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Cosmic Brownies. Attack of the Demon Sun. Not To Scale. 1.5*10 8 km. 0.56m. 2.9m. 2.9m. Φ = π -2 ϴ. ϴ = tan -1 (2.9/.56) = 1.38 rad. Φ = 0.38 rad. Φ. 2.9m. ϴ ϴ. 0.56 m. ϴ = 1.38 rad. Φ = 0.38 rad. Night Fall @ 18:30. Day Break @ 5:30. 0 .38*780 π. 11:13 – 12:47. - PowerPoint PPT Presentation

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Cosmic Brownies

Cosmic BrowniesAttack of the Demon SunNot To Scale1.5*108 km2.9m2.9m0.56m2.9m0.56m = -2 = tan-1(2.9/.56) = 1.38 rad = 0.38 rad = 1.38 rad = 0.38 radDay Break @ 5:30Night Fall @ 18:30780 min in the dayHorizon1.38*7801.38*7800.38*780343 min343 min94 min11:13 12:475:30 11:1312:47 18:30So during the time of 11:13 and 12:47 We should be getting the most hits

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The time we detect the maximum number of muons should be at precisely the peak of the solar day. However is seems to more often be around 1pm.

The amount of muons hitting our detector should increase and decrease in a 24 hour cycle. This does not mean however that at noon there will be a peak in the number of muons produced. Assuming there is a consistent stream of cosmic rays coming in from the sun, then at noon it should peak, although the particles creating the muons in the atmosphere will be much older than the light we see because the particles travel slower. There are other factors in the amount of muons, for example as the distance between the earth and sun increases or decreases.list of causes of changes in # of cosmic rayssolar day (roughly 24 hour cycle what we were looking at)11 years Schwabe cycle(increase/decrease in sunspots)22 years Hale cycle(suns poles full revolution of suns poles)