Design Analysis VRV
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CHAPTER 4
DESIGN ANALYSIS
4.1 Overview
Design is the creation of a plan or convention for the construction of an object or a
system while analysis is the process of breaking a complex topic or substance into smaller parts
in order to gain a better understanding of it. This chapter will cover on the design of this system
by conducting a cooling load study and perform the analysis.
4.2 Cooling Load Cal!la"ion
Internal and external cooling load is a vital criteria to estimate the building cooling load.
Internal load can be described as heat produce by occupants, machine and lighting.
https://en.wikipedia.org/wiki/Plan_(drawing)https://en.wikipedia.org/wiki/Convention_(norm)https://en.wikipedia.org/wiki/Complexityhttps://en.wikipedia.org/wiki/Plan_(drawing)https://en.wikipedia.org/wiki/Convention_(norm)https://en.wikipedia.org/wiki/Complexity
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4.2.1 Solar Hea" Gain "#r! Gla$$
The area of the house is on 1! north of the "arth#s e$uatorial plane. The house
coordinate is %!&1'( latitude and 1!%&'". )sing window heat gain software, the values of
window heat gain in *tu+hr- unit can be obtained by key in the parameter such as window
orientation, solar heat gain coefficient value /0- and latitude of the location. olar heat gain
is influenced by the gla2ing type, the number of panes, and any glass coatings. olar heat gain of
gla2ing ranges from above 34 for uncoated water5white clear glass to less than 64 for
highly reflective coatings on tinted glass. 7 typical double5pane I0) has a /0 of around
.8. This value decreases somewhat by adding a low5" coating and decreased substantially
when adding a tint. In this project, all windows is covered with tint and assuming clearness and
sunshine percentage is 1 and 14, type of concrete is old surface and /0 value is .66, the
solar heat gain is available in 7ppendix 6 as well as (9: label (ational 9enestration :ating
ouncil). *ase on building survey, all windows are exposing to the sunlight and each of the solar
gain will be calculated accordingly. 9rom 7ppendix 6, the solar heat gain occurring in ;ay at
16? *tu+hr-s$.ft-, 7 = 6.@6 B @.6> = 1@.>6 ft6
/ence
$s = >?B1@.>6 = @,>@&.3 *tu+hr
http://www.commercialwindows.org/reflective.phphttp://www.commercialwindows.org/lowe-phphttp://www.commercialwindows.org/tint.phphttp://www.commercialwindows.org/reflective.phphttp://www.commercialwindows.org/lowe-phphttp://www.commercialwindows.org/tint.php
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;aster *edroom window 1! (orth of "ast-
0iven,
) = >? *tu+hr-s$.ft-, 7 = >.63 B @.%@ = 61.%6 ft6
/ence
$s = >?B61.%6 = 3,>?6.3 *tu+hr
*edroom C6 window 1! outh of Aest-
0iven,
) = >@ *tu+hr-s$.ft-, 7 = 6.1> B %.%3 = 11.3? ft6
/ence
$s = >@B11.3? = &,63.& *tu+hr
*edroom C> window 1! outh of Aest-
0iven,
) = >@ *tu+hr-s$.ft-, 7 = 6.1> B %.%3 = 11.3? ft6
/ence
$s = >@B11.3? = &,63.& *tu+hr
*edroom C& window 1! outh of Aest-
0iven,
) = >@ *tu+hr-s$.ft-, 7 = 1.@& B &.%? = 8.%> ft6
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/ence
$s = >@B8.%> = 6,81.3 *tu+hr
Dining /all window 1! outh of Aest-
0iven,
) = >@ *tu+hr-s$.ft-, 7 = @.%@ B @.3? = &%.6 ft6
/ence
$s = >@B&%.6 = 1@,686 *tu+hr
9amily 7rea window 1! outh of Aest-
0iven,
) = >@ *tu+hr-s$.ft-, 7 = 1.@& B &.@ = 8.%&& ft6
/ence
$s = >@B8.%&& = 6,81%.3& *tu+hr
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4.2.2 Hea" Gain "#r! %all and Roo&
Aalls and :oofs can have an important effect on interior comfort conditions in both the
residential and non5residential sectors. Aalls and roofs come into direct contact with the exterior
environmental conditions. everal factors can be utili2ed to reduce energy consumption and
improve interior comfort conditions. ight colored exterior walls can help to reduce interior
temperatures by reducing solar heat gain. In addition, shade trees and bushes can reduce this heat
gain. 9or roof, insulation in the attic is important because the attic is a large source of heat gain
from the roof.
Total "$uivalent Temperature Difference T"TD- is used to account for the added heat
transfer due to the sun shining on exterior walls, roofs, and windows, and the capacity of the wall
and roof to store heat. The T"TD is substituted for ∆T in the e$uation for conduction. 9or this
project, a heat transfer software will be used to determine the heat gain through wall and roof.
:esistance value :-, which is thermal resistance of a material that will be used is determine by
the material itself and for this case the wall is common brick type which give :=.3 and roof is
ceramic tile which give : = 6.>1. :eferring to 7ppendix 6, the e$uivalent temperature difference"TD- for all areas occurring at 16pm is and transmission coefficient )- for @ inch thickness of
medium weight concrete, define as below-
:oof< ) = .18
The cooling load calculation for wall that expose to the sunlight is describe as below
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Aall TD
;ain /all 5 Aall 1! (orth of "ast-
0iven,
) = .>? , "TD = 8>%.>
/ence
$s = .>?B8>%.> = [email protected] *tu+hr
Dining /all 5 Aall 1! (orth of "ast-
0iven,
) = .>? , "TD = &81.6
/ence
$s = .>?B&81.6 = 13>.88 *tu+hr
9amily 7rea 5 Aall 1! (orth of "ast-
0iven,
) = .>? , "TD = 13
/ence
$s = .>?B13 = 86 *tu+hr
;aster bedroom 5 Aall 1! (orth of "ast-
0iven,
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) = .>? , "TD = 1686.
/ence
$s = .>?B1686. = &[email protected] *tu+hr
*edroom C6 5 Aall 1! (orth of "ast-
0iven,
) = .>? , "TD = &81.6
/ence
$s = .>?B&81.6 = 13>.88 *tu+hr
:oof TD
;aster *edroom roof
0iven,
) = .18 *tu+hr-s$.ft-, 7 = >.63 B @.%@ = 61.%6 ft6
/ence
$s = .18B61.%6B&@8%.> = 18,1&.11 *tu+hr
*edroom C6 roof
0iven,
) = .18 *tu+hr-s$.ft-, 7 = 6.1> B %.%3 = 11.3? ft6
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/ence
$s = .18B11.3?B&@8%.> = ?&%.13 *tu+hr
*edroom C> roof 1! outh of Aest-
0iven,
) = .18 *tu+hr-s$.ft-, 7 = 6.1> B %.%3 = 11.3? ft6
/ence
$s = .18B11.3?B&@8%.> = ?,&%.13 *tu+hr
4.2.' Hea" Gain "#r! Ceiling and (loor
The transmission coefficient for ceiling and floor can be found from 7ppendix 6. 7ccording
to the transmission coefficient table, the ) value for bottom and top surface is .@1 *tu+hr-
s$.ft- while outdoor and indoor temperature are >! 3@- and 6@! 83.3- respectively. The
total of heat gain thru ceiling and floor is as below = 1@.>6 ft6
/ence
$s = .@1B1@.>[email protected] = 81.@8 *tu+hr
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;aster *edroom eiling and 9loor
0iven,
) = .@1 *tu+hr-s$.ft-, 7 = >.63 B @.%@ = 61.%6 ft6
/ence
$s = .@1B61.%[email protected] = ?&.%6 *tu+hr
*edroom C6 eiling and 9loor
0iven,
) = .@1 *tu+hr-s$.ft-, 7 = 6.1> B %.%3 = 11.3? ft6
/ence
$s = [email protected][email protected] = %6.66 *tu+hr
*edroom C> eiling and 9loor
0iven,
) = .@1 *tu+hr-s$.ft-, 7 = 6.1> B %.%3 = 11.3? ft6
/ence
$s = [email protected][email protected] = %6.66 *tu+hr
*edroom C& eiling and 9loor
0iven,
) = .@1 *tu+hr-s$.ft-, 7 = 1.@& B &.%? = 8.%> ft6
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/ence
$s = .@1B8.%>[email protected] = >>.8 *tu+hr
Dining /all eiling and 9loor
0iven,
) = .@1 *tu+hr-s$.ft-, 7 = @.%@ B @.3? = &%.6 ft6
/ence
$s = .@1B&%[email protected] = 1?3.%6 *tu+hr
9amily 7rea eiling and 9loor
0iven,
) = >@ *tu+hr-s$.ft-, 7 = 1.@& B &.@ = 8.%&& ft6
/ence
$s = .@1B8.%&&[email protected] = >>.1> *tu+hr
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4.2.4 Hea" Gain &ro) Peo*le
The heat gain come from people consist of two types which are sensible and latent heat. The
calculation is based on 7ppendix 6. In building survey, the maximum of person that stay in this
house are four &- people. The example calculation as below
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*edroom C6
"stimate number of people will occupied at this area is at a time is 6,
Es= 6B61 = &6
$= 6B1& = 63
*edroom C>
"stimate number of people will occupied at this area at a time is 1,
Es= 1B61 = 61
$= 1B1& = 1&
*edroom C&
"stimate number of people will occupied at this area at a time is 1,
Es= 1B61 = 61
$= 1B1& = 1&
Dining /all
"stimate number of people will occupied at this area at a time is @,
Es= @B61 = 16@
$= @B1& = 3&
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9amily 7rea
"stimate number of people will occupied at this area at a time is &,
Es= &B61 = 3&
$= &B1& = %@
4.2.+ Hea" Gain &ro) Lig#"ing S,$"e)
/eat gain from lighting can be determined using e$uation E=A x >.& x *9 x 9.
7ccording to 7ppendix 6, the fluorescent lamp has typical value of 1.% A+s$.ft. *elow is the
calculation for sensible heat gain by lighting = 1@.>6 ft6
$s = 1.%B1@.>6B1.6%B>.&1= 1&.>% *tu+hr
;aster *edroom
7 = >.63 B @.%@ = 61.%6 ft6
$s = 1.%B61.%6B1.6%B>.&1= 1>8.%? *tu+hr
*edroom C6
7 = 6.1> B %.%3 = 11.3? ft6
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$s = 1.%B11.3?B1.6%B>.&1= [email protected] *tu+hr
*edroom C>
7 = 6.1> B %.%3 = 11.3? ft6
$s = 1.%B11.3?B1.6%B>.&1= [email protected] *tu+hr
*edroom C&
7 = 1.@& B &.%? = 8.%> ft6
$s = 1.%B8.%>B1.6%B>.&1= &3.1& *tu+hr
Dining /all
7 = @.%@ B @.3? = &%.6 ft6
$s = 1.%B&%.6B1.6%B>.&1= 63?. *tu+hr
9amily 7rea
7 = 1.@& B &.@ = 8.%&& ft6
$s = 1.%B8.%&&B1.6%B>.&1= &3.6> *tu+hr
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4.' Sele"ion o& S,$"e)
7fter the entire cooling load has been determined for each area, the next step is to find the
total cooling load for entire house. The total cooling load will help to determine the selection of
F:F model that suitable with the load. This is important due to undersi2e of the system will
cause the desired temperature unable to achieve and oversi2e the system will cause the waste of
energy. Table &.1 show the list of the cooling load for each area and the total cooling load for
entire house.
Ta-le 4.1 ummari2ed of ooling oad
(loor Loa"ion
T,*e o& Cooling Ca*ai", /0"!#r To"alCooling
Ca*ai",
/0"!#r%indow %all Roo&
Ceiling
and
&loor Peo*le Lig#"
1
;ain /all @,>@&.3 [email protected] (7 81.@8 6,1 1&.>% 3,?68.%?
Dining /all 1@,686 13>.3 (7 1?3.%6 6,1 63?. 1?,&>.6?
9amily 7rea 6,81%.3& 86. (7 >>.1> 1& &3.6> &,3??.6
*edroom C& 6,81.3
(7 (7
>>.8
>% &3.1&
>,1&6.1
6;aster*edroom 3,>?6.3 &[email protected] 18,1&.11 ?&.%6 8 1>8.%? 6@,?6%.1
*edroom C6 &,63.& 13>.3 ?&%.13 %6.66 8 [email protected] 1&,8&6.%?
*edroom C> &,63.& (7 ?,&%.13 %6.66 >% [email protected] 1&,63.36
To"al 31555.67
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7s per table &.1, total cooling load is ?1,333.@ *tu+hr without considering any safety
factor. afety factor is to be applied to all rooms to cover up the error of the calculation. To get
an ideal and effective air conditioner system, safety factor of 14 is applied. The value after
adding 14 safety factor are called "ffective :oom Total /eat ":T/-. Table &.6 determine the
actual total capacity after safety factor of 14 is applied.
Ta-le 4.2 E&&e"ive Roo) Cooling Load
(loor Loa"ion
To"al Cooling
Ca*ai",
/0"!#r
E&&e"ive Roo)
Cooling Load
/0"!Hr
1
;ain /all 3,?68.%? ?,36.>%
Dining /all 1?,&>.6? 6,?&8.@6
9amily 7rea &,3??.6 %,>3?.16
*edroom C& >,1&6.1 >,&%@.61
6
;aster
*edroom 6@,?6%.1 6?,@18.@1
*edroom C6 1&,8&6.%? 1@,[email protected]%
*edroom C> 1&,63.36 1%,@6?.8
TOTAL ?1333.@ 11,88.&@
7fter safety factor been applied to the existing cooling, the new total cooling load is 11,88.&@
*tu+hr. The selection of the model will be based on comparison of design capacity of that model
versus cooling load re$uired by the house. 7fter some survey and market research, Daikin F:F
system with model number :GE16T/H1"- is suitable since this model provide cooling
capacity up to 11&, *tu+hr and maximum of indoor unit that can be connected is 6.
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Table &.61 shows the specification for Daikin F:F model :GE16T/H1"-. 7s per
below specification, the recommended total pipe length is >,63 ft and the weight for outdoor
unit itself is 13% kg. 7lthough manufacturers routinely increase the maximum allowable
refrigerant pipe run, the longer the lengths of refrigerant pipes, the more expensive the initial and
operating costs. 9or most F:F units, the maximum allowable vertical distance between an
outdoor unit and its farthest indoor unit is approximately 1% ft &@ m-. The maximum
permissible vertical distance between two individual indoor units is approximately &% ft 1& m-
and the maximum actual refrigerant piping lengths allowable between outdoor and farthest
indoor units is up to &? ft 1&? m-. 9or indoor unit, there are & models that need to be used base
on cooling load re$uirement. Indoor units are available in multiple configurations such as wall5
mounted, ceiling5mounted cassette suspended, and concealed ducted types. 9or this project, wall
mounted type has been choose due to flexibility and ease of installation. tarting from 8,%
*tu+hr to >, *tu+hr cooling capacity will be used to cool down from >,&%@.61 *tu+hr up to
6?,@18.@1 *tu+hr cooling load. The list of indoor unit as indicate in table &.6.1.
Ta-le 4.2.1 Li$" o& Indoor !ni"
Model Type Cooling CapacityFXAQ07P Wall mounted type 7500
FXAQ09P Wall mounted type 9500FXAQ18P Wall mounted type 18000FXAQ30P Wall mounted type 30000
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Ta-le 4.2.2 S*ei&ia"ion &or O!"door Dai8in 9R9
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Ta-le 4.2.2 S*ei&ia"ion &or Indoor Dai8in 9R9 /(:A;7
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Ta-le 4.2.' S*ei&ia"ion &or Indoor Dai8in 9R9 /(:A;73P
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Ta-le 4.2.+ S*ei&ia"ion &or Indoor Dai8in 9R9 /(:A;15P
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4.'.1 Co$" Anal,$i$
*elow table is total cost to purchase indoor and outdoor unit for Daikin F:F 1J.
Quantity Location
Indoor Outdoor
Model/ Type
RatedCoolingCapacity(Btu/h)
Price(RM)
Quantity Model
RatedCoolingCapacity(Btu/h)
Price(RM)
1 Main Hall
FXAQ09P
9500 2,187
1 RXQ12THY1€ 114,000 28,500
Wall mount!t"#
1 $inin% Hall
FXAQ18P
18000 &,000
Wall mount!t"#
1 'it(n
FXAQ07P
7500 1,820
Wall mount!t"#
1*!+oom
4
FXAQ07P
7500 1,820
Wall mount!t"#
1Ma-t+
*!+oom
FXAQ&0P
&0000 4,551
Wall mount!t"#
1*!+oom
2
FXAQ12P
18000 &,000
Wall mount!t"#
1*!+oom
2
FXAQ12P
18000 &,000
Wall mount!t"#
.u/ Total 108,500 19,&78
114,000 28,500
+an! Total n!oo+ 3ut!oo+ RM) 47,878
*elow table is installation cost for F:F
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ITEM DESCRIPTION UNIT QTY
AMOUNTBEFORE GSTRM!
AMOUNTAFTERGSTRM!
A
Supply materal and manpo!er ton"tall ndoor and outdoor #ara$le
%e&r'erant #olume ()! a((e""ore",*ttn'", ppe !or+", (ondut !rn',
$ra(+et and "upport &or Floo" # -all,nn', Famly Area and /edroom 4.
otal re&r'erant ppe len'tappromately 204&t otal
manpo!er " 4
6ot 1 5,133 5,441
/
Supply materal and manpo!er ton"tall ndoor and outdoor #ara$le
%e&r'erant #olume ()! a((e""ore",*ttn'", ppe !or+", (ondut !rn',
$ra(+et and "upport &or Floo" $a"ter /edroom, /edroom 2 and
/edroom 3.otal re&r'erant ppe len'tappromately 71&t otal
manpo!er " 4
6ot 1 4,387 4,50
e"tn' and omm""onn' 6ot 1 1,500 1,590
:rand otal 11,020 11,81
*elow table is operational cost for F:F
odel
Po!eron"umpton
-our"perday
;ner'yon"umpton
per year +!
% peryear
Main Hall
FXAQ09P 30 Watt 9 98.55 21.4
Wall mount!t"#
$inin%Hall
FXAQ18P 30 Watt 9 98.55 21.4Wall mount!t"#
Famil" A+a
FXAQ07P 20 Watt 9 5.7 14Wall mount!t"#
*!+oom4
FXAQ07P 20 Watt 9 5.7 14Wall mount!t"#
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Ma-t+ *!+oom
FXAQ&0P 70 Watt 9 229.95 53.Wall mount!t"#
*!+oom2
FXAQ12P 30 Watt 9 98.55 21.4Wall mount!t"#
*!+oom2
FXAQ12P 30 Watt 9 98.55 21.4Wall mount!t"#
3ut!oo+ nit
RXQ12THY16 9.2
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%epla(e=AS &an$earn'" 10 1 140 337 49
%epla(ere&r'erant 10 8 70 133 220Su$totalrepar)repla(e 1,392
otal%> 3,777
9igure :efrigerant pipes must remain clean, dry, and leak free. Ahen stored prior to
installation, the edges of refrigerant pipes need to be sealed. (itrogen gas must be used during
welding to prevent oxidation of the interiors of refrigerant pipes. 7 detailed installation manual
must be followed. The installer should be familiar with the control options available for F:9
systems. "ach individual indoor unit can be controlled by a programmable thermostat or a
multiple indoor units serving the same 2one can be controlled by the same thermostat.
*elow table is total cost to purchase split aircond
Quantity Location
Model
Brand Indoor
RatedCoolingCapacity(Btu/h)
Pricebefore
!T (RM)
Price after !T (RM)
1 Main Hall
*.Q09*8A5
9500 &,82 4,05Wall mount!t"#
1$inin%Hall
Pana-oni(
P:18H'F
18000 4,01 4,257Wall mount!t"#
1Famil" A+a
AR07&.*4
7500 &,179 3,370Wall mount!t"#
1*!+oom
4
AR07&.*4
7500 &,179 3,370Wall mount!t"#
1Ma-t+
*!+oom
.&07H;&
&0000 7,255 7,90Wall mount!t"#
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1*!+oom
2
.120H6;
12000 &,788 4,015Wall mount!t"#
1*!+oom
&
.120H6;
12000 &,788 4,015Wall mount!t"#
Total 9,500 29,0&1 &0,77&
Total Price after !T +,-..+
Installation cost for plit 7
ITEM DESCRIPTION UNIT QTY
AMOUNTBEFOREGSTRM!
AMOUNTAFTERGSTRM!
A
Supply materal and manpo!er ton"tall ndoor and outdoor Splt unt()! a((e""ore", *ttn'", ppe !or+",(ondut !rn', $ra(+et and "upport &orFloor 1 -all, nn', Famly Area and/edroom 4.otal manpo!er " 4 %150)ead
Wrn' %250)unt
6ot 1 3,850 4,081
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/
Supply materal and manpo!er ton"tall ndoor and outdoor Splt unt()! a((e""ore", *ttn'", ppe !or+",(ondut !rn', $ra(+et and "upport &orFloor 2 a"ter /edroom, /edroom 2and /edroom 3.
otal manpo!er " 4 %150)eadWrn' %250)unt
6ot 1 3,100 3,28
e"tn' and omm""onn' 6ot 1 1,500 1,590
:rand otal 8,450 8,957
Kperational cost for plit 7
Model B"andPo/e"
Con%*&ption 0/!
1o*"%
pe"day
Ene"gyCon%*&ption pe"
yea"0/2!
RM pe"yea"
Main "all
*.Q09*8A5
2.8 9 9198 2,005Wall mount!t"#
#ining
"all
P:18H'F
Pana-oni(
5.28 9 17344 3,780
Wall mount!t"#
$a%ily&rea
AR07&.*4
2.1 9 898 1,503
Wall mount!t"#
Bedroo%'
FXAQ07P;
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*elow table is total cost for repair and maintenance for plit 7
Co%t Ite&%
Pe"iodyea"% Qty'
(a)o"Co%tRM!
Mate"ial Co%tRM!
Ann*alCo%tRM!
Maintenance %epla(e ar*lter"ndoor
0.5 7 35 154 504
e(+)(lean
&an (ol(onden"ate"y"tem"
1 7 105 280 393
%epla(e ar*lter"outdoor
1 7 84 175 27
Su$totalmantenan(e
1,14
Repair/Replace Fan (ol
motorrepla(ement 10 7 490 3000 392
%epla(e(apa(tor 10 7 35 315 37%epla(etermo"en"or 10 7 35 140 19
%epla(ere&r'erant 10 7 105 980 118Su$totalrepar)repla(
e 57 otal%> 1,730
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CHAPTER +
DISC=SSION
+.1 In"rod!"ion
It is important to know how much the total of the cooling load of a project so that a good
selection can be done and to avoid waste. Aith the availability of calculation and formula, the
cooling load of each area can be determined. Knce the total of cooling load has been discovered,
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then only searching activity for the suitable system can be done. "very manufacturer will provide
information such as cooling load capacity of a model. Ahen the differentiation between cooling
load re$uirement and cooling load capacity is executed, then only the specific model can be
selected by choosing the lesser of the differentiation so that the efficiency can be maintained and
optimi2ed.
+.2 Co)*ari$on o& Ca*i"al Co$" -e"ween 9R9 and S*li" AC
(ig!re +.1 < apital ost omparison
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9igure %.1 is comparison chart between F:F and plit 7 for total capital cost. 9or
initial cost, the F:F capital cost is 164 or :; %,@? higher than plit 7 due to the price of
outdoor F:F it is expensive. /owever the final decision for system selection will be based on
operational cost and :eturn on Investment :KI-.
+.' Co)*ari$on o& Re*air and >ain"enane Co$" -e"ween 9R9 and S*li" AC
(ig!re +.2 Re*air and >ain"enane Co$" Co)*ari$on
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9igure %.6 shows a comparison of repair and maintenance cost between variable
refrigerant volume and split air conditioner. The information is obtained from Daikin and 0
/F7 website 6J. (ormal maintenance for a F:F, similar to that of any DG system, consists
mainly of changing filters and cleaning coils. The large number of compressors in a F:F may
create a higher probability of compressor failure, although the redundancy also leads >J. *oth
systems will be schedule to service every @ month and annually based on the preventive
maintenance schedule. In this case, the service cost for F:F is :; @1 higher than split 7 due
to price of material and labor cost as F:F is more high technology than split 7. 9or repair cost,
the recommendation is to replace every 1 years and the amount has been divided accordingly so
that 1 year of service cost can be figured out. This comparison is applicable for 1 year of service
and :KI will be calculated for 1 years of service to determine which system is most profitable.
+.4 Co)*ari$on o& Energ, Con$!)*"ion -e"ween 9R9 and S*li" AC
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(ig!re +.4 Energ, Con$!)*"ion Co)*ari$on
The energy efficiency of F:F systems derives from several factors. The F:9 essentially
eliminates duct losses, which are often estimated to be between 14 to 64 of total airflow in a
ducted system.> F:F systems typically include two to three compressors, one of which is
variable speed, in each condensing unit, enabling wide capacity modulation. This approach
yields high part5load efficiency, which translates into high seasonal energy efficiency, because
/F7 systems typically spend most of their operating hours in the range of &4 to 34 of
maximum capacity >J. 9rom figure %.&, it is very obvious that the indoor F:F unit consume
very less energy compared with split 7 and this give a maximum saving in electricity. The F:F
outdoor unit may consume more energy, but it#s still much lower than split 7.
+.+ Co)*ari$on o& O*era"ional Co$" -e"ween 9R9 and S*li" AC
(ig!re +.+ Kperational ost omparison
9igure %.% shows a comparison of operational cost between F:F and split air conditioner
system. The total operating hours in one year is estimated as >6& hours including public
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holidays and weekends. In this case, F:F system has a lower operational cost compared to split
air conditioner. Kperational cost of F:F for one year is :; 8,68 while operational cost for split
air conditioner in one year is :; 16,&%. In one year, cost saving of :; %,&6> could be
generated if F:F system is been used.
+.6 Co)*ari$on o& Overall Co$" -e"ween 9R9 and S*li" AC
(ig!re +.6 Overall Co)*ari$on Co$" &or 1 Year
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In many cases, the initial cost of a F:9 system is higher than that of a split air
conditioner system. 9igure %.@ is comparison chart between F:F and plit 7 for overall cost in
one year operation. The F:F system is spending approximately :; 6>,%> higher than split air
conditioner and this is normal due to the F:F system depend on payback period in order to gain
saving. This overall cost is calculated for 1 year period, including capital cost which gives an
advantage to split air conditioner system. 9or long term standpoint and to gain back the F:F
investment, an :KI analysis is re$uired.
+.6 Re"!rn on Inve$")en" anal,$i$
ROI 3 #, Yea"%
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(ig!re +.6 Re"!rn on Inve$")en"
:eturn on investment :KI- is the benefit to an investor resulting from an investment of
some resource. 7 high :KI means the investment gains compare favorably to investment cost. 7s
a performance measure, :KI is used to evaluate the efficiency of an investment or to compare
the efficiency of a number of different investments &J. 9igure %.@ shows that F:F is able to
return back the capital investment in 1 years and generate tremendous saving after the said
period. The saving is calculated based on operational cost saving minus the maintenance cost.
Ahen the net cost saving is obtained, it will accumulate every year and :KI is achievable at 1
years. Aithout doubt, the efficiency of F:F system is proven by generating an operational cost
saving every year.
+.< Sele"ion o& Air Condi"ioning $,$"e)
Kbservation from table &.1, the total cooling load is ?1,333.@ *tu+hr and the total
effective cooling load is 11,88.&@ *tu+hr in order to provide cooling for a 6 storey terrace
house that have a built up 1 s$+ft. 9rom the table it can be seen also that the heat gain
through the wall has the highest value due to material of the wall is poured concrete 3 lb+ft> with
thickness @ inches. The most important factor in finali2ing the selection is to make the cost
comparison. Knce the specification of a model has met the re$uirement of the project, purchase
cost can be obtained by doing internet survey or directly contact with the supplier.
Ahen the purchase cost for F:F and split unit is available, the cost of installation can be
obtained by engaging the $ualified contractor that has experience installing this system. Ahen all
the costs are available, comparison can be made by checking which system has lowered cost and
suitable with this project. *ased on the analysis performed, the most suitable air conditioning
system for this project is variable refrigerant volume because is more cost effective compared to
split air conditioner. The F:F is capable to save :; &,366 yearly, return back the investment in
1 years and generate :; &3,66 cost saving after 6 years of operation.
https://en.wikipedia.org/wiki/Investmenthttps://en.wikipedia.org/wiki/Investment
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CHAPTER 6
CONCL=SION AND RECO>>ENDATION
F:F systems offer controls that match the space cooling loads to that of the indoor coil
over a range of operation. Fariable speed compressors and fans in the outdoor units modulate
their speed, saving energy at part5load conditions. Kutdoor sections should be si2ed to match
building peak loads, not the sum of the peak load for each 2one, reducing the capacity of outdoor
units when compared to a conventional unitary system. The system offers designers and
occupants the ability to choose multiple individuali2ed 2ones, which improves system
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controllability. The system capabilities and limitations should be evaluated carefully to determine
the suitability of the F:F for a project and to optimi2e its design.
APPENDI: 2
olar heat gain table for cooling load calculation
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etting for window orientation at 1! (orth of "ast
olar /eat 0ain value from Lanuary to December for 1! ( of " orientation
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etting for window orientation at 1! outh of Aest
olar /eat 0ain value from Lanuary to December for 1! of A orientation
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: Falue for ommon *rick
oftware for /eat Transfer through ;aterial
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Transmission coefficient of ommon *uilding ;aterial
: Falue for :oofing
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Thermal onductivity )- for 7sbestos5cement :oof
Transmission oefficient for eiling and 9loor
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:eference
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&J https
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