Discussion- Torsion of Rolled Steel Sections in Building Structures
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Transcript of Discussion- Torsion of Rolled Steel Sections in Building Structures
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8/13/2019 Discussion- Torsion of Rolled Steel Sections in Building Structures
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i s c u s s i o n
91
Torsion o f Rol led Stee l S ect ions inBui ld ing S t ruc turesPaper presented by JO HN G. HOTCH KISS (January , 1966, Issue)
Discussion by J O H N C B U R T O NI S HOULD LI KE to suggest a very careful dimensionalanalysis of E x a m p l e 4 on p a g e 30 for I feel such ananalysis may rev ea l an e r r o r of the m a g n i t u d e of 10 int h e ca l cu l a t i o n s .Discussion by J O H N G H O T C H K I S SW E A P PR E C I A TE y o u r ca l l i n g a t t en t i o n to E x a m p l e 4.Th e e r ro r i n v o lv ed the in co r rec t so lu t io n for the m a x i m u m w a r p i n g m o m e n t at m i d s p a n as d e t e r m i n e d f r omJohn C. Burton is Associate Civil E ngineer, San Diego Gas Electric
Company, San Diego, Calif.John G. Hotchkiss is Senior Regional E ngineer, A merican Institute of
Steel Construction, New York, N. Y.
A P R I L / 1 9 6 6
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8/13/2019 Discussion- Torsion of Rolled Steel Sections in Building Structures
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w = 2 k / f t
ftl
ro102 J 2
A-k.T2 12
11 600 psi1
1 ^
4 3 , 2 0 0 psi
- l l , 6 0 0 p s i 43 ,200ps i
Figures 17 and 18 {corrected)
T a b l e 2 . T h e c o r r e c t e q u a t i o n a p p e a r i n g i n T a b l e 2 ,D2ml2S h o r t M e t h o d , p a g e 4 1 , s h o u l d r e a d , m a x Mw = — - —h
( l b - in . ) . Th e t e rm h was o m i t t e d i n t h e o r ig in a l a r tw o rk .A t y p o g r a p h i c e r r o r i n t h e N o m e n c l a t u r e o n p a g e 3 1
should also be no ted . The def in i t ion of m sh o u ld r eadU n i fo rm ly d i s t r i b u t ed t o r s io n a l l o ad ( l b - in . / i n . o r
l b - f t / f t ) '5 .E x a m p l e 4 r e v i s e d )Given: A b e a m b u i l t - u p b y w e l d i n g t h r e e p l a te s r e s e m
bl ing an I -sect ion i s loa ded wi th a un i form ly d ist r ib u te d tors ional m om en t m = 1 ,000 lb-f t / f t over theen t i r e sp an o f 4 6 f t. Th e en d co n n ec t io n s a re as su m e dto b e b o l t ed web c l i p an g l es , Ty p e 2 co n s t ru c t i o n .De te rm in e i f t h e ad d i t i v e t o r s io n a l n o rm al s t res ses a rew i t h i n p e r m i s si b l e l i m it s b y t h e Q u i c k M e t h o d a n dch eck r esu l t s b y t h e Ex ac t m eth o d , e = 6 in . , w =2,000 lb / f t , see Fig . 17 .)
Solution:m = (2 ,0 0 0 X 6 ) /1 2
m o m en t , s ee F ig . 5 )1 ,000 lb- in . / in . (posi t ive
Dete rm in e t h e t o r s io n a l co n s t an t s an d p ro p er t i e sf ro m Ch ar t 1 :Cw = -b*m = — 123 X 5 3 . 52 X 0 . 5 024 24
= 103 ,000 in . 62 1K = -bfi + -hh*
J
= - X 1 2 X 0 . 5 0 3 + - X 53 X 0 .5 03= 3 .2 1 i n .4
bh 1 2 X 5 3 . 5 2W m « = — = = 1 6 0 , 5 m /4 4X = 0 . 6 2 \ — = 0 . 6 2 ^ - ^ ^ = 0 . 0 0 3 4 1 i n . - 1*C W ^ 1 0 3 , 0 0 0
\l = 0 .0 0 3 4 1 X 552 = 1 .8 8Cw 103 ,000ow = 642 in .4W max 1 6 0 . 5
D e t e r m i n e t h e m o m e n t o f i n e r t i a Iy/2 :S in ce Sw = a n d Cw —
ly U a , X Z^nth en - = ;—2 h2/26 4 2 X 1 6 0 . 5
5 3 . 5 2 / 2 72 in.4
D e t e r m i n e m a x i m u m w a r p i n g m o m e n t a t m i d s p a nf r o m T a b l e 2 , S h o r t M e t h o d . ( N o t e t h e m o m e n t Mwas u sed i n Tab le 2 is expressed in lb - in . an d shou ld n otbe confused wi th Mw th e b im o m en t ex p ressed as l b -in .2 u sed e l sewh ere i n t h i s p ap er . ) S in ce \l = 1 .88 , al i n e a r i n t e r p o l a t i o n b e t w e e n \l = 1 .5 an d 2 .0 g iv esD2 = 0 . 0 9 1 1 .
D 2ml2 0 .0 91 1 X 1 ,000 X 5522T h e n m a x Mw — 5 3 . 5
m a x aw= 518 ,000 lb- in .
M w 518 ,000 X 6
= 43 ,200 psi (where a = b/2)
D e t e r m i n e m a x i m u m m o m e n t d u e to p l a n e b e n d i n g a tm i d s p a n :m a x Mb = wP 2 ,000 X 46
2- 529 ,000 lb-ft
M b 529 ,000 X 12m a x ab = — — —— = 11 ,600 psiSx 547C o m b i n e d n o r m a l s t r e s s e s : m a x aw + m a x