Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin....

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Direct and Inverse Variation Algebra I

Transcript of Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin....

Page 1: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Direct and Inverse Variation

Algebra I

Page 2: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Direct Variation

• When the line passes through the origin.

• When y increases, x increases.• Equation: y = kx, where k 0.• Constant of variation – k• Say “ y varies directly with x”

Page 3: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Identifying the constant of variation

y = 6x

6 is the constant of variation (k)

These can be graphed on the calculator using ‘y=‘ button, to see what the graph should look like.

Page 4: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Examples:

y = 28, x = 7 find x when y = 52

Page 5: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Examples:

y = 28, x = 7 find x when y = 52

y = kx y = kx

Page 6: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Examples:

y = 28, x = 7 find x when y = 52

y = kx y = kx28 = k(7) 52 = 4x 7 7 4 44 = k 13 = x y = 4x

Page 7: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Example:

y = 27, x = 6 find x when y = 45

Page 8: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Example:

y = 27, x = 6 find x when y = 45

27 = k(6) 45 = 9/2x 6 6 (2/9)45 = x9/2 = k 10 = x

Y = 9/2x

Page 9: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Example:

y = -7, x = -14 find y when x = 20

Page 10: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Example:

y = -7, x = -14 find y when x = 20

-7 = k(-14) y = (½)20-14 -14 y = 10½ = k

y = ½x

Page 11: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Inverse (Indirect) Variation

• Line going away from the origin.• When one value (x or y) increases, the

other value (x or y) decreases.• Equation xy = k • Say “y varies inversely as x” or “y is

inversely proportional to x”.

Page 12: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Different forms of the equation

xy = k

Y = k/x or x = k/y

Page 13: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Example:

If y = 12 when x = 5, find y when x = 3

xy = k 3y = 60(5)(12) = k 3 3 60 = k y = 20

xy = 60

Page 14: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Example:

If y = 7, when x = -2; find y when x = 7

If y = 8.5, when x = -1; find x when y = -1

If y = 8, when x = 1.55; find x when y = -0.62

Page 15: Direct and Inverse Variation Algebra I. Direct Variation When the line passes through the origin. When y increases, x increases. Equation: y = kx, where.

Example:

If y = 7, when x = -2; find y when x = 7 xy = -14 y = -2

If y = 8.5, when x = -1; find x when y = -1 xy = -8.5 x = 8.5

If y = 8, when x = 1.55; find x when y = -0.62 xy = 12.4 x = -20