Design GP Building for Pop.above 5000

34
DESIGN OF STRUCTURE Construction of GP Building with population above 5000

description

Design of RCC building for grampanchayats

Transcript of Design GP Building for Pop.above 5000

Page 1: Design GP Building for Pop.above 5000

DESIGN OF STRUCTURE

Construction of GP Building with population above 5000

Page 2: Design GP Building for Pop.above 5000

Design Parametres:-

Unit weight of RCC = 25KN/cum

Concrete mix : M25

Steel : Fe415

Cover to Reinforcement : 25mm

Characteristic compressive strength of concrete = 25N/sqmm

Yield strength of steel = 415N/sqmm

Item

S1(End Panel)--Two

adjacent edges

discontinuous

S2(End Panel)--

Two adjacent

edges

discontinuous

S3(End Panel)-

-Two adjacent

edges

discontinuous

S4(End

Panel)--one

short edge

discontinuou

s

S5(Portico

slab)--Three

edges

discontinuou

s

Length of slab panel ly in m 3.51 3.51 5.64 3.51 2.06

Width of slab panel lx in m 3.51 2.93 2.93 2.13 1.83

ly/lx 1 1.2 1.92 1.65 1.13

Overall depth required in mm 110 92 92 67 57

Width of slab panel considered 'b' in

'm'

1.00 1.00 1.00 1.00 1.00

Depth provided 'D' in 'm' 0.115 0.115 0.115 0.115 0.1

Dia.of bars assumed 8mm 8mm 8mm 8mm 8mm

Dead load in KN/sqm 4.00 4.00 4.00 4.00 3.50

Live load in KN/sqm 2.50 2.50 2.50 2.50 2.50

Floor finishes in KN/sqm 1.00 1.00 1.00 1.00 1.00

Total Load in KN/sqm 7.50 7.50 7.50 7.50 7.00

Short span(-) moment coefficient at

continuous edge

0.047 0.060 0.089 0.089 0.067

Short span(-) moment at continuous

edge

4.34 3.86 5.73 3.03 1.57

Short span(+) moment coefficient at

mid span

0.035 0.045 0.067 0.067 0.050

Short span(+) moment at mid span 3.23 2.90 4.31 2.28 1.17

Long span(-) moment coefficient at

continuous edge

0.047 0.047 0.047 0.047 0.057

Long span(-) moment at continuous

edge

4.34 3.02 3.02 1.60 1.34

Long span(+) moment coefficient at

mid span

0.035 0.035 0.035 0.035 0.043

Long span(+) moment at mid span 3.23 2.25 2.25 1.19 1.01

Design Moment Me1(-)ve in KN-m 6.51 5.79 8.59 4.54 2.36

Effective depth for balanced section

in 'mm'

48.57 45.81 55.79 40.56 29.22

Effective depth provided 'd' in 'mm' 86 86 86 86 71

Actual depth of neutral axis 'xu' in

'mm'

8.79 7.78 11.78 6.04 3.77

Maximum depth of neutral axis 'xumax'

in 'mm'

41.28 41.28 41.28 41.28 34.08

Area of steel required Ast in 'mm2' 219.06 193.87 293.53 150.64 94

Main Steel provided at continuous

edge

8mm@150mm c/c 8mm@150mm c/c 8mm@150m

m c/c

8mm@150m

m c/c

8mm@200m

m c/c

Area of steel provided in mm2 334.93 334.93 334.93 334.93 251.2

Design Moment Me1(+)ve in KN-m 4.85 4.34 6.47 3.42 1.76

Effective depth for balanced section

in 'mm'

41.91 39.67 48.4 35.19 25.24

Actual depth of neutral axis 'xu' in

'mm'

6.47 5.77 8.73 4.51 2.8

DESIGN OF TWO WAY SLAB:-

Slab panel Description

Page 3: Design GP Building for Pop.above 5000

Maximum depth of neutral axis 'xumax'

in 'mm'

41.28 41.28 41.28 41.28 34.08

Area of steel required Ast in 'mm2' 161.22 143.93 217.54 112.54 69.74

Main Steel provided at mid span 8mm@150mm c/c 8mm@150mm c/c 8mm@150m

m c/c

8mm@150m

m c/c

8mm@200m

m c/c

Area of steel provided in mm2 334.93 334.93 334.93 334.93 251.2

Design Moment Me1(-)ve in KN-

m(Long span)

6.51 4.54 4.54 2.40 2.00

Effective depth for balanced section

in 'mm'

48.57 40.54 40.54 29.47 26.95

Actual depth of neutral axis 'xu' in

'mm'

8.79 6.04 6.04 3.15 3.2

Maximum depth of neutral axis 'xumax'

in 'mm'

41.28 41.28 41.28 41.28 34.08

Area of steel required Ast in 'mm2' 219.06 150.53 150.53 78.41 79.7

Dist. Steel provided at continuous

edge

8mm@175mm c/c 8mm@175mm c/c 8mm@175m

m c/c

8mm@175m

m c/c

8mm@200m

m c/c

Area of steel provided in mm2 287.09 287.09 287.09 287.09 251.2

Dist.steel at mid span 8mm@175mm c/c 8mm@175mm c/c 8mm@175m

m c/c

8mm@175m

m c/c

8mm@200m

m c/c

Page 4: Design GP Building for Pop.above 5000

Design Parametres:-

Concrete mix : M25

Steel : Fe415

Cover to Reinforcement : 40mm

Characteristic compressive strength of concrete = 25N/sqmm

Yield strength of steel = 415N/sqmm

Item

Piles--

P1(6,7,13,14)

Piles--

P2(2,3,5,8,9,10,11)

Piles--

P3(1,4,12,15)

Max.Load 'P' in KN 480 395.7 264.3

Dia.of pile proposed in 'mm' 450 375 300

No.of Under Reams proposed 2 2 2

Dia.of under reamed in 'm' 1.125 0.94 0.75

Depth of the pile proposed in 'm' 4.50 3.75 3.50

Bearing capacity of the pile in KN 617.4 396.9 264.6

Main Reinforcement 7-12mm 5-12mm 4-12mm

Stirrups 8mm@300 c/c 8mm@300 c/c 8mm@300 c/c

(Note:-The above design is as per clauses 6.3, 6.3.1, 6.6 and 8.3.2.2 of IS 2911(PartIII)-1973 duly

reducing bearing resistence by 25% for submerged condition)

DESIGN OF PILES

Page 5: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F3

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 147.00KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.45m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 493.00KN

493.00KN

Add self weight of the footing&Weight 73.950KN

of back fill (15%)

Total Load = 566.95KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 220.50KN/sqm

Size of the footing required:-

Area of the footing required = 2.57Sqm

Provide square footing of size 1.80mx1.80m,the area comes to 3.24Sqm

Width = 1.80m

Depth = 1.80m

The net ultimate bearing pressure acting on the footing due to direct load = 174.98KN/sqm

Design moment = 5.10KN-m

Section Modulus for the above section = (1/6)xbd2 = 0.97cum

Soil pressure due to moment = M/Z = 5.26KN/sqm

Max.Soil pressure = pu + mu = 180.24KN/sqm <220.50KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 169.72KN/sqm >0

Hence O.K

Hence,the design soil pressure = 180.24KN/sqm

Depth of the footing required:-

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = Mu = 55.53KN-m

(Considering 1m width of footing)

DESIGN OF FOOTINGS(1,4,9,12)

Page 6: Design GP Building for Pop.above 5000

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 126.87mm

Over all depth required assuming 12mm dia bars = = 182.87mm

However assume 350mm overall depth,then the effective depth comes to 294.00mm

The actual depth of neutral axis = 21.66mm

Area of steel required = 539.84sqmm

Assuming 12mm dia bars,the spacing comes to 209mm

Provide 12mm bars at a spacing of 175mm

Then the area of reinforcement provided = 645.94Sqm

Percentage of reinforcement provided = 0.22

ii)One way shear criteria:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 88.50KN

Nominal shear stress Tv = 0.301N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.220%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.339 N/sqmm Hence Vuc = 99.67KN

0.339 >0.301

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 2536mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 513.70KN

Nominal shear stress Tv = VFd/b0d = 0.69 N/sqmm

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

Page 7: Design GP Building for Pop.above 5000

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.690

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 566.95KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 1164.38KN >566.95KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 8: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F2

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 147.00KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.23m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 408.25KN

408.25KN

Add self weight of the footing&Weight 61.238KN

of back fill (15%)

Total Load = 469.49KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 220.50KN/sqm

Size of the footing required:-

Area of the footing required = 2.13Sqm

Provide rectangular footing of size 1.65mx1.80m,the area comes to 2.97Sqm

Width = 1.65m

Depth = 1.80m

The net ultimate bearing pressure acting on the footing due to direct load = 158.08KN/sqm

Design moment = 3.00KN-m

Section Modulus for the above section = (1/6)xbd2 = 0.89cum

Soil pressure due to moment = M/Z = 3.37KN/sqm

Max.Soil pressure = pu + mu = 161.45KN/sqm <220.50KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 154.71KN/sqm >0

Hence O.K

Hence,the design soil pressure = 161.45KN/sqm

The maximum bending moment at the face of the column wrt the section along width ML = 49.75KN-m

(Considering 1m width of footing)

The maximum bending moment at the face of the column wrt the section along length MB = 40.69KN-m

(Considering 1m width of footing)

Depth of the footing required:-

DESIGN OF RECTANGULAR FOOTINGS(7,8,9,10,11,13,14)

Page 9: Design GP Building for Pop.above 5000

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = ML = 49.75KN-m

(Considering 1m width of footing)

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 120.08mm

Over all depth required assuming 16mm dia bars = = 178.08mm

However assume 300mm overall depth,then the effective depth comes to 242.00mm

Longitudinal direction:-

Calculation of reinforcement :-

The actual depth of neutral axis = 23.83mm

Area of steel required = 593.96sqmm

Assuming 12mm dia bars,the spacing comes to 190mm

Provide 12mm bars at a spacing of 175mm along width

Then the area of reinforcement provided = 645.94Sqm

Percentage of reinforcement provided = 0.267

Check for one way shear:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 87.67KN

Nominal shear stress Tv = 0.362N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.267%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.369 N/sqmm Hence Vuc = 89.30KN

0.369 >0.362

Hence,no shear reinforcement is required.

Transverse direction:-

Maximum factored bending moment = MB = 40.69KN-m

(Considering 1m width of footing)

Page 10: Design GP Building for Pop.above 5000

Over all depth provided = 300.00mm

Effective depth assuming 10mm dia bars 245.00mm

Calculation of reinforcement :-

The actual depth of neutral axis = 19.08mm

Area of steel required = 475.55sqmm

Reinforcement in central band = 0.96

Total reinforcement

Reinforcement to be provided in central band = 454.87sqmm

Reinforcement to be provided in each edge band = 10.34sqmm

However provide 10mm dia bars at a spacing of 150mm along length

Then the area of reinforcement provided = 523.33Sqm

Percentage of reinforcement provided = 0.214

Check for one way shear:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 75.07KN

Nominal shear stress Tv = 0.306N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.214%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.335 N/sqmm Hence Vuc = 82.08KN

0.335 >0.306

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 1888mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 443.54KN

Nominal shear stress Tv = VFd/b0d = 0.97 N/sqmm

Page 11: Design GP Building for Pop.above 5000

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.970

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 469.49KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 595.13KN >469.49KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 12: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F1

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 147.00KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.23m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 283.50KN

283.50KN

Add self weight of the footing&Weight 42.525KN

of back fill (15%)

Total Load = 326.03KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 220.50KN/sqm

Size of the footing required:-

Area of the footing required = 1.48Sqm

Provide square footing of size 1.40mx1.40m,the area comes to 1.96Sqm

Width = 1.40m

Depth = 1.40m

The net ultimate bearing pressure acting on the footing due to direct load = 166.34KN/sqm

Design moment = 4.05KN-m

Section Modulus for the above section = (1/6)xbd2 = 0.46cum

Soil pressure due to moment = M/Z = 8.80KN/sqm

Max.Soil pressure = pu + mu = 175.14KN/sqm <220.50KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 157.54KN/sqm >0

Hence O.K

Hence,the design soil pressure = 175.14KN/sqm

Depth of the footing required:-

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = Mu = 29.97KN-m

(Considering 1m width of footing)

DESIGN OF FOOTINGS(1,2,3,4,5,12,15)

Page 13: Design GP Building for Pop.above 5000

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 93.20mm

Over all depth required assuming 12mm dia bars = = 149.20mm

However assume 250mm overall depth,then the effective depth comes to 194.00mm

The actual depth of neutral axis = 17.86mm

Area of steel required = 445.09sqmm

Assuming 12mm dia bars,the spacing comes to 254mm

Provide 12mm bars at a spacing of 200mm

Then the area of reinforcement provided = 565.20Sqm

Percentage of reinforcement provided = 0.291

ii)One way shear criteria:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 68.48KN

Nominal shear stress Tv = 0.353N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.291%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.381 N/sqmm Hence Vuc = 73.91KN

0.381 >0.353

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 1696mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 311.80KN

Nominal shear stress Tv = VFd/b0d = 0.95 N/sqmm

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

Page 14: Design GP Building for Pop.above 5000

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.950

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 326.03KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 595.13KN >326.03KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 15: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F3

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 98.00KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.45m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 493.00KN

493.00KN

Add self weight of the footing&Weight 73.950KN

of back fill (15%)

Total Load = 566.95KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 147.00KN/sqm

Size of the footing required:-

Area of the footing required = 3.86Sqm

Provide square footing of size 2.10mx2.10m,the area comes to 4.41Sqm

Width = 2.10m

Depth = 2.10m

The net ultimate bearing pressure acting on the footing due to direct load = 128.56KN/sqm

Design moment = 5.10KN-m

Section Modulus for the above section = (1/6)xbd2 = 1.54cum

Soil pressure due to moment = M/Z = 3.31KN/sqm

Max.Soil pressure = pu + mu = 131.87KN/sqm <147.00KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 125.25KN/sqm >0

Hence O.K

Hence,the design soil pressure = 131.87KN/sqm

Depth of the footing required:-

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = Mu = 57.64KN-m

(Considering 1m width of footing)

DESIGN OF FOOTINGS(1,4,9,12)

Page 16: Design GP Building for Pop.above 5000

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 129.26mm

Over all depth required assuming 12mm dia bars = = 185.26mm

However assume 350mm overall depth,then the effective depth comes to 294.00mm

The actual depth of neutral axis = 22.51mm

Area of steel required = 561.05sqmm

Assuming 12mm dia bars,the spacing comes to 201mm

Provide 12mm bars at a spacing of 175mm

Then the area of reinforcement provided = 645.94Sqm

Percentage of reinforcement provided = 0.22

ii)One way shear criteria:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 84.53KN

Nominal shear stress Tv = 0.288N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.220%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.339 N/sqmm Hence Vuc = 99.67KN

0.339 >0.288

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 2536mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 530.14KN

Nominal shear stress Tv = VFd/b0d = 0.71 N/sqmm

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

Page 17: Design GP Building for Pop.above 5000

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.710

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 566.95KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 1164.38KN >566.95KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 18: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F2

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 98.00KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.23m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 408.25KN

408.25KN

Add self weight of the footing&Weight 61.238KN

of back fill (15%)

Total Load = 469.49KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 147.00KN/sqm

Size of the footing required:-

Area of the footing required = 3.19Sqm

Provide rectangular footing of size 1.80mx2.10m,the area comes to 3.78Sqm

Width = 1.80m

Depth = 2.10m

The net ultimate bearing pressure acting on the footing due to direct load = 124.20KN/sqm

Design moment = 3.00KN-m

Section Modulus for the above section = (1/6)xbd2 = 1.32cum

Soil pressure due to moment = M/Z = 2.27KN/sqm

Max.Soil pressure = pu + mu = 126.47KN/sqm <147.00KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 121.93KN/sqm >0

Hence O.K

Hence,the design soil pressure = 126.47KN/sqm

The maximum bending moment at the face of the column wrt the section along width ML = 55.28KN-m

(Considering 1m width of footing)

The maximum bending moment at the face of the column wrt the section along length MB = 38.97KN-m

(Considering 1m width of footing)

Depth of the footing required:-

DESIGN OF RECTANGULAR FOOTINGS(7,8,9,10,11,13,14)

Page 19: Design GP Building for Pop.above 5000

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = ML = 55.28KN-m

(Considering 1m width of footing)

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 126.58mm

Over all depth required assuming 16mm dia bars = = 184.58mm

However assume 350mm overall depth,then the effective depth comes to 292.00mm

Longitudinal direction:-

Calculation of reinforcement :-

The actual depth of neutral axis = 21.71mm

Area of steel required = 541.25sqmm

Assuming 12mm dia bars,the spacing comes to 209mm

Provide 12mm bars at a spacing of 175mm along width

Then the area of reinforcement provided = 645.94Sqm

Percentage of reinforcement provided = 0.221

Check for one way shear:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 81.32KN

Nominal shear stress Tv = 0.278N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.221%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.340 N/sqmm Hence Vuc = 99.28KN

0.340 >0.278

Hence,no shear reinforcement is required.

Transverse direction:-

Maximum factored bending moment = MB = 38.97KN-m

(Considering 1m width of footing)

Page 20: Design GP Building for Pop.above 5000

Over all depth provided = 350.00mm

Effective depth assuming 10mm dia bars 295.00mm

Calculation of reinforcement :-

The actual depth of neutral axis = 15.00mm

Area of steel required = 373.87sqmm

Reinforcement in central band = 0.92

Total reinforcement

Reinforcement to be provided in central band = 345.11sqmm

Reinforcement to be provided in each edge band = 14.38sqmm

However provide 10mm dia bars at a spacing of 175mm along length

Then the area of reinforcement provided = 448.57Sqm

Percentage of reinforcement provided = 0.152

Check for one way shear:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 61.97KN

Nominal shear stress Tv = 0.210N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.152%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.282 N/sqmm Hence Vuc = 83.19KN

0.282 >0.210

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 2088mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 443.61KN

Nominal shear stress Tv = VFd/b0d = 0.73 N/sqmm

Page 21: Design GP Building for Pop.above 5000

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.730

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 469.49KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 595.13KN >469.49KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 22: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F1

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 98.00KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.23m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 283.50KN

283.50KN

Add self weight of the footing&Weight 42.525KN

of back fill (15%)

Total Load = 326.03KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 147.00KN/sqm

Size of the footing required:-

Area of the footing required = 2.22Sqm

Provide square footing of size 1.60mx1.60m,the area comes to 2.56Sqm

Width = 1.60m

Depth = 1.60m

The net ultimate bearing pressure acting on the footing due to direct load = 127.36KN/sqm

Design moment = 4.05KN-m

Section Modulus for the above section = (1/6)xbd2 = 0.68cum

Soil pressure due to moment = M/Z = 5.96KN/sqm

Max.Soil pressure = pu + mu = 133.32KN/sqm <147.00KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 121.40KN/sqm >0

Hence O.K

Hence,the design soil pressure = 133.32KN/sqm

Depth of the footing required:-

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = Mu = 31.28KN-m

(Considering 1m width of footing)

DESIGN OF FOOTINGS(1,2,3,4,5,12,15)

Page 23: Design GP Building for Pop.above 5000

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 95.22mm

Over all depth required assuming 12mm dia bars = = 151.22mm

However assume 300mm overall depth,then the effective depth comes to 244.00mm

The actual depth of neutral axis = 14.61mm

Area of steel required = 364.23sqmm

Assuming 12mm dia bars,the spacing comes to 310mm

Provide 12mm bars at a spacing of 200mm

Then the area of reinforcement provided = 565.20Sqm

Percentage of reinforcement provided = 0.232

ii)One way shear criteria:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 58.79KN

Nominal shear stress Tv = 0.241N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.232%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.347 N/sqmm Hence Vuc = 84.67KN

0.347 >0.241

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 1896mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 311.34KN

Nominal shear stress Tv = VFd/b0d = 0.67 N/sqmm

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

Page 24: Design GP Building for Pop.above 5000

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.670

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 326.03KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 595.13KN >326.03KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 25: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F3

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 73.50KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.45m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 493.00KN

493.00KN

Add self weight of the footing&Weight 73.950KN

of back fill (15%)

Total Load = 566.95KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 110.25KN/sqm

Size of the footing required:-

Area of the footing required = 5.14Sqm

Provide square footing of size 2.40mx2.40m,the area comes to 5.76Sqm

Width = 2.40m

Depth = 2.40m

The net ultimate bearing pressure acting on the footing due to direct load = 98.43KN/sqm

Design moment = 5.10KN-m

Section Modulus for the above section = (1/6)xbd2 = 2.30cum

Soil pressure due to moment = M/Z = 2.22KN/sqm

Max.Soil pressure = pu + mu = 100.65KN/sqm <110.25KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 96.21KN/sqm >0

Hence O.K

Hence,the design soil pressure = 100.65KN/sqm

Depth of the footing required:-

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = Mu = 59.24KN-m

DESIGN OF FOOTINGS(1,4,9,12)

Page 26: Design GP Building for Pop.above 5000

(Considering 1m width of footing)

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 131.04mm

Over all depth required assuming 12mm dia bars = = 187.04mm

However assume 350mm overall depth,then the effective depth comes to 294.00mm

The actual depth of neutral axis = 23.15mm

Area of steel required = 577.17sqmm

Assuming 12mm dia bars,the spacing comes to 150mm

Provide 12mm bars at a spacing of 150mm

Then the area of reinforcement provided = 753.60Sqm

Percentage of reinforcement provided = 0.256

ii)One way shear criteria:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 79.61KN

Nominal shear stress Tv = 0.271N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.256%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.363 N/sqmm Hence Vuc = 106.72KN

0.363 >0.271

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 2536mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 540.49KN

Nominal shear stress Tv = VFd/b0d = 0.72 N/sqmm

Page 27: Design GP Building for Pop.above 5000

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.720

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 566.95KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 1164.38KN >566.95KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 28: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F2

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 73.50KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.23m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 408.25KN

408.25KN

Add self weight of the footing&Weight 61.238KN

of back fill (15%)

Total Load = 469.49KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 110.25KN/sqm

Size of the footing required:-

Area of the footing required = 4.26Sqm

Provide rectangular footing of size 1.80mx2.60m,the area comes to 4.68Sqm

Width = 1.80m

Depth = 2.60m

The net ultimate bearing pressure acting on the footing due to direct load = 100.32KN/sqm

Design moment = 3.00KN-m

Section Modulus for the above section = (1/6)xbd2 = 2.03cum

Soil pressure due to moment = M/Z = 1.48KN/sqm

Max.Soil pressure = pu + mu = 101.80KN/sqm <110.25KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 98.84KN/sqm >0

Hence O.K

Hence,the design soil pressure = 101.80KN/sqm

The maximum bending moment at the face of the column wrt the section along width ML = 71.47KN-m

(Considering 1m width of footing)

The maximum bending moment at the face of the column wrt the section along length MB = 31.37KN-m

(Considering 1m width of footing)

Depth of the footing required:-

DESIGN OF RECTANGULAR FOOTINGS(7,8,9,10,11,13,14)

Page 29: Design GP Building for Pop.above 5000

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = ML = 71.47KN-m

(Considering 1m width of footing)

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 143.93mm

Over all depth required assuming 16mm dia bars = = 201.93mm

However assume 350mm overall depth,then the effective depth comes to 292.00mm

Longitudinal direction:-

Calculation of reinforcement :-

The actual depth of neutral axis = 28.35mm

Area of steel required = 706.73sqmm

Assuming 12mm dia bars,the spacing comes to 160mm

Provide 12mm bars at a spacing of 150mm along width

Then the area of reinforcement provided = 753.60Sqm

Percentage of reinforcement provided = 0.258

Check for one way shear:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 90.91KN

Nominal shear stress Tv = 0.311N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.258%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.363 N/sqmm Hence Vuc = 106.00KN

0.363 >0.311

Hence,no shear reinforcement is required.

Transverse direction:-

Maximum factored bending moment = MB = 31.37KN-m

(Considering 1m width of footing)

Page 30: Design GP Building for Pop.above 5000

Over all depth provided = 350.00mm

Effective depth assuming 10mm dia bars 295.00mm

Calculation of reinforcement :-

The actual depth of neutral axis = 12.02mm

Area of steel required = 299.66sqmm

Reinforcement in central band = 0.82

Total reinforcement

Reinforcement to be provided in central band = 245.18sqmm

Reinforcement to be provided in each edge band = 27.24sqmm

However provide 10mm dia bars at a spacing of 150mm along length

Then the area of reinforcement provided = 523.33Sqm

Percentage of reinforcement provided = 0.177

Check for one way shear:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 49.88KN

Nominal shear stress Tv = 0.169N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.177%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.302 N/sqmm Hence Vuc = 89.09KN

0.302 >0.169

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 2088mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 448.68KN

Nominal shear stress Tv = VFd/b0d = 0.74 N/sqmm

Page 31: Design GP Building for Pop.above 5000

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.740

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 469.49KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 595.13KN >469.49KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing

Page 32: Design GP Building for Pop.above 5000

Design Parametres:-

Footing designation = F1

Concrete mix M25

Steel Fe415

Cover to Reinforcement 50mm

Safe Bearing Capacity(From soil Report)= 73.50KN/sqm

Unit weight of RCC = 25.0KN/cum

Width of Column b = 0.23m

Depth of Column d = 0.23m

Characteristic compressive strength of concrete = 25.00N/sqmm

Yield strength of steel = 415.00N/sqmm

Load calculations:-

Factored Load on the column from analysis = 283.50KN

283.50KN

Add self weight of the footing&Weight 42.525KN

of back fill (15%)

Total Load = 326.03KN

Ultimate Bearing Capacity of the soil qu = 1.5xSBC = 110.25KN/sqm

Size of the footing required:-

Area of the footing required = 2.96Sqm

Provide square footing of size 1.80mx1.80m,the area comes to 3.24Sqm

Width = 1.80m

Depth = 1.80m

The net ultimate bearing pressure acting on the footing due to direct load = 100.63KN/sqm

Design moment = 4.05KN-m

Section Modulus for the above section = (1/6)xbd2 = 0.97cum

Soil pressure due to moment = M/Z = 4.18KN/sqm

Max.Soil pressure = pu + mu = 104.81KN/sqm <110.25KN/sqm

Hence O.K

Min.Soil pressure = pu - mu = 96.45KN/sqm >0

Hence O.K

Hence,the design soil pressure = 104.81KN/sqm

Depth of the footing required:-

i)Bending moment criteria:-

The critical section for bending is at the face of the column.Hence,the

Maximum factored bending moment = Mu = 32.29KN-m

DESIGN OF FOOTINGS(1,2,3,4,5,12,15)

Page 33: Design GP Building for Pop.above 5000

(Considering 1m width of footing)

Adopting Limit state method of design Mu = 0.138 fckbd2

The effective depth of footing required = d = [Mu/(0.138fckb)]0.5

= 96.74mm

Over all depth required assuming 12mm dia bars = = 152.74mm

However assume 300mm overall depth,then the effective depth comes to 244.00mm

The actual depth of neutral axis = 15.10mm

Area of steel required = 376.31sqmm

Assuming 12mm dia bars,the spacing comes to 300mm

Provide 12mm bars at a spacing of 175mm

Then the area of reinforcement provided = 645.94Sqm

Percentage of reinforcement provided = 0.265

ii)One way shear criteria:-

The critical section of one way shear is at a distance of 'd' from the face of the column

Hence,the factored design shear force VFd = 56.70KN

Nominal shear stress Tv = 0.232N/sqmm <2.8 N/sqmm

(As per Table 20 of 1S 456)

Hence,the section is safe from shear point of view

The percentage area of the tensile reinforcement provided = 0.265%

The design shear strength of concrete for the above steel percentage from

Table 19 of IS 456 is

0.367 N/sqmm Hence Vuc = 89.55KN

0.367 >0.232

Hence,no shear reinforcement is required.

iii)Two way shear criteria:-

The critical section for two-way shear is along the perphery of the square at a

distance d/2 from the face of the column

Hence perimetre of the preriphery b0 = 1896mm

Hence,the factored shear force VFd = qu(B2-AB

2)= 316.02KN

Nominal shear stress Tv = VFd/b0d = 0.68 N/sqmm

Page 34: Design GP Building for Pop.above 5000

Permissible shear stress in concrete for two-way shear for M20 grade concrete

Tc' =ks . Tc

ks = (0.5+l/b)> 1

Hence ks = 1

Tc = 0.25(fck)1/2

= 1.25 N/sqmm

Hence,Tc' = 1.25 N/sqmm

1.12 >0.680

Hence,the section provided is safe from two-way shear point of view

iv)Check for transfer of bearing stress:-

Pu = 326.03KN

Compressive bearing resistance = 0.45 fck(A1/A2)1/2

.

For the column face A1/A2 = 1 and for the other face A1/A2 > 2 but should be taken as 2.

In any case, the column face governs.Force transferred to the base through column

at the interface = 595.13KN >326.03KN

Hence O.K

There is no need to design separate dowel bars to tranfer the load to the base of the footing