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Code: 2K1M5:9
PAGE 25
DIFFERENTIAL EQUATIONS, LAPLACE TRANSFORMS AND
FOURIER SERIES semester-vCode: 2K6M5:14RLevel : K
Unit : 1.1 Type : MCQ
1.The particular integral of is
(a) (b)
(c)
(d)
Code: 2K6M5:14RLevel : U
Unit : 1.1 Type : MCQ
1.The complementary function of is
(a)
(b)
(c)
(d)
2.The C. F. of
(a) Ax6 + Bx-5
(b) Ax5 + Bx-1 (c) Ax-5 + Bx4
(d) Ax5 + Bx-53.The C. F. of
(a)
(b)
(c)
(d)
4.The C. F. of (x2D2 xD + 1) y = is
(a) (b) (A + B log x)x(c)
(d)
5.The C. F. of (x2D2 xD - 3) y = x2 is
(a) Ax(3 + Bx -(3 (b) Ax(3 + Bx(2(c) Ax(4 + Bx(2(d) Ax(3 + Bx-(46.The C. F. of (x2D2 + 8xD + 12) y = x4 is
(a) Ax-4 + Bx7
(b) Ax3 + Bx-4 (c) Ax2 + Bx4
(d) Ax2 + Bx57.The C.F. of (x2D2 + xD + 2) y = x2 is
(a) x(A coslog x + B sinlog x) (b) (A coslog x + B sinlog x)
(b) e-x (A coslog x + B sinlog x) (d) ey (A cos( log x) + B sin(log x))8.The P. I. of (x2D2 + xD + 2) y = x2 is
(a)
(b)
(c)
(d)
9.The P. I. of (x2D2 + 2xD + 2) y = 6x2 is
(a)
(b) x2
(c) x3
(d)
10.The P. I. of (x2D2 +8xD +12) y = x4 is
(a)
(b)
(c)
(d)
11. The P. I. of (x2D2 + xD - 3) y = x2 is
(a) x3
(b) x2
(c) x4
(d) x
Code: 2K6M5:14RLevel : K
Unit : 1.1 Type : VSA
1. If , what is the value of ?2.If & f()(0, what is the value of ?
Code: 2K6M5:14RLevel : U
Unit : 1.1 Type : PA
1. Solve (x2D2+3xD+1)y =
2.Solve (x2D2+4xD+2)y=ex.
3.Solve (x2D2+xD+3)y=x2.
4.Solve (x2D2+xD+2)y=x2.
5. Solve (x2D2+7xD+13)y=logx.
6. Solve (x2D2+2xD)y=6x2+2x+1.
Code: 2K6M5:14RLevel : U
Unit : 1.1 Type : E
1.(a) Solve (x2D2 + 3xD + 1) y =
(b) Solve (x2D2 + 4xD + 2) y = ex2.(a) Solve (x2D2 xD + 1) y =
(b) Solve (x2D2 + xD - 3) y = x23.(a) Solve (x2D2 + 8xD + 12) y = x4
(b) Solve (x2D2 + xD + 2) y = x24.(a) Solve (x2D2 + 2xD) y = 6x2 + 2x + 1
(b) Solve (x2D2 + 3xD + 4) y = x25.(a) Solve (x2D2 + 7xD + 13) y = log x
(b) Solve (x4D4 + 6x3D3 + 9x2D2 + 3xD +1) y = (1 + logx) 2Code: 2K6M5:14RLevel : U
Unit : 1.2 Type : MCQ
1.The Auxiliary equation of (5 + 2x)2 is
(a) m2- 4m + 2=0(b) m2-2m+4=0(c) m2+4m+2=0(d) m2+2m+4=0
2.The A. E. of (3x+2)2
(a) m2-4=0
(b) m2+4=0
(c) m2+2=0
(d) m2-2=0
3.The A. E. of (1+x)2 2
(a) m2+1=0
(b) m2+2 = 0
(c) m2-1=0
(d) m2-2=0
Code: 2K6M5:14RLevel : U
Unit : 1.2 Type : PA
1.Solve (5+2x)2
2.Solve (1+2x)2
3.Solve (x+a)2
Code: 2K6M5:14RLevel : U
Unit : 1.2 Type : E
1.Solve (3x+2)2
2.Solve (1+x)2
3.(x+a)2
Code: 2K6M5:14RLevel : U
Unit : 1.3 Type : MCQ
1.The C. F. of (D2+n2) y = sec nx is
(a) A cos nx B sin nx
(b) A cos nx + B sin nx
(c) A sin nx + B cos nx
(d) A sin nx B cos nx
2.The C. F. of (D2 1) y = is
(a) Aex + Be2x
(b) Aex + Be-x
(c) Aex + Be3x3.The C. F. of y2 + y = cosec x is
(a) A cos x +Bx sin x
(b) A cos x + B sin x
(c) A cos x + B cos 2x
(d) B cos 2x A sin 2x
4. The C. F. of y2 + 4y = 4 tan 2x is
(a) A cos 3x + B sin 3x
(b) A cos 2x + B sin 2x
(c) A cos x + B sin x
(d) A cos 5x + B sin 5x
Code: 2K6M5:14RLevel : U
Unit : 1.3 Type : VSA
1.Find the C. F. of y2 + y = cosec x
2.Find the C. F. of y2 y =
3.Find the C. F. of y2 + n2y = sec nx
4.Find the C. F. of y2 + 4y = 4 tan 2x
Code: 2K6M5:14RLevel : U
Unit : 1.3 Type : PA
1. Solve y2 + n2y = sec nx
2.Solve y2 + 4y = 4 tan 2x
Code: 2K6M5:14RLevel : U
Unit : 1.3 Type : E
1.y2 y =
2.y2 + y = cosec x
Code: 2K6M5:14RLevel :U
Unit : 2.1 Type : MC
1.The P.D.E. obtained by eliminating a from z = 2ax is
(a) 2p=z
(b) px=z
(c) ax=z
(d) 2x=z2.The P.D.E. obtained by eliminating a from z = 2ax+a2 is
(a) z = xp+p2 /4(b) z = 2px+p2 (c) z = xp+x2p2(d) xz = p+p2 /4
3.The P.D.E. obtained by eliminating a & b from z = (x+a)(y+b) is
(a) z = pq
(b) px = qy
(c) zp = xq
(d) zq = yx
4.The P.D.E. obtained by eliminating a & b from z = f(x2+y2) is
(a) px = pq
(b) pq = xy
(c) py = qx
(d) z = pq
5.The P.D.E. obtained by eliminating a & b from z = f(x3+y3) is
(a) py2 = qx2
(b) py = qx
(c) z = pq
(d) px2 = qy26.The P.D.E. obtained by eliminating a & b from z = ax + by + ab is
(a) z = px+qy+pq
(b) z = qx + py
(c) xz + xp + yq + pq = 0
(d) xz + yp = pq
7.The P.D.E. obtained by eliminating a & b from z = ax by + ab is
(a) z = px + qy - pq
(b) z = px qy + pq
(c) z = px + qy + pq
(d) pq = z
8.The P.D.E. obtained by eliminating a & b from z = ax + by + a is
(a) z = px + qy + p
(b) z = px + qy + q
(c) px = qy
(d) zq = xq + p+q
Code: 2K6M5:14RLevel :K
Unit : 2.1 Type : VSA
1.Define the order of partial Differential Equation.
2.By eliminating a, b from (x, y, z, a, b) = 0 What is the form of Partial Differential Equation?
Code: 2K6M5:14RLevel :U
Unit : 2.1 Type : VSA
1.What is the order of P.D.E. (z /(x + (z / (y = 0?
2.What is the order of P.D.E. (2z / (x2 + ((z / (y)2 +2z = 6
3.What is the order of P.D.E. (2z / (x2 + ((z / (x) +5z = 6
4.Obtain P.D.E. by eliminating a from z = 2ax.
5.Obtain P.D.E. by eliminating a from z = 5ax
6.Obtain P.D.E. by eliminating a & b from z = (x+a)(y+b)
7.Obtain P.D.E. by eliminating a & b from z = (x+2a) (y+2b)
8.Obtain P.D.E. by eliminating a & b from z = (x+3a) (y+5b)
9.Obtain P.D.E. by eliminating a & b from z = (x+6a) (y+5b)
10.Obtain P.D.E. by eliminating a & b from z = (x-2a) (y-3b)
11.Obtain P.D.E. by eliminating function f from z = f(2x-y)
12.Obtain P.D.E. by eliminating function f from z = f(3x+2y)
13.Obtain P.D.E. by eliminating function f from z = f(5x+6y).
Code: 2K6M5:14RLevel :U
Unit : 2.1 Type : PA
1.Obtain a P.D.E. eliminating a, b from (x2 + y2) / a2 + (z2 / b2 )=1
2.Obtain a P.D.E. eliminating a, b from z = ax + by + ( (a2 + b2)
3.Obtain a P.D.E. eliminating a, b from (x-a)2 + (y-b)2 + z2 = a2 + b24.Obtain a P.D.E. eliminating a, b from z = (x2 + a) (y2 + b)
5.Obtain a P.D.E. eliminating a, b from a (x2 + y) + bz2 =1.
6.Obtain a P.D.E. eliminating a, b from z = ax + y ( (x2 ( a2) + bz2
7.Obtain a P.D.E. eliminating a, b from (x-a)2 + (y-b)2 + z2 = 1
8.Obtain a P.D.E. eliminating arbitrary function f from z = ey f (x + y)
9.Obtain a P.D.E. eliminating arbitrary function f from z = (x + y) f (x2 ( y2)
10.Obtain a P.D.E. eliminating arbitrary function f from z = ax + by +cz = f (x2 + y2 + z2)
11.Obtain a P.D.E. eliminating arbitrary function f from z = f (x2 + y2, z xy) =0
12.Obtain a P.D.E eliminating arbitrary function f from z = f (x2+y2+z2, x+y+z)=0.
13.Obtain a P.D.E eliminating arbitrary function f from z = f(z2 xy, x/z) =0
14.Obtain a P.D.E eliminating arbitrary function f from xyz = f(x + y + z)
15.Obtain a P.D.E eliminating arbitrary function f from z = y2 + 2 f(1 / x + log y)
16.Obtain a P.D.E eliminating arbitrary function f from f = (xy + z2, x + y + z) =0
17.Obtain a P.D.E eliminating arbitrary function f from
i) z = f(my lx)
ii) z = f(x2 y2)
18.Obtain a P.D.E eliminating arbitrary function f & g from z = f(y+ax)+xg(y+ax).
19.Obtain a P.D.E eliminating arbitrary function f & g from z = f(y) + g(x + y + z)
20.Obtain a P.D.E eliminating arbitrary function f & g from z = x f(y) + y g(x)
21.Obtain a P.D.E eliminating arbitrary function f & g from z = f(x+ay) + g(x-ay)
22.Obtain a P.D.E of all spheres whose centre lie on the plane z = 0 and whose radius is constant r
23.Obtain a P.D.E of all spheres whose centres lie on z axis
24.Obtain a P.D.E of all planes through the origin
25.Obtain a P.D.E of all planes having equal x & y intercepts
26.Obtain a P.D.E of all planes which are at a constant distance a from the origins
Code: 2K6M5:14RLevel :U
Unit : 2.1 Type : E
1.a) Obtain a P.D.E. eliminating a, b from (x2 + y2) / a2 + (z2 / b2 )=1
b) Obtain a P.D.E by eliminating arbitrary function f from z = ey f (x + y)
2.a) Obtain a P.D.E. eliminating a, b from z = ax + by + ( (a2 + b2 )
b) Obtain a P.D.E. eliminating arbitrary function f from z = (x + y) f (x2 ( y2)
3.a) Obtain a P.D.E. eliminating a, b from (x-a)2 + (y-b)2 + z2 = 1
b) Obtain a P.D.E. eliminating arbitrary function f from z=ax +by +cz =f(x2 +y2 + z2 ).
4.a) Obtain a P.D.E. eliminating a, b from a (x2 + y2) + bz2 =1.
b) Obtain a P.D.E. eliminating arbitrary function f from z = f (x2 + y2, zxy) =0
5.a) Obtain a P.D.E. eliminating a, b from x/a + y/a + z/b = 1 b) Obtain a P.D.E eliminating arbitrary function f from z = f(z2 xy, x/z) =0
6.a) Obtain a P.D.E of all spheres whose centre lie on the plane z = 0 and whose radius is constant r
b) Obtain a P.D.E eliminating arbitrary function f & g from z = f(x+ay)+ g(x-ay)
7.a) Obtain a P.D.E of all planes which are at a constant distance a from the origin.
b) Obtain a P.D.E eliminating arbitrary function f from f = (xy + z2, x+y+z) =0
Code: 2K6M5:14RLevel :U
Unit : 2.2 Type : MC
1.The solution of ( z / ( x = ex is
a) z = ex + f(y)b) z = xex + f(y)c) z = ex + f(x)b) z = ex + xf(y)
2.The solution of x ( x/ ( y = 1 is
a) z = x2 + f(y) b) z = log x + f(y)c) z = log x + f(x)d) z=xlogx+ f(y)
3.The solution of y ( z / ( y = 5 is
a) z = 5log x + f(y)b) z = 5log y + f(x)c) z = 5/2 y2 + f(y)d) z=5logy + f(x)
4.The solution of x2 (z / (x = 6 is
a) z = -6/x + f(x)b) z = -6/x + f(y)c) z = 3x + f(y) d) z = 6/x + f(y)
5.The solution to be assumed while solving the equation p2 + q2 =4 is
a) p = a
b) q = a
c) q = ap
d) z =ax + by + c
Code: 2K6M5:14RLevel :K
Unit : 2.2 Type : VSA
1.Define singular solution
2.Define complete solution
3.Define general solution
4.What is the solution to be assumed while solving PDE f(p, q) = 0
5.How do we assume a solution for PDE f1(x, p) = f2 (y, q)
6.The solution to be assumed while solving the equation f(p, q) = 0 is
a) p = a
b) q = ac) z = ax + by + cd) p = q = a
7. The solution to be assumed while solving the equation f1(x, p) = f2(y, q) is
a) f1(x, p) = f2(y, q) = ab) p = a c) q = a
d) q = ap
Code: 2K6M5:14RLevel :U
Unit : 2.2 Type : VSA
1.Write the solution of ( z / ( x = sin x
2.Write the solution of ( z / ( x = ex3.Write the order of x ( z / ( x = 1
4.Write the order of y ( z / ( y = 5
5.Write the order of x2 ( z / ( x = a
6.Write the order of y ( z / ( y = 6
7.Write the equation q p + x y = 0 in the form f1(x, p) = f2(y, q)
8.Write the equation p + q = sin x + sin y in the form f1(x, p) = f2(y, q)
9.Write the equation p2 y(1 + x2) = qx210.Write the equation p + x = qy in the form f1(x, p) = f2(y, q)
11.Write p + q = px + qy in the form f1(x, p) = f2(y, q)
Code: 2K6M5:14RLevel :U
Unit : 2.2 Type : PA
1.Solve p2 + q2 = 4
2.Solve p + q = x + y
3.Solve x ( z / ( x = 2x + y 4.Solve p + q = sinx +siny
5.Solve (2 z / ( x2 = xy + 3x
6.Solve p + x = qy
7.Solve x ( z / ( x = 2x + y
8.Solve (2 z / ( x ( y = x2 + y2 9. Solve p = q2
10. Solve ( p + ( q = 2x and (2 z / ( x ( y = cosx* cosy
11. Solve p2 2q2 = 4pq
12. Solve pq + p + q = 0
13. Solve p + q = 2x and x + y ( z / ( x = 0
14. Solve xp y2 q2 = 1 and (2 z / ( y2 = siny
15. Solve pq = xy
Code: 2K6M5:14RLevel :U
Unit : 2.2 Type : E
1.Solve i) pq = 1
ii) pq + p + q = 0
2.Solve i) pq = 4
ii) pq + p + 2q = 0
3.Solve i) q2 3p + q = 0
ii) p3 + q3 = 0
4.Solve i) 3p2 ( 2 q2 = 4pq
ii) p2 + q2 = npq
5.Solve i) p + q = x + y
ii) ( p + ( q = 2x
6.Solve i) p2 + q2 = x + y
ii) ( p + ( q = x
7.Solve i) p + q = sin x + sin y
ii) pq = xy
8.Solve i) 2yp2 = q
ii) xp y2 q2 = 1
9.Solve i) p2 y (1 + x2) = qx2
ii) py + qx = pq
10.Solve pq + qx = y
ii) p + q = px + qy
11.Solve i) p + x = qy
ii) py + qx = pq
Code: 2K6M5:14RLevel :K
Unit : 2.3 Type : MC
1.The tentative solution for f(x, p, q) = 0 is
a) x = constantb) y = constantc) p = constantd) q = constant
2.The tentative solution for f(y, p, q) = 0 is
a) x = constantb) y = constantc) p = constantd) q = constant
3.The tentative solution for f(z, p, q) = 0 is
a) x = ap
b) y = aq
c) p = aq
d) q = ap
4.The Clairauts form of P.D.E is
a) z = xp + yq + f(x, y)
b) z = xp + qy + f(p, q)
c) z = xp yq f(p, q)
d) z = xp + yq f(p, q)
5.Lagranges equation is obtained by eliminating
a) u & v from f(u, v) = 0
b) p & q from f(p, q) = 0
c) x & y from f(x, y) = 0
d) x & z from f(x, z) = 0
6.u(x, y, z) = c1 & v(x, y, z) = c2 are the solutions of the equations
a) dx / R = dy / P = dz / Q
b) dx / Q = dy / P = dz / R
c) dx / P = dy / Q = dz / R
d) dx / p = dy / q = dz / r
Code: 2K6M5:14RLevel :U
Unit : 2.3 Type : MC
1.For solving f(z, p, q) = 0, the substitution used is:
a) p=a
b) q=a
c) q=apd) p=q
2.For solving 9(2pz+3q)=z2, the substitution used is:
a) p=a
b) q=a
c) p=q+ad) p=aq
3.For solving z=pq, the substitution used is:
a) p=a
b) q=a+pc) q=apd) p=q24. The tentative solution for z = pq + 3q is
a) p =ab) q = ac) q = apd) p = aq
Code: 2K6M5:14RLevel :K
Unit : 2.3 Type : VSA
1.Write Lagranges equation
2.Write Clairauts form of P.D.E ?
3.What is the solution for Clairauts form of P.D.E ?
Code: 2K6M5:14RLevel :K
Unit : 2.3 Type : PA
1.Explain the procedure of solving the equation f (x, p, q) = 0 and hence solve p+q=x2.Explain the procedure of solving the equation f (y, p, q) = 0 and hence solve q=2yp23.Explain the procedure of solving the equation f (z, p, q) = 0 and hence solve z=p2+q2Code: 2K6M5:14RLevel :U
Unit : 2.3 Type : PA
1.Solve completely i) q = xp + q2
ii) p = y2 q22.Solve completely i) p = 2qx
ii) q = 2yp23.Solve completely 9(p2 z + q2) = 4
4.Solve completely i) p(1 + q) = qz
ii) pq = x
5.Solve completely 4(1 + z3) = 9z4 pq
6.Solve completely i) p2 z2 + q2 = 1
ii) q2 = yp47.Solve completely i) (p + (q = x
ii) z = p2 + q28.Solve completely i) p2 z2 + q2 = 1
ii) (p + (q = y
9.Solve completely i) p + q = z
ii) z2 (p2 + q2 + 1) = a210.Solve completely i) p(1+q2) = q(z-1)
ii) p2 = qz
11.Solve completely z = px + qy + pq
12.Solve completely z = px + qy + p/q-p
13.Solve completely (1-x) p + (2-y) q = 3-z
14.Solve completely z/pq = x/q + y/p + ( pq
15.Solve completely (y2 + z2) p- xyq = -xz
16.Solve completely (y + z) p + (z + x) q = x + y
17. Solve completely x2 p + y2 q = (x + y) z
18.Solve completely (x2 yz)p + (y2 zx)q = z2 - xy
19.Solve completely xp + yq = z
20.Solve completely xp - yq = xy
21.p tan x + q tan y = tan z
22.(y-z)p + (z-x)q = x-y
23.Solve x(y-z)p + y(z-x)q = z(x-y)
24.Solve x(y2 z2) + y(z2 x2) q = z(x2 - y2)
25.Solve xzp + yzq = xy
26.Solve up xq + x2 y2 = 0
27.Solve z(xp yq) = y2 x2
28.Solve (mz ny)p + (nx lz)q = ly - mx
29. Solve p q = log ( x + y)
30.Solve (xz + yz)p + (xz yz)q = x2 + y2
31.(x2 y2 z2)p + 2xyz = 2xz
32.(yz/x) p + xzq = y233.Solve (y + z x)p + (z + x y)q = x + y - z
34.Solve y2 zp = x2 zq = x2 y
35.Solve z = px + qy + 2 ( pq.
Code: 2K6M5:14RLevel :K
Unit : 2.3 Type : E
1.a) Explain the procedure of solving the equation f(x, p, q) = 0
b) Derive Lagranges equation.
Code: 2K6M5:14RLevel :U
Unit : 2.3 Type : E
1.a) Solve i) p = 2qx
ii) 9(p2 z + q2) = 4
b) Solve (y + z)p + (z + x)q = x + y
2.a) i) p = y2 q2
ii) p(1+q) = qz
b) Solve x(y2- z2) + y(z2 x2)q = z(x2 y2) = 0
3.a) q = 2yp2
ii) z = p2 + q2
b) Solve x(y z)p + y(z x)q = z(x y)
4.a) Solve i) q = xp + p
ii) pz + q = 1
b) Solve (mz ny)p + (nx lz)q = ly mx
5.a) Solve z = px + qy + p/q - p
b) Solve xzp + yzq = xy
6.a) Solve z = px + qy = 2(pq
b) p tan x + q tan y = tan z
7.a) Solve z px + qy + pq
b) Solve yp xq + x2 y2 = 0
8.a) Solve z/pq = x/q + y/p + (pq
b) Solve (xz + yz)p + (xz yz)q = x + y
9.a) Solve z = px + qy + 3 (pq
b) Solve y2 z p x2 z q = x2 y
Code: 2K6M5:14RLevel :K
Unit : 3.1 Type : MC
1.L(eat) is
a) b)
c)
d)
2.Le-at is
a)
b)
c) d)
3.L (coshat) is
a) b) c)
d)
4.L (sinhat) is
a)
b)
c)
d)
5.L (cosat) is
a)
b)
c)
d)
Code: 2K6M5:14RLevel :K
Unit : 3.1 Type : VSA
1.Define Laplace transform
Code: 2K6M5:14RLevel :U
Unit : 3.1 Type : VSA
1.Find L(t3 + 2t + 3)
2.Find L(t3 3t2 + 2)
3.Find L(at2 + bt + c)
4.Find L(t2 5t 7)
Code: 2K6M5:14RLevel :K
Unit : 3.1 Type : PA
1.Prove that L(f`(t)) = s2 L(f(t)) sf(0) f1 (0)
Code: 2K6M5:14RLevel :U
Unit : 3.1 Type : PA
1.Find L{f(t)}, where f(t) = 0 when 0 1
= 0 when t < 4
3.Find the Lapalce transform of
f (t) = e-1 when 0 4
4.Find the Laplace transform of
f(t) = sin t when 0