Design: D Whitfield, Logarithms – making complex calculations easy John Napier John Wallis Jost...
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Design: D Whitfield, www.pifactory.co.uk
Logarithms – making complex calculations easyJohn Napier
John Wallis
Jost Burgi
Johann Bernoulli
Design: D Whitfield, www.pifactory.co.uk
Logarithms
102 = 100“10 raised to the power 2 gives 100”
Base
IndexPower
ExponentLogarithm
“The power to which the base 10 must be raised to give 100 is 2”
“The logarithm to the base 10 of 100 is 2”
Log10100 = 2
Number
Design: D Whitfield, www.pifactory.co.uk
Logarithms
102 = 100Base
Logarithm
Log10100 = 2
Number
Logarithm
Nu
mb
er
Base
y = bx
Logby = x
23 = 8 Log28 = 3
34 = 81 Log381 = 4
Log525 =2 52 = 25
Log93 = 1/2 91/2 = 3
logby = xis the inverse of
y = bx
Design: D Whitfield, www.pifactory.co.uk
103 = 1000 log101000 = 3
24 = 16 log216 = 4
104 = 10,000 log1010000 = 4
32 = 9 log39 = 2
42 = 16 log416 = 2
10-2 = 0.01 log100.01 = -2
log464 = 3 43 = 64
log327 = 3 33 = 27
log366 = 1/2 361/2 = 6
log121= 0 120 = 1
p = q2 logqp = 2
xy = 2 logx2 = y
pq = r logpr = q
logxy = z xz = y
loga5 = b ab = 5
logpq = r pr = q
c = logab b = ac
Design: D Whitfield, www.pifactory.co.uk
103 = 1000 log101000 = 3
24 = 16 log216 = 4
104 = 10,000 log1010000 = 4
32 = 9 log39 = 2
42 = 16 log416 = 2
10-2 = 0.01 log100.01 = -2
log464 = 3 43 = 64
log327 = 3 33 = 27
log366 = 1/2 361/2 = 6
log121= 0 120 = 1
p = q2 logqp = 2
xy = 2 logx2 = y
pq = r logpr = q
logxy = z xz = y
loga5 = b ab = 5
logpq = r pr = q
c = logab b = ac
Design: D Whitfield, www.pifactory.co.uk
103 = 1000 log101000 = 3
24 = 16 log216 = 4
104 = 10,000 log1010000 = 4
32 = 9 log39 = 2
42 = 16 log416 = 2
10-2 = 0.01 log100.01 = -2
log464 = 3 43 = 64
log327 = 3 33 = 27
log366 = 1/2 361/2 = 6
log121= 0 120 = 1
p = q2 logqp = 2
xy = 2 logx2 = y
pq = r logpr = q
logxy = z xz = y
loga5 = b ab = 5
logpq = r pr = q
c = logab b = ac
Design: D Whitfield, www.pifactory.co.uk
103 = 1000 log101000 = 3
24 = 16 log216 = 4
104 = 10,000 log1010000 = 4
32 = 9 log39 = 2
42 = 16 log416 = 2
10-2 = 0.01 log100.01 = -2
log464 = 3 43 = 64
log327 = 3 33 = 27
log366 = 1/2 361/2 = 6
log121= 0 120 = 1
p = q2 logqp = 2
xy = 2 logx2 = y
pq = r logpr = q
logxy = z xz = y
loga5 = b ab = 5
logpq = r pr = q
c = logab b = ac
Design: D Whitfield, www.pifactory.co.uk
103 = 1000 log101000 = 3
24 = 16 log216 = 4
104 = 10,000 log1010000 = 4
32 = 9 log39 = 2
42 = 16 log416 = 2
10-2 = 0.01 log100.01 = -2
log464 = 3 43 = 64
log327 = 3 33 = 27
log366 = 1/2 361/2 = 6
log121= 0 120 = 1
p = q2 logqp = 2
xy = 2 logx2 = y
pq = r logpr = q
logxy = z xz = y
loga5 = b ab = 5
logpq = r pr = q
c = logab b = ac
Design: D Whitfield, www.pifactory.co.uk
Laws of logarithmsEvery number can be expressed in exponential form… every number can be expressed as a log
Let p = logax and q = logay
So x = ap and y = aq
xy = ap+q
p + q = loga(xy)
p + q = logax + logay = loga(xy)
loga(xy) = logax + logay
Design: D Whitfield, www.pifactory.co.uk
Laws of logarithmsEvery number can be expressed in exponential form… every number can be expressed as a log
Let p = logax and q = logay
So x = ap and y = aq
xy = ap-q
p - q = loga(x/y)
p - q = logax - logay = loga(x/y)
loga(x/y) = logax - logay
Design: D Whitfield, www.pifactory.co.uk
Laws of logarithmsEvery number can be expressed in exponential form… every number can be expressed as a log
Let p = logax and q = logax
So x = ap and x = aq
x2 = ap+q
p + q = loga(x2)
p + q = logax + logax = loga(x2)
logaxn = nlogax
Design: D Whitfield, www.pifactory.co.uk
Laws of logarithmsEvery number can be expressed in exponential form… every number can be expressed as a log
loga(x/y) = logax - logay
loga(xy) = logax + logay
logaxn = nlogax
am.an = am+n
am/an = am-n
(am)n = am.n
Design: D Whitfield, www.pifactory.co.uk
Change of base property
Logax =Logbx
Logba
Design: D Whitfield, www.pifactory.co.uk
Solving equations of the form ax = b
3x = 9
4x = 64
5x = 67
Solve by taking logs:
log5x = log67
xlog5 = log67