Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Section 2.1 The Addition Principle of...
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Transcript of Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Section 2.1 The Addition Principle of...
![Page 1: Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. Section 2.1 The Addition Principle of Equality.](https://reader035.fdocuments.us/reader035/viewer/2022081808/5a4d1afe7f8b9ab059985cf5/html5/thumbnails/1.jpg)
Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
Section 2.1
The Addition Principle of
Equality
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2Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
Equations
An equation uses an equal sign (=) and indicates that two expressions are equal.
6 + 7 = 13An equation always has an equal sign.
6 + 7 = xThe solution of an equation is the number which makes the equation true.
6 + 7 = 1313 is the solution for this equation since it makes 6 + 7 = x true.
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3Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
Equivalent Equations
Equations that have exactly the same solution are called equivalent equations.
x = 77 is the solution to the equation 6 + x = 13.
6 + x = 13
The process of finding all solutions of an equation is called solving the equation.
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4Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
The Addition Principle
6 + x = 13
Left side Right side
We need to find the value of x.
6 + x + (6) = 13 + (6) Adding (6) to both sides of the equation will maintain the balance of the equation.
x = 7
Solution to the equation.
The Addition PrincipalIf the same number is added to both sides of anequation, the results on both sides are equal in value.
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5Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
Example
a 6.2 = 3.5
Check your answer in the original equation.
a 6.2 + (6.2) = 3.5 + (6.2)
6.2 is the opposite of 6.2. Add 6.2 to both sides of the equation.
a = 2.7
(2.7) 6.2 = 3.5
Solve a 6.2 = 3.5.
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6Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
Example
Solve for c.3c 8 = 2c 15
3c 8 + 8 = 2c 15 + 8 Add 8 to both sides of the equation.
3(7) 8 = 2(7) 15
3c = 2c 7
3c + (2c) = 2c 7 + (2c) Add 2c to both sides of the equation.c = 7
21 8 = 14 15
29 = 29
Check your answer in the original equation.
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7Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
Example
Is 5 the solution of the equation –10 + 4 = x – 2?
Solve for the solution.Thus, 5 is not the solution.
Substitute 5 for x and see if we obtain an identity.
–10 + 4 = x – 2–10 + 4 = 5 – 2
–6 ≠ 3
–10 + 4 = x – 2–6 = x – 2–4 = x
Check: Replacing x with –4 in the original equation, verifies the solution.
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8Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc.
Example
Find the value of y that satisfies the equation
The LCD is 10.
Be sure to check your answer in the original equation.
2 1 35 2 10y
2 2 1 5 35 2 2 5 10
y
4 5 310 10 10
y
4 210 10
y
2 110 5
y Add to both sides of
the equation and simplify.
410
Simplify.
Simplify.