Design Sheet for Innoculum
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Transcript of Design Sheet for Innoculum
1 DESIGN PROPERTIES CSM WRM Units
a Ultimate Tensile unit strength U 200.00 250.00 N/mm per Kg/m2
glass mat
(p 10, BS4994-87)
b Ultimate Tensile Strength S 89.29 200.00 N/mm2
S = U/Tg
c Unit Modulus X 14000.00 16000.00 N/mm per Kg/m2
glass mat
(p 10, BS4994-87)
d Unit modulus of 1 mat X1 6300.00 9760.00 N/mm per Kg/m2
glass mat
e Modulus of Elasticity E 6250.00 12800.00 N/mm for (1 mat as specified at 9b)
E=X/Tg
f Fiber content {wt %} Fc 33.00 45.00 %
(ref p 20, Figure 5 BS4994-87)
g Resin to glass ratio r 2.03 1.22 No Unit
h Layer Thickness Constant TG 2.24 1.25 mm per Kg/m2 glass mat
i Inter Laminar Lap Shear Strength Tou 7.00 6.00 N/mm
j In Plane Poisson's Ratio IPPR 0.30 0.30
k Single mat thickness T-1 1.01 0.76 mm (for 1 mat as specified at 9b)
2 CALCULATION OF SAFETY FACTOR
a Factor for Method of Manufacturing = Hand Lay-Up
K1 = 1.50
b Factor for Strength Loss = yes
Strength Loss = N/A
K2 = 1.30 SINCE TP LINING
c Factor for Design Temperature
[1.25-.0125(HDT-20-Dt)] HDT = 100 Degree Cel.
DT = 100 Degree Cel.
K3 = 1.00
d Factor For Cyclic Loading
Number Of Cycles in life time = 3650
[1.1+.9(log N-3)/3] K4 = 1.27
e Factor for Curing Temperature
Post Curing = not post cured
Post Cure TEMPERATURE = - [Degree Cel.]
K5 = 1.50
= 11.14
f Over all Safety Factor K-cal = 11.14425 K
3 CALCULATIONS FOR ALLOWABLE DESIGN LOADS
CSM WRM
a LOAD LIMITED UNIT LOAD Ul = 17.95 22.43 N/mm per Kg/m2 Reinforcement
[=U/K]
b DESIGN STRAIN
b1 Max allowable resin-strain e-res = 0.200 %
[min of 0.1*e-r and 0.2]
b2 Resin strain limited unit load Urs = 28.00 32.00 N/mm per Kg/m2 Reinforcement
b3 Allowable reinforcement strain e-rein = 0.128 0.140
[(Ul/X)*100]
b4 Design Strain (reinforcement limited) e-d,rein = 0.128 %
[minimum of e-l's of csm and wrm]
b5 Over all design strain e-d = 0.128 %
[min of all strains]
c STRAIN LIMITED LOADS
c1 CSM-Strain limited unit load Us = 17.95 20.51 N/mm per Kg/m2 Reinforcement
[=X*e-d/100]
d DESIGN UNIT LOADS
d1 Design Unit Load Ud = 17.95 20.51 N/mm per Kg/m2 Reinforcement
[Minimum among Ul and Us]
e Allowed Unit load per current mat Ud-1 = 8.076 12.511 N/mm (for mats specified at 9b)
CALCULATION OF THICKNESS
Dimension of biggest panel a = 500 b/a = 13.04
b = 6520
Moment due to liquid head
Mp = 0.67β1pa2
β1 = 0.124
= 152.8153
Mass of reinforcment required
mcsm = (6*Mp/Ucsm*tg)0.5
= 4.775792
no of layer required for above mass requirementNo. of layer N = 10.61287
= 11
thickness t = 10.89
Thickness to prevent deflection
tmin = (α1pa4/Elam)
0.25α1 = 0.058
= 8.082386
Since t>tmin hence safe
CALCULATION FOR BOTTOM
Dimension of biggest panel a = 950 b/a = 8.863158
b = 8420
Moment due to liquid head
Mp = β1pa2
β1 = 0.125
= 830.018
Mass of reinforcment required
mcsm = (6*Mp/Ucsm*tg)0.5
= 11.13027
no of layer required for above mass requirementNo. of layer N = 24.73394
= 25
thickness t = 22.5
Thickness to prevent deflection
tmin = (α1pa4/Elam)
0.25α1 = 0.142
= 10.11008
Since t>tmin hence safe
CALCULATION OF THICKNESS
Dimension of biggest panel a = 500 b/a = 4.6
b = 2300
Moment due to liquid head
Mp = 0.67β1pa2
β1 = 0.124
= 152.8153
Mass of reinforcment required
mcsm = (6*Mp/Ucsm*tg)0.5
= 4.775792
no of layer required for above mass requirementNo. of layer N = 10.61287
= 11
thickness t = 9.9
Thickness to prevent deflection
tmin = (α1pa4/Elam)
0.25α1 = 0.058
= 8.082386
Since t>tmin hence safe
CALCULATION FOR BOTTOM
Dimension of biggest panel a = 430 b/a = 9.069767
b = 3900
Moment due to liquid head
Mp = β1pa2
β1 = 0.125
= 114.4069
Mass of reinforcment required
mcsm = (6*Mp/Ucsm*tg)0.5
= 4.132264
no of layer required for above mass requirementNo. of layer N = 9.18281
= 10
thickness t = 9
Thickness to prevent deflection
tmin = (α1pa4/Elam)
0.25α1 = 0.0284
= 6.761019
Since t>tmin hence safe
CALCULATION OF THICKNESS
Dimension of biggest panel a = 500 b/a = 3.8
b = 1900
Moment due to liquid head
Mp = 0.67β1pa2
β1 = 0.124
= 152.8153
Mass of reinforcment required
mcsm = (6*Mp/Ucsm*tg)0.5
= 4.775792
no of layer required for above mass requirementNo. of layer N = 10.61287
= 11
thickness t = 9.9
Thickness to prevent deflection
tmin = (α1pa4/Elam)
0.25α1 = 0.058
= 8.082386
Since t>tmin hence safe
CALCULATION FOR BOTTOM
Dimension of biggest panel a = 380 b/a = 5
b = 1900
Moment due to liquid head
Mp = β1pa2
β1 = 0.125
= 89.3475
Mass of reinforcment required
mcsm = (6*Mp/Ucsm*tg)0.5
= 3.651769
no of layer required for above mass requirementNo. of layer N = 8.115041
= 9
thickness t = 8.1
Thickness to prevent deflection
tmin = (α1pa4/Elam)
0.25α1 = 0.0284
= 6.761019
Since t>tmin hence safe