Different signs; product is negative. Same signs; product is positive. Multiply 2 and – 5....
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Different signs; product is negative. Same signs; product is positive. Multiply 2 and – 5. Different signs; product is negative. Find the product. EXAMPLE 1 Multiply real numbers a. – 3 (6) b. 2 (–5) (–4) = 40 . – (–4) (–3) 1 2 Multiply – and – 4 1 2 = – 6 = – 18 = 2 (– 3) (–10) (–4) =
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Transcript of Different signs; product is negative. Same signs; product is positive. Multiply 2 and – 5....
Different signs; product isnegative.
Same signs; product ispositive.
Multiply 2 and – 5.
Different signs; product isnegative.
Find the product.
EXAMPLE 1 Multiply real numbers
a. – 3 (6)
b. 2 (–5) (–4)
= 40
c. – (–4) (–3)12
Multiply – and – 412
= – 6
= – 18
= 2 (– 3)
(–10) (–4)=
GUIDED PRACTICE for Example 1
Find the product.
1. – 2 (– 7) = 14
2. – 0.5 (– 4) (– 9) = – 18
3. (–3) (7)43
= – 28
Multiplicative property of – 1 Identity property of multiplication
Commutative property ofmultiplication
Associative property of multiplicationMultiplicative property of zero
Property illustratedStatement
EXAMPLE 2 Identify properties of multiplication
x (7 0.5)a. (x 7) 0.5 =
b. 8 0 = 0
c. – 6 y =
y (– 6)
d. 9 (– 1) =– 9
e. 1 v =v
GUIDED PRACTICE for Example 2
Identify the property illustrated.
Multiplicative property of – 1 Commutative property ofmultiplication
Associative property of multiplicationMultiplicative property of zero
Commutative property ofmultiplication
Multiplicative property of – 1
4. –1 8 = – 8
12 x =
x 125.
y (4 9) (y 4) 9 =6.
7. 0 (– 41) = 0
8. – 5 (– 6) = – 6 (– 5)
9. –13 (– 1) – 8=
Multiplicative property of –1.
Product of 0.25 and –4 is –1.
Associative property ofmultiplication
Commutative property of multiplication
EXAMPLE 3 Identify properties of multiplication
Find the product (–4x) 0.25. Justify your steps.
= –x
0.25 (–4x)(–4x) 0.25 =
= (0.25 (–4))x
= –1 x
Lakes
EXAMPLE 4 Solve a multi-step problem
In 1900 the elevation of Mono Lake in California was about 6416 feet. From 1900 to 1950, the average rate of change in elevation was about – 0.12 foot per year.From 1950 to 2000, the average rate of change was about – 0.526 foot per year. Approximate the elevation in 2000.
Substitute values.
EXAMPLE 4 Solve a multi-step problem
SOLUTION
STEP 1
STEP 2
= 6416 + (–6) Multiply –0.12and 50.
New elevation =
Calculate the elevation in 1950. Use the elevation in 1900 as the original elevation. The time span 1950 – 1900 = 50 years.
6416 +(–0.12)(50)
Write a verbal model.
= 6410 Add 6416 and –6.
New elevation
(feet)
Original elevation
(feet)
Average rate of change (feet/year)
Time passed (years)
= + •
New elevation =
= 6383.7
Multiply –0.526and 50.
Substitute values.
EXAMPLE 4 Solve a multi-step problem
STEP 3
= 6410 + (–26.3)
Add 6410 and –26.3.
Calculate the elevation in 2000. Use the elevation in 1950 as the original elevation. The time span 2000 – 1950 = 50 years.
6410 +(– 0.526)(50)
EXAMPLE 4 Solve a multi-step problem
ANSWER
The elevation in 2000 was about 6383.7 feet above sea level.
GUIDED PRACTICE for Example 3 and 4
Find the product. Justify your steps.
310
10. (5y) = ( 5)y 3
10Associative property ofmultiplication
3
2= y Product of and 5 is .
310
3 2
3
2= y Multiplicative property of .
3 2
GUIDED PRACTICE for Example 3 and 4
0.8 (–x) (–1)11. 0.8 (–1) (–x)=
Multiplicative property of –1
Commutative property of multiplication
= 0.8x Multiply
= – 0.8 (–x)
GUIDED PRACTICE for Example 3 and 4
Product of –0.5 and –6is 3.
= –3y Commutative property of multiplication
12. (–y)(–0.5)(–6) = (–y)(3)
GUIDED PRACTICE for Example 3 and 4
Using the data in Example 4, approximate the elevation of Mono Lake in 1925 and in 1965.
13.
ANSWER
about 6413 ft; about 6402.11 ft
