Discrete Random Variables 3 To be able to calculate the expected value and variance of a discrete...
-
Upload
nicole-mccarthy -
Category
Documents
-
view
214 -
download
0
Transcript of Discrete Random Variables 3 To be able to calculate the expected value and variance of a discrete...
Discrete Random Variables 3
•To be able to calculate the expected value and variance of a discrete random variable•To investigate the effect of multipliers and constants on the expected value and the variance of a discrete random variable•To be able to calculate the expected value and variance of distributions like y=aX+b
Expected value and variance formulae
E(X) = ΣxP(X=x) = Σxp(x)
E(X²) = Σx²p(x)E(Xn) = Σxnp(x)
Var(X) = E(X²) – (E(X))²
Variance Var(X) = E(X²) – (E(X))²Example2 four sided die numbered 1,2,3,4 are spun and their faces are
added (X).a) Find the probability distribution of Xb) Find E(M)c) Find Var(M)
a) + 1 2 3 4
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
x 2 3 4 5 6 7 8
p(x) 1/162/16
3/164/16
3/162/16
1/16
Variance Var(X) = E(X²) – (E(X))²
b) Find E(M)
x 2 3 4 5 6 7 8
p(x) 1/162/16
3/164/16
3/162/16
1/16
E(M) = Σxp(x)= 2/16 +
6/16 + 12/16 +
20/16 + 18/16 +
14/16 + 8/16
= 80/16 = 5
Var(X) = E(X²) – (E(X))²=(4/16 +18/16 +
48/16 + 100/16 +
108/16 + 98/16 +
64/16)-25= 440/16 – 25 = 2.5
The random variable X has probability functionP(X = x) = kx, x = 1,2,3 k(x+1) x = 4,5 where k is a constant.
(a) Find the value of k. (2) (b) Find the exact value of E(X). (2)(c) Show that, to 3 significant figures, Var(X) = 1.47. (4) (d) Find, to 1 decimal place, Var(4 – 3X). (2) (Total 10 marks)
Effect of multipliers and variance
Effect of multiplier and constant on E(X) and Var(X)
E(X)= 3 and Var(X)=5
a)Calculate E(2X) b)Calculate E(X+6)c) Find Var(3X)d)Find E(4X-1)e)Find Var(4X-1)f) Find Var(2-3X)
Effect of multiplier and constant on E(X) and Var(X)E(X)= 3 and Var(X)=5
a) E(2X) = 2E(X) = 2 x 3 = 6
b) E(X+6) = E(X)+6 = 3+6 = 9
c) Var(3X) = 3²Var(X) = 9x5 = 45
d) E(4X-1) = 4E(X)-1 = 4x3-1 = 11
e) Var(4X-1) = 4²Var(X) = 16x5 = 80
f) Var(2-3X) = -3²Var(X) = 9x5 = 45