6.4 x 0.55 = 3.5 LTheophylline Volume: 0.45 L/kg x 80 kg
36.0 LProportion in Serum: 3.5 L / 36.0 L = 9.8%
Severe Asthmatic Male
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 3
Answers.
2. Proportion in Serum?Weight : 80 kgTheophylline Volume: 0.45 L/kgBlood Volume: 8% of body weightHematocrit: 0.45
Blood volume: 0.08 x 80 kg = 6.4 LSerum (55%): 6.4 x 0.55 = 3.5 LTheophylline Volume: = 0.45 L/kg x 80 kg
= 36.0 LProportion in Serum: = 3.5 L / 36.0 L
= 9.8%
Severe Asthmatic Male
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 3
Answers.
3. If we need to produce a peak serum theophylline concentration near the mid-point of target… (~15 mg/L), what should the dose be?
Therapeutic Range: 10 – 20 g/mL = mg/Lmid point: 15 mg/L
Amount in body at 15 mg/L:15 mg/L x 36.0 L = 540 mg
Dose:15 mg/L x 3.5 L = 52.5 mg
Severe Asthmatic Male
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 3
Answers.
3. If we need to produce a peak serum theophylline concentration near the mid-point of target… (~15 mg/L), what should the dose be?
Therapeutic Range: 10 – 20 g/mL = mg/Lmid point: 15 mg/L
Amount in body at 15 mg/L:15 mg/L x 36.0 L = 540 mg
Dose: actual dose???540 mg peak of 15 mg/L
Severe Asthmatic Male
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 3
Answers.
3. If we need to produce a peak serum theophylline concentration near the mid-point of target… (~15 mg/L), what should the dose be?
Dose: actual dose???540 mg = peak of 15 mg/L600 mg = peak conc?
= 600 mg / 36 L= 16.6 mg/L
500 mg = peak conc?= 500 mg / 36 L= 13.9 mg/L
Severe Asthmatic Male
Equations
Conc = Dose / V
V = Dose/Conc
Distribution Problem 3
Answers.Body Weight: 80 kgBlood Volume: 8% of body weight
Serum is 55% of Blood
Serum = (0.08) x (0.55) x (80) = 3.52 L
Serum conc. = 15 g/mL= 15 mg/L
Amount in Serum:= (3.5 L) x 15 mg/L)= 52.5 mg
Amount in Body, based on volume of 36 L= (15) x (36) = 540 mg
Percent in Serum: 52.5 mg / 540 mg = 9.8%
Volume0.45 L/kg
36.0 L
Volume of Distribution
Blood
Liver
Kidney
GI TractOralDose
IVDose
Fourth Example: Levofloxacin in a different patient
Distribution QuestionExample 4
Mr. JR, as 45 yr old male weighing 80 kg and
appears to have CommunityAcquired Pneumonia. He is
prescribed 500 mg of levofloxacin, once per day for 7 days.
Immediately following the first dose, given by I.V. bolus, a plasma
concentration is measured as 6.0 mg/L.
1. Calculate the apparent volume of distribution.2. What percent of the drug is in plasma?3. Other Questions about “Distribution”?
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma concentration is measured as 6.0 mg/L.
1. Calculate the apparent volume of distribution.Conc = Dose / VolumeVolume = Dose / Conc
= 500 mg / 6.0 mg/L=
Equations
Conc = Dose / V
V = Dose/Conc
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
1. Calculate the apparent volume of distribution.Conc = Dose / VolumeVolume = Dose / Conc
= 500 mg / 6.0 mg/L= 83.33 liters
Expressed per kg of body weight=
Equations
Conc = Dose / V
V = Dose/Conc
Notice that this volume is slightly different than the 100 L calculated for a different patient
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
1. Calculate the apparent volume of distribution.Conc = Dose / VolumeVolume = Dose / Conc
= 500 mg / 6.0 mg/L= 83.33 liters
Expressed per kg of body weight= 83.33 liters / 80 kg=1.04 L/kg
Equations
Conc = Dose / V
V = Dose/Conc
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
1. Calculate the apparent volume of distribution. Volume = 83.33 liters
Vol per kg of body weight = 1.04 L/kg
2. What percent of the drug is in plasma?Blood is ~8% of body weightMr. JR weighs 80 kg. Blood Volume is ~ 6.4 LPlasma volume is ~55% of blood volume.Plasma volume = 6.4 L x 0.55 = 3.52 L.
Equations
Conc = Dose / V
V = Dose/Conc
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
2. What percent of the drug is in plasma?
Plasma volume = 6.4 L x 0.55 = 3.52 L.Conc in plasma = 6.0 mg/L
Amount in plasma =
Equations
Conc = Dose / V
V = Dose/Conc
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
2. What percent of the drug is in plasma?
Plasma volume = 6.4 L x 0.55 = 3.52 L.Conc in plasma = 6.0 mg/L
Amount in plasma = 3.52 L x 6.0 mg/L= 21.12 mg.
How much is in the body?volume distrib. = 83.33 L Conc in plasma = 6.0 mg/LAmount in body =
Equations
Conc = Dose / V
V = Dose/Conc
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
2. What percent of the drug is in plasma?
Plasma volume = 6.4 L x 0.55 = 3.52 L.Conc in plasma = 6.0 mg/L
Amount in plasma = 3.52 L x 6.0 mg/L= 21.12 mg.
How much is in the body?volume distrib. = 83.33 L Conc in plasma = 6.0 mg/L
Amount in body = 6.0 mg/L x 83.33L= 500 mg (dose)
Equations
Conc = Dose / V
V = Dose/Conc
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
2. What percent of the drug is in plasma?
Amount in plasma = 3.52 L x 6.0 mg/L= 21.12 mg.
Amount in body = 6.0 mg/L x 83.33L= 500 mg (dose)
Proportion in plasma ?=
Equations
Conc = Dose / V
V = Dose/Conc
Distribution QuestionExample 4
Mr. JR, receives 500 mg and the initial plasma
concentration is measured as 6.0 mg/L.
2. What percent of the drug is in plasma?
Amount in plasma = 3.52 L x 6.0 mg/L= 21.12 mg.
Amount in body = 6.0 mg/L x 83.33L= 500 mg (dose)
Proportion in plasma= 21.12 mg / 500 mg= 0.042= 4.2%
Equations
Conc = Dose / V
V = Dose/Conc
Distribution QuestionExample 4
Volume of Distribution
Blood
Liver
Kidney
GI TractOralDose
IVDose
Fifth Example: Cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplant
patient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.
Immediately after the dose a bloodsample is taken and the blood concentrationis measured as 200 ng/mL.
(a) What is the apparent volume of distrib?(b) What percent of CsA in the body is
located in blood / plasma in this patient?
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.
Immediately after the dose a bloodsample is taken and the blood concentrationis measured as 200 ng/mL. (200 ug/L)
(a) What is the apparent volume of distrib?Conc = Dose / VolumeVolume = Dose / Conc
=
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.
Immediately after the dose a bloodsample is taken and the blood concentrationis measured as 200 ng/mL. (200 ug/L)
(a) What is the apparent volume of distrib?Conc = Dose / VolumeVolume = Dose / Conc
= 600 mg / 200.0 ug/L= 600 mg / 0.2 mg/L= 3,000 liters
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.
If, immediately after the dose a bloodsample is taken and the plasma concentrationis measured as 100 ng/mL. (100 ug/L)
(a) What is the apparent volume of distrib?Conc = Dose / VolumeVolume = Dose / Conc
=
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.
If, immediately after the dose a bloodsample is taken and the plasma concentrationis measured as 100 ng/mL. (100 ug/L)
(a) What is the apparent volume of distrib?Conc = Dose / VolumeVolume = Dose / Conc
= 600 mg / 100.0 ug/L= 600 mg / 0.1 mg/L= 6,000 liters
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.Immediately after the dose a bloodsample is taken and the blood concentrationIs measured as 200 ng/mL.
(a) What is the apparent volume of distrib?(b) What percent of CsA in the body is
located in whole blood in this patient?Blood is ~8% of body weightMs. MJ weighs 55 kg. MJ’s hematocrit is 0.45 (45% cells)
Blood Volume=
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.Immediately after the dose a bloodsample is taken and the blood concentrationIs measured as 200 ng/mL.
(a) What is the apparent volume of distrib?(b) What percent of CsA in the body is
located in whole blood in this patient?Blood is ~8% of body weightMs. MJ weighs 55 kg. MJ’s hematocrit is 0.45 (45% cells)
Blood Volume= 55 kg x 0.08= 4.4 L
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.Immediately after the dose a bloodsample is taken and the blood concentrationIs measured as 200 ng/mL.
(b) What percent of CsA in the body is located in whole blood in this patient?Blood Volume= 4.4 LHow much is in Blood?
=
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.Immediately after the dose a bloodsample is taken and the blood concentrationIs measured as 200 ng/mL.
(a) What percent of CsA in the body is located in whole blood in this patient?Blood Volume= 4.4 LHow much is in Blood?
= 4.4 L x 0.2 mg/L= 0.88 mg
How much is in the body?Amount in body =
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Blood sample measures 200 ng/mL.
(b) What percent of CsA in the body is located in whole blood in this patient?Blood Volume= 4.4 LHow much is in Blood?
= 4.4 L x 0.2 mg/L= 0.88 mg
How much is in the body?Amount in body = 0.2 mg/L x 3000L
= 600 mg (dose)Proportion in whole blood ?
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Blood sample measures 200 ng/mL.
(a) What percent of CsA in the body is located in whole blood in this patient?
How much is in Blood?= 0.88 mg
How much is in the body?= 600 mg (dose)
Proportion in whole blood ?= 0.88 mg / 600 mg= 0.0015= 0.15%
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.Immediately after the dose a bloodsample is taken and the plasma concentrationis measured as 100 ng/mL.
(b) What percent of CsA in the body is located in plasma in this patient?Plasma Volume = 4.4 L x 0.55 = 2.42 LHow much is in plasma?
=
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Cyclosporin is “highly bound to RBC” and the “Blood : Plasma ratio is 2”.Immediately after the dose a bloodsample is taken and the plasma concentrationis measured as 100 ng/mL.
(a) What percent of CsA in the body is located in plasma in this patient?Plasma Volume = 2.42 LHow much is in Plasma?
= 2.42 L x 0.1 mg/L= 0.242 mg
How much is in the body?Amount in body =
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Plasma sample measures 100 ng/mL.
(b) What percent of CsA in the body is located in whole plasma in this patient?Plasma Volume = 2.42 LHow much is in Plasma?
= 2.42 L x 0.1 mg/L= 0.242 mg
How much is in the body?Amount in body = 0.1 mg/L x 6000L
= 600 mg (dose)Proportion in Plasma ?
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Cyclosporin (CsA), 600 mg isadministered to a female transplantpatient – MJ, who weighs 55 kg, by IV bolus. Plasma sample measures 100 ng/mL.
(a) What percent of CsA in the body is located in plasma in this patient?
How much is in Plasma?= 0.242 mg
How much is in the body?= 600 mg (dose)
Proportion in plasma ?= 0.242 mg / 600 mg= 0.000403= 0.0403%
Equations
Conc = Dose / V
V = Dose/Conc
A Fifth Example - cyclosporin
Comparison Blood : Plasma
Concentration (ng/mL) 200100
Tissue Volume (L) 4.42.42
Amount in Tissue (mg) 0.88 0.242App Vol. Dist. (L) 3,000
6,000Dose (mg) 600 600Percent in blood/plasma (%) 0.15 0.04
A Fifth Example - cyclosporin
Does the difference in apparent volumes imply anything about where cyclosporin distributes to?
If you are told*(published knowledge) that a particular concentration must be achieved
in this patient; e.g. 400 ng/mL in whole blood …What volume of distribution would you use?
What is your recommended dose?
~ 0.88 mg
Comparison Blood : Plasma
Concentration (ng/mL) 200100
Tissue Volume (L) 4.42.42
Amount in Tissue (mg) 0.88 0.242App Vol. Dist. (L) 3,000
6,000Dose (mg) 600 600Percent in blood/plasma (%) 0.15 0.04
A Fifth Example - cyclosporin
Does the difference in apparent volumes imply anything about where cyclosporin distributes to?
If you are told*(published knowledge: ~ MIC, ED
, therap range)
that a particular concentration must be achieved in this patient; e.g. 400 ng/mL in whole blood …
What volume of distribution would you use? (VolBLOOD)
What is your recommended dose? (1.2 gm)
~ 0.88 mg
50
General Principles of Distribution
Summary1. The calculated apparent Volume depends
on the fluid being sampled.
2. Drugs can go anywhere (phys.-chem. prop.) leaving extra-cellular water to distribute into bone, fat or … anywhere, any tissue.
3. The apparent Volume depends on the host, and the physical/chemical properties of the drug or metabolite.
4. The calculated apparent Volume rarely reflects a real physiologic volume.
5. The minimum volume* of distribution is vascular volume (8% IBW: 6’ ♂ = 6.4L).
6. There is no maximum volume*.6