CS4432: Database Systems II

CS 4432 lecture #10 - b+ tree indexing

1

CS4432: Database Systems IILecture #10

Professor Elke A. Rundensteiner


2

Example Sequential Index

continuous

free space

102030

405060

708090

39313536

323834

33

overflow area(not sequential)


3

• Without re-organization we get unpredictable performance

• Too much/often re-organization brings too much overhead

• DBA does not know when to reorganize

• DBA does not know how full to loadpages of new index

Problems … Problems … Problems …


4

Another type of index

• Give up “sequentiality” of index• Predictable performance under

updates• Achieve always balance of “tree” • Automate restructuring under

updates


5

Root

B+Tree Example n=3

100

120

150

180

30

3 5 11

30

35

100

101

110

120

130

150

156

179

180

200


6

Sample non-leaf

to keys to keys to keys to keys

< 57 57 k<81 81k<95 95

57

81

95


7

B+ Trees in Practice

• Typical order: 100. Typical fill-factor: 67%.– average fanout = 133

• Typical capacities:– Height 4: 1334 = 312,900,700 records– Height 3: 1333 = 2,352,637 records

• Can often hold top levels in buffer pool:– Level 1 = 1 page = 8 Kbytes– Level 2 = 133 pages = 1 Mbyte– Level 3 = 17,689 pages = 133 MBytes


8

Sample non-leaf

to keys to keys to keys to keys

< 57 57 k<81 81k<95 95

57

81

95


9

Sample leaf node:

From non-leaf node

to next leafin

sequence5

7

81

95

To r

eco

rd

wit

h k

ey 5

7

To r

eco

rd

wit

h k

ey 8

1

To r

eco

rd

wit

h k

ey 8

5


10

In textbook’s notationn=3

Leaf:

Non-leaf:

30

35

30

30 35

30


11

Size of nodes: n+1 pointersn keys

(fixed)


13

Full nodemin. node

Non-leaf

Leaf

n=3

12

01

50

18

0

30

3 5 11

30

35

counts

even if

null

Non-leaf: (n+1)/2 pointers

Leaf: (n+1)/2 pointers to data


14

B+tree rules tree of order n

(1) All leaves at same lowest level(balanced tree)

(2) Pointers in leaves point to records except for “sequence pointer”


16

Root

B+Tree Example : Searches

100

120

150

180

30

3 5 11

30

35

100

101

110

120

130

150

156

179

180

200


17

Insert into B+tree

(a) simple case– space available in leaf

(b) leaf overflow(c) non-leaf overflow(d) new root


18

(a) Insert key = 32 n=33 5 11

30

31

30

100

32


19

(a) Insert key = 7 n=3

3 5 11

30

31

30

100

3 5

7

7


20

(c) Insert key = 160 n=3

10

0

120

150

180

150

156

179

180

200

160

18

0

160

179


21

(d) New root, insert 45 n=3

10

20

30

1 2 3 10

12

20

25

30

32

40

40

45

40

30new root


22

Recap: Insert Data into B+ Tree

• Find correct leaf L. • Put data entry onto L.

– If L has enough space, done!– Else, must split L (into L and a new node L2)

• Redistribute entries evenly, copy up middle key.• Insert index entry pointing to L2 into parent of L.

• This can happen recursively– To split index node, redistribute entries evenly, but

push up middle key. (Contrast with leaf splits.)

• Splits “grow” tree; root split increases height. – Tree growth: gets wider or one level taller at top.


23

(a) Simple case (b) Coalesce with neighbor (sibling)

(c) Re-distribute keys(d) Cases (b) or (c) at non-leaf

Deletion from B+tree


24

(a) Delete key = 11 n=33 5 11

30

31

30

100


25

(b) Coalesce with sibling– Delete 50

10

40

100

10

20

30

40

50

n=4

40


26

(c) Redistribute keys– Delete 50

10

40

100

10

20

30

35

40

50

n=4

35

35


27

40

45

30

37

25

26

20

22

10

141 3

10

20

30

40

(d) Coalese and Non-leaf coalese– Delete 37

n=4

40

30

25

25

new root


28

Delete Data from B+ Tree

• Start at root, find leaf L where entry belongs.• Remove the entry.

– If L is at least half-full, done! – If L has only d-1 entries,

• Try to re-distribute, borrowing from sibling (adjacent node with same parent as L).

• If re-distribution fails, merge L and sibling.

• If merge occurred, must delete entry (pointing to L or sibling) from parent of L.

• Merge could propagate to root, decreasing height.


29

• Concurrency control harder in B-Trees• B-tree consumes more space• B-tree automatically decides :

– when to reorganize– how full to load pages of new index

• Buffering– B-tree: has fixed buffer requirements– Static index: must read several overflow blocks to be efficient (variable size buffers)

Discussion of B-trees (vs. static indexed sequential files)


30

ComparisonB-tree vs. indexed seq.

file• Less space, so

lookup faster• Inserts managed

by overflow area• Requires

temporary restructuring

• Unpredictable performance

• Consumes more space, so lookup slower

•Each insert/delete potentially restructures

•Build-in restructuring

• Predictable performance


31

• Speaking of buffering… Is LRU a good policy for B+tree

buffers?Of course not!

Should try to keep root in memory at all times

(and perhaps some nodes from second level)


33

Interesting problem:

For B+tree, how large should n be?

…

n is number of keys / node


34

assumptions: n children per node and N records in database

(1) Time to read B-Tree node from disk is (tseek + tread*n) msec.(2) Once in main memory, use binary search to locate key, (a + b log_2 n) msec(3) Need to search (read) log_n (N) tree nodes

(4) t-search = (tseek + tread*n + (a + b*log_2(n)) * log n (N)


35

Can get: f(n) = time to find a record

f(n)

nopt n

FIND nopt by f’(n) = 0

What happens to nopt as:•Disk gets faster? CPU get faster? …


36

Bulk Loading of B+ Tree

• For large collection of records, create B+ tree.• Method 1: Repeatedly insert records slow.• Method 2: Bulk Loading more efficient.


37

Bulk Loading of B+ Tree

• Initialization: – Sort all data entries – Insert pointer to first (leaf) page in new (root) page.

3* 4* 6* 9* 10* 11* 12* 13* 20* 22* 23* 31* 35* 36* 38* 41* 44*

Sorted pages of data entries; not yet in B+ treeRoot


38

Bulk Loading (Contd.)

• Index entries for leaf pages always entered into right-most index page

• When this fills up, it splits.

Split may go up right-most path to root.

3* 4* 6* 9* 10*11* 12*13* 20*22* 23* 31* 35*36* 38*41* 44*

Root

Data entry pages

not yet in B+ tree3523126

10 20

3* 4* 6* 9* 10* 11* 12*13* 20*22* 23* 31* 35*36* 38*41* 44*

6

Root

10

12 23

20

35

38

not yet in B+ treeData entry pages


39

Summary of Bulk Loading

• Method 1: multiple inserts.– Slow.– Does not give sequential storage of leaves.

• Method 2: Bulk Loading – Has advantages for concurrency control.– Fewer I/Os during build.– Leaves will be stored sequentially (and

linked) – Can control “fill factor” on pages.

CS4432: Database Systems II

Documents

Transcript of CS4432: Database Systems II