Cu06997 lecture 4_bernoulli-17-2-2013
-
Upload
henk-massink -
Category
Documents
-
view
2.301 -
download
1
Transcript of Cu06997 lecture 4_bernoulli-17-2-2013
CU06997 Fluid Dynamics
Principles of fluid flow 2.5 Application of the conservations laws to fluid flows (page 25-32)
2.6 Application of the energy equation (page 32 -36)
2.8 Velocity and discharge measurement (page 42 – 48)
1
Flowing water and energy
][2
2
1111 m
g
uyzH
u1
Reference /datum [m]
Surface level [m]
Total head H [m]
P1
z1
y1
u12/2g Velocity head [m], [snelheidsh..]
y = Pressure head [m]
[drukhoogte]
z = Potential head [m]
. [plaatshoogte]
1
Bernoulli’s Equation, no energy losses
Pressure Head[m] [drukhoogte]
Potential Head[m] [plaatshoogte]
Velocity Head[m] [snelheidshoogte]
𝑦1 + 𝑧1 +𝑢1
2
2𝑔= 𝑦2 + 𝑧2 +
𝑢22
2𝑔= 𝐻 = 𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡[𝑚]
y =p
ρ∙g=
𝑧 =
u2
2g=
2
Bernoulli’s law (without energy losses)
u2>0
Reference[m]
Surface Level [m]
Total Head [m]
P2
z2
y2
u22/2g Velocity head [m]
constant22
2
333
2
22211
g
uzy
g
uzyzy
P3 z3
y3
u32/2g
u3>u2 u1=0
P1
z1
y1
2
Pitot
𝑢 = 2 ∙ 𝑔 ∙ ℎ2
𝑢 = Fluid Velocity [m/s]
𝑔 = earths gravity [m/s2]
h = Difference in pressure [m]
3
u=0
Flowing water and energy
u1
Reference / datum [m]
Surface Level [m]
Total Head [m]
P1
z1
h1
v12/2g Velocity head [m]
Prandtl buis
][2
2
1111 m
g
uyzH
Small orifice
𝑄 = 𝐶𝑣 ∙ 𝐶𝑐 ∙ 𝐴0 ∙ 2𝑔 ∙ ℎ2
𝑄 = Flow rate [m3/s]
𝐴 = Wetted Area [m2]
𝐶𝑣 = velocity coefficient (0,97-0,99) [-]
𝐶𝑐 = contraction coefficient (0,61-0,66) [-]
𝑔 = earths gravity [m/s2]
h = Difference in pressure [m]
4
Large orifice
𝑄 =2
3∙ 𝑏 ∙ 2𝑔 ∙ (ℎ2
32 − ℎ1
32)
2
𝑄 = Flow rate [m3/s]
𝑏 = Width orifice [m2]
𝑔 = earths gravity [m/s2]
h1 = Difference in pressure from top [m]
h2 = Difference in pressure from bottom [m]
5
Bernoulli’s law, with head loss
u1
Reference [m]
Surfacelevel y +z [m]
Total Head H [m]
P1
z1
y1
u12/2g
P2 z2
y2
u22/2g
u2>u1
21
2
222
2
111
22 H
g
uzy
g
uzy
Head loss [m] ΔH
Velocity Head [m]
6
Bernoulli expressed in m (head)
𝐸𝑡𝑜𝑡𝑎𝑙 = 𝐸𝑝𝑜𝑡𝑒𝑛𝑡𝑖𝑎𝑙 + 𝐸𝑘𝑖𝑛𝑒𝑡𝑖𝑐
= 𝑚 ∙ 𝑔 ∙ 𝑑 + 12𝑚 ∙ 𝑢2
= 𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡 [𝐽 = 𝑁𝑚]
𝐸𝑡𝑜𝑡𝑎𝑙
𝑚∙𝑔= 𝑑 +
𝑢2
2𝑔=
𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡
𝑚∙𝑔 [m]
𝑑 = 𝑧 + 𝑦 = 𝑧 +𝑝
𝜌 ∙ 𝑔 [𝑚]
𝑯 = 𝒚 + 𝒛 +𝑽𝟐
𝟐∙𝒈 [m] Total Head
7
𝐻 = 𝑦 + 𝑧 +𝑢2
2∙𝑔 [m]
You also could express the energy in Pa (N/m2) instead of m.
𝑝 = 𝜌 ∙ 𝑔 ∙ 𝑦
If you combine 1 en 2 by multiply al parameters with 𝜌 ∙ 𝑔 (they don’t
change)
𝜌 ∙ 𝑔 ∙ 𝐻 = 𝜌 ∙ 𝑔 ∙ 𝑦 + 𝜌 ∙ 𝑔 ∙ 𝑧 + 𝜌 ∙ 𝑔 ∙𝑢2
2 ∙ 𝑔
𝐻 = 𝑝 + 𝜌 ∙ 𝑔 ∙ 𝑧 + 𝜌 ∙𝑢2
2 [𝑃𝑎]
7