CTS QUESTIONS AND SOLUTIONS.pptx

8/10/2019 CTS QUESTIONS AND SOLUTIONS.pptx

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QUESTIONS

&

ANSWERS

COGNIZANT TECHNOLOGY SOLUTIONS


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You are having 31kg of rice. You are provided with a

1kg stone for weighing. In how many weights the 31kg

of rice can be weighed. ?

Answer: 5

Explanation: 1+2+4+8+16 = 31.

2


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A starts at 11:00AM and travels at a speed of 4km/hr. Bstarts at 1:00PM and travels at 1km/hr for the first 1hr and

2km/hr for the next hr and so on. At what time they will

meet each other ?

Ans: 8.00 pm

Explanation:

Time 11.00 12.00 1.00pm

2.00pm

3.00pm

4.00pm

5.00pm

6.00pm

7.00pm

8.00pm

8.30pm

8.45pm

A 0 4 8 12 16 20 24 28 32 36

B 1 3 6 10 15 21 28 363


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There are 81 coins, among them one coin weighs less

compared to other. You are given a physical balance to

weigh. In how many weighing the odd coin can be found. 4 times.

Explanation: divide into three groups of 27 each. Weigh two

groups and chose one Divide into three groups of 9 each and chose one out of two.

Divide into three groups of 3 each and chose one.

Choose any two and weigh it to find the least.

4


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LOGICAL DEDUCTION

Statements:

Some shirts are biscuits.

No Biscuit is book

Conclusions:

I Some shirts are books

II Some books are biscuits.

I + E = O

None of the given

conclusion follow

Choice is D.

5


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LOGICAL DEDUCTION

Statements:

No women can vote.

Some women are politicians.

Conclusions:

I Male politicians can vote.

II Some politicians can vote.

No Conclusion.

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LOGICAL DEDUCTION

Statements:

No man is a donkey.

Rahul is a man.

Conclusions:

I Rahul is not a donkey.

II All men are not Rahul.

I + E = O

Conclusion I follows.

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LOGICAL DEDUCTION

Statements:

All poles are guns.

Some boats are not poles.Conclusions:

I All guns are boats.

II Some boats are not guns.

No conclusion.

We cannot come to a

conclusion that Some

boats are not gunsdefinitely.

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LOGICAL DEDUCTION

Statements:

All rats are cows.

No cow is whiteConclusions:

I No white is rat.

II No rat is white.III Some whites are rats.

IV All cows are rats.

A + E = E

No rat is white.

Conclusion II follows.

Correct choice is E.

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LOGICAL DEDUCTION

Statements:

All apples are brinjals.

All brinjals are ladyfingers.

All ladyfingers are oranges.

Conclusions:

I Some oranges are brinjals.

II All brinjals are apples.

III Some apples are oranges.

IV All ladyfingers are apples.

A + A = A

All apples are

oranges.

Choice is E.

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LOGICAL DEDUCTION

Statements:

All poles are guns.




No conclusion.

We cannot come to a



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LOGICAL DEDUCTION

Statements:

All poles are guns.




No conclusion.

We cannot come to a



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LOGICAL DEDUCTION

Statements:

All poles are guns.




No conclusion.

We cannot come to a



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LOGICAL DEDUCTION

Statements:

All poles are guns.




No conclusion.

We cannot come to a



14


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LOGICAL DEDUCTION

Statements:

All poles are guns.




No conclusion.

We cannot come to a



Because all boats

could be guns.All poles are guns does not imply that all things which are not

poles are not guns.

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LOGICAL DEDUCTION

Statements:

Most clocks are fans;

Some fans are walls

Conclusions :

I. Some walls are fans

II. Some clocks are walls

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I + I

NO CONCLUSION

GIVEN CONCLUSION 1 ISREPLICA OF SECOND

STATEMENT.


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LOGICAL DEDUCTION

Statements:

All birds are dogs;

Some dogs are cats

Conclusions :

I. Some cats are not dogs

II. All dogs are not birds

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A + I

NO CONCLUSION


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LOGICAL DEDUCTION

Statements:

Some fools are intelligent;

Some intelligent are great

Conclusions :I. Some fools are great

II. All great are intelligent.

NO CONCLUSION.

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LOGICAL DEDUCTION

Statements:

All Men are married;

Some men are educated

Conclusions :I. Some married are educated

II. Some educated are married.

BOTH CONCLUSIONS FOLLOWS..

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LOGICAL DEDUCTION

Statements: All bags are chalks; All chalks are bottles.Conclusions :

I Some bottles are bags.

II. All bags are bottles

III. All bottles are bags

IV. Some chalks are not bagsA) Only I, II and IV follow B) Only I, III and IV follow.C) Only II, III and IV follow. D) All Follow E) none of these

E) None of these. Only II follows.

Because I says some bottles are not bags (False)

By III all bottles need not be bags. (False)

Clearly IV is negative and contradicts the given statement 2. (False)

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LOGICAL DEDUCTION

Statements: Some trees are buses; All buses are hatsConclusions :

I Some trees are hats

II. Some hats are trees

III. All hats are buses

IV. Some buses are hatsA) None follows B) Only I, II and IV follow.C) Only II, III and IV follow. D) All Follow E) none of these

Conclusion is Some trees are hats.

Hence both I & II only follows.

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LOGICAL DEDUCTION

Statements :

All cars are tables;

Some children are tables

Conclusions :

I. Some cars are children

II. Some children are cars

No conclusion.

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LOGICAL DEDUCTION

Statements : Some dogs bark; All dogs bite

Conclusions :

I. Those dogs who do not bark, also bite.II. Those dogs who do not bark, not necessary

bite.

Conclusion I follows.

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LOGICAL DEDUCTION

Statements :

No magazine is cap;All caps are cameras

Conclusions :

I. No camera is magazine

II. Some caps are magazines

The conclusion is some magazines are not cameras

Hence none of the Given conclusion follows.

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LOGICAL DEDUCTION

Statements :

Some coolers are watches; no watch is bed

Conclusions :

I. No watch is cooler

II. No cooler is watch

III. Some watches are bedsIV. Some coolers are beds

A. None follows B. Only I and IV follow C. Only either II or III follows

C. Only either III or IV follows E. Only either II or IV follows

I + E = OHence Some coolers are not beds implies some coolers are beds. Hence onlyIV follows.

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LOGICAL DEDUCTION

Statements :

Some frogs are bricks; all bricks are cakes

Conclusions :

I. Some cakes are not frogs.

II. Some cakes are frogs.

III. No cake is frogIV. All frogs are cakes

A. None follows B. Only I and II follow C. Only either I, II and IIIfollow D. Only II, III or IV follows E. Only III and IV follow

I + A = I

Some frogs are cakes implies some cakes are frogs and some cakes arenot frogs.

Hence Only I and II follows. CHOICE B.

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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LOGICAL DEDUCTION

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ANALYTICAL ALGEBRA

48

A group of friends goes for dinner and gets bill of Rs 2400 . Two of them says

that they have forgotten their purse so remaining make an extra contribution of

Rs 100 to pay up the bill. Tell the no. of person in that group

Let N = number of people and S = Each personsshare.

NS = 2400S =2400

[1]

Now N 2 friends will pay S + 100 each.(N 2)(S + 100) = 2400NS + 100N 2S = 2600 [2]

Using [1] in [2], 2400 + 100N 2 2400

=2600

2400N + 100N24800 = 2600 N100N2200N 4800 = 0.

Solving, N = 6 or 8. Hence there are 8 friends in the group.


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ALGEBRA

11/25/2014C.S.VEERARAGAVAN 98948 34264

[email protected] 49

Given the following functions

(1) f(n a b c ) = ac if n=1

(2) f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) if n > 1.

Then what is the value f( 2 a b c ) = ?f( 2 a b c) = f(1 a c b) + f(1 a b c) + f(1 b a c)

= ab + ac + bc


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ALGEBRA

11/25/2014C.S.VEERARAGAVAN 98948 34264


There are 600 tennis players. 4% wear wrist band on one wrist Of

the remaining, 25% wear wrist bands on both hands.

How many players don't wear a wrist band?

There are 600 tennis players

4% wear wrist band on one wrist = 600 * 04 = 24.

Remaining players = 576

Of the remaining, 25% wear wrist bands on both hands

and Of the remaining, 75% do not wear wrist bands .

so players not wearing wrist bands =3

4*576 =144*3 = 432


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NUMBER SYSTEM


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NUMBER SYSTEM

11/25/2014C.S.VEERARAGAVAN 98948 34264


If all the 6 are replaced by 9, then the algebraic sum of all the numbers from 1 to 100(bothinclusive) varies by

Sum of all numbers from 1 to n is given by n(n+1)/2so sum of all numbers from 1 to 100 is 100*(100+1)/2 = 50506 comes 20times in the numbers from 1 to 100

6 comes in 'units' place 10 times in the numbers 1 to 100 i.e. 6,16,26,...., 96

6 comes in 'tens' place 10 times in the numbers 1 to 100 i.e. 60,61,62,....., 69

sum of these 6's is 10(6*10)+10(6*1)=600+60=660

if all 6's are replaced by 9

then sum of those 9's will be 10(9*10)+10(9*1)=990

now algebraic sum will be 5050-660+990= 5380

SHORTCUT:from 1 to 100, 6 is used 10 time at unit place and 10 timesat tenth place so on replaces it by 9 ,its value increased 30(10*3=30)due

to unit place and 300 (10*30 = 300) due to tenth place so total increase

will be 330

PROBABILITY


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PROBABILITY

Out of forty students, there are 14 who are taking Physics and29 who are taking Calculus. What is the probability that arandomly chosen student from this group is taking only theCalculus class?

n(Physics) = 14 & n(Calculus) = 29.

n(total) = 14 + 29 n (both) = 40.

n(both) = 3.

n(Calculus only) = 29 3 = 26.

P(Calculus only) =26

40

=13

20

=65%.

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VENN DIAGRAM


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VENN DIAGRAMIn town of 500 people, 285 read Hindu and 122 read Indian express and

127read Times of India 20 read Hindu and times of India and 29 read Hindu and

Indian express and 35 read Times of India and Indian express. 50 read no newspaper. Then how many read only one paper?

N(Total) = 500 N(Hindu) = 285

N(Indian) = 212 N(Times) = 127

N(H T) = 20 N(H I) = 29

N(T I ) = 35

N(H T I) = 450(285 + 122 + 127) + (20 + 29 + 35) = 450 (534) + (84)

N(H) = 285 49 = 136. N (I) = 12264 = 58 N(T) = 127 55 = 72

Number of persons who read only one paper = 266

H T

I50

X

20 - X

29 - X 35 - X

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VENN DIAGRAM


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VENN DIAGRAMIn a group of persons traveling in a bus, 6 persons can speak Tamil, 15 can

speak Hindi and 6 can speak Gujarati. In that group, none can speak any other

language. If 2 persons in the group can speak two languages and one personcan speak all the three languages, then how many persons are there in the

group ?

A) 21 B) 23 C) 22 D)24

X + Y + Z = 2

H = 15 14(X + Y)

T = 6 5 (X + Z)

G = 6 5 (Y + Z)

14 (X + Y) + 5 (X + Z) + 5 (Y + Z) + 3 = 242(X + Y + Z) = 27 4 = 23.

H T

G

1

X

Y Z

55

VENN DIAGRAM


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VENN DIAGRAM

Out of a total of 120 musicians in a club , 5% can play all the three instruments-

Guitar, Violin and Flute. It so happens that the number of musicians who can

play any two and only two of the above instruments is 30.

The number of musicians who can play the guitar alone is 40.

What is the total number of those who can play violin alone or flute alone ?

A) 30 B) 38 C) 44 D) 45

5% of 120 = 6 can play all 3.

X + Y + Z = 30

V + F = 120 (40 + 30 + 6)

= 44

G V

F

6

X

Y Z

40

56

VENN DIAGRAM


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VENN DIAGRAM

57

In a town 65% people watched the news on television, 40% read a

newspaper and 25% read a newspaper and watched the news on

television also.

What percent of the people neither watched the news on television

nor read a news paper ?

A) 5 B) 10 C) 15 D) 2065 + 40 25 = 80

80% watched tv or read newspaper or both.

Hence 20% neither watched tv nor read newspaper.

POWERS


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POWERS

58

A secret can be told only 2 persons in 5 minutes .the same person

tells to 2 more persons and so on. How long will take to tell it to

768 persons ?

a)47.5 min b)50 min c) 500 min d)49 min

29= 512 & 210= 1024.

In 9 x 5 = 45 minutes secret spread to 512 persons.

768 = 512 + of 512.

Hence 45 + of 5 = 47.5 min.

AGE


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AGE

59

When I was married 10 years ago my wife is the 6th member of the

family.

Today my father died and a baby born to me.

The average age of my family during my marriage is same as today.

What is the age of Father when he died?

Let the age of Father ten years ago be x. Remaining 6 persons total be y.

Average 10 years ago =x+y6

After 10 years Average =

y+5(10)

6 =

50+y

6

Equating both we have x = 50

Present Age of Father = 60

BOAT & STREAMS


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BOAT & STREAMS

60

A son and father goes for boating in river upstream .

After rowing for 1 mile son notices the hat of his father falling in the river.

After 5 min. he tells his father that his hat has fallen.

So they turn round and are able to pick the hat at the point from where theybegan boating after 5min.

Tell the speed of river?

The hat fallen after travelling one mile and after that they travelled for 5MIN.

so that hat travelled down stream for one mile and they collected the hatafter 5mins of travel down stream.

So the total time they spent after losing hat is 10 minutes.

In this 10 minutes the hat exactly travelled 1 mile(i.e with river speed).

the river speed is 6miles/hour.

HCF & LCM


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HCF & LCM

61

There are three departments having students 64,58,24 .

In an exam they have to be seated in rooms such that each roomhas equal number of students and each room has students of one

type only (No mixing of departments).

Find the minimum number rooms required ?

The HCF is 2.

Hence 32 + 29 + 12= 73.

PERMUTATION & COMBINATION


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PERMUTATION & COMBINATION

62

Argentina had football team of 22 player of which captain is from

Brazilian team and goalki from European team.

For remaining player they have picked 6 from Argentinean and 14

from European.

Now for a team of 11 they must have goalki and captain so out of 9

now they plan to select 3 from Argentinean and 6 from European.

Find out number of methods available for it.

6C3* 14C6= 160600

DATA SUFFICIENCY


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DATA SUFFICIENCY

63

(a) if the data in statement I alone are sufficient to answer the question;

(b) if the data in statement II alone are sufficient to answer the question;

(c) if the data in either in I or II alone are sufficient to answer the question;

(d) if the data in both the statements together are not sufficient to answer the question;

(e) if the data in both the statements together are needed;

How many visitors saw the exhibition yesterday?

I. Each entry pass holder can take up to three persons with him / her.

II. In all, 243 passes were sold yesterday.

Ans: D

DATA SUFFICIENCY


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DATA SUFFICIENCY

64






How much was the total sale of the company?I. The company sold 8000 units of product A each costing Rs. 25.

II. The company has no other product line

Ans: E

DATA SUFFICIENCY


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DATA SUFFICIENCY

65






In what proportion would Raj, Karan and Altaf distribute profit among them

I. Raj gets two-fifth of the profit.

II. Karan and Althaf have made 75% of the total investment.

Ans: D

DATA SUFFICIENCY


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DATA SUFFICIENCY

66






What time did the train leave today.

I. The train normally leaves on time

II. The scheduled departure is at 14.30.

Ans: D

DATA SUFFICIENCY


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DATA SUFFICIENCY

67






On which day in January, Subhas left for Germany?

I. Subhas has so far spent 10 years in Germany.

II. Subhas' friend Anil left for Germany on 15th February and joined

Subhas 20 days after Subhas' arrival.

Ans: D.

CONVERT THE GIVEN BINARY NUMBERS


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CONVERT THE GIVEN BINARY NUMBERS.

68

(11100111)2= ( )16

1110 0111

14 7

(E7)16



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69

(01011010)2=( )8

01 011 010

1 3 28



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70

(11110000)2= ( )10

1 1 1 1 0 0 0 0

7 6 5 4 3 2 1 0

27 26 25 24 23 22 21 20

128 64 32 16 0 0 0 0

(240)10


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(01001110)2= ( )8

01 001 110

1 1 6

1168

2 sides coloured = 12 * (N-2)CUBES & CUBOIDS


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N = 3 sides coloured = 8

( )

1 side coloured = 6 * (N-2)2

0 sides coloured = (N-2)3

CUBES & CUBOIDS

a cube is coloured orange on one face, pink on the opposite face,

brown on one face and silver on a face adjacent to the brown face.

The other two faces are left uncoloured.

It is then cut into 125 smaller cubes of equal size.

Now, answer the following questions based on the above statements:

73

How many cubes have at least one face coloured pink ?

A) 1 B)9 C) 16 D) 25

Ans: D



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CUBES & CUBOIDS






74

How many cubes have all the faces uncoloured ?

A) 24 B)36 C) 48 D) 64Ans: C



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CUBES & CUBOIDS






75

How many cubes have at least two faces coloured ?

A) 19 B)20 C) 21 D) 23Ans: C



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CUBES & CUBOIDS






76

How many cubes are coloured orange on one face and have the

remaining faces uncoloured?A) 8 B) 12 C) 14 D) 16

Ans: D



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CUBES & CUBOIDS






77

How many cubes one coloured silver on one face, orange or pink on

another face and have four uncoloured faces?

A) 8 B) 10 C) 12 D) 16

Ans: A

REASONING LINEAR ARRANGEMENT S P


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REASONING LINEAR ARRANGEMENT

78

Five children are sitting in a row.

S is sitting next to P but not T.

K is sitting next to R who is sitting on the extreme left and

T is not sitting next to K.

Who are sitting adjacent to S?

A) K and P B) R and P C) Only P D) P and T E) Insufficient Information.Ans: D

S P

P S

R K

K T

T S

S TR K S P T



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79

In the Olympic Games, the flags of six nations were flown on the masts in the

following way.

The flag of America was to the left of Indian tricolour and to the right of the flag of

France.

The flag of Australia was on the right of the Indian flag but was to the left of the flag

of Japan, which was to the left of the flag of China.

Find the two flags which are in the centre.

A) India and Australia B) America and India C) Japan and Australia D) America

and Australia

Ans: A



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80

There are five friends Sachin, Kunal, Mohit, Anuj and Rohan.

Sachin is shorter than Kunal but taller than Rohan.

Mohit is tallest.

Anuj is a little shorter than Kunal and little taller than Sachin.

Who is the shortest?

(a) Rohan(b) Sachin

(c) Anuj

(d) Kunal

(e) None of these

Ans: A

Rohan Sachin Anuj Kunal Mohit



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81



Mohit is tallest.


If they stand in the order of their heights, who will be in the middle?

(a) Kunal

(b) Rohan

(c) Sachin

(d) Anuj

(e) None of these

Ans: D




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82



Mohit is tallest.


If they stand in the order of increasing heights, who will be the second?

(a) Anuj

(b) Sachin

(c) Rohan

(d) Kunal

(e) None of these

Ans: B




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SO G G

83



Mohit is tallest.


Who is the second tallest?

(a) Sachin (b) Kunal (c) Anuj (d) Rohan (e) None of these

Ans: B




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84



Mohit is tallest.


Who is taller than Anuj but shorter than Mohit?

(a) Kunal

(b) Rohan

(c) Sachin

(d) Date Inadequate (

(e) None

Ans: A




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85

In a March Past, seven persons are standing in a row.

Q is standing left to R but right to P.

O is standing right to N and left to P.

Similarly, S is standing right to R and left to T.

Find out who is standing in the middle.

A) P B) Q C) R D) O

REASONING CIRCULAR ARRANGEMENT


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86

Mr. A, Miss B, Mr. C and Miss D are sitting around

a table and discussing their trades.

1. Mr. A sits opposite to cook

2. Miss B sits right to the barber.

3. The washer man is on the left of the tailor

4. Miss D sits opposite Mr. CWhat are the trades of A and B?

A. Tailor and Barber

B. Tailor and cook

C. Barber and cook

D. washer man and cook

A

TABLE

COOK

TABLEBARBER

B

TAILOR

WASHER

MAN

D

/C

C

/D



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87

In a pile of 10 books, there are 3 of History, 3 of Hindi, 2 of mathematics and 2 of

English. Taking from above,

there is an English book between a history and mathematics book,

a history book between a mathematics and an English book,

a Hindi book between an English and a mathematics book,

a mathematics book between two Hindi books and

two Hindi books between a Mathematic and a History book.

Book of which subject is at the sixth position from top ?

A. English B. Hindi C. Mathematics D. History

ENGLISH

HISTORY

MATHS

HISTORY

REASONING


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88

One boy can eat 100 chocolates in half a minute, and anothercan eat half as many in twice the length of time. How many

chocolates can both boys eat in 15 seconds?1st boy eats 100 chocolates / 30 sec so he can eat 50 in 15sec

2nd boy can eat one-half of 100 in twice of 30 sec

so he can eat 50 in 60 sec or that is 12.5 in 15 sec

so, together they can eat 50 + 12.5 or 62.5 chocolates in 15seconds.

REASONING PERCENTAGE


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89

Potatoes are made up of 99% water and 1% "potato matter."Jack bought 100 pounds of potatoes and left them outside in the sun for a while.

When he returned, he discovered that the potatoes had dehydrated and were now only madeup of 98% water.

How much did the potatoes now weigh?

initially water weigh 99 pounds & patato matter weigh 1 pound.

after dehydration water = 98%

=> potato matter = 2% = 1 pound

100% = (1/2) * 100 = 50 pounds

So, potato now weigh 50 pounds.

REASONING


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You own a pet store.

If you put in one canary per cage, you have one canary too many.

If you put in two canaries per cage, you have one cage too many.

How many canaries and cages do you have?

Ans: four canaries and three cages.

CTS QUESTIONS AND SOLUTIONS.pptx

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