Connnecction Design Combined

7/24/2019 Connnecction Design Combined

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Design of base plates at parapet:

Given:

For steel element: For supporting element:

d = 150.00 mm l = large mmbf = 100.00 mm w = large mm

Fy = 415.00 Mpa f'c = 10 Mpa

Pu = 15,230.00 N

Required base plate area:

If A1 = A2:

φc = 0.65

A1 required =

= mm2

Checking if A1 required > Column area:

A1 required=

Acolumn= bf x d= 150mm(100mm)

= 15000 mm2

> mm2

1 Remarks:

2 A1 revised= 30,000.00 mm2

use A1= mm2

15230N

no revision needed-you can proceed-2 governs

30000.00

For large supporting

elements:= doesn't apply

= 2.00DESIGNER'S DECISION:

= 2.00

=0.85(0.65)(10Mpa)(2)

1378.28

1378.280543 mm2

1378.28

use larger area

2

1

A

A

2

1

A

A

2

1

A A

1 required

2

1

(0.85 ' )

u

c c

P A

A f

A



Optimizing base plate dimension:

=

200 mm -

200 mm -

use A1= mm2

Checking the bearing strength of concrete:

=

= 442,000.00 N > N OK

Computing Required base plate thickness:

= 2.76506462 mm

use: 6.35 mm

In English system 1/4 in

Final base plate size:

B= mmN= mm

t= mm

150

= mm

0.95(150) - 0.8(100)2

= 31.25 mm

204.46

0.85(0.65)(10)(40000)(2)

15,230.00

40000.00

mm

Use:

Use:

=

200 - 0.95(150mm)

2= 28.75 mm

200

200 - 0.8(100mm)

2= 60.00 mm

(150mmX100mm)^0.52

= 61.24 mm

61.24 mm

2(15230N)

0.9(415Mpa)(200mm)(200mm)61.2372435695795 mm

-

200

6.35

0.95 0.8

2

f d b

1 + N A

1A

= B N

2

1

1

= 0.85 'c p c c

A

P f A A

0.95d =

2

N m

0.95d =

2

N m

0.8bn =

2

f B

db

n' =4

f

maximum of m, n, n' =

2 =

0.9

ureqd

y

P t

F BN



Choosing of anchor bolts:

Given:

Plate element: Bolt element:

t = mm Fy = 248.00 Mpa

Fy = Mpa Fu = 415.00 Mpa

Fu = Mpa Fnv = 188 Mpa

Vux = N = 506.71 mm2

Vuz = N = 4.00 pcs -

d = 12.7 mm

φ = 0.75

lcx = 23.65 mm

lcz = 23.65 mm

d = 1/2 in

Bearing strength of bolts:

At x-direction:

80,128.87 N

= N N

Governing Rn:

Rn = N

Ru = N

At z-direction:= 2.4(12.7mm)(6.35mm)(414Mpa)

= 80,128.87 N

= N < 80,128.87 N

Governing Rn:

Rn = N

Ru = N


At x-direction:

= 71,445.76 N

At Z-direction:

= 71,445.76 N

from bolt hole to

edge of plate x

direction:

= 30.00

mm

74,608.18

from bolt hole to

edge of plate z

direction:

= 30.00

mm

248

414

= sufficient!!0.75(188Mpa)(506.70753497mm2)

1.2(23.65mm)(6.35mm)(414Mpa)

6.35

=

=

18380 Areaanchor bolt

=

55,956.14

sufficient!!0.75(188Mpa)(506.70753497mm2)

<

74,608.18

80,128.87

2.4(12.7mm)(6.35mm)(414Mpa)

74,608.18

74,608.18

no. of bolts

sufficient!!

sufficient!!

4940

55,956.14

1.2(23.65mm)(6.35mm)(414Mpa)

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

A

u nv anchor bolt R F

A





d = 150.00 mm l = 200.00 mmbf = 100.00 mm w = 200.00 mm

Fy = 415.00 Mpa f'c = 10 Mpa

Pu = 17,060.00 N


If A1 = A2:

φc = 0.65

A1 required =

= mm2


A1 required=


= 15000 mm2

> mm2

1 Remarks:

2 A1 revised= 30,000.00 mm2

use A1= mm2

17060N


30000.00


elements:= 1.00


= doesn't apply

=0.85(0.65)(10Mpa)(1)

3087.78

3087.782805 mm2

3087.78

use larger area

2

1

A

A

2

1

A

A

2

1

A A

1 required

2

1

(0.85 ' )

u

c c

P A

A f

A

Design of base plates at parapet wall column:

Given:




=

200 mm -

200 mm -

use A1= mm2


=

= 221,000.00 N > N OK


= 2.92647519 mm

use: 6.35 mm



B= mmN= mm

t= mm

150

= mm

0.95(150) - 0.8(100)2

= 31.25 mm

204.46

0.85(0.65)(10)(40000)(1)

17,060.00

40000.00

mm

Use:

Use:

=

200 - 0.95(150mm)

2= 28.75 mm

200

200 - 0.8(100mm)

2= 60.00 mm

(150mmX100mm)^0.52

= 61.24 mm

61.24 mm

2(17060N)

0.9(415Mpa)(200mm)(200mm)61.2372435695795 mm

-

200

6.35

0.95 0.8

2

f d b

1 + N A

1A

= B N

2

1

1

= 0.85 'c p c c

A

P f A A

0.95d =

2

N m

0.95d =

2

N m

0.8bn =

2

f B

db

n' =4

f


2 =

0.9

ureqd

y

P t

F BN




Given:


t = mm Fy = 248.00 Mpa



Vux = N = 506.71 mm2

Vuz = N = 4.00 pcs -

d = 12.7 mm

φ = 0.75

lcx = 23.65 mm

lcz = 23.65 mm

d = 1/2 in


At x-direction:

80,128.87 N

= N N

Governing Rn:

Rn = N

Ru = N


= 80,128.87 N

= N < 80,128.87 N

Governing Rn:

Rn = N

Ru = N


At x-direction:

= 71,445.76 N

At Z-direction:

= 71,445.76 N

from bolt hole to

edge of plate x

direction:

= 30.00

mm

74,608.18

from bolt hole to

edge of plate z

direction:

= 30.00

mm

248

414


1.2(23.65mm)(6.35mm)(414Mpa)

6.35

=

=

210 Areaanchor bolt

=

55,956.14


<

74,608.18

80,128.87

2.4(12.7mm)(6.35mm)(414Mpa)

74,608.18

74,608.18

no. of bolts

sufficient!!

sufficient!!

240

55,956.14

1.2(23.65mm)(6.35mm)(414Mpa)

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

A


A




Design of miscellaneous connections:

Given:


d = 100.00 mm l = 100.00 mmbf = 100.00 mm w = 100.00 mm

Fy = 415.00 Mpa f'c = 10 Mpa

Pu = 740.00 N


If A1 = A2:

φc = 0.65

A1 required =

= mm2


A1 required=


= 10000 mm2

> mm2

1 Remarks:

2 A1 revised= 10,000.00 mm2

use A1= mm2

740N


10000.00


elements:= 1.00


= doesn't apply

=0.85(0.65)(10Mpa)(1)

133.94

133.9366516 mm2

133.94

use larger area

2

1

A

A

2

1

A

A

2

1

A A

1 required

2

1

(0.85 ' )

u

c c

P A

A f

A




=

180 mm -

100 mm -

use A1= mm2


=

= 99,450.00 N > N OK


= 0.74185548 mm

use: 6 mm



B= mmN= mm

t= mm

55.55555556

= mm

0.95(100) - 0.8(100)2

= 7.5 mm

107.50

0.85(0.65)(10)(18000)(1)

740.00

18000.00

mm

Use:

Use:

=

180 - 0.95(100mm)

2= 42.50 mm

180

100 - 0.8(100mm)

2= 10.00 mm

(100mmX100mm)^0.52

= 50.00 mm

50.00 mm

2(740N)

0.9(415Mpa)(180mm)(100mm)50 mm

-

100

6

0.95 0.8

2

f d b

1 + N A

1A

= B N

2

1

1

= 0.85 'c p c c

A

P f A A

0.95d =

2

N m

0.95d =

2

N m

0.8bn =

2

f B

db

n' =4

f


2 =

0.9

ureqd

y

P t

F BN




Given:


t = mm Fy = 248.00 Mpa



Vux = N = 506.71 mm2

Vuz = N = 4.00 pcs

d = 12.7 mm

φ = 0.75

lcx = 3.65 mm

lcz = 3.65 mm

d = 1/2 in


At x-direction:

75,712.32 N

= N N

Governing Rn:

Rn = N

Ru = N

At z-direction:= 2.4(12.7mm)(6mm)(414Mpa)

= 75,712.32 N

= N < 75,712.32 N

Governing Rn:

Rn = N

Ru = N


At x-direction:

= 71,445.76 N

At Z-direction:

= 71,445.76 N

from bolt hole to

edge of plate x

direction:

= 10.00

mm

10,879.92

from bolt hole to

edge of plate z

direction:

= 10.00

mm

248

414


1.2(3.65mm)(6mm)(414Mpa)

6

=

=


=

8,159.94


<

10,879.92

75,712.32

2.4(12.7mm)(6mm)(414Mpa)

10,879.92

10,879.92

no. of bolts

sufficient!!

sufficient!!

590

8,159.94

1.2(3.65mm)(6mm)(414Mpa)

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

A


A




Design of base plates at wall supporting billboard:

Given:


d = 150.00 mm l = 200.00 mmbf = 100.00 mm w = 200.00 mm

Fy = 415.00 Mpa f'c = 10 Mpa

Pu = 1,060.00 N


If A1 = A2:

φc = 0.65

A1 required =

= mm2


A1 required=


= 15000 mm2

> mm2

1 Remarks:

2 A1 revised= 30,000.00 mm2

use A1= mm2

1060N


30000.00


elements:= 1.00


= doesn't apply

=0.85(0.65)(10Mpa)(1)

191.86

191.8552036 mm2

191.86

use larger area

2

1

A

A

2

1

A

A

2

1

A A

1 required

2

1

(0.85 ' )

u

c c

P A

A f

A




=

200 mm -

200 mm -

use A1= mm2


=

= 221,000.00 N > N OK


= 0.72947139 mm

use: 6.35 mm



B= mmN= mm

t= mm

150

= mm

0.95(150) - 0.8(100)2

= 31.25 mm

204.46

0.85(0.65)(10)(40000)(1)

1,060.00

40000.00

mm

Use:

Use:

=

200 - 0.95(150mm)

2= 28.75 mm

200

200 - 0.8(100mm)

2= 60.00 mm

(150mmX100mm)^0.52

= 61.24 mm

61.24 mm

2(1060N)

0.9(415Mpa)(200mm)(200mm)61.2372435695795 mm

-

200

6.35

0.95 0.8

2

f d b

1 + N A

1A

= B N

2

1

1

= 0.85 'c p c c

A

P f A A

0.95d =

2

N m

0.95d =

2

N m

0.8bn =

2

f B

db

n' =4

f


2 =

0.9

ureqd

y

P t

F BN




Given:


t = mm Fy = 248.00 Mpa



Vux = N = 506.71 mm2

Vuz = N = 4.00 pcs -

d = 12.7 mm

φ = 0.75

lcx = 23.65 mm

lcz = 23.65 mm

d = 1/2 in


At x-direction:

80,128.87 N

= N N

Governing Rn:

Rn = N

Ru = N


= 80,128.87 N

= N < 80,128.87 N

Governing Rn:

Rn = N

Ru = N


At x-direction:

= 71,445.76 N

At Z-direction:

= 71,445.76 N

from bolt hole to

edge of plate x

direction:

= 30.00

mm

74,608.18

from bolt hole to

edge of plate z

direction:

= 30.00

mm

248

414


1.2(23.65mm)(6.35mm)(414Mpa)

6.35

=

=


=

55,956.14


<

74,608.18

80,128.87

2.4(12.7mm)(6.35mm)(414Mpa)

74,608.18

74,608.18

no. of bolts

sufficient!!

sufficient!!

850

55,956.14

1.2(23.65mm)(6.35mm)(414Mpa)

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

1.2 Fn c u

R l t

1.2 F 2.4 d t Fn c u u

R l t 2.4 d t Fu

A


A


Connnecction Design Combined

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