Deoxyribonucleic Acid (DNA). The double helix Nitrogenous Bases and Pentose Sugars.

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Deoxyribonucleic Acid (DNA)

Transcript of Deoxyribonucleic Acid (DNA). The double helix Nitrogenous Bases and Pentose Sugars.

Page 1: Deoxyribonucleic Acid (DNA). The double helix Nitrogenous Bases and Pentose Sugars.

Deoxyribonucleic Acid

(DNA)

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The double helix

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Nitrogenous Bases and Pentose Sugars

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Purine and Pyrimidine Structure

(1)  Pyrimidines are planar

(2)  Purines are nearly planar

(3) Numbering is different

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Numbering Is Different

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Bases Have Tautomeric Forms

Uracil

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Nucleosides vs. Nucleotides

Glycosidic bond

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Nucleotides formed by condensation reactions

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Monophosphates

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Deoxyribonucleotides

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Ribonucleotides

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Only RNA Is Hydrolyzed by Base

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Nucleoside Diphosphate and Triphosphate

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Dinucleotides and Polynucleotides

Ester bonds

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Watson-Crick Base Pairs

A=T

G=C

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Hoogsteen Base Pairs

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Other Base Pairs Are Possible

Homo Purines Hetero PurinesWatson-Crick,

Reverse Watson-Crick, Hoogsteen,

Reverse Hoogsteen, Wobble,

Reverse Wobble

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Base Pairing Can Result in Alternative DNA Structures

Triplex Tetraplex

Hairpin Loop Cruciform

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• Periodicity: A pair of strong vertical arcs (C & N atoms) indicate a very regular periodicity of 3.4 Å along the axis of the DNA fiber.

• Astbury suggested that bases were stacked on top of each other "like a pile of pennies".

• Helical nature: Cross pattern of electron density indicates DNA helix and angles show how tightly it is wound.

• Diameter: lateral scattering from electron dense P & O atoms.

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DNase can only cleave external bond demonstrating periodicity

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Watson and Crick Model (1953)

• 2 long polynucleotide chains coiled around a central axis

• Bases are 3.4 Å (0.34 nm) apart on inside of helix

• Bases flat & lie perpendicular to the axis

• Complete turn = 34 Å • 10 bases/turn• Diameter = 20 Å• Alternating major and

minor grooves

Hydrophobic

Hydrophilic

Complementarity

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Base Pairing Results from H-Bonds

Only A=T and GC yield 20 Å Diameter

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A:C base pair incompatibility

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Bases Are Flat

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Chains Are Antiparallel…

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Base Pairs and Groove Formation

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Base flipping can occur

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Helix Is Right-Handed

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Biologically Significant Form = B-DNA

Low Salt = Hydrated, 10.5 bp/turn

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A- DNA Exists Under High Salt Conditions

Side-view Top-view

Base pairs tilted, 23 Å, 11bp/turn

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Z-DNA Is a Left-Handed Helix

Zig-zag conformation, 18 Å, 12 bp/turn, no major groove

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Propeller Twist Results from Bond Rotation

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Reassociation Kinetics

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Denaturation of DNA Strands and the Hyperchromic Shift

• Denaturation (melting) is the breaking of H, but not covalent, bonds in DNA double helix duplex unwinds strands separate

• Viscosity decreases and bouyant density increases• Hyperchromic shift – uv absorption increases with

denaturation of duplex• Basis for melting curves because G-C pairs have three

H bonds but A-T pairs have only two H bonds• Duplexes with high G-C content have a higher melting

temperature because G-C pairs require a higher temperature for denaturation

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Molecular Hybridization

• Reassociation of denatured strands• Occurs because of complementary base pairing • Can form RNA-DNA Hybrids• Can detect sequence homology between species• Basis for in situ hybridization, Southern and

Northern blotting, and PCR

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Hybridization

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Reassociation Kinetics• Derive information about the complexity of

a genome• To study reassociation, genome must first

be fragmented (e.g. by shear forces)• Next, DNA is heat-denatured• Finally, temperature is slowly lowered and

rate of strand reassociation (hybridization) is monitored

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• Initially there is a mixture of unique DNA sequence fragments so hybridization occurs slowly. As this pool shrinks, hybridization occurs more quickly

• C0t1/2 = half-reaction time or the point where one half of the DNA is present as ds fragments and half is present as ss fragments

• If all pairs of ssDNA hybrids contain unique sequences and all are about the same size, C0t1/2 is directly proportional to the complexity of the DNA

• Complexity = X represents the length in nucleotide pairs of all unique DNA fragments laid end to end

• Assuming that the DNA represents the entire genome and all sequences are different from each other, then X = the size of the haploid genome

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The Tm

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The Hyperchromic Shift (Melting Curve Profile)

Tm = temperature at which 50% of DNA is denatured

Maximum denaturation = 100% single stranded

Double stranded

50% double, 50% single stranded

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High G-C Content Results in a Genome of Greater Bouyant Density

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Ideal C0t Curve

100% ssDNA

100% dsDNA

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Larger genomes take longer to reassociate because there are more DNA

fragments to hybridize

Largest genomeSmallest genome

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C0t1/2 Is Directly Proportional to Genome Size

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Genomes are composed of unique, moderately repetitive and highly repetitive

sequences

Highly repetitive DNA

Moderately repetitive DNA

10-4 10-2 100 102 104

Fra

ctio

n r

emai

nin

gsi

ngl

e-st

ran

ded

(C

/C0)

Unique DNA sequences

0

100

C0t (moles x sec/L)

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More complex genomes contain more classes of DNA sequences

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G-C Content Increases Tm