Continuous Compounding
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Transcript of Continuous Compounding
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Continuous Compounding
Continuous Compounding
• Based on the assumption that cash payments occur once per year but compounding is continuous throughout the year.
Review: Future Amount, F
Future Amount or Future Worth • F = P(1 + i)n
Where: • P = principal • i = interest per period (in
decimal) • n = number of interest
periods • (1 + i)n = single payment
compound amount factor.
PW
FW
0 1 2 3 4 … n
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For m periods of year…
Future Amount or Future Worth
• F = P(1 + i)n
• F = P(1 + 𝑁𝑅
𝑚)mn
PW
FW
0 1 2 3 4 … m
Future Worth of Continuous Compounding
Let x = 𝑚
𝑁𝑅
• F = P(1 + i)n
• F = P(1 + 𝑁𝑅
𝑚)mn
• F = P(1 + 1
𝑥)x(NR)n
• F = P[(1 + 1
𝑥)x](NR)n
• But lim𝑥→∞
(1 + 1
𝑥)x = e
Thus, • F = Pe(NR)n
Where: • P = principal • e = 2.71828… • NR = nominal rate • n = number of years • e(NR)n = continuous
compounding amount factor
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Present Worth of Continuous Compounding
Present Amount or Present Worth
• P = F
e(NR)n
PW
FW
0 1 2 3 4 … m
Problem #15
• Money is deposited in a certain account for which the interest is compounded continuously.
• If the balance doubles in 6 years, what is the annual percentage rate?
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Solution
• F = Pe(NR)n
• 2P = Pe(NR)6
• 2 = e6(NR)
Take ln on both sides
• ln 2 = ln e6(NR)
• ln 2 = 6(NR) ln e
• ln 2 = 6(NR)
• NR = ln 2
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• NR = 0.1155
• NR = 11.5524%
ME Board Problem #16
• A nominal interest of 3% compounded continuously is given on the account.
• What is the accumulated amount of Php 10,000 after 10 years?
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Solution
• F = Pe(NR)n
• F = (10,000) e(0.03)10
• F = (10,000) e(0.3)
• F = Php 13,498.5880
Nominal and Effective Rate of Interest
Rate of Interest
• The cost of borrowing money.
• Also refers to the amount earned by a unit principal per unit time.
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Two Types of Rate of Interest
Two Types of Rate of Interest
1. Nominal Rate of Interest
• The basic annual rate of interest.
2. Effective Rate of Interest
• The actual or the exact rate of interest earned on the principal during a one-year period .
Problem #17
• A principal is invested at 5% compounded quarterly.
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Solution
• Nominal Rate of Interest = 5%
• Effective Rate of Interest => 5%, because of the compounding which occur four times a year.
Effective Rate of Interest
Effective Rate of Interest
• ER = (1 + i)m – 1 or ER = (1 + 𝑁𝑅
𝑚)m – 1
Where: • m = number of interest period per year • i = interest per period • NR = nominal rate of interest
Note: • NR is the mode of compounding is annually
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Solution
• Nominal Rate of Interest = 5%
• Effective Rate of Interest => 5.0945%, because of the compounding which occur four times a year.
• ER = (1 + 𝑁𝑅
𝑚)m – 1
• ER = (1 + 0.05
4)4 – 1
• ER = 0.0509
• ER = 5.0945%
ECE Board Problem #18
• What is the effective rate corresponding to 18% compounded daily?
• Take 1 year is equal to 360 days.
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Solution
• ER = (1 + i)m – 1
• ER = (1 + 0.18
360)360 – 1
• ER = 0.1971
• ER = 19.7163%
ECE Board Problem #19
• What nominal rate, compounded semi-annually, yields the same amount as 16% compounded quarterly?
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Solution
• ER1
2
= ER1
4
• (1 + 𝑁𝑅
2)2 – 1 = (1 +
𝑁𝑅
4)4 – 1
• (1 + 𝑁𝑅
2)2 = (1 +
0.16
4)4
• (1 + 𝑁𝑅
2)2 = 1.1698
• 1 + 𝑁𝑅
2 = 1.0816
•𝑁𝑅
2 = 0.0816
• NR = 0.1632 • NR = 16.32%
ECE Board Problem #20
• What rate of interest compounded annually is the same as the rate of interest of 8% compounded quarterly.
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Solution
• ER1 = ER1
4
• (1 + i)1 – 1 = (1 + 𝑁𝑅
4)4 – 1
• (1 + i) = (1 + 0.08
4)4
• (1 + i) = 1.0824
• i = 0.0824
• i = 8.2432%
ECE Board Problem #21
• Find the nominal rate, which if converted quarterly could be used instead of 12% compounded semi-annually?
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Solution
• ER1
4
= ER1
2
• (1 + i)4 – 1 = (1 + 𝑁𝑅
2)2 –
1
• (1 + i)4 = (1 + 0.12
2)2
• (1 + i)4 = 1.1236
• i = 0.0295
• i = 2.9563%
But :
• i = 𝑁𝑅
𝑚
• 0.0295 = 𝑁𝑅
4
Thus,
• NR = 0.1182
• NR = 11.8252%
ECE Board Problem #22
• What is the corresponding effective rate of 18% compounded semi-annually?
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Solution
• ER = (1 + i)m – 1
• ER = (1 + 0.18
2)2 – 1
• ER = 0.1881
• ER = 18.81%
ME Board Problem #23
• What is the corresponding effective interest rate of 18% compounded quarterly?
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Solution
• ER = (1 + i)m – 1
• ER = (1 + 0.18
4)4 – 1
• ER = 0.1925
• ER = 19.2518%
ME Board Problem #24
• Compute the equivalent rate of 6% compounded semi-annually to a rate compounded quarterly.
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Solution
• ER quarterly = ER annually
• (1 + 𝑖
4)4 – 1 = (1 +
0.06
2)2 – 1
• (1 + 𝑖
4)4 = (1 +
0.06
2)2
• i = 0.0595
• i = 5.9556%
EE Board Problem #25
• A man borrowed Php 100,000 at the interest rate of 12% per annum, compounded quarterly.
• What is the effective rate?
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Solution
• ER = (1 + i)m – 1
• ER = (1 + 0.12
4)4 – 1
• ER = 0.1255
• ER = 12.5508%
ME Board Problem #26
• An interest rate is quoted as being 7.5% compounded quarterly.
• What is the effective annual interest rate?
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Solution
• ER = (1 + i)m – 1
• ER = (1 + 0.075
4)4 – 1
• ER = 0.0771
• ER = 7.7135%
ME Board Problem #27
• A bank pays one percent interest on savings account four times a year.
• The effective annual interest rate is
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Solution
• ER = (1 + i)m – 1
• ER = (1 + 0.01)4 – 1
• ER = 0.0406
• ER = 4.0604%